laporan baja 2

8/16/2019 Laporan Baja 2

1/24

4.1.1.1 Gording AProfilKanal = 280 x 95 x 10 x 15d = 280 mm Ag = 53,30 cm 2

b = 95 mm Ix = 6280 cm 4

tw = 10 mm Iy = 399 cm4

tf = 15 mm ix = 10,85 cmr = 15 mm iy = 2,74 cm

= 400 cm !x = 448,57 cm 3

"# = 6326,59 $g%cm &' = 3163,295 $g%cm(y = 320 m)a * = 200000 m)a+ = 80000 m)a

ll = 100 $g dl = 50,17 $g%mll = - .100 $g x / .25 x 4 m

=90 63 $g%m

= 1,2 dl 1,6 ll= 1,2 x 50,17 1,6 x 90,63= 205,212 $g%m= 2,052 $g%cm

K ntr l nd#tan

i in = L

360 =400360 = 1,11 cm

t r adi =5 ×q× L 4

384 × E × I =5 × 2,052 × 400 4

384 × 2000000 × 6280 = 0,054 cm

i in t r adi1,67 cm 0,054 cm : $ ;

a K ntr l K $#atan + r< = d 2 .tf r

= 280 2 .15 15 = 220 mm = 22 cm

h

tw =22010 = 22 mm >

1100√ fy =

1100√ 320 = 61,49 mm

a = 150 cm(asumsi ) = 1500 mm

Kn =

5 + 5

(ah)2

=

5 + 5

(1500220 )2

= 5,11 mm

K#at n minal g r

h

tw = 1,1 √kn×Efy


2/24

22 = 1,1 √5,11 x20000032022 = 62,16 : ?$;&n = 0,6 x fy x Aw

= 0,6 x 3200 x .28x1= 53760 $g%cm2

@&n &'0,9 x 53760 3163,29548384 $g 3163,295 $g : $;

b K ntr l $#at m m n l nt#r cal b#c$ling

B !aya)

bf

2 tf =95

2 x15 = 3,17 mm > C) =170

√ 320 = 9,5 mm

B Dadanh

tw =22010 = 22 mm > C) =

1680√ fy =

1680√ 320 = 93,91

mmEx = .b x tf .F B tf tw.GF B tf .GF B tf

= .95x15 .280B15 10.G280B15 .G280B15= 533875 mm= 53387,5 cm

"n = ")= Ex x fy

= 3200 x 53387,5= 170840000 $g%cm

at ral D#c$ling

b = 150 cm

) = 1,76 x iy√ Efy= 1,76 x 2,74 √20000003200= 120,56 cm

(y = 3200 Kg%cm 2

(r = 700 Kg%cm 2

(l = (yB(r = 3200B700

) nam)ang$ m)a$


3/24

= 2500 $g%cm2

H = J bt 3

= ((13 ×bf ×tf 3) x2) (13 ×h×tw 3)= ((13 × 9,5 × 1,5

3) x2) (13 × 22 × 13

)= 21,375 7,333= 28,71 cm 4

M

120,56 cm L 150 cm > 435,78 cmBentang Menengah


4/24

"n = /b ( Mr +( Mp− Mr )( Lr− L Lr − Lp))≤ Mp"r = !x.fyBfr

= 448,57 .3200B700

= 1121425 $g%cm"y= fy x !x

= 3200 x 448,57= 1435424 $g%cm

") = 1,5 x "y= 1,5 x 1435424= 2153136 $g%cm

") = fy x Ex = 3200 x 53387,5= 170840000 $g%cm

/b =

12,5 Mmax

2,5 Mmax +3 Ma +4 Mb+3 Mc ≤ 2,3

=

12,5 x93978,77

2,5 x 93978,77 +3 x 14

x93978,77 +4 x 12

x93978,77 +3 x 34

x93978,77≤ 2,3

= 1,67 ≤ 2,3

"n = /b ( Mr +( Mp− Mr )( Lr− L Lr − Lp))≤ Mp

= 1,67 (1121425 +(2153136 − 1121425 )( 435,78 − 150435,78 − 120,56 ))= 3434821,363 $g%cm L 170840000 $g%cm

@"n "#0,9x 3434821,363 6326,593091339,23$g %cm 6326,59 $g%cm: $;

