pembahasan persamaan kuadrat x
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PEMBAHASAN SOAL PERSAMAAN KUADRAT
1. Jawab : A
x2
- 3x + 2 = 0a = 1, b = -3, c = 2
x1,2=b(b)
24.( a ) .(c)2.(a)
x1,2=(3 )(3)
24.(1 ) .(2)2.(1)
x1,2=398
2
x1,2=31
2
x1,2=31
2 x1=3+12 x1 = 2
x2=312 x2 = 1
2. Jawaban : ADiket : x2+ 2x 8 = 0 , akar akar = x1dan x2x2+ 16x 16p = 0, dengan akar akarna 2 x1dan !x2
Ditana : ni"ai p ada"a# . . . .
Jawab :
x2+ 2x 8 = 0
$ x 2 %$x +& % = 0
x1= 2 x2= -&
2 x1= &
! x2= -20
'er(a)aan ang di)ak(*d :
$x &%$ x + 20 % = 0x2+ 16x 80 = 0
16p = 80 p = !
3. Jawab :
x1+ x2= 3
x1 x2= 2
2 x1= !
x1=5
2
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010%2
1$8%
2
1$
2=+
++
+ xx
010%&&$%&
12$
2
=+++++
x
xx
0!18
0&01616112
2
2
=++
=++++++
xx
xxx
. Jawab :
x1,2=b(b)
24.( a ) .(c)2.(a)
x1,2=(2)(2)
2
4. (224 ) .(2)2.(2)
x1,2=2416232
4
x1,2=236162
4 =2294 2
4
x1,2=
94 24
2
=22928
4
x1,2=22(81)
2
4
x1,2=
2282
4
x1,2=24 22
4
x1=2+422
4 , adi x1 =2
x2=24 22
4 , adi x2 =44 2
4 = 1 -2
8. Jawab : 2 2x a = 0
3
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arat ra(ina" ada"a# D 4 0 dan D ada"a# bi".k*adrat (e)p*rna.
b2 &ac 4 0
$-2%2- &.1,$-a% 4 0 ....... & + &a 4 0
&$1+a% 4 0
aka $ 1 + a % )er*pakan bi".k*adrat (e)p*rna
/nt*k a = 0, 1 + 0 = 1a = 3, 1 + 3 = &
a = 8, 1 + 8 = 5
adi a = 0,3,8
5. Jawab : D
$ p + 1 %x2 2$p + 3%x + 3p = 0 )e)p*nai akar per(a)aan ke)bar )e)p*nai
(arat D = 0
Jadi b2 &ac = 0
$ 2$p + 3 %%2 & $ p+1 %.3p = 0
& $ p+ 3%2 12p$p+1% = 0
&$p2+6p+5% 12p2- 12p = 0
&p2 + 2&p + 36 12p2 - 12p = 0
-8p2+12p + 36= 0
2p2+ 3p + 5 = 0
$2p + 3%$ p -3% = 0
aka 2p + 3 = 0 ata* p -3 = 0
2p = -3 p = 3
' = -32
Jadi ni"ai p = -32 dan 3
10. Jawab : A
'er(a)aan k*adrat x
2
+ bx + c = 0 (arat )e)p*nai d*a akar ke)bar bi".k)p"ekada"a# D 7 0
Jadi b2 &ac 7 0 )aka b27 &c
11. Jawab : A
= $x-1%$x-3% = 0
= x2 &x +3 = 0
a = 1, b = -&, c = 3
rdinat titik ba"ik $b2a
,(b24ac)
4 a %
= $
1612
42.1
,% = $2,-1%
Jadi titk ba"ikna ada"a# $2,-1%
12. Jawab : D
= 8 2x x2= 0
a = -1, b = -2, c = 8
'er(a)aan (*)b* (i)etri :
x = $b2a % =
22.(1) = -1
13. Jawab :
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e"a"*i titik $-12 , 0%, )aka = ax2 !x 3
0 = a$-12%2 !$-12% 3
0 =1
4a+
5
23x 4
0 = a + 10 12
a = 21&. Jawab : D
2x2+ !x 3 = 0, )aka a = 2, b = !, c = -3
x1+ x2 =qb x1. x2 =
c
a
=25 =
32
1
x1+ 1
x2=x
1+x
2
x1x
2=
52
32
=5
3=12
3
1!. Jawab : 9
2x2 + 6x 1 = 0 )aka a = 2, b = 6 , c =-1
p + = =qb x1. x2 =
c
a
=62=3
=12
p2 + 2= $ p + % 2p
= $-3%2 2 $12 %
= 5 + 1
= 10
16. Jawab : 9
