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Page 1: Motivasi Mt Upsr 2011
Page 2: Motivasi Mt Upsr 2011

1. WHOLE NUMBERS2. FRACTIONS3. DECIMALS 4. MONEY5. PERCENTAGE

Page 3: Motivasi Mt Upsr 2011

POINTS TO PONDER

TOPIC CONTENTSWHOLE NUMBERS

•WRITE NUMBER•PLACE /DIGIT VALUE•ROUND OFF•OPERATIONS ( +, - x ,÷ )•NUMBER LINE•MIXED OPERATIONS

FRACTIONS •EQUIVALENT /SIMPLEST FORM•+, -, x, ÷•NUMBER LINE•CONVERT TO DECIMALS/PERCENTAGE•FRACTION OF THE SHADED REGION•FRACTION OF A WHOLE NUMBER

Page 4: Motivasi Mt Upsr 2011

DECIMALS •OPERATIONS ( +, - x ,÷ )•NUMBER LINE•PLACE /DIGIT VALUE•CONVERT TO FRACTIONS•ROUND OFF

MONEY •TOTAL OF MONEY/PRICE/BALANCE•COST PRICE/SELLING PRICE/PROFIT/LOSS•INCOMPLETE BILL•PERCENTAGE OF SAVING/TOTAL OF SAVING

PERCENTAGE •CALCULATE THE PERCENTAGE•DISCOUNT•PERCENTAGE OF THE SHADED REGION•CALCULATE THE VALUE FROM THE GIVEN PERCENTAGE•CONVERT TO FRACTIONS

Page 5: Motivasi Mt Upsr 2011

Solution : 7 digit number

Million HundredThousands

TenThousands

Thousands Hundreds Tens Ones

Seven million Fifty thousand Three

Answer: C. 7 050 003

Seven million fifty thousand and three in numerals isA 7 500 030 C 7 050 003B 7 050 300 D 7 005 003

1.

Seven million fifty thousand and three

7 5 30 0 0 0

Page 6: Motivasi Mt Upsr 2011

4 567 123

PLACE VALUE DIGIT VALUE

THOUSANDS 7 000

Page 7: Motivasi Mt Upsr 2011

Round off 6354 to the nearest ten

A 6300 C 6355

B 6350 D 6360

Page 8: Motivasi Mt Upsr 2011

(2003)

Which of the following numbers when rounded off to the nearest ten thousand becomes 5 490 000? A 5 499 042B 5 495 047C 5 494 374D 5 484 916

Page 9: Motivasi Mt Upsr 2011

The diagram below shows a number line.

Find the value of W.44 880 45 380 W

A 45 880 C 46 880B 46 380 D 47 380

Answer : C. 46 880

+ 500 + 500 + 500

44 880 45 380 W

45 380+ 500 45 880

45 380- 44 880 500

45 880+ 500 46 380

46 380+ 500 46 880

Solution : Find the difference

Page 10: Motivasi Mt Upsr 2011

406 532 71 908

Find the difference between the value of digit 6 and the value of digit 9 in the two numbers.

A 300 C 5100B 3000 D 8400

Answer : C. 5100

Solution : Difference = subtraction

406 532 71 908Th

6 Thousands = 6000 9 Hundreds = 900

6 0 0 0 - 9 0 0 5 1 0 0

6000 - 900 =

H

Page 11: Motivasi Mt Upsr 2011

66 674 ÷ 37 =

A 182B 1082C 1802D 1820

1 80 _37 )66 674 37 29 6 29 6 00 07

Page 12: Motivasi Mt Upsr 2011

Diagram shows an incomplete number line. Find the value of Q.

811

411

831Q

Page 13: Motivasi Mt Upsr 2011

4313

Page 14: Motivasi Mt Upsr 2011

2341

423

5.75

435

Page 15: Motivasi Mt Upsr 2011

480 52

What number must be written in the above?

480 X 25

=

240

240 x 5 =1200

Page 16: Motivasi Mt Upsr 2011

41

41

18

÷ 8 =

÷

41 X

81 =

321

Page 17: Motivasi Mt Upsr 2011

FRACTION

Diagram 8 consists of several squares of equal size . Find the fraction of the shaded region of the whole diagram .

A

B

C

D

1214

3858

Diagram 8

÷ 2

÷ 2

6 16

=

3 8

=

Page 18: Motivasi Mt Upsr 2011

1002

The diagram shows a decimal labelled W, X, Y and Z

Which letter represents

2 . 2 2 2

W X Y Z

?

10 100 1000Whole number .

