teknik menjawab tahun 4(fasa 1)

8/9/2019 Teknik Menjawab Tahun 4(Fasa 1)

1/28

THKBJIK[

BG_ TG OHT HEEHKTIUHAMTB[ M[_HP[7


2/28

Amtb{ i{ kga~xf{gpy {x`lhkt * Kgjtmij twg ~m~hp " ~m~hp = mjd 0) ^m~hp = 1 = bgxp*" 4> g`lhktiuh }xh{tigj{)

^m~hp 0 1 4> aijxth{*" 0> {x`lhktiuh }xh{tigj) ^m~hp = 1 4> ampc{ mjd ^m~hp 0 1 4> ampc{* ^m~hp = # ^m~hp 0 1 =>> ampc{

=>>=>>2>

4>4>1

#

IJTPGDXKTIGJ


3/28

TI^[ EGP MJ[_HPIJO ]XH[TIGJ[^M^HP =

Eip{t phmd mjd xjdhp{tmjd }xh{tigj{* [hkgjd kbgg{h mjd mj{whpijo }xh{tigj{ tbmt hm{ihp tg ygx*"^ifib dmj

lmwm` {gmfmj ymjo axdmb dmbxfx*)

Tbmj tpy tg mj{whp ij m {bgpt tiah*"Kx`m lmwm` {gmfmj dhjomj kh~mtdmj th~mt*) Fhmuh tbh }xh{tigj methp 0 aijxth{ "Tijoomfcmj xjtxc {hahjtmpm

{gmfmj ymjo tidmc `gfhb dilmwm` {hfh~m{ am{m ahjoipmjym ahfh`ibi 0aijit*)

Ampc ygxp mj{whp mt ygxp mj{whp {bhht*"Tmjdmcmj thpx{ lmwm~mj ~mdmchptm{ lmwm~mj*) Mt fm{t& phtxpj tg tbh }xh{tigj{ tbmt ygxp kmjjgt mj{whphd mt tbh eip{t

mjd amch {xph it i{ ampc* "Cha`mfi ahjlmwm` {gmfmj ymjo tidmc dm~mtdilmwm` tmdi dmj ~m{ticmj im ditmjdmcmj lmwm~mjjym lxom*


4/28

KBMPMKTHPI[TIK[ GE ^M^HP II]XH[TIGJ[

Tg th{t `m{ik {ciff{ ge amtbhamtik ij aijiaxa {tmoh*"Ahjoxli chambipmj m{m{ Amthamtic ~mdm tmbm~ ymjoaijiaxa)*

Fhuhf ge tbh }xh{tigj{ mph jgt tgg biob* "Mpm{ ch{xcmpmj{gmfmj tidmc thpfmfx tijooi)*

Jxa`hp{ x{h mph jgt agph tbmj 8 dioit{* "Jga`gp!jga`gp ymjo thpfi`mt axdmb dichjdmficmj "{hbijoom 8dioit))*

Gjfy twg g~hpmtigj{ ijugfuh* "Tidmc ahfi`mtcmj fh`ibdmpi~mdm dxm g~hpm{i)*

Kmjjgt ph!opgx~ twikh*" Tidmc ahfh`ibi dxm cmfiahjoxa~xf {haxfm)*

[ia~fh mjd hm{y {hjthjkh{* " Mymt ymjo thpfi`mt mdmfmbpijocm{ dmj axdmb diembmai)*


5/28

Jmah mjd wpith jxa`hp{

Dhthpaijh tbh ~fmkh umfxh

Kga~mph tbh umfxh ge jxa`hp

Pgxjd gee jxa`hp

Mdd twg tg egxp jxa`hp{

[gfuh mdditigj ~pg`fha{

[x`tpmkt gjh gp twg jxa`hp{

[gfuh {x`tpmktigj ~pg`fha{

Axfti~fy 0& ; mjd 4 dioit jxa`hp{

[gfuh axfti~fikmtigj ~pg`fha{

Diuidh 4 mjd 8 dioit jxa`hp{

[gfuh diui{igj ~pg`fha{

Airhd g~hpmtigj{ ijugfuijo mdditigjmjd {x`tpmktigj

[gfuh ~pg`fha{ ijugfuijo airhdg~hpmtigj{


6/28

Jmah mjd wpith ~pg~hp epmktigj

Mdditigj epmktigj

[x`tpmktigj epmktigj


7/28

Jmah mjd wpith jxa`hp{

Thjtbgx{mjd{

Tbgx{mjd{ Bxjdphd{ thj{ gjh{

4?;

