final form 4 kertas 2 2011 (jawapan)

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  • 7/29/2019 Final Form 4 Kertas 2 2011 (Jawapan)

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    CONFIDENTAL 3472/2

    3472/2 CONFIDENTAL

    3472/2

    Form Four

    Additional Mathematics

    Paper 2

    October 2011

    SEKOLAH MENENGAH SAINS TELUK INTAN

    PEPERIKSAAN DIAGNOSTIK TINGKATAN 4 2011

    ADDITIONAL MATHEMATICS

    Form FourPaper 2

    Marking Scheme

    .

    This marking scheme consists of 11 printed pages.

  • 7/29/2019 Final Form 4 Kertas 2 2011 (Jawapan)

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    CONFIDENTAL 2 3472/2

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    No. Solution Marks

    1 y = 2x3

    2x - 10x + (2x3) + 9 = 0

    (x1)(x3) = 0

    x= 1 , 3

    y= -1 , 3

    K1

    K1

    K1

    N1

    N15

    2 (a)

    (b)

    k= , = - m= 2

    y

    6

    x 3-

    Range :

    K1

    N1

    K1

    N1, N1

    N1

    Shape of

    graph

    N1

    (0 , 6), ( ,-)

    and (3,0)

    N1

    8

    3 7 or k

    (+3)(+3) = m or 259)(3

    6 m 16)7(3

    k = = -5

    -5 = m6

    m = 1

    K1

    K1

    K1, K1

    N1, N1

    6

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    CONFIDENTAL 3 3472/2

    [See overleaf]

    3472/2 CONFIDENTAL

    4 or n= 5

    96)2(5 k

    k= 3

    P1

    K1

    K1

    N1

    K1

    N1

    6

    5 (a)

    (b)

    x =

    = 30

    22 3015

    13635

    = 9

    and m = 3, n = 7

    K1

    N1

    K1

    N1

    K1, K1

    N1, N1

    8

    6 (a)

    (b)

    (c)

    = - 1.5

    342

    pdx

    dy

    2)10(3

    12

    x

    = -0.008

    K1

    N1

    K1

    K1

    N1

    K1

    N17

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    CONFIDENTAL 4 3472/2

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    7 (a)

    (b)

    (c)

    4)1()1( baf

    2)1()1( baf

    a = 3 dan b = 1

    Let yxf )(1 xyf )(

    3

    1y

    x

    3

    1

    )(1

    x

    xf

    2

    2313

    xxg

    3

    113

    y

    xxy

    2

    13

    13

    )(

    y

    yg

    2)(

    xxg

    2)4( g

    K1

    K1

    N1, N1

    K1

    N1

    K1

    N1

    N1

    N1

    10

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    CONFIDENTAL 5 3472/2

    [See overleaf]

    3472/2 CONFIDENTAL

    8 (a)

    (b)

    (c)

    Midpoint ofAB

    = =

    =

    =

    15

    2APm dan

    2

    15PRm

    10

    5

    8

    15

    2

    x

    y

    5

    8

    2

    15 xy

    K1

    K1

    K1

    N1

    K1

    K1

    N1

    K1

    K1

    N1

    10

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    CONFIDENTAL 6 3472/2

    3472/2 CONFIDENTAL

    9 (a)

    (b)

    (c)

    Uniform scale

    All bars are correctly drawnMode = 46.5

    23.98

    40.5

    45.12

    K1

    K1N1

    K1

    K1

    K1

    N1

    P1

    K1

    N1

    10

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    CONFIDENTAL 7 3472/2

    [See overleaf]

    3472/2 CONFIDENTAL

    10 (a)

    (b)

    (c)

    (d)

    CT = 18 cm

    = 71.57= 1.249 rad

    = 5.791 cm

    = 7.494 cm

    = 18.9737 cm

    BT= 18.97376= 12.9737 cm

    38.47 cm

    K1

    N1

    K1

    N1

    K1

    N1

    K1

    K1

    K1

    N1

    10

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    11 (a)

    (b)

    cm

    K1

    K1

    K1

    N1

    N1

    K1

    K1

    K1

    K1

    N1

    10

    12 (a)

    (b)

    (c)

    (d)

    K1

    N1

    K1, P1

    N1

    K1

    N1

    K1

    K1

    N1

    10

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    CONFIDENTAL 9 3472/2

    [See overleaf]

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    13 (a)

    (b)

    (c)

    (d)

    = 19.5957 cm

    = 14.6968 cm

    K1

    N1

    K1

    K1

    N1

    K1

    N1

    K1

    K1

    N1

    10

    14(a)(i)

    (ii)

    (b)(i)

    (ii)

    K1

    N1

    K1, K1

    N1

    K1, K1

    N1

    K1

    N1

    10

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    15 (a)

    (b)

    (c)

    (d)(i)

    (ii)

    = 105.5

    = 137.15

    K1

    N1

    K1

    N1

    K1, K1

    N1

    N1

    K1

    N1

    10

    END OF MARKING SCHEME