assigment g10 ec latest

7/31/2019 Assigment g10 Ec Latest

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UNIVERSITI TEKNIKAL MALAYSIA MELAKA

FAKULTI TEKNOLOGI KEJURUTERAAN

ELECTRIC CIRCUIT 2

BTNT 1023

GROUP ASSIGNMENT :

PSPICE AND MATLAB

LECTURER :

ENCIK MOHD FAUZI BIN AB RAHMAN

PREPARED BY :

MOHAMMAD FIRDAUS BIN NORAZMAN B 071110213

HIFDZUL MALIK BIN ZAINAL B 071110202

AZWAN BIN MUHAMAD B 071110396

ELLYANA SHAIRA BINTI ABD AZIZ B 071110236


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1.0 TITLEGroup Assignment : Electric Circuit

2.0 OBJECTIVE To analyze the given circuits using the specific software in order to identify the

required needs.

To familiarize PSPICE and MATLAB function by doing a circuit simulationon certain circuit analysis.

3.0 EQUIPMENTS PSPICE MATLAB

4.0 REQUIREMENTS

1. The circuits were analyzed by using the specific software that mention in thequestions and the comparison between manual calculation and software

analysis were done.

2. The report were including the manual calculation, print screen of softwareanalysis and the comparison. The report were submitted in hardcopy as well.

3. The software analysis and report were submitted in CD.


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5.0 QUESTIONS AND ANSWERS

1)The switch in Figure 1 has been in position 1 for a long time. At t= 0, it isswitched to position 2. Use Pspice to find i(t) for 0


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Result

**** 05/30/12 02:42:53 ******* PSpice Lite (April 2011) ******* ID# 10813 ****

** Profile: "SCHEMATIC1-SOLAN 1" [ C:\OrCAD\OrCAD_16.5_Lite\tools\capture\tes-

PSpiceFiles\SCHEMATIC1\SOLAN 1.sim ]

**** CIRCUIT DESCRIPTION

******************************************************************************

** Creating circuit file "SOLAN 1.cir"

** WARNING: THIS AUTOMATICALLY GENERATED FILE MAY BE OVERWRITTEN BY

SUBSEQUENT SIMULATIONS

*Libraries:

* Profile Libraries :

* Local Libraries :

* From [PSPICE NETLIST] section of C:\OrCAD\OrCAD_16.5_Lite\tools\pspice\PSpice.ini file:

.lib "nomd.lib"

*Analysis directives:

.DC LIN V_V1 0 0.2 1

.PROBE V(alias(*)) I(alias(*)) W(alias(*)) D(alias(*)) NOISE(alias(*))

.INC "..\SCHEMATIC1.net"

**** INCLUDING SCHEMATIC1.net ****

* source TES

R_R1 N00208 N00215 4k TC=0,0

R_R2 N00215 N00271 1k TC=0,0

R_R3 0 N00215 2k TC=0,0

L_L1 N00271 0 100m

C_C1 N00625 0 100u

V_V1 N00208 0 10Vdc

X_U1 N00625 N00215 Sw_tClose PARAMS: tClose=0.2 ttran=1u Rclosed=0.01


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+ Ropen=1Meg

V_PRINT1 N00215 0 0V

.PRINT TRAN I(V_PRINT1)

**** RESUMING "SOLAN 1.cir" ****

.END

**** 05/30/12 02:42:53 ******* PSpice Lite (April 2011) ******* ID# 10813 ****


PSpiceFiles\SCHEMATIC1\SOLAN 1.sim ]

**** Voltage Controlled Switch MODEL PARAMETERS

******************************************************************************

X_U1.Smod

RON .01

ROFF 1.000000E+06

VON 1

VOFF 0

JOB CONCLUDED

*** 05/30/12 02:42:53 ******* PSpice Lite (April 2011) ******* ID# 10813 ****


PSpiceFiles\SCHEMATIC1\SOLAN 1.sim

**** JOB STATISTICS SUMMARY

******************************************************************************

Total job time (using Solver 1) = 0.00

Conclusion Question 1

The switch in Figure 1 has been in position 1 for a long time. At t= 0, it is switched to

position 2. By using Pspice we find i(t) for 0 < t< 0.2 s. We had set the start value by o,

end value 0.2 and the increment is 1. Circuit description explains all about the circuit after it run

successfully.


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2)Use PSpice to find vo(t) in the circuit if Figure 2. Let is = 2 cos(103t) A.