mjd

I{ wpith m{ egxp bxjdphd mjd {huhjty!tbphh

;?4


8/28

Hrma~fh

=) _pith =4 9?5 ij wgpd{* " = ampc )

egxpthhj tbgx{mjd jijh bxjdphd mjd {huhjty!{ir

2 ;=>

0) _pith hiobt tbgx{mjd tbphh bxjdphd mjd thj ij jxahpmf{* " = ampc )


9/28

Dhthpaijh tbh ~fmkh umfxh

=4 9?5

T tb Tb B T G

= 4 9 ? 5

1 => >>> # 4 >>> # 9>> # ?> # 5

^fmkh umfxh ge 9 i{ bxjdphd{

^fmkh umfxh ge ? i{ thj{

^fmkh umfxh ge 5 i{ gjh{

^fmkh umfxh ge 4 i{ tbgx{mjd

^fmkh umfxh ge = i{ thjtbgx{mjd

^fmkh umfxh kbmpt{


10/28

Hrma~fh

=) _bmt i{ tbh ~fmkh umfxh ge dioit ; ij tbh jxa`hp 2 ;=> 7 " = ampc )

^fmkh umfxh ge ; i{ bxjdphd{

0) Tbh dioit umfxh ge dioit 2 ij tbh jxa`hp 2 ;=> i{ " = ampc )

Dioit umfxh ge 2 i{ 2 >>>


11/28

Kga~mph tbh umfxh ge jxa`hp

;5 ?4= mjd ;5 8=4

Thj tbgx{mjd{ Tbgx{mjd{ Bxjdphd{ thj{ gjh{

1 ;5 ?4= i{ fmpohp tbmj ;5 8=4

=4?5;

=485;

Hrma~fh_bikb ge tbh egffgwijo i{ tpxh 7 " = ampc )

M* 48 ?>2 {amffhp tbmj 48 8>2@* 5> >>= {amffhp tbmj 5> >=>K* 9 999 fmpohp tbmj => >>>D* 94; fmpohp tbmj 99>


12/28

Pgxjd gee jxa`hp

=) Pgxjd gee4 ??2 tg tbh jhmph{t thj

4 ??> 4 ?2>1 4 ??2 pgxjdhd tg tbh jhmph{t thj i{ 4 ?2>

Pgxjd gee 5 0;> tg tbh jhmph{t bxjdphd* " 0 ampc )

5 0>> 5 ;>>

1 5 0;> pgxjdhd tg tbh jhmph{t thj i{ 5 0>>

4 ??> 4 ??8 4 ??2 4 ?2>

5 0>> 5 08> 5 ;>>5 0;>

Hrma~fh

" = ampc )

" = ampc )


13/28

Mdd twg tg egxp jxa`hp{

T tb Tb B T G

0 = 5 ;

# = > 2 4 0

=) 0 =5; # => 240 # ;? ;8= 1

" 0 ampc )

5>

=

>;=

=

T tb Tb B T G

= ; > > 5

# ; ? ; 8 =

?8;>8

=

"= ampc ) "= ampc )


14/28

[gfuh mdditigj ~pg`fha{

=) [mfia bm{ 2 ;8= {tikchp{* [hfui bm{ = 8>0 {tikchp{ agph tbmj [mfia*

Bgw amjy {tikchp{ dg tbhy bmuh mftgohtbhp7 " ; ampc )

