tugas matematika kelompok

22
TUGAS MATEMATIKA KELOMPOK DIFRENTIATION : HALAMAN 33-40 “

Upload: achmadtrybuana

Post on 18-Aug-2015

58 views

Category:

Education


2 download

TRANSCRIPT

Page 1: Tugas matematika kelompok

TUGAS MATEMATIKA KELOMPOK

“ DIFRENTIATION : HALAMAN 33-40 “

Page 2: Tugas matematika kelompok

Disusun Oleh :

Nama : 1.Achmad Trybuana Kurniasandy

2.Aulia Ramadhani

3.Barry Alkhafi

4.Faizal

Kelas : 1 EA

Semester : 2 ( DUA )

POLITEKNIK MANUFAKTUR NEGERI BANGKA BELITUNG

2014/2015Kawasan Industri Air Kantung, Sungailiat-Bangka 33211

Telp : 0717-93586, 95252 Faks : 0717-93585E-mail : [email protected]

Website : http://polman-babel.ac.id

Temukan turunan dari fungsi yang diberikan1. f(x) = 20ex 6. f(x) = 15x2 +10ex

2. y = e3x 7. g(x) = e7x−2x3

3. g(x) = e5x3

8. f(t) = 100

e−0.5 t

4. y = -4e5x3

9. g(t) = 2500e2t+1

5. h(x) = e−10 x3

10. f(x) = 1

√2 πex2

2

“ HALAMAN 33-40 “

Page 3: Tugas matematika kelompok

Jawaban :

1. f(x) = 20ex

fꞌ(x) = 20.ddx

(ex)

= 20ex

2. y = e3x

yꞌ(x) = e3x.ddx

(5x3)

= e5x3

(15x2)

= 15x2e5x3

3. g(x) = e5x3

gꞌ(x) = e5x3

(.ddx

(5x3)

= e5x3

( (15x2)

= 15x2e5x3

4. y = -4e5x3

yꞌ= -4.ddx

(e5x3

)

= -4.e5x3

.ddx

(5x3)

= -4.e5x3

(15x2)

= -60x2e5x3

5. h(x) = e−10 x3

hꞌ(x) = e−10 x3

.ddx

(-10x3)

= e−10 x3

(-30x2)

= -30x2e−10 x3

6. f(x) = 15x2 + 10ex

Page 4: Tugas matematika kelompok

fꞌ(x) = 15x2 + 10.ddx

(ex)

= 30x + 10ex

7. g(x) = e7x−2x3

gꞌ(x) = e7x−2x3

.ddx

(7x-2x3)

= e7x−2x3

(7-6x)

= 7-6xe7x−2x3

8. f(t) = 100e−0.5 t

fꞌ(t) = 100.e0.5t

= 100. e0.5t.ddx

(0.5t)

= 100. e0.5t(0.5)

= 50e0.5t

9. g(t) = 2500e2t+1

gꞌ(t) = 2500e2t+1.ddx

(2t+1)

= 2500e2t+1.(2)

= 5000e2t+1

10. f(x) = 1

√2 π ex22

fꞌ(x) = 1

√2 π .e12

x2.ddx

(12

x2)

= 1

√2 π .e12

x2.(x)

= x

√2 π .e12

x2

Page 5: Tugas matematika kelompok

Jawaban :

1. f(x) = 20 ln x

fꞌ(x) = 20 . ddx

(ln x)

= 20.1x

= 20x

2. y = ln 3x

yꞌ = 13x

. ddx

(3x)

= 13x

. (3x)

= 1x

3. g(x) = ln(5x3)

gꞌ(x) = 1

5x3 . ddx

(5x3)

= 1

5x3.(15x2)

= 3x

4. y = - 4 ln (5x3)

yꞌ = - 4.1

5x3.ddx

(5x3)

Temukan turunan dari fungsi yang diberikan1. f(x) = 20 ln x 6. f(x) = 15x2 + 10ln x

2. y = ln 3x 7. g(x) = ln(7x-2x3)

3. g(x) = ln(5x3) 8. f(t) = ln(3t2 + 5t – 20)

4. y = -4 ln (5x3) 9. g(t) = ln(et)

5. h(x) = ln(-10x3) 10. f(x) = ln(ln x)

Page 6: Tugas matematika kelompok

= - 4. 1

5x3.(15x2)

= -4.3x

= - 12x

5. h(x) = ln(-10x3)

hꞌ(x) = 1

−10x3 . ddx

(-10x3)

= 1

−10x3(-30x2)

= 3x

6. f(x) = 15x2 + 10ln x

fꞌ(x) = 15x2 + 10.ddx

(ln x)