2 2 2 2

W X Y Z 1002.

Page 19: Motivasi Mt Upsr 2011

Round off 54.019 to two decimal places

A 54.02 C 54.20B 54.10 D 55.02

Page 20: Motivasi Mt Upsr 2011

Diagram shows two number cards.

Find the difference between digit 3 and digit 8.

A 0.05 C 0.38

B 0.22 D 0.77

6.78 2.34

Page 21: Motivasi Mt Upsr 2011

2000

A 4.027B 4.63C 4.937D 5.0

100

71000

75

5.007- 0.07

Page 22: Motivasi Mt Upsr 2011

65 sen 400 =

A RM26 C RM2 600

B RM260 D RM26 000

Page 23: Motivasi Mt Upsr 2011

Fifty-eight thousand eight ringgit and eighty sen is written as

A RM58 800.08 C RM58 008.80B RM58 080.80 D RM58 800.08

sen.

.

Fifty-eight thousand eight ringgit and eighty sen

RM sen

M T O

5 8 0 0 8 8 0

RM

Page 24: Motivasi Mt Upsr 2011

Puan Anita paid with a RM50 note and received a balance of RM13.60.Calculate the price of one metre of red cloth.

Quantity Item Price per Unit Price

4 metres Yellow Cloth RM4.90 RM19.60

3 metres Red Cloth

TOTAL

Diagram below is incomplete bill which shows two items bought by Puan Anita

Page 25: Motivasi Mt Upsr 2011

Convert fraction to percentage

Find the value of percentage

%7510043

RM200 daripada %5

%7510075

25 25

43

5 X RM200 = RM10

100

Page 26: Motivasi Mt Upsr 2011

BASIC FACTS

FRACTIONS

DECIMALS 0.25 0.5 0.75

PERCENTAGE 25% 50% 75%

21

41

43

1.0

100%

44

Page 27: Motivasi Mt Upsr 2011

• TIME• LENGTH• MASS• VOLUME OF LIQUID

Page 28: Motivasi Mt Upsr 2011

HAVE YOU MEMORIZED ALL THE IMPORTANT FACTS…?

TIME

1 minute 1 hour 1 day 1 week 1 year 1 year 1 leap year 1 decade 1 century 1 century

= = = = = = = = = =

60 seconds 60 minutes 24 hours 7 days 52 weeks 12 months 366 days 10 years 10 decades 100 years

1 millenium = 1000 years = 100 decades

Page 29: Motivasi Mt Upsr 2011

1 cm = 10 mm 1 m = 100 cm 1 m = 1 000 mm 1 km = 1 000 m

Length

Mass

1 kg = 1 000 g

Volume of Liquid

1 l = 1 000 ml

Money

Profit= sales price - cost price

Loss= cost price - sales price

Average

Total item values

Numbers of items=

HAVE YOU MEMORIZED ALL THE IMPORTANT FACTS…?

Page 30: Motivasi Mt Upsr 2011

500 500 250

1 km = 1000 m

21

41

51

250 250

250 200

200200

200

200

43

53

Page 31: Motivasi Mt Upsr 2011

30 30 20 2020

15

15

15

15

1 hour = 60 minutes

hour21

hour31 hour

41

Page 32: Motivasi Mt Upsr 2011

The diagram shown a time line.endstart

10 : 30 p.m 7 : 30 a.m

Find the duration between the two given

10:30 11:30

p.m

12:30 1:30 2:30 3:30 4:30 5:30 6:30 7:30

a.m

1 hr 1 hr 1 hr 1 hr 1 hr 1 hr 1 hr 1 hr = 9 hours1 hr

9.

Page 33: Motivasi Mt Upsr 2011

How many days are there in the month shown on the calendar?

A 28 days C 30 daysB 29 days D 31 days

Name of the month

MAY

31 days

Page 34: Motivasi Mt Upsr 2011

How many years are there in

21

decade ?

A 5 C 12B 10 D 50

1 102

=

1

5

= 5

1 decade = 10 years

Page 35: Motivasi Mt Upsr 2011

The diagram shows the length of a plank.

State the length of the plank in m.

5 . 5 cm

5 . 5 cm

1 0 0= 0. 5 5 m

Page 36: Motivasi Mt Upsr 2011

Which of the following is the height of a year 6 student?

A 1.3 cm

B 13 cm

C 130 cm

D 1300 cm

130 cm

Page 37: Motivasi Mt Upsr 2011

Calculate the average length , in m , of the strings.

