intervensi 3

3
Intervensi III NAMA :..................................................... ................KELAS :................................... Selesaikan soalan berikut menggunakan kaedah tiang. B i l Soalan 1 27 x 14 = 2 42 x 28 = 3 58 x 36 = 4 273 x 14 =

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Intervensi IIINAMA :.....................................................................KELAS :...................................

Selesaikan soalan berikut menggunakan kaedah tiang.

Bil Soalan

1 27 x 14 =

242 x 28 =

358 x 36 =

4273 x 14 =

5426 x 21 =

6524 x 36 =

7671 x 24 =

8721x 36 =