= 30x + 10.1x

= 30x + 10x

7. g(x) = ln(7x-2x3)

gꞌ(x) = 1

7 x−2x3.ddx

(7x-2x3)

= 1

7 x−2x3. (7x-2x3)

= 7−6 x2

7 x−2x3

8. f(t) = ln(3t2 + 5t – 20)

fꞌ(t) = 1

3t 2+5 t−20.ddx

(3 t 2+5 t−20¿

= 1

3t 2+5 t−20. (6 t+5 )

= 6 t+5

3t 2+5 t−20

9. g(t) = ln(et)

Page 7: Tugas matematika kelompok

gꞌ(t) = 1

et . ddx

(et)

=1

et(e)

= e

et

10. f(x) = ln(ln x)

fꞌ(x) = 1ln x

. ddx

(ln x)

= 1ln x

. (1x

)

= 1

ln x . x

Jawaban :

1. f(x) = 20 (3x)

fꞌ(x) = 20.ddx

(3x)

= 20(ln3)3x

2. y = 53x

yꞌ = (ln 5)53x.ddx

(3x)

Temukan turunan dari fungsi yang diberikan

1. f(x) = 20 (3x) 6. f(x) = 15x2 + 10(5x3)

2. y = 53x 7. g(x) = 37 x−2 x3

3. g(x) =25 x3

8. f(t) = 100

10−0.5 t

4. y = -4(25 x3

) 9. g(t) = 2500(52t+1)

5. h(x) = 4−10 x3

10. f(x) = 8 x2

2

Page 8: Tugas matematika kelompok

= (ln 5)53x.(3)

= 3(ln 5)53x

3. g(x) = 25 x3

gꞌ(x) = (ln 2)25 x3

.ddx

(5x3)

= (ln 2)25 x3

(15x2)

= 15x2(ln 2)25 x3

4. y = -4(25 x3

)

yꞌ = -4.ddx

(25 x3

)

= -4(ln 2)25 x3

.(15x2)

= -60x2(ln 2)25 x3

5. h(x) = 4−10 x3

hꞌ(x) = (ln 4)4−10 x3.ddx

(-30x2)

= (ln 4)4−10 x3. (-30x2)

= -30x2(ln 4)4−10 x3

6. f(x) = 15x2 + 10(5x3)

fꞌ(x) = 15x2 + 10.ddx

(53x)

= 30x + 10(ln 5)53.3

= 30x + 30(ln 5)53

7. g(x) = 37 x−2 x3

gꞌ(x) = (ln 3)37 x−2 x3

.ddx

(7x-2x3)

= (ln 3)37 x−2 x3

.(7-6x2)

= 7-6x2(ln 3)37 x−2 x3

Page 9: Tugas matematika kelompok

8. f(t) = 100

10−0.5 t

fꞌ(t) = 100. 100.5t

= 100.(ln 10)100.5t.ddx

(0.5t)

= 100.(ln 10)100.5t. 0.5 = 50(ln 10)100.5t

9. g(t) = 2500(52t+1)

gꞌ(t) = 2500.ddx

(52t+1)

= 2500(ln 5)52t+1.ddx

(2t+1)

= 2500(ln 5)52t+1.2

= 5000(ln 5)52t+1

10. f(x) = 8 x2

2

= 8−12

x2

fꞌ(x) = (ln 8)8−12

x2.ddx

(−12

x2)

= (ln 8)8−12

x2.(-x)

= (-x).(ln 8)8−12

x2

Temukan turunan dari fungsi yang diberikan

1. f(x) = 20log4 6. f(x) = 15x2 + 10log2 x

2. y = log10 3x 7. g(x) = log6(7x-2x3)

3. g(x) = log8(5x3) 8. f(t) = log16(3t2+5t – 20)

4. y = -4log8(5x3) 9. g(t) = log2(et)

Page 10: Tugas matematika kelompok

5. h(x) = log5(-10x3) 10. f(x) = log10(log10x)

Jawaban :

1. f(x) = 20log4

fꞌ(x) = 20.ddx

(log4x)

= 20. 1¿¿

= 20x ln 4

2. y = log10 3x

yꞌ = 1¿¿

.ddx

(3x)

= 1¿¿ (3)

= 3

x ln 10

3. g(x) = log8(5x3)

gꞌ(x) = 1¿¿

.ddx

(5x3)

= 1¿¿

= 3x ln 8

4. y = -4log8 (5x3)

yꞌ = 4¿¿

.ddx

(5x3)

= 4¿¿ .(15x2)