80 cm

1 . 8 5 m

1 . 8 5 0

+

2

4

0

1 . 0 5 m 1 8

5

1

2 . 9

0 0

Table 1 shows the length of strings needed to tie box Z and Box Y.

Box Length of stringZ 1.05 mY 80 cm

A 0.925 C 9.250B 1.850 D 11.40

0 . 8 m=

0 . 8 0 m

0

5

1 0

0

0.925

Page 38: Motivasi Mt Upsr 2011

The diagram shows the mass of a cabbage . What is the mass of the cabbage ?

A 1 kg 300 g C 1 kg 750 gB 1 kg 500 g D 1 kg 800 g

1 kg

250 g

250 g250 g

750 g

1000 g

+

1750 g=

= 1kg 750 g

=

Page 39: Motivasi Mt Upsr 2011

Step 1:i) Convert 52 kg 600 g to kg. 1 kg = 1000 g 600 g = 600 ÷ 1000 = 0.6 kg52 kg 600 g = 52 kg + 0.6 kg = 52.6 kg

The table shows the masses of three pupils.

Kim Haris Mohan

40.8 kg 52 kg 600 g 47 kg

Find the total mass in kg .

Step 2:ii) Find the total mass.

40.8 kg 52.6 kg+ 47.0 kg 140.4 kg

Page 40: Motivasi Mt Upsr 2011

Which of the following is the suitable dose of cough syrup that should be given to an adult patient?

A 1.5 mℓB 15 mℓC 150 mℓD 1500 mℓ

15 mℓ

Page 41: Motivasi Mt Upsr 2011

The diagram shows the volume of fresh milk and apple juice in two containers

a) the volume of the fresh milk is ________ b) the volume of apple juice is __________

Page 42: Motivasi Mt Upsr 2011

The diagram shows the volume of fresh milk and apple juice in two containers

a) the volume of the fresh milk is ________

1 ℓ 2 ℓ half

21

21

2 ℓ + =212 ℓ

500 mℓ

or 2 ℓ 500 mℓ + = 2 ℓ 500 mℓ

or2 ℓ 500 mℓ = 2 . 5 ℓ

Page 43: Motivasi Mt Upsr 2011

The diagram shows the volume of fresh milk and apple juice in two containers

1 ℓ

3 ℓ

b) the volume of apple juice is __________

2 ℓ

5 ℓ 4 ℓ

5 ℓ

or

5000 mℓ

Page 44: Motivasi Mt Upsr 2011

The table shows the volume of four types of canned drinks

Drink VolumeW 1 l 480 mlX 1 l 250 mlY 1 l 420 mlZ 1 l 500 ml

Which two types of canned drinks have a total volume of 2.75 l ?

Try and error

W + X = 2.73 l

Y + Z = 2.92 l

W + Y = 2.90 l

X + Z = 2.75 l

Answer = D

= 1.480 l

= 1.250 l

= 1.420 l= 1.500 l

1.480 l + 1.250 l =

1.420 l + 1.500 l =

1.480 l + 1.420 l =

1.250 l + 1.500 l =

Page 45: Motivasi Mt Upsr 2011

ChoosingTheOperation

Working

Backwards

Using Logic Guessin

gAnd

Checking

Make a table Chart/ systematic

Identifying

patterns and

sequences

Finding

Facts

Draw a diagram

Problem SolvingStrategi

es

Page 46: Motivasi Mt Upsr 2011

Ena takes 25 minutes to wrap a gift. Find the total time needed ,

in hours and minutes , to wrap 7 similar gifts.

Solution

Steps:

i) 25 minutes x 7 = 175 minutes

ii ) 1 hour = 60 minutes

175 minutes = 175 ÷ 60

= 2 hours 55 minutes

Page 47: Motivasi Mt Upsr 2011

1072

1072

213

213

The diagram shows a road map.

Jamal cycled from his house to the mosque and then to the library. Find the distance , in km , he has cycled.

House to mosque

+

Mosque to library

House to mosque to library

= 1072

1053

10125

+

=

=

=

10105 10

2

10215

1026 5

16

=

=

Page 48: Motivasi Mt Upsr 2011

The total mass of 9 similar packets of sugar is 9.81 kg. What is the mass , in g , of each packet of sugar ?

A 1 900 C 1 009B 1 090 D 109

9 packets of sugar = 9.81 kg.

1 packet of sugar = 9.81 9 = 1.09kg= 1090 g

Page 49: Motivasi Mt Upsr 2011

What is the average of 320 ml and 1.65 l ?

A 941 l C 0.962 lB 950 l D 0.985 l

1. 9 7 l

+

1 . 9 7 l2

1 8

1

.