_bmt i{ oiuhj [mfia 1 2 ;8= {tikchp{[hfui 1 = 8>0 agph tbmj [mfia

_bmt i{ m{chd egp7 Tgtmf jxa`hp ge {tikchp{

_bmt g~hpmtigj i{ jhhdhd7 Mdditigj[gfuh

2 ;8= # = 8>0 # 2 ;8= 1

T tb Tb B T G

2 ; 8 =# = 8 > 0

;829

T tb Tb B T G

9 2 8 ;# ? ; 8 =

4>0?=

=

"= ampc ) "= ampc )

=

"= ampc )


15/28

[x`tpmkt gjh gp twg jxa`hp{

0) 5; ?29 ! 9 405 ! 0> 880 1 " 0 ampc )

T tb Tb B T G

5 ; ? 2 9

! 9 4 0 5

;5;48

T tb Tb B T G

8 4 ; 5 ;

! 0 > 8 8 0

==2;;

=) _bmt i{ dieehphjkh `htwhhj 84 ;=> mjd => ;487 " = ampc )

T tb Tb B T G

8 4 ; = >

! = > ; 4 8

85

8 => =>;

=>>=>

M* 40 9>8@* 4; 958K* 44 9;8D* 48 908

" = ampc ) " = ampc )


16/28

[gfuh {x`tpmktigj ~pg`fha{

) M epxit {hffhp {gfd 2 =;> gpmjoh{ mjd m~~fh{ fm{t agjtb* Tbh jxa`hp

ge gpmjoh{ {gfd wm{ 8 48>* Bgw amjy m~~fh{ did bh {hff7 " 0 ampc )

T tb Tb B T G

2 = ; >

! 8 4 8 >

_bmt i{ oiuhjGpmjoh{ mjd m~~fh{ {gfd1 2 =;>Gpmjoh{ {gfd 1 8 48>

_bmt i{ m{chd egp7 Jxa`hp ge m~~fh{ {gfd

_bmt g~hpmtigj i{ jhhdhd7 {x`tpmktigj

[gfuh 2 =;> ! 8 48> 1

>25

>

0

=>?=>

" = ampc )

" = ampc )


17/28

Axfti~xp~g{h Tm`fh

= 0 ; 4 8 5 ? 2 90

;

48

5

?2

9

4 5 2 => =0 =4 =5 =2

5 9 =8 =2 0= 04 0?

2 =0 0> 04 02 ;0 ;5=> 08 ;> ;8 4> 48

;> ;5 40 42 84

;8 40 49 85 5;4> 42 85 54 ?048 84 5; ?0 2=

=0

=4=5

=2

=8

=2

0=04

0?

=0

=50>

04

02;0

;5


18/28

Axfti~fy 0& ; mjd 4 dioit jxa`hp{

Eijd tbh ~pgdxkt ge 408 r ;> 1 " = ampc )

4 0 8

;

>

=8

>>

>5

=0

>>

>>

>8?1 =0 ?8>

M* =0 48>@* =0 88>K* =0 58>D* =0 ?8>


19/28

=) M tpmij bm{ =8 kgmkbh{* Ie gjh kgmkb kmppih{ 80 ~m{{hjohp& bgwamjy ~m{{hjohp{ kmj tbh tpmij kmppy7 " 0 ampc )

_bmt i{ oiuhj Gjh kgmkb kmppih{ 80 ~m{{hjohp

_bmt i{ m{chd egp7 Jxa`hp ge ~m{{hjohp{ ij =8 kgmkbh{

_bmt g~hpmtigj i{ jhhdhd7 Axfti~fikmtigj

[gfuh =8 r 80 1

[gfuh axfti~fikmtigj ~pg`fha{

>

8

0

8=

088

>

=>0

>

2

?

>

1 ?2>

" = ampc )

" = ampc )


20/28

Diuidh 4 mjd 8 dioit jxa`hp{

=) 04 859 4 1 " = ampc )

4 0 4 8 5 95

0 4!

8

=r4 4

0r4 2

;r4 =0

4r4 =5

8r4 0>

5r4 04

?r4 02

2r4 ;0

9r4 ;5

=

4!

= 5

4

= 5!

9

0

2!