= −60 x2

¿¿

Page 11: Tugas matematika kelompok

= −12x ln 8

5. h(x) = log5(-10x3)

hꞌ(x) = 1¿¿

.ddx

(-10x3)

= 1¿¿

.(-30x2)

= 3x ln 5

6. f(x) = 15x2 + 10log2 x

fꞌ(x) = 15x2 + 10.ddx

.(log2 x)

= 30x + 10. 1¿¿

= 30x + 10x ln 2

7. g(x) = log6(7x-2x3)

gꞌ(x) = 1¿¿

.ddx

(7x-2x)

= 7−6 x2

¿¿

= 7−6 x2

7 x−2x3 ¿¿

8. f(t) = log16(3t2+5t – 20)

fꞌ(t) = ddx

(log16(3t2+5t-20)

= 1¿¿

.ddx

(3t2+5t-20)

= 1¿¿ .(6t + 5)

= 6 t+5

3t 2+5 t−20¿¿¿

9. g(t) = log2(et)

Page 12: Tugas matematika kelompok

gꞌ(t) = ddx

.( log2(et))

= 1¿¿

.ddx

(et)

= 1¿¿ . (et)

= 1¿¿

10. f(x) = log10(log10x)

fꞌ(x) = ddx

(log10(log10x))

= 1¿¿

.ddx

(log10 x)

= 1¿¿

. 1¿¿

.ddx

(x)

= 1¿¿

Temukan turunan dari fungsi yang diberikan

1. f(x) = 5 sin 3x 6. s(t) = 4 cot5t

2. y = 14

cos(2x2) 7. g(x) = 6tan3( 2x3 )-20√ x

3. g(x) = 5tan( 3 x5 ) 8. f(x) = 2xsinx+cos2x

4. f(x) = 10sec2x9. h(x) =

sin 3 x1+sin 3x

5. y = 23

sec(2x3)10. f(x) = e4xsin2x

Jawaban :

1. f(x) = 5sin3x

fꞌ(x) = 5 cos3xddx

(3x)

= 15 cos 3x

Page 13: Tugas matematika kelompok

2. f(x) = 14

cos(2x2)

fꞌ(x) = 14

-sin 2x2 ddx

(2x2)

= 14

-sin 2x2.4x

= −4 x4

sin2x2

= -xsin2x2

3. g(x) = 5tan( 3 x5 )gꞌ(x) = 5 sec2( 3 x5 ) ddx (3 x5 ) = 5 sec2( 3 x5 ).35 = 3 sec2( 3 x5 )

4. f(x) = 10 sec 2x

fꞌ(x) = 10 sec 2x tan 2xddx

(2x)

= 20 sec 2x tan 2x

5. y = 23

sec(2x3)

yꞌ = 23

sec 2x3 tan 2x3 ddx

(2x3)

= 23

sec 2x3 tan 2x3.6x2

= 4x2sec 2x3 tan 2x3

6. s(t) = 4 cot 5t

sꞌ(t) = -4 csc2 5t ddt

(5t)

= -20 csc2 5t

Page 14: Tugas matematika kelompok

7. g(x) = 6tan3( 2x3 )-20√ x

gꞌ(x) = 6 sec6( 2x3 ) ddx ( 2 x3 )-10x−12

= 6 sec6( 2x3 ).( 2x3 )−10 x−12

= 4 sec6( 2x3 ) - 10

√x

8. f(x) = 2x sinx + cos 2x

fꞌ(x) = 2 cos x ddx

(x) + (-sin 2x)ddx

(2x)

= 2 cos x – 2 sin 2x

9. h(x) = sin 3 x1+sin 3x

hꞌ(x) = cos3 x

ddx

(3x )

cos3 xddx

(3x )

= 3cos3 x3cos3 x

= 1

10. f(x) = e4xsin2x

fꞌ(x) = e4x ddx

(4x). cos 2xddx

(2x)

= 4e4x.2cos 2x

Temukan turunan dari fungsi yang diberikan

1. f(x) = sin-1( -x3) 6. f(x) = cos-1(x2)

2. h(x) = cos -1(ex) 7. h(x) = csc-1(2x)

3. g(x) = tan-1(x2) 8. g(x) = 4 sec-1( x2 )

4. f(x) = cot-1(7x-5) 9. f(x) = x sin-1(7x2)

Page 15: Tugas matematika kelompok

5. y = 15

sin-1(5x3) 10. y = arcsin(√1−x2 )

Jawaban :

1. f(x) = sin−1(−x3)

fꞌ (x) = −1

√1−¿¿¿ . ddx

.¿)

= −3 x2

√1−x9

2. h(x) = cos -1(ex)

hꞌ(x) = −1

√1−(ex)2.ddx

(ex)