320 ml = 0.32 l

0 . 3 2 l1 . 6 5 l

0 9

7

8

1 6 1 0

0

1 0

5

0

Page 50: Motivasi Mt Upsr 2011

A jug of juice contains 300 ml of water and 5 ml of syrup cordial.How much syrup cordial needed to be mixed with 6 ℓ of water to have the same taste ?A 0.1 C 100 B 4 D 1 200

300 mℓ = 5 mℓ

× 20 = ×20

6000 mℓ = 100 mℓ

6 ℓ = 6000 mℓ

6000 ÷ 300 = 20

Page 51: Motivasi Mt Upsr 2011
Page 52: Motivasi Mt Upsr 2011

2D & 3D Shape

Page 53: Motivasi Mt Upsr 2011

Diagram 3 shows a piece of cylindrical wood.

The wood is cut into three parts. How many flat faces are there altogether?

2D & 3D Shape

Page 54: Motivasi Mt Upsr 2011

Diagram 2 shows a number of rectangular cards, P and a number of square card, Q.

Which of the following combinations of cards can form a box in the shape of cuboid?A 1 piece of P and 5 piece of Q B 2 pieces of P and 4 piece of Q C 3 pieces of P and 3 piece of Q D 4 pieces of P and 2 piece of Q

P Q4 cm 4 cm

8 cm

2D & 3D Shape

Page 55: Motivasi Mt Upsr 2011

A solid has 6 flat surfaces and the following characteristics;

2 square surfaces

4 rectangular surfaces

8 vertices

What is the name of the solid?A Cuboid B Cube C Pyramid D Cylinder

2D & 3D Shape

Page 56: Motivasi Mt Upsr 2011

The diagram consists of several squares of equal size. Find the perimeter of the shaded area.

2D & 3D Shape

Page 57: Motivasi Mt Upsr 2011

Diagram below shows a square UWXY and a rectangle JKLM. JYXK is a straight line.

Find the perimeter, in cm, of the whole diagram.

2D & 3D Shape

Page 58: Motivasi Mt Upsr 2011

2D & 3D Shape

Page 59: Motivasi Mt Upsr 2011
Page 60: Motivasi Mt Upsr 2011

Diagram below shows two squares, PQRS and SEFG

Find the area, in cm2, of the shaded region

Page 61: Motivasi Mt Upsr 2011

Calculate the area, in cm2, of the shaded region

Diagram below shows a combination of a rectangle EFGH

and a square EMHN.

2D & 3D Shape

Page 62: Motivasi Mt Upsr 2011

2D & 3D Shape

Page 63: Motivasi Mt Upsr 2011

2D & 3D Shape

Page 64: Motivasi Mt Upsr 2011

2D & 3D Shape

Page 65: Motivasi Mt Upsr 2011

2D & 3D Shape

Page 66: Motivasi Mt Upsr 2011

2D & 3D Shape

Page 67: Motivasi Mt Upsr 2011

In diagram below, triangle X, P, Q, R and S are drawn on squares of equal size.

Which triangle has the same characteristic as X ?

2D & 3D Shape

Page 68: Motivasi Mt Upsr 2011

2D & 3D Shape

Page 69: Motivasi Mt Upsr 2011

2D & 3D Shape

Page 70: Motivasi Mt Upsr 2011

0102030405060708090

1st Qtr 2nd Qtr 3rd Qtr 4th Qtr

EastWestNorth

Page 71: Motivasi Mt Upsr 2011
Page 72: Motivasi Mt Upsr 2011
Page 73: Motivasi Mt Upsr 2011
Page 74: Motivasi Mt Upsr 2011

Determine the frequency, mode, range, average, maximum and minimum value from a pie chart,

Page 75: Motivasi Mt Upsr 2011

The Owners of 8 Dolls

Page 76: Motivasi Mt Upsr 2011

Frequency :

Page 77: Motivasi Mt Upsr 2011

Range : Maximum - Minimum

Maximum

Minimum

Range : 3 - 1 = 2

Page 78: Motivasi Mt Upsr 2011

Mode : Most popular or frequent value

What is the most common number of dolls collected ?

Page 79: Motivasi Mt Upsr 2011

Average :

Page 80: Motivasi Mt Upsr 2011

Study the pie chart and answer the following question.

Page 81: Motivasi Mt Upsr 2011

Study the pie chart and answer the following question.

Page 82: Motivasi Mt Upsr 2011

Study the pie chart and answer the following question.

Page 83: Motivasi Mt Upsr 2011