Figure 2

PSpice Schematic


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Simulation settings

Simulation Result


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Simulation Output:

**** 05/30/12 04:28:53 ********* PSpice 9.1 (Mar 1999) ******** ID# 0 ********

** circuit file for profile: Q2 Zul

**** CIRCUIT DESCRIPTION

** WARNING: THIS AUTOMATICALLY GENERATED FILE MAY BE

OVERWRITTEN BY SUBSEQUENT PROFILES

*Libraries:

* Local Libraries :

* From [PSPICE NETLIST] section of pspice91.ini file:

.lib "nom.lib"

*Analysis directives:

.AC DEC 1 159.15 159.15

.PROBE

.INC "esaimen q2-SCHEMATIC1.net"

**** INCLUDING "esaimen q2-SCHEMATIC1.net" ****

* source ESAIMEN Q2

C_C1 0 N00052 4uF

L_L1 0 N00060 10mH

R_R1 N00052 N00025 2

R_R2 N00060 N00025 6

R_R3 N00052 N00060 8

R_R4 0 N00025 4

I_Is N00025 0 DC 0Adc AC 2Aac

.PRINT AC+ VM([N00052])

+ VP([N00052])

**** RESUMING "esaimen q2-SCHEMATIC1-Q2 Zul.sim.cir" ****

.INC "esaimen q2-SCHEMATIC1.als"

**** INCLUDING "esaimen q2-SCHEMATIC1.als" ****

.ALIASES

C_C1 C1(1=0 2=N00052 )


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L_L1 L1(1=0 2=N00060 )

R_R1 R1(1=N00052 2=N00025 )

R_R2 R2(1=N00060 2=N00025 )

R_R3 R3(1=N00052 2=N00060 )

R_R4 R4(1=0 2=N00025 )

I_Is Is(+=N00025 -=0 )

.ENDALIASES

**** RESUMING "esaimen q2-SCHEMATIC1-Q2 Zul.sim.cir" ****

.END

**** SMALL SIGNAL BIAS SOLUTION TEMPERATURE = 27.000 DEG C

NODE VOLTAGE NODE VOLTAGE NODE VOLTAGE NODE

VOLTAGE

(N00025) 0.0000 (N00052) 0.0000 (N00060) 0.0000

VOLTAGE SOURCE CURRENTS

NAME CURRENT

TOTAL POWER DISSIPATION 0.00E+00 WATTS

**** AC ANALYSIS TEMPERATURE = 27.000 DEG C

FREQ VM(N00052) VP(N00052)

1.592E+02 6.638E+00 -1.600E+02

JOB CONCLUDED

TOTAL JOB TIME 1.22


Question 2 are also need to be solve by using PSpice in order to find Vo(t) in the circuit of

Figure 2. Then, is = 2 cos(103t) A. this time we set the start value by 159.15, end value

159.15 and the decade is 1.


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3)Determine Vo and Io in the circuit of Figure 3 using MATLAB by applyingmesh analysis.

Figure 3

Calculation

1 I3 = 4 -30

VO = 2 (I3I1)

= 2I3 -2I1 2

Substitute 1 into 2:

VO = 2 (I3- I1)

= 2I3- 2I1

= 2 (4 -30)2I1

= (8 -30)2I13

For Mesh 1 :

3VO + 2 (I1- I3) + j4I1 = 0 4

Substitute 1 and 3 into equation 4 :

3VO + 2 (I1 - I3) + j4I1 = 0

3[(8 -30)2I1] + 2I12(4 -30) + j4I1 = 0

(24 -30)6I1 + 2I1(8 -30) + j4I1 = 0

-4I1 + j4I1 + (16 -30) = 0

(4 - j4)I1 = 16 -30


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For Mesh 2 :

-3VOj2IO = 0

- j2IO = 3VO

- j2IO = 3[(8 -30)2I1)

- j2IO = (24 -30)6I1

6I1j2IO = 24 -30

To use Cramers Rule, equation 5 and 6 in matrix form as :

4j4 0 I1 16 -30

6 - j2 IO 24 -30

Obtain the determinants :

= 4j4 0

6 - j2

= (4j4)(-j2)(0)(6)

= -8j8

= 11.31 -135

1 = 16 -30 0

24 -30 - j2

= (16 -30)(-j2)(0)(24 -30)

= -16j27.71

= 32 -120

O = 4j4 16 -30

6 24 -30

= (4j4)(24 -30)(6)(16 -30)

= -48j83.14

= 96 -120

=


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Thus :

I1=

=

= 2.733 + j0.732 A

= 2 15 A

IO =

=

= 8.199 + j2.197 A

= 8.49 15 A

So,

-3VOj2IO = 0

- j2IO = 3VO

VO =

=

= 1.465j5.467 V

= 5.66 -75 V


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Software analysis

Comparison between calculation and analysis

CALCULATION MATLAB

I1 (A) 2.733 + j0.732

2 15

0.7325 + 2.7325i

2 75

IO (A) 8.199 + j2.197

8.49 15

2.1975 + 8.1925i

8.48 75

VO (V) 1.465j5.467

5.66 -75

5.4617 - 1.4650i

5.65 -15

Table 1


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For Question 3, we are needed to determine the IO and VO in the circuit. Then

we had applied mesh analysis to calculate the IO and VO. Firstly, we draw three loop

in this circuit. We assigned mesh currents. We labelled it as I1, IO and I3. For I3, it

have given there that is 4 -30 A. After that, applied KVL to each of the meshes.

