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  • 7/21/2019 Pembahasan Persamaan Kuadrat x

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    PEMBAHASAN SOAL PERSAMAAN KUADRAT

    1. Jawab : A

    x2

    - 3x + 2 = 0a = 1, b = -3, c = 2

    x1,2=b(b)

    24.( a ) .(c)2.(a)

    x1,2=(3 )(3)

    24.(1 ) .(2)2.(1)

    x1,2=398

    2

    x1,2=31

    2

    x1,2=31

    2 x1=3+12 x1 = 2

    x2=312 x2 = 1

    2. Jawaban : ADiket : x2+ 2x 8 = 0 , akar akar = x1dan x2x2+ 16x 16p = 0, dengan akar akarna 2 x1dan !x2

    Ditana : ni"ai p ada"a# . . . .

    Jawab :

    x2+ 2x 8 = 0

    $ x 2 %$x +& % = 0

    x1= 2 x2= -&

    2 x1= &

    ! x2= -20

    'er(a)aan ang di)ak(*d :

    $x &%$ x + 20 % = 0x2+ 16x 80 = 0

    16p = 80 p = !

    3. Jawab :

    x1+ x2= 3

    x1 x2= 2

    2 x1= !

    x1=5

    2

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    010%2

    1$8%

    2

    1$

    2=+

    ++

    + xx

    010%&&$%&

    12$

    2

    =+++++

    x

    xx

    0!18

    0&01616112

    2

    2

    =++

    =++++++

    xx

    xxx

    . Jawab :

    x1,2=b(b)

    24.( a ) .(c)2.(a)

    x1,2=(2)(2)

    2

    4. (224 ) .(2)2.(2)

    x1,2=2416232

    4

    x1,2=236162

    4 =2294 2

    4

    x1,2=

    94 24

    2

    =22928

    4

    x1,2=22(81)

    2

    4

    x1,2=

    2282

    4

    x1,2=24 22

    4

    x1=2+422

    4 , adi x1 =2

    x2=24 22

    4 , adi x2 =44 2

    4 = 1 -2

    8. Jawab : 2 2x a = 0

    3

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    arat ra(ina" ada"a# D 4 0 dan D ada"a# bi".k*adrat (e)p*rna.

    b2 &ac 4 0

    $-2%2- &.1,$-a% 4 0 ....... & + &a 4 0

    &$1+a% 4 0

    aka $ 1 + a % )er*pakan bi".k*adrat (e)p*rna

    /nt*k a = 0, 1 + 0 = 1a = 3, 1 + 3 = &

    a = 8, 1 + 8 = 5

    adi a = 0,3,8

    5. Jawab : D

    $ p + 1 %x2 2$p + 3%x + 3p = 0 )e)p*nai akar per(a)aan ke)bar )e)p*nai

    (arat D = 0

    Jadi b2 &ac = 0

    $ 2$p + 3 %%2 & $ p+1 %.3p = 0

    & $ p+ 3%2 12p$p+1% = 0

    &$p2+6p+5% 12p2- 12p = 0

    &p2 + 2&p + 36 12p2 - 12p = 0

    -8p2+12p + 36= 0

    2p2+ 3p + 5 = 0

    $2p + 3%$ p -3% = 0

    aka 2p + 3 = 0 ata* p -3 = 0

    2p = -3 p = 3

    ' = -32

    Jadi ni"ai p = -32 dan 3

    10. Jawab : A

    'er(a)aan k*adrat x

    2

    + bx + c = 0 (arat )e)p*nai d*a akar ke)bar bi".k)p"ekada"a# D 7 0

    Jadi b2 &ac 7 0 )aka b27 &c

    11. Jawab : A

    = $x-1%$x-3% = 0

    = x2 &x +3 = 0

    a = 1, b = -&, c = 3

    rdinat titik ba"ik $b2a

    ,(b24ac)

    4 a %

    = $

    1612

    42.1

    ,% = $2,-1%

    Jadi titk ba"ikna ada"a# $2,-1%

    12. Jawab : D

    = 8 2x x2= 0

    a = -1, b = -2, c = 8

    'er(a)aan (*)b* (i)etri :

    x = $b2a % =

    22.(1) = -1

    13. Jawab :

    4

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    e"a"*i titik $-12 , 0%, )aka = ax2 !x 3

