projek skor kimia 2014 siri 3

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SKOR A KIMIA 2014 TAJUK: FORMULA DAN PERSAMAAN KIMIA/STOIKIOMETRI SET 1 Diagram 1 shows the structural formula of ascorbic acid (Vitamin C). Rajah 1 menunjukkan formula struktur bagi asid askorbik (Vitamin C) Diagram 1 Rajah 1 (a) (i) What is the meaning of molecular formula? Apa maksud formula molekul? …..……………………………………………………………………………………… …………………………………………………………………………………………… [2 marks / 2 markah] (ii) Write the molecular formula of compound X. Tuliskan formula molekul bagi sebatian X. ………………………………………………………………………………………… [1 mark / 1 markah] (iii) Calculate the relative molecular mass of compound X. Given relative atomic mass of C = 12, H =1, 0 =16. Hitungkan jisim molekul relatif bagi sebatian X. Diberi jisim atom relative bagi C = 12, H =1, 0 =16. 2mark (b) (i) A team of students took a 29.575 g sample of pure zinc, and burned it in air to produce a oxide of zinc with mass 36.855g. Find the empirical formula of this oxide. Given the relative atomic mass of Zn = 65, 0 = 16. Satu pasukan murid mengambil sampel zink tulen sebanyak 29.575g, dan membakarkan dalam udara untuk menghasilkan oksida zink dengan jisim 36.855. Carikan formula empirik untuk oksida ini.

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SKOR A KIMIA 2014TAJUK: FORMULA DAN PERSAMAAN KIMIA/STOIKIOMETRISET 1Diagram 1 shows the structural formula of ascorbic acid (Vitamin C).Rajah 1 menunjukkan formula struktur bagi asid askorbik (Vitamin C)

Diagram 1 Rajah 1

(a) (i) What is the meaning of molecular formula?Apa maksud formula molekul?.. [2 marks / 2 markah](ii) Write the molecular formula of compound X.Tuliskan formula molekul bagi sebatian X. [1 mark / 1 markah](iii) Calculate the relative molecular mass of compound X.Given relative atomic mass of C = 12, H =1, 0 =16. Hitungkan jisim molekul relatif bagi sebatian X. Diberi jisim atom relative bagi C = 12, H =1, 0 =16.

2mark(b) (i) A team of students took a 29.575 g sample of pure zinc, and burned it in air to produce a oxide of zinc with mass 36.855g. Find the empirical formula of this oxide. Given the relative atomic mass of Zn = 65, 0 = 16.Satu pasukan murid mengambil sampel zink tulen sebanyak 29.575g, dan membakarkan dalam udara untuk menghasilkan oksida zink dengan jisim 36.855. Carikan formula empirik untuk oksida ini.Diberi jisim atom relatif Zn = 65, 0 = 16 [4mrk]

SKOR A KIMIA 2014TAJUK: FORMULA DAN PERSAMAAN KIMIA/STOIKIOMETRISET 21Diagram 1.1 shows the formulae of 4 types of gases released during the eruption of a volcano. Rajah 1.1 menunjukkan formula bagi 4 jenis gas yang terbebas semasa letusan gunung berapi.

N2

CO2

H2S

H2O

Diagram 1.1 /Rajah 1.1

a)State the meaning of molar mass of a substance by using one suitable examples.

Nyatakan maksud jisim molar bagi suatu bahan dengan menggunakan satu contoh yang sesuai.