i(a" ' : x2 $x1 + x2% + x1x2 = 0, akar akarna x1= ; 1 dan x2 = < 1
'er(a)aan = x2+ x 2 = 0 )aka a = 1, b = , c = -2
; + < =qb = -
; < =c
a = -2
(e#ingga x1+ x2 = $; 1% + $< 1%
= ; + < 2
= --2
= -5
x1. x2 = $; 1%$< 1%
= ;< $; +
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= x2 + 5x + 6 = 0
1. Jawab = A
akar akarna 3x1 dan 3x2 dinatakan dengan 3x. n>er( 3x ada"a#x
3
?$x% = 2x2
- x ! = 0
?$x
3
= 2$x
3 2-
x
3 - ! = 0
=2x
2
9 - x ! = 0
= 2x2- 5x &! = 0
18. Jawab : 9
)x2 3x + @ = 0 , ) 0 dan a = ), b = -3, c = @
karena (a"a# (at* akarna d*a ka"i akar ang "ain, )aka x1= 2x2,(e#ingga
x1 + x2 =ab x1. x2 =
c
a
2x2 + x2 =3
m 2x2 . x2 =
1
2m
3x2 =3
m $ x2 %2 =
1
4m
x2 =1
m (
1
m)2
= 1
4m
1
m2 =
1
4m
)2= &)
)2 &) = 0
)$) - &% = 0
) = & ata* ) = 0
15. Jawab : A
&x2 px + 2! = 0 )aka a = &, b = -p, c = 2!
arat ked*a akar (a)a ada"a# D = 0
b2 &ac = 0$-p%2 &.&.2! = 0
p2 &00 = 0
$p-20%$p+20% = 0
p = 20 ata* p = -20
20. Jawab : A
2 + $) + 1% + & = 0 )aka a = 1, b = ) + 1, c = &
arat ked*a akar nata berbeda ada"a# D 4 0
b2 &ac 4 0
$)+1%2 &.1.& 4 0
2 + 2) + 1 16 4 0
2+ 2) 1! 4 0$)+!%$)-3% 4 0
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) 7 -! ata* ) 4 3
21. Jawab :
e"a"*i titik $-1
2 ,0%, )aka = ax2
22.23.
2&. Jawab : D
x1,2 =bD
2a
x1,2 =1414
24.5(55)25
x1,2 =14196+1100
10
x1,2 =141296
10
x1,2 =1436
10
x1 =22
10=2
1
5
x2 =5010
=5
2!. Jawab :
x1,2 =bD
2a
x1,2 =
2
929
24.2.7
x1,2 =(92)(81182+2 )56
4
x1,2 =(92)(27182 )
4
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x1,2 =(92)9 (322 )
4
x1,2 =(92)3(322 )
4
x1,2 =(92)3 (21)
4
x1 =(92 )+3 (21)
4=
92+3234
=11
2+1
22
x1 =(92 )3 (21 )
4=92323
4=32
26. Jawab :
x1,2 =bD
2a
x1,2 =44
24.1(3)2.1
x1,2 =428
2
x1,2 =427
2
x1=4+27
2=2+7
x2=4+27
2=27
2. Jawab : 9
x1,2 =bD
2a
x1,2 =(12)(12)
24.4 (9)
2.(4)
x1,2 =12144144
8
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x1,2 =120
8
x1 =12+0
8=1
1
2
x1 =120
8=1
1
2
28. Jawab : D
x1,2 =bD
2a
x1,2 =44
24.1(5)2.1
x1,2 =41620
2
x1,2 =44
2
x1,2 =42 i
2
x1 =4+2 i
2=2+i
x2 =42i
2=2i
25. Jawab =
2x2 x 3 = 0
$2x 3%$x + 1% = 0
x1= ; =3
2 ata* x2 = < = -1
& ; =4.
3
2 = 6
& < = &.$-1% = -&
'er(a)aan k*adrat ang akar akarna & ; = 6 dan & < = -& ada"a# :
$ x 6 %$ x + & % = 0
x2 2x 2& = 0
30. Jawab : 9
x2+ bx + c = 0, akar akarna x1 dan x2per(a)aan k*adrat ang akar akarna x1 + x2 dan x1.x2 ada"a# :
$x $x1 + x2 %%$ x $x1 . x2 % = 0
x1 + x2 = -b
$x $-b%%$ x c% = 0$x + b%$x c% = 0
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x2+ $ b c %x bc = 0
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