= −e x

√1−(ex)2

3. g(x) = tan-1(x2)

gꞌ(x) = 1

1+(x2)2.ddx

(x2)

= 2 x

1+ x4

4. f(x) = cot-1(7x-5)

fꞌ(x) = −1

1+(7 X−5)2.ddx

(7x-5)

= −7

49 X2−70 X+25

5. y = 15

sin-1(5x3)

Page 16: Tugas matematika kelompok

yꞌ = 1

√1+(5 x3)2.ddx

(5x3).115

= 1

√1+25 x6 .15x2.115

= 15 x2

√1+25 x6 .15

6. f(x) = cos-1(x2)

fꞌ(x) = 1

√1−(x2)2.ddx

(x2)

=−2 x

√1+x4

7. h(x) = csc-1(2x)

hꞌ(x) = −1

|2 x|√(2x )2−1. ddx

. (2x)

= - 2

2x √4 x2−1

8. g(x) = 4 sec-1( x2 )

gꞌ(x) = 4.

−1

|x2|√( x2 )2 .ddx

.( x2 )

=

−4

x2 √ x24 −1

. 14

=

−4

x2 √ x24 – 1.4

9. f(x) = x sin-1(7x2)

fꞌ(x) = 1.1

√1−(7 x¿¿2)2¿.ddx

.7x2

= 14 x

√1−49 x4

Page 17: Tugas matematika kelompok

10. y = arcsin(√1−x2 )

yꞌ = 1

√1−(√1−x2 )2.ddx

.√1−x2

= 1

√1−(1−x2 ) . 12

(1 – x2)

= 1−x2

2√ x2

Temukan turunan dari fungsi yang diberikan

1. f(x) = x7 + 2x10 , Temukan fꞌꞌꞌ(x)6. s(t) = 16t2-

2t3

+10 , Temukan sꞌꞌ(t)

2. h(x) = 3√ x , Temukan hꞌꞌ(x) 7. g(x) = ln3x , Temukan D x3 [ g(x )]

3. g(x) = 2x , Temukan g(5)(x)8. f(t) =

10

x5+ x

3

5 , Temukan f(4)(x)

4. f(x) = 5ex , Temukan f(4)(x) 9. f(x) = 32x , Temukan fꞌꞌꞌ(x)

5. y(x) = sin3x , Temukan d3 yd3 x

10. y = log 25x , Temukan d4 yd4 x

Jawaban

1. f(x) = x7 + 2x10

fꞌ(x) = 7x6 + 20x9

fꞌꞌ(x) = 42x5 + 180x8

fꞌꞌꞌ(x) = 210x4 + 1440x7

2. h(x) = 3√ x = x13

hꞌ(x) = 13

x23

hꞌꞌ(x) = −29x

−53

3. g(x) = 2x

gꞌ(x) = 2

gꞌꞌ(x) = 0

gꞌꞌꞌ(x) = 0

Page 18: Tugas matematika kelompok

g4(x) = 0

4. f(x) = 5ex

fꞌ(x) = 5ex.1

fꞌꞌ(x) = 5ex.1 = 5ex

fꞌꞌꞌ(x) = 5ex.1

= d3gd3 x

= 5ex

5. y = sin 3x

d1 yd1 x

= 3 cos 3x

d2 yd2 x

= -9 sin 3x

d3 yd3 x

= - 27 cos 3x

6. s(t) = 16t2 - 2t3

+ 10

sꞌ(t) = 32t - 23

sꞌꞌ(t) = 32

7. g(x) = ln 3x

D1(x)[ g(x )] = 33x

= 1x

= x−1

D2(x)[ g(x )] = −x−2

D3(x)[ g(x )] = 2 x−3

8. f(x) = 10

x5 + x

3

5 = 10 x−5 +

15

x3

fꞌ(x) = -50 x−6 + 35

x2

fꞌꞌ(x) = 300 x-7 + 65

x

Page 19: Tugas matematika kelompok

fꞌꞌꞌ(x) = -2100 x-8 + 65

f4(x) = 16800 x-9

9. f(x) = 32x

fꞌ(x) = 32x ln 3 . 2

fꞌꞌ(x) = 32x ln 3 . 23

fꞌꞌꞌ(x) = 32x ln 3 . 2 . 13

= 32x ln 3 . 29

10. g = log2 5x

d ꞌ yd ꞌ x

= 1

5x ln 2 . 5 =

55x ln 2

d ꞌꞌ yd ꞌꞌ x

= 55

. 12

.1

d ꞌꞌꞌ yd ꞌꞌꞌ x

= 0 =d4 yd4 x

= 0