final form 4 kertas 2 2011 (jawapan)
TRANSCRIPT
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7/29/2019 Final Form 4 Kertas 2 2011 (Jawapan)
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Form Four
Additional Mathematics
Paper 2
October 2011
SEKOLAH MENENGAH SAINS TELUK INTAN
PEPERIKSAAN DIAGNOSTIK TINGKATAN 4 2011
ADDITIONAL MATHEMATICS
Form FourPaper 2
Marking Scheme
.
This marking scheme consists of 11 printed pages.
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7/29/2019 Final Form 4 Kertas 2 2011 (Jawapan)
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No. Solution Marks
1 y = 2x3
2x - 10x + (2x3) + 9 = 0
(x1)(x3) = 0
x= 1 , 3
y= -1 , 3
K1
K1
K1
N1
N15
2 (a)
(b)
k= , = - m= 2
y
6
x 3-
Range :
K1
N1
K1
N1, N1
N1
Shape of
graph
N1
(0 , 6), ( ,-)
and (3,0)
N1
8
3 7 or k
(+3)(+3) = m or 259)(3
6 m 16)7(3
k = = -5
-5 = m6
m = 1
K1
K1
K1, K1
N1, N1
6
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CONFIDENTAL 3 3472/2
[See overleaf]
3472/2 CONFIDENTAL
4 or n= 5
96)2(5 k
k= 3
P1
K1
K1
N1
K1
N1
6
5 (a)
(b)
x =
= 30
22 3015
13635
= 9
and m = 3, n = 7
K1
N1
K1
N1
K1, K1
N1, N1
8
6 (a)
(b)
(c)
= - 1.5
342
pdx
dy
2)10(3
12
x
= -0.008
K1
N1
K1
K1
N1
K1
N17
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7 (a)
(b)
(c)
4)1()1( baf
2)1()1( baf
a = 3 dan b = 1
Let yxf )(1 xyf )(
3
1y
x
3
1
)(1
x
xf
2
2313
xxg
3
113
y
xxy
2
13
13
)(
y
yg
2)(
xxg
2)4( g
K1
K1
N1, N1
K1
N1
K1
N1
N1
N1
10
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CONFIDENTAL 5 3472/2
[See overleaf]
3472/2 CONFIDENTAL
8 (a)
(b)
(c)
Midpoint ofAB
= =
=
=
15
2APm dan
2
15PRm
10
5
8
15
2
x
y
5
8
2
15 xy
K1
K1
K1
N1
K1
K1
N1
K1
K1
N1
10
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9 (a)
(b)
(c)
Uniform scale
All bars are correctly drawnMode = 46.5
23.98
40.5
45.12
K1
K1N1
K1
K1
K1
N1
P1
K1
N1
10
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10 (a)
(b)
(c)
(d)
CT = 18 cm
= 71.57= 1.249 rad
= 5.791 cm
= 7.494 cm
= 18.9737 cm
BT= 18.97376= 12.9737 cm
38.47 cm
K1
N1
K1
N1
K1
N1
K1
K1
K1
N1
10
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11 (a)
(b)
cm
K1
K1
K1
N1
N1
K1
K1
K1
K1
N1
10
12 (a)
(b)
(c)
(d)
K1
N1
K1, P1
N1
K1
N1
K1
K1
N1
10
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13 (a)
(b)
(c)
(d)
= 19.5957 cm
= 14.6968 cm
K1
N1
K1
K1
N1
K1
N1
K1
K1
N1
10
14(a)(i)
(ii)
(b)(i)
(ii)
K1
N1
K1, K1
N1
K1, K1
N1
K1
N1
10
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15 (a)
(b)
(c)
(d)(i)
(ii)
= 105.5
= 137.15
K1
N1
K1
N1
K1, K1
N1
N1
K1
N1
10
END OF MARKING SCHEME