.[1 mark]b)Calculate the molar mass of each gas shown in Diagram1.1[Relative atomic mass : H, 1; C, 12; O, 16; N, 14; S, 32 ]Hitung jisim molar bagi setiap gas yang ditunjukkan dalam Rajah 2. [ Jisim atom relatif : H,1 ; C,12 ; O,16 ; N,14 ; S,32 ]

[4 marks] c)Compare the number of molecules in 0.9 g of water vapour and 2.2 g of carbon dioxide.Explain.[Relative atomic mass: H, 1; C, 12; O, 16; Avogadro Constant, NA = 6.02 x 1023] Bandingkan bilangan molekul dalam 0.9 g wap air dan 2.2 g karbon dioksida.Terangkan. [ Jisim atom relatif : H,1 ; C,12 ;O,16 : Pemalar Avogadro ,NA = 6.02 x 1023]

[4 marks]

SKOR A KIMIA 2014TAJUK: FORMULA DAN PERSAMAAN KIMIA/STOIKIOMETRISET 3Table 4.1 shows formula of four ions. Jadual 4.1menunjukkan formula bagi 4 ion.

Name of ions Nama ion

Formula of ions Formula ion

Lead ionIon Plumbum

Pb2+

Silver ion Ion argentum

Ag+

Nitrate ion Ion nitrat

NO3 -

Chloride ion Ion klorida

Cl-

Table 4.1/Jadual 4.1a) Write the formula for each compound below : Tuliskan formula kimia bagi sebatian di bawah :

i) Lead (II) nitrate Plumbum(II) nitrat :..ii)Silver chloride: Argentum klorida:.2markah

b)When lead(II) nitrate solution is added to sodium chloride solution , lead(II) chloride and sodium nitrate solution are formed.Apabila larutan plumbum(II) nitrat ditambahkan kepada larutan natrium klorida , plumbum klorida dan larutan natrium nitrat terbentuk.

i)Write the ionic equation for the reaction occurs. Tuliskan persamaan ion bagi tindak balas yang berlaku.

[ 2 marks ] ii)State two information obtained from reaction in (b), in term of qualitative aspect andquantitative aspect.Nyatakan dua maklumat yang boleh didapati daripada tindak balas dalam (b), daripada aspek kualitatif dan kuantitatif

Qualitative aspect : Aspek kualitatif:.

.....

Quantitative aspect : Aspek kuantitatif:

..

.2 markah

c) The following equation shows the decomposition of lead(II) nitrate by heat. Tindak balas berikut menunjukkan penguraian plumbum(II) nitrat oleh haba.

___Pb(NO3)2 (s)___PbO (s)+ ___NO2 (s) + O2 (g)

i) Complete the chemical equation above. Lengkapkan persamaan kimia di atas.[ 1 mark ] ii)State the observation obtained from above reaction .Nyatakan pemerhatian yang diperolehi daripada tindak balas di atas.

Compound Sebatian

Colour of the residue when hotWarna baki bila panas

Colour of the residue when coldWarna baki bila sejuk

PbO

Gases Gas

Colour of the gas released Warna gas yang terbebas

NO2

O2

[ 3 marks ]

SKOR A KIMIA 2014TAJUK: FORMULA DAN PERSAMAAN KIMIA/STOIKIOMETRISET 4(a) The following are the formulae of two compounds. Berikut adalah formula bagi dua sebatian.

Al2O3PbO2

(i) Based on the two formulae, write the formula for aluminium ion and lead ion Berdasarkan kedua-dua formula tersebut, tuliskan formula bagi ion aluminium dan ion plumbum. ..[2 marks](ii) Name both compounds based on the IUPAC nomenclature system.

Namakan kedua-dua sebatian tersebut berdasarkan sistem penamaan IUPAC . ..[2 marks](b) The following information is about an organic compound, K. Berikut adalah penerangan tentang sebatian karbon K.

Empirical formula is CH2O. Formula empirical

Relative molecular mass is 60. Jisim molekul relatif

Reacts with calcium carbonate to produce a type of gas that turns lime water chalky. Bertindak balas dengan kalsium karbonat menghasilkan gas yang mengeruhkan air kapur.

Based on the information given: Berdasarkan penerangan yang diberikan.