    0 = a$-12%2 !$-12% 3

    0 =1

    4a+

    5

    23x 4

    0 = a + 10 12

    a = 21&. Jawab : D

    2x2+ !x 3 = 0, )aka a = 2, b = !, c = -3

    x1+ x2 =qb x1. x2 =

    c

    a

    =25 =

    32

    1

    x1+ 1

    x2=x

    1+x

    2

    x1x

    2=

    52

    32

    =5

    3=12

    3

    1!. Jawab : 9

    2x2 + 6x 1 = 0 )aka a = 2, b = 6 , c =-1

    p + = =qb x1. x2 =

    c

    a

    =62=3

    =12

    p2 + 2= $ p + % 2p

    = $-3%2 2 $12 %

    = 5 + 1

    = 10

    16. Jawab : 9

    i(a" ' : x2 $x1 + x2% + x1x2 = 0, akar akarna x1= ; 1 dan x2 = < 1

    'er(a)aan = x2+ x 2 = 0 )aka a = 1, b = , c = -2

    ; + < =qb = -

    ; < =c

    a = -2

    (e#ingga x1+ x2 = $; 1% + $< 1%

    = ; + < 2

    = --2

    = -5

    x1. x2 = $; 1%$< 1%

    = ;< $; +

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    = x2 + 5x + 6 = 0

    1. Jawab = A

    akar akarna 3x1 dan 3x2 dinatakan dengan 3x. n>er( 3x ada"a#x

    3

    ?$x% = 2x2

    - x ! = 0

    ?$x

    3

    = 2$x

    3 2-

    x

    3 - ! = 0

    =2x

    2

    9 - x ! = 0

    = 2x2- 5x &! = 0

    18. Jawab : 9

    )x2 3x + @ = 0 , ) 0 dan a = ), b = -3, c = @

    karena (a"a# (at* akarna d*a ka"i akar ang "ain, )aka x1= 2x2,(e#ingga

    x1 + x2 =ab x1. x2 =

    c

    a

    2x2 + x2 =3

    m 2x2 . x2 =

    1

    2m

    3x2 =3

    m $ x2 %2 =

    1

    4m

    x2 =1

    m (

    1

    m)2

    = 1

    4m

    1

    m2 =

    1

    4m

    )2= &)

    )2 &) = 0

    )$) - &% = 0

    ) = & ata* ) = 0

    15. Jawab : A

    &x2 px + 2! = 0 )aka a = &, b = -p, c = 2!

    arat ked*a akar (a)a ada"a# D = 0

    b2 &ac = 0$-p%2 &.&.2! = 0

    p2 &00 = 0

    $p-20%$p+20% = 0

    p = 20 ata* p = -20

    20. Jawab : A

    2 + $) + 1% + & = 0 )aka a = 1, b = ) + 1, c = &

    arat ked*a akar nata berbeda ada"a# D 4 0

    b2 &ac 4 0

    $)+1%2 &.1.& 4 0

    2 + 2) + 1 16 4 0

    2+ 2) 1! 4 0$)+!%$)-3% 4 0

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    ) 7 -! ata* ) 4 3

    21. Jawab :

    e"a"*i titik $-1

    2 ,0%, )aka = ax2

    22.23.

    2&. Jawab : D

    x1,2 =bD

    2a

    x1,2 =1414

    24.5(55)25

    x1,2 =14196+1100

    10

    x1,2 =141296

    10

    x1,2 =1436

    10

    x1 =22

    10=2

    1

    5

    x2 =5010

    =5

    2!. Jawab :

    x1,2 =bD

    2a

    x1,2 =

    2

    929

    24.2.7

    x1,2 =(92)(81182+2 )56

    4

    x1,2 =(92)(27182 )

    4

    7

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    x1,2 =(92)9 (322 )

    4

    x1,2 =(92)3(322 )

    4

    x1,2 =(92)3 (21)

    4

    x1 =(92 )+3 (21)

    4=

    92+3234

    =11

    2+1

    22

    x1 =(92 )3 (21 )

    4=92323

    4=32

    26. Jawab :

    x1,2 =bD

    2a

    x1,2 =44

    24.1(3)2.1

    x1,2 =428

    2

    x1,2 =427

    2

    x1=4+27

    2=2+7

    x2=4+27

    2=27

    2. Jawab : 9

    x1,2 =bD

    2a

    x1,2 =(12)(12)

    24.4 (9)

    2.(4)

    x1,2 =12144144

    8

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    x1,2 =120

    8

    x1 =12+0

    8=1

    1

    2

    x1 =120

    8=1

    1

    2

    28. Jawab : D

    x1,2 =bD

    2a

    x1,2 =44

    24.1(5)2.1

    x1,2 =41620

    2

    x1,2 =44

    2

    x1,2 =42 i

    2

    x1 =4+2 i

    2=2+i

    x2 =42i

    2=2i

    25. Jawab =

    2x2 x 3 = 0

    $2x 3%$x + 1% = 0

    x1= ; =3

    2 ata* x2 = < = -1

    & ; =4.

    3

    2 = 6

    & < = &.$-1% = -&

    'er(a)aan k*adrat ang akar akarna & ; = 6 dan & < = -& ada"a# :

    $ x 6 %$ x + & % = 0

    x2 2x 2& = 0

    30. Jawab : 9

    x2+ bx + c = 0, akar akarna x1 dan x2per(a)aan k*adrat ang akar akarna x1 + x2 dan x1.x2 ada"a# :

    $x $x1 + x2 %%$ x $x1 . x2 % = 0

    x1 + x2 = -b

    $x $-b%%$ x c% = 0$x + b%$x c% = 0

    9

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    x2+ $ b c %x bc = 0

    10