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TEKNIK MENJAWABTEKNIK MENJAWAB
MATEMATIKMATEMATIK
KERTAS 2KERTAS 2
OLEH :OLEH :
SITI NOR RAYA BT ABDUL RAHIMSITI NOR RAYA BT ABDUL RAHIM
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AGIHAN SOALANAGIHAN SOALAN
KERTAS 1KERTAS 1 -- 1 jam 151 jam 15 minitminit
-- 4040 soalansoalan objektifobjektif
-- 4040 markahmarkah
KERTAS 2KERTAS 21 jam 451 jam 45 minitminit
-- 2020 soalansoalan subjektifsubjektif-- 6060 markahmarkah
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TOPIK DALAM KERTAS 2TOPIK DALAM KERTAS 2
Directed numbersDirected numbers
Square, square roots, cubes, cubes rootsSquare, square roots, cubes, cubes roots
Linear equationsLinear equations
Linear InequalitiesLinear Inequalities Algebraic ExpressionsAlgebraic Expressions
Algebraic FormulaeAlgebraic Formulae IndicesIndices
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KERTAS 2KERTAS 2
StatisticsStatistics
TrigonometryTrigonometry
Graph of FunctionsGraph of Functions
Geometrical ConstructionsGeometrical Constructions Loci in Two DimensionsLoci in Two Dimensions
TransformationsTransformations Scale DrawingsScale Drawings
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KERTAS 1KERTAS 1 Whole numbersWhole numbers
Number pattern andNumber pattern andsequencessequences
FractionsFractions
DecimalsDecimals
PercentagesPercentages
IntegersIntegers
Lines and AnglesLines and Angles
PolygonsPolygons CirclesCircles
Algebraic expressionsAlgebraic expressions
Perimeter and AreaPerimeter and Area
Solid GeometrySolid Geometry Graph of FunctionsGraph of Functions
Linear EquationsLinear Equations
Ratios, rates andRatios, rates andProportionsProportions
CoordinatesCoordinates
Loci in two dimensionsLoci in two dimensions
StatisticsStatistics TransformationsTransformations
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Directed numbersDirected numbers
BODMASBODMASselesaikanselesaikan kurungankurungan,, kuasakuasa
duadua atauatau tigatiga, division, multiplication,, division, multiplication,additionaddition dandan subtractionsubtraction
KuasaiKuasai pendarabanpendaraban,, pembahagianpembahagian,,pecahanpecahan dandan perpuluhanperpuluhan dengandengan baikbaik..
MestiMesti hafalhafal sifirsifir
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Examples 1:Examples 1:
86865(32 + 565(32 + 56 7)7)
Solution:Solution:
= 86= 865( 32 + 8)5( 32 + 8)
= 86= 865( 40)5( 40)= 86= 86200200
== -- 114114
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Examples 2:Examples 2:
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Examples :Examples :
1. 1001. 1004( 244( 24 4 + 9)4 + 9)2.2.0.60.6(( -- ++ 33//55))
3. 5.64 x 0.23. 5.64 x 0.2((--11 ))4. ( 34. ( 322 11//88)) 0.050.05
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Squares, square roots, cube andSquares, square roots, cube and
cube rootscube roots
Example 1 :Example 1 :
Solve a)Solve a) 0.250.25
b) (b) ( 6464 -- 33 125)125)22
Solution:Solution:
a) 0.5 N1a) 0.5 N1
b) ( 8b) ( 85)5) 22 K1K1
= (3)= (3)22
= 9 N1= 9 N1
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Example 2:Example 2:
a)a) 33 0.2160.216
b) (3.3b) (3.3 33 27)27)22
Solution:Solution:
a) 0.6 N1a) 0.6 N1 b) ( 3.3b) ( 3.3 3)3) 22
= (1.1)= (1.1)
22
K1K1= 1.21 N1= 1.21 N1
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Examples:Examples:
1. a)1. a) 33 0.5120.512
b) 4b) 422 x (x (33 --2727//88))
2. a)2. a) 33 --0.0270.027b) 2b) 233 ((22//55))
22
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StatisticsStatistics
Bar chartsBar charts
Line graphsLine graphs
PictogramsPictograms
Pie chartsPie charts Mode, median, meanMode, median, mean
Frequency tableFrequency table
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Bar chartBar chart
0
10
20
30
40
50
60
70
80
90
Jan Feb March April
Month
Totalsales
Month
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Dual Bar chartDual Bar chart
010
20
30
4050
60
70
80
90
3 Bijak 3 pintar 3 cerdas 3 Arif
BoyGirl
Number ofstudents
Class
Mesti tulis petunjuk
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Line GraphLine Graph
0
10
20
30
40
50
60
70
80
90
3 Bijak 3 Cerdas 3 Arif 3 Pintar
Class
Jangan sambungkan point yg pertama dari sifar. Labelkankedua-dua axes.
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Pie ChartPie Chart
3a
3b
3c
3d
3e
3c3c9003d
1200
3e800
3b500
3a200
Mesti labelkan sudut dan nama sektor. Ukuran mesti tepat.