At this part, use Ohms Law to express the voltages in terms of the mesh currents.

Next, solve the resulting simultaneous equation to get the mesh currents. For this

circuit, it has two equations. To get the mesh currents, it has some method. The first

method is by using the substitution method and the second method is by using

Cramers Rule. We were using Cramers Rule to solve the equation. To use

Cramers Rule, we cast equation 5 and 6 in matrix form. After we get the current

and voltage value by using calculation method, we simulate it by using MATLAB

software. Lastly, we compared the value with calculation and MATLAB in Table 1.

In Table 1 show the value of current and voltage for both method. The value for

both method are same but difference degree.


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4)Determine the wattmeter reading of the circuit in Figure 4. (Applicationquestion, no software needed)

Figure 4

= 100,

10mH j100x10x = j

500uF

=

= -

j20

The frequencydomain circuit is shown below

Figure 4


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At node 2,

+

=

0 =(20+j)V1(19+j)V2

Solving (1) and (2) yields

V1= 1.5568j 4.1405

I =

= 0.2111 + j 0.1035 , S =

V1 * I = - 0.04993j 0.5176

P = Re (S) = 50 mW


This question needs us to determine the wattmeter reading of the circuit in Figure 4. This

time, no software needed. We had constructed the frequency domain circuit. Next, we

make a calculation at node 2. Finally we get the answer, P = Re (S) = 50 mW.


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5)Use PSpice to generate the magnitude and phase Bode plots ofVo in the circuitof Figure 5

Figure 5

PSpice Schematic


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Magnitude Bode Plots

Phase Bode Plots


For this question, we had use PSpice to generate the magnitude and phase Bode

plots ofVo in the circuit of Figure 5. Bode plots are really log-log plots, so they collapse a

wide range of frequencies (on the horizontal axis) and a wide range of gains (on the

vertical axis) into a viewable whole. As we know bode plots is a plots of frequency

response. Gain and phase are displayed in separate plot. To get the phase bode plot, we

need to add p to the equation in magnitude bode plots.


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6.0 DISCUSSION:

Bode magnitude of the system response in absolute units, returned as a 3-D array

with dimensions (number of outputs) (number of inputs) (number of frequency points).

For a single-input, single-output (SISO) sys, mag(1,1,k) gives the magnitude of the

response at the kth frequency. For MIMO systems, mag(i,j,k) gives the magnitude of the

response from the jth input to the ith output. We can convert the magnitude from absolute

units to decibels using:

magdb = 20*log10(mag)

In Pspice, if the library is not available, you need to add the library, by clicking on

the Add Library button. This will bring up the Add Library window. Select the desired

library. For Spice you should select the libraries from the Capture/Library/PSpice folder.

Analog: contains the passive components (R,L,C), mutual inductane, transmission line, and

voltage and current dependent sources (voltage dependent voltage source E, current-

dependent current source F, voltage-dependent current source G and current-dependent

voltage source H).

Source: give the different type of independent voltage and current sources, such as

Vdc, Idc, Vac, Iac, Vsin, Vexp, pulse, piecewise linear, etc. Browse the library to

see what is available.

Eval: provides diodes (D), bipolar transistors (Q), MOS transistors, JFETs

(J), real opamp such as the u741, switches (SW_tClose, SW_tOpen), various

digital gates and components.

Abm: contains a selection of interesting mathematical operators that can be applied

to signals, such as multiplication (MULT), summation (SUM), Square Root

(SWRT), Laplace (LAPLACE), arctan (ARCTAN), and many more.Special: contains a variety of other components, such as PARAM, NODESET and

others.

Spice allows us to do a DC bias, DC Sweep, Transient with Fourier analysis, AC analysis,

Montecarlo/worst case sweep, Parameter sweep and Temperature sweep.


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We are also use MATLAB in this assigment, the MATLAB application is built

around the MATLAB language, and most use of MATLAB involves typing MATLAB

code into the Command Window (as an interactive mathematical shell), or executing text

files containing MATLAB code and functions. Then, the variables are defined using the

assignment operator, =. MATLAB is a weakly programming language. It is a weakly typed

language because types are implicitly converted. It is a dynamically typed language

because variables can be assigned without declaring their type, except if they are to be

treated as symbolic objects, and that their type can change.

7.0 CONCLUSION:

Finally, after finishing this assignment, students are now able to analyze the given

circuits using the specific software in order to identify the required output or result needs.

After that, students are also able to familiarize with PSPICE and MATLAB software with

the function by doing a circuit simulation on certain circuit analysis. Other than that, while

we finishing this assignment there are some problem appear when we want to construct the

circuit, but as an engineering student we had learn on how to troubleshoot and solve the

problem. Lastly, we had finished this assignment successfully.

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