(i) Determine the molecular formula of K. [Relative atomic mass: H = 1, C = 12, O = 16]Tentukan formula molekul bagi K. [Jisim atom relative : H = 1 , C=12 , O = 16][3 marks]

(ii) Write a balanced chemical equation for the reaction of compound K with calcium carbonate. Tuliskan persamaan kimia seimbang bagi tindak balas antara sebatian K dengan kalsium karbonat. ..[2 marks]

(c) Diagram 5.1 shows the apparatus set up for experiment of decomposition of copper(II) carbonate. In this experiment copper(II) oxide and carbon dioxide gas are formed.Diagram 8 menunjukkan susunan radas untuk eksperimen penguraian kuprum(II) karbonat. Dalam eksperimen ini kuprum(II)oksida dan karbon dioksida dihasilkan.

Copper(II) carbonate powder Serbuk kuprum(II)karbonat Heat panaskan

Lime water Air kapurDiagram 5.1/Rajah 5.1

Based on Diagram 5.1 Berdasarkan rajah 5.1

(i) State two observations. Nyatakan dua pemerhatian. .. ..

(ii) Write a balanced chemical equation for the reaction Tuliskan persamaan kimia seimbang bagi tindak balas ..

(ii) State two informations from the chemical equation in (c)(ii). Nyatakan dua maklumat dari persamaan kimia dalam (c)(ii) .. .. .. ..

(iv) Calculate the mass of the copper(II) oxide formed from the decomposition of 12.4 g of copper(II) carbonate.[ Relative atomic mass of C = 12; O = 16; Cu = 64]Hitungkan jisim kuprum(II)oksida yang terbentuk dari penguraian 12.4 g kuprum(II)karbonat. [Jisim atom relatif of C = 12, O = 16, Cu = 64]

SKOR A KIMIA 2014TAJUK: FORMULA DAN PERSAMAAN KIMIA/STOIKIOMETRISET 5

Table 8 shows formula of four ions.Jadual 8 menunjukkan formula bagi empat ion

Name of ionsNama ionSilver ion Ion ArgentumZinc ionIon zink Nitrate ion Ion nitratChloride ionIon klorida

Formula of ionsFormula ionAg+Zn2+NO3-Cl-

TABLE 8/Jadual 8

1. Write the formula for each compound below :Tuliskan formula bagi setiap sebatian dibawah

(i)Silver nitrate............................................................................................Argentum nitrat

(ii)Zinc chloride: .......................................................................................................Zink nitrat

0. Silver chloride: .......................................................................................................Argenum klorida

0. Zinc nitrate: .......................................................................................................Zink nitrat[4 marks]1. When silver nitrate solution is added to zinc chloride solution, white precipitate, silver chloride and zinc nitrate solution are formed.Apabila larutan argentum nitrat ditambahkan kedalam larutan zink klorida, mendakan putih, argentum klorida dan larutan zink nitrat terhasil.

(i) Identify the reactants and products of the reaction.Kenalpasti bahan tindakbalas dan hasil tindakbalas bagi tindakbalas di atasReactants :............................................................................................................Bahan tindakbalasProducts : ............................................................................................................Hasil tindakbalas [2 marks](ii) Write the chemical equation for the reaction occurs in (b).Tuliskan persamaan kimia bagi tindakbalasa di(b)...........................................................................................................................................[1 mark]

1. The following equation shows the decomposition of silver nitrate by heat.Persamaan kimia di bawah menunjukkan tindakbalas penguraian sebatian argentum nitrat oleh haba

2AgNO3 2Ag+ 2NO2+ O2

If 85.0 g of silver nitrate is heated completely, calculate :Jika 85.0g argentum nitrat telah dipanaskan selengkapnya, hitungkan

(i)the mass of silver formed. Given that the relative atomic mass of N =14; O = 16; Ag =108 Jisim argentum yang terhasil[ Jisim atom relatif: N, 14; O, 16; Ag, 108]

3 marks]

(ii)the volume of oxygen gas formed at room conditions.Given that the Molar volume : 24 dm3 at room conditionsIsipadu gas oksigen yang terbebas pada suhu bilik[ Isipadu molar gas pada suhu bilik: 24dm3 mol-1]

[ 2 marks]