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pictogramspictograms
20052005 20042004 20032003
20022002 20012001
represent 50 studentsrepresent 50 students
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Mode, median and meanMode, median and mean ModeModefrequencyfrequency tertinggitertinggi
MedianMedianitem yangitem yang terdapatterdapat didi tengahtengah
tengahtengah datadata
MeanMeanpuratapurata/ average/ average
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Determine the mode, median and mean forDetermine the mode, median and mean for
data given : 3, 5, 5, 4, 5, 6, 7, 9, 4data given : 3, 5, 5, 4, 5, 6, 7, 9, 4
Answer :Answer :
Mode = 5Mode = 5 Median = 3, 4, 4, 5, 5, 5, 6, 7, 9Median = 3, 4, 4, 5, 5, 5, 6, 7, 9
= 5 (= 5 ( susunsusun dahuludahulu datadata mengikutmengikut
tertibtertib menaikmenaik))Mean =Mean = 3 + 4+ 4+ 5+ 5+ 5+ 6+ 7+ 93 + 4+ 4+ 5+ 5+ 5+ 6+ 7+ 9
99
== 484899
= 5.33= 5.33
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Determine mode, median and mean from theDetermine mode, median and mean from the
frequency table belowfrequency table below
44664455FrequencyFrequency
33221100ScoreScore
a) Mean = 2b) Median = (19 +1) 2 = 10 th
= 2c) Mean = 0(5) + 1(4) + 2(6) + 3(4)
19= 4 + 12 + 12
19= 28 19= 1. 47
Common mistake = 28 4 = 7
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Construct a frequency table.Construct a frequency table. 4, 2, 1, 5, 3, 2, 2, 2, 4, 1, 1, 5, 5, 2, 2, 5, 24, 2, 1, 5, 3, 2, 2, 2, 4, 1, 1, 5, 5, 2, 2, 5, 2
Answer :Answer :
Determine the mode, median and meanDetermine the mode, median and mean
Saving
frequency
1 2 3 4 5
3 7 1 24
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IndicesIndices Law of indicesLaw of indices
aamm x ax ann = a= a m+nm+n
aamm aann = a= a mm--nn
((aamm))nn == aamxnmxn aa1/n1/n == nnaa
aa--nn == 11/a/ann
aan/mn/m == nnaamm
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Examples 1:Examples 1: kk22 x kx k44 kk--22
= k= k 2+42+4((--2)2)
= k= k 88
Common mistakeCommon mistake::
= k= k 2+42+422
= k= k 44
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Examples 2:Examples 2: Simplify : (2mSimplify : (2m33nn22))33 x mx m--44nn22 mm22nn--33
Solution:Solution:
= 2= 233mm99nn66 x mx m--44nn22 mm22nn--33 K1K1
= 8m= 8m 9+(9+(--4)4)--22 nn 6+26+2--((--3)3) K1K1
= 8m= 8m33nn1111 N1N1 Common mistakeCommon mistake
=2=2
33
mm
99
nn
66
x mx m
--44
nn
22
mm
22
nn
--33
K1K1 == 66mm 9+(9+(--4)4)--22 nn 6+26+2--((--3)3) K0K0
== 66mm33nn1111 N0N0
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Examples 3:Examples 3:
Evaluate :Evaluate : 88 1/31/3 x 27x 27 1/31/3
22 --11
Solution :Solution :== ( 2( 233))1/31/3 x ( (3x ( (333))1/31/3
22--11
= 2 x 3 x 2= 2 x 3 x 2
= 12= 12
Or 216Or 216 1/31/3 x 2x 2= ( 6= ( 633))1/31/3 x 2x 2
= 6 x 2 = 12= 6 x 2 = 12
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Examples 4:Examples 4: 33 --22 x 3x 3 nn = 81, find the value of n= 81, find the value of n
Solution:Solution:
33 --22 x 3x 3 nn = 3= 344 (( tukarkantukarkan kpdkpd basebase ygyg
samasama iaituiaitu 33 ------ 81= 381= 344
))--2 + n = 4 (2 + n = 4 ( ambilambil indeksindeks sahajasahaja--abaikanabaikan
base)base)
n = 4 + 2 (n = 4 + 2 ( selesaikanselesaikan sptspt linear equation)linear equation)
= 6= 6
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Examples:Examples:1. m1. m33 mm22 x mx m--33
2.2. kk22hh33 x (3x (322khkh22))22
3k3k44hh66
3. 163. 16 1/31/3 x 4x 41/31/3 88 --1/31/3
4. 54. 5 --22 x 125 = 5x 125 = 5nn, find the value of n, find the value of n
5. x5. x33 = 8, find the value of x= 8, find the value of x--11
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SELAMAT MENCUBASELAMAT MENCUBA
SEMOGA BERJAYA!!!SEMOGA BERJAYA!!!SASARKAN A UNTUK MATEMATIKSASARKAN A UNTUK MATEMATIK
PMR 2010PMR 2010