SKEMA JAWAPAN MATEMATIK TAHUN 5 AKHIR TAHUN

KERTAS 2

1 70 000 N12

N1

3 Enam puluh lima perpuluhan satu tujuh lima N14 2.8 kg N15

N1

6

K1

7 13.400 17.960 + 0.756 K1 32.116 N1

8 7 km 50 m – 750 m = 7050 m – 750 m = 6300 m = (6300 ÷ 1000) km K1 = 6.3 km N1

9 RM 916.50 ÷ 13 = RM70.50 K1RM 70.50 x 7 = RM493.50 K1

10 10 jam 44 minit 6 saat + 5 jam 28 minit 59 saat = 15 jam 72 minit 65 saat K1 = 16 jam 13 minit 5 saat N1

11 116 g x 9 = 1 044 g K1 = (1 044 ÷ 1 000)kg = 1.044 kg N1

12 12 843 x 8 = 102 744 K1102 744 ÷ 12 = 8 562 K1

13ℓ = x 1 000 mℓ

= 600 mℓ K12 ℓ 40 mℓ + 600 mℓ = 2 040 mℓ + 600 mℓ = 2 640 mℓ K1

141 - = K1

x 350 = 150 biji butang K1

15 1 900 ÷ 20 = 95 K195 x 12 K1= 1140 biji manggis N1

16 Isi padu B : 8 cm x 6 cm x 6 cm = 288 K1Isi padu A : 288 + 72 = 360 K1X: 360 ÷ 5 cm ÷ 6 cm = 72 ÷ 6 cm = 12 cm N1

17 RM1 869.40 + RM1 239.50 + RM1 125.60= RM4 234.50 K1

Purata/Average = RM4 234.50 K1 6 = RM705.75 N1

18 2.5 kg = 2.5 x 1000 = 2 500 g K12 500g – 600g K1= 1900g N1

19jam = ( x 60) minit

= 50 minit K1

jam minit

31

+

1 0 2 5 5 0

4+ 1

8 5- 6 0

5 2 5 = 5:25 p.m N1

20 DC = 8 cm N1Luas kawasan berlorek = 8 cm x 5 cm K1 = 40 N1

K1