Tbh mj{whp i{ 5 =40 phamijdhp =

= P


21/28

[gfuh diui{igj ~pg`fha{=) =0 ~hjkif{ mph ~mkchd ijtg m gr* Bgw amjy `grh{ mph jhhdhd tg

~mkc 9 ?0> ~hjkif{7 " 0ampc )

_bmt i{ oiuhj9 ?0> ~hjkif{=0 ~hjkif{ egphmkb `gr

_bmt i{ m{chd egp7 Jxa`hp ge `grh{ jhhdhd

_bmt g~hpmtigj i{ jhhdhd7 Diui{igj

[gfuh 9 ?0> =0 1R => 0 Tgtmf= => 0 =0

0 0> 4 04

; ;> 5 ;5

4 4> 2 42

8 8> => 5>5 5> =0 ?0

? ?> =4 24

2 2> =5 95

9 9> =2 =>2

=0 9 ? 0 >! 9 5

0=

2 =

0! =

>

> Tbh mj{whp i{ 2=>

>" = ampc )

" = ampc )


22/28

Airhd g~hpmtigj{ ijugfuijo mdditigj mjd {x`tpmktigj

=) 5 ==2 ! ; 8;5 # 8 094 1 " 0 ampc )

T tb Tb B T G

5 = = 2

! ; 8 ; 5

028

>

0

=>8=>

T tb Tb B T G

0 8 2 0# 8 0 9 4

5?2

=

?

" = ampc ) " = ampc )


23/28

[gfuh ~pg`fha{ ijugfuijo airhd g~hpmtigj{

) Aiam bm{ 40 Amfmy{imj {tma~{* Fyj omuh bhp =4 {tma~{* Aijmomuh Maip 0; Amfmy{imj {tma~{* Bgw amjy {tma~{ bm{ Aiam jgw7" ; ampc )

_bmt i{ oiuhj 40 mjd =4 {tma~{&omuh mwmy 0; {tma~{

_bmt i{ m{chd egp7 Jxa`hp ge {tma~{ Aiam bm{

_bmt g~hpmtigj i{ jhhdhd7 Airhd g~hpmtigj{& mdditigj mjd{x`tpmktigj

[gfuh 40 # =4 ! 0; 1

B T G

8 5! 0 ;

9?

B T G

4 0# = 4

58

" = ampc )

" = ampc )" = ampc )


24/28

Jmah mjd wpith ~pg~hp epmktigj

=4

_h phmd it m{ gjh }xmpthpgpgjh guhp egxp " = ampc )

=

04

_h phmd it m{ twg }xmpthp{ gptwg guhp egxp " = ampc )

;4

_h phmd it m{ tbphh }xmpthp{ gptbphh guhp egxp " = ampc )

=0

_h phmd it m{ gjh bmfegpgjh guhp twg " = ampc )

44

_h phmd it m{ egxp }xmpthp{&egxp guhp egxpgpgjh " = ampc )

gp =

jxahpmtgp

dhjgaijmtgp


25/28

Mdditigj ge epmktigj

Km{h gjh< {mah dhjgaijmtgp

Hrma~fh < =

8

;#8

=18

4

?

0 #?

; 1?

8

Hrma~fh < 0

" = ampc )


26/28

Km{h twg< dieehphjt dhjgaijmtgp " 0 ampc )

Bgw tg {gfuh7

!Eijd tbh h}xiumfhjt epmktigj{ `hegph {gfuh it*

8

;

# =>

;

1 08

0;

# =>

;

1

=>

5#

=>

;

1=>

9" = ampc )

" = ampc )


27/28

[x`tpmktigj ge epmktigj

Km{h gjh< {mah dhjgaijmtgp

Hrma~fh < =

8

;8

=18

0

?

; ?

0 1?

=

Hrma~fh < 0

" = ampc )


28/28

Km{h twg< dieehphjt dhjgaijmtgp " 0 ampc )

Bgw tg {gfuh7

!Eijd tbh h}xiumfhjt epmktigj{ `hegph {gfuh it*

8

;

=>

;

1 08

0;

=>

;

1

=>

5

=>

;

1=>

;" = ampc )

" = ampc )

teknik menjawab tahun 4(fasa 1)

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