pps imam master

7/25/2019 Pps Imam Master

1/11

NO. 1

Diketahui :

- L = 50 m

- n = 1 : 150 = 0,007

- q = 25 m3/dt /m

- h = 35 cm = 0,35 m

- g =9,81 m/dt

- gradasi asir kasar

- !s = 2,25 gr/ cm

- e = 0,90

- k = "5 m/#am

- #enis tanah $umur

- c = 0,02 % k&e'isien manning (

- )# air = 1t&n/ m3

- )# tanah = 2,25 t&n/ m3

- )# )et&n = 2,35 t&n/ m3

Ditan*a : +encanakan k&nstruksi am)ang

.aa) : k&ntr&$ terhada ni$ai )anding ra*aan seim)ang dimana

= % 1/n ( D D = n

= 50 0,00"7

= 0,335 m

4 = D h

= 0,335 0,35

= 0,"85

4' = c D/h 4

= 0,02 35,0

035,0 0,"85

= 0,0131 m

1


2/11

h 136 % 4 6 h' ( h1

2g

q

2

2

= 0

h 136 % 0,"85 6 0,0131 ( h 1

281,92

252

= 0

h 136 0,"719 h 12 31,8552 = 0

h 1dicari dengan cara tria$ err&r

dari tria$ err&r didaat h1= -3,1029 m

h2 =2

2

1

2

1

2

1 h

hg

qh+

=2

1029,3

1029,381,9

252

1029,32

2

+

= ",2102

arena h1 h2diangga se)esar h2#adi h1= ",2102 m

1,0 0,2 1,0 5,0 1,0 ,0 1,0 0,2 2,0

",2102

0,3350,1

0,2

0,"85

",2102

&ntr&$ terhada ge#a$a iing dimana % asir kasar ( = 12

e$as ;atas = L/4


3/11

arena h1 h2 , $2 h1

L1 = 1m

L2 = 2 42

= 2 ",2102 = 12,20 m

L3 = 2m

41 = ",2102 m

42 = ",2102 m

L = L1 241 L2 242 L3= 0,2"12

="85,0

2"12,0= 58,78 12 >>?man

k&ntr&$ terhada ni$ai )anding ra*aan seim)ang dimana asir kasar = 0,5

=H

LW

L = 1/3 % L1 L2 L3( 2 %41 42(

= 1/3 % 1 12 2 ( 2 %",2102 ",2102 (

= 29,808

= "85,0

808,29

= 3,5"32 5,0 >?man

!e#a$a asir aung

e$as @i$ai )anding ra*aan seim)ang


4/11

= "58,090,01

125,2

1

1=

+

=

+

e

GS

AFS

IC

L

H=

BC ="85,0

"58,02"12,0=

HICL = 38,"7 5,0 > ?man

eceatan a$iran air rem)esan

E =2"12,0

"85,0"5=

L

KH= 1,0"2 m/ #am

= 0,000295 m/dt>>>>?man

Cta)i$itas dinamika tu)uh )endung

42=0,3F2 =0,335

41=0,5

F1 =0,"85

a sta)i$itas terhada gu$ing

41 = G * air *12 = G 1,0 0,"852= 0,25 t&n

42 = G * tanah *22 = G 2,25 0,3352= 0,12" t&n

H&ment gu$ing % Hr ( = 41 h1 42 h2

= %0,25 0,5 ( % 0,12" 0,3 (

= 0,1"03 t&n meter


5/11

0,2

1 0,2 1 5,0 1,0 ,0 1,0 1 0,2 2

0,335EE

EE

E

0,"85

@& ;erat % t&n ( Lengan thd ? % m ( H&ment thd ? % t/m(

E

E

E

E

E

0,335 2,2 2,35 = 1,732

5 0,135 2,35 = 1,58"

1 0,2 2,35 = 0,70

G 1 0,135 2,35 = 0,159

0,1 2,35 =0,90

1 0,2 2,35 = 0,70

G 1 0,135 2,35 = 0,159

3,2 0,335 2,35 = 2,15

% G 2,2 ( 5 1 1 3,2 = 15,3

% G 5 ( 1 1 3,2 = 11,70

% G 1 ( 1 3,2 = 8,7

%1/31 ( 5 1 1 3,2 =1,533

% G ( 1 3,2 = ",200

% G 1 ( 3,2 = 3,700

% 1/3 1 ( 3,2 = 3,533

% G 3,2 ( = 1,"00

2",99

1855"

,089

2,311

5,828

1,739

0,5"2

3,

I = 7,""" I = "3,02

H& = "3,02 t&nm

Hr = 0,1"03 t&nm

H& Hr = "3,02 t&nm 0,1"03 t&nm >>> ?man

E = 1 611W

Mo

= 1 6,17""",7

02,"3= 0,528

!a*a gema dia)aikan #adi h = 0

% 1 E ( 1tg J K h 1 % L h ( % 41 42(1tg J K 41 42

7,""" 0,2 K 0,5 0,3

1,533 K 0,8 t&n ?man

NO. 2

5


6/11

Cuatu tanah memun*ai keda$aman e'ekti' 1,55 m dengan ni$ai 'act&r keda$aman 30 su)

&rder tanah *ang memun*ai #enis tanah n&> dengan umur guna tanah 800 tahun

;eraa er&si *ang masih daat di)iarkan #ika )erat &$ume tanah % 1,5 gr/cm2(

Diketahui :

- + = 1,55 m = 155 cm

- Bd = 1,00

- t = 800 tahun

- .t = 1,5 gr/cm3

Ditan*a : M

.aa) :

+eq = + Bd

= 155 1,00

= 155 cm

M = T

q+e .t 10

=800

155 1,5 10

= 2,809 gr/cm3/tahun

= 280,9 t&n/ha/tahun

NO.3

"


7/11

;eraa sediment *ang terangkut untuk sungai terse)ut diatas #ika diketahui tanah di D?C

terse)ut termasuk #enis tanah *ang memun*ai er&si )erat 4itung dengan met&de k&tak

hitam .ika diketahui $uas daerah engairan sungai "000 ha, curah hu#an rata-rata tahunan

se)esar 1,95 m dan k&e'isien enga$iran 0,5

Diketahui :

- ? = 7500 ha = 75000000 m2

- i = 1,95 m

- c = 0,5

- a = 0,0003

- ) = 2,25

Ditan*a : Ns = >>

.aa) :

Ns = a N )

N = c i ?

= 0,5 1,95 75000000

= "5812500 m3/th

Ns = 0,0003 % "5812500 (2,25

= 1,17035 101m3/th

= 1,5"85 1010m3/th/ha

NO. 4

Diketahui :

7


8/11

- DO+ = 1 #am " menit " detik

= 1 % "/"0 ( % "/3"00 (

= 1,102 #am

- E = 2,25 m/dt

- Eq = 1,85 m/dt

- Ea = 1,5 m/dt

- D* = 2Pd / 3"5 hr

- ; = 50 m

- h = 5,0 m = 5000 mm

- Q = 50

- + = 1,75 m

- C = 8000 ha

- L = 7500 m

- < = 250 mm = 0,250 m

- < = 2500 mm = 2,500 m

Ditan*a : CC , NC dan DC >>>>

8


9/11

.aa) :

C ; C

h

tg Q = 55

0,50 ===

tgh

tg

Sc

Sc

h

? = % ; Cc ( h= % 50 5 ( 5,0

= 2,75 m3

N = ? E

N = 275 2,25 = "18,75 m3/dt = "18750 L/dt

Nq = 275 1,85 = 508,25 m3/dt = 508250 L/dt

Na = 275 1,5 = 398,75 m3/dt = 398750 L/dt

NN = % Nq / s ( DO+

= 3"00102,180000000

25,508

= 0,025 m = 25 m

L&g Ns= -1,102 6 % 0,052 DO+ ( 6 % 0,77" L&g N ( % 1,3735 L&g Nq (

% 0,9892 L&g NN ( 6 % 0,9"1 L&g Na ( % 0,2"93 D* (

9


10/11

= -1,102 6 % 0,052 1,102 ( 6 % 0,77" L&g "18,750 ( % 1,3735 L&g 508,25 (

% 0,9892 L&g 25 ( 6 % 0,9"1 L&g 398,750 ( % 0,2"93 ",282 (

= 2,13"5

Ns = 13",93 kg

;esarn*a sediment *ang tersusensi

L&g CC = -8,73 3,81 L&g N? 6 1,5 L&g +/L ,82 L&g DD

N? = % N / C ( DO+

=80000000

"18750 % 1,102 3"00 (

= 30,"8 mm

1 kaki = 30,8 cm = 0,308 m

1 mi$e = 1,"093 km = 1"09,30 m1 mi$e2 = 2,5899 km2= 258,99 ha

L

R=

7500

75,1= 0,00023

= 0,00023 m 308,0

30,1"09

= 1,21 't / mi$e

DD = 80000000

7500=

S

L

= 0,938 m / ha

= 0,938 308,0

99,258

= 797,023 't / mi$e2

L&g CC = -8,73 3,81 L&g 30,"8 6 1,5 L&g 1,21 ,82 L&g 797,023

= 10,3"

CC = 2,72 1010m3/ km2

;esarn*a kandungan rata-rata sediment tahunan % Ns (, #ika hu#an rata-rata tahunan


11/11

Ns = 3,3

3,2

(03937,0%007,01

(03937,0%"31,1

PE

PE

+

=( )

3,3

3,2

(500,203937,0%007,01

500,213937,0"31,1

+

= 2,3"7 m3/ km2

;esarn*a sediment *ang tersusensi

L&g Ds = 2,"5 L&gP

P2 0," $&g

S

h26 1,5"

= 2,"5 L&g2500

250 2 0," L&g

80

500026 1,5"

= 5,515 t&n / km2 / th

11

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