4.1.1.2 Gording Bll = 100 $g dl = 105,34 $g%mll = - .100 $g x / .25 x 6 m

=122,87 $g%m= 1,2 dl 1,6 ll= 1,2 x 65,27 1,6 x 122,87


5/24

= 274,92 $g%m= 2,75 $g%cm

K ntr l nd#tan

i in = L

360 =600360 = 1,67 cm

t r adi =5 ×q× L 4

384 × E × I =5 × 2,75 × 600 4

384 × 2000000 × 6280 = 0,37 cm

i in y t r adi1,67 cm 0,37 cm : $ ;

a K ntr l K $#atan + r< = d 2 .tf r

= 280 2 .15 15 = 220 mm = 22 cm

h

tw =22010 = 22 mm >

1100√ fy =

1100√ 320 = 61,49 mm

a = 150 cm(asumsi ) = 1500 mm

Kn =5 + 5

(ah)2

=5 + 5

(1500220 )2

= 5,11 mm

K#at n minal g r

h

tw = 1,1 √kn×Efy22 = 1,1 √5,11 x200000320

22 = 62,16 : ?$;&n = 0,6 x fy x Aw

= 0,6 x 3200 x .28x1= 53760 $g%cm2

@&n &'0,9 x 53760 46989,3948384 $g 46989,39 $g : $;

K ntr l $#at m m n l nt#r cal b#c$ling

B !aya)

bf

2 tf =95

2 x15 = 3,17 mm > C) =170

√ 320 = 9,5 mm

B Dadan ) nam)ang

$ m)a$


6/24

htw =

22010 = 22 mm > C) =

1680√ fy =

1680√ 320 = 93,91


= .95x15 .280B15 10.G280B15 .G280B15= 533875 mm= 53387,5 cm

"n = ")= Ex x fy= 3200 x 53387,5= 170840000 $g%cm

at ral D#c$ling

b = 150 cm

) = 1,76 x iy√ Efy

= 1,76 x 2,74 √20000003200= 120,56 cm

(y = 3200 Kg%cm 2

(r = 700 Kg%cm 2

(l = (yB(r = 3200B700= 2500 $g%cm2

H = J bt3

= ((13 ×bf ×tf 3) x2) (13 ×h×tw 3)= ((13 × 9,5 × 1,5 3) x2) (13 × 22 × 1 3)= 21,375 7,333= 28,71 cm 4


7/24

= 70049,44 cm 6

1 =π Sx √ E×G×J × A2

=

3,14

448,57 √2000000 x 800000 x28,71 x53,30

2

= 244920,21 $g%cm 2

2 = 4 ( SxG× J )2

× Iw Iy

= 4( 448,57800000 × 28,71 )2

×70049,44

399

= 2,68 x 10 B7 $g%cm2

r = iy

( X 1

fy− fr )√ 1 +√ 1+ x2 × fl 2

= 2,74 (244920,212500 )√ 1+√ 1 +2,68 × 10 −7 × 2500 3= 435,78 cm

) L D > M 120,56 cm L 150 cm > 435,78 cmBentang Menengah


= 448,57 .3200B700= 1121425 $g%cm

"y= fy x !x= 3200 x 448,57= 1435424 $g%cm

") = 1,5 x "y= 1,5 x 1435424= 2153136 $g%cm

") = fy x Ex

= 3200 x 53387,5= 170840000 $g%cm

/b =12,5 Mmax

2,5 Mmax +3 Ma +4 Mb+3 Mc ≤2,3


8/24

=

12,5 x93978,77

2,5 x 93978,77 +3 x 1

4 x93978,77 +4 x 1

2 x93978,77 +3 x 3

4 x93978,77

≤ 2,3

= 1,67 ≤ 2,3


= 1,67 (1121425 +(2153136 − 1121425 )( 435,78 − 150435,78 − 120,56 ))= 3434821,363 $g%cm L 170840000 $g%cm

@"n "#0,9x 3434821,363 93978,773091339,23$g %cm 93978,77 $g%cm: $;

4.1.1.3 Gording Cll = 100 $g dl = 47,575 $g%mll = - .100 $g x / .35 x 6 m

=122,87 $g%m= 1,2 dl 1,6 ll= 1,2 x 47,575 1,6 x 122,87

= 253,68 $g%m= 2,54 $g%cm

K ntr l nd#tan

i in = L

360 =600360 = 1,67 cm

t r adi =5 ×q× L 4

384 × E × I

=

5 × 2,54 × 600 4

384 × 2000000 × 6280 = 0,34 cm

i in y t r adi1,67 cm 0,34 cm : $ ;

a K ntr l K $#atan + r


9/24

< = d 2 .tf r = 280 2 .15 15 = 220 mm = 22 cm

h

tw =22010 = 22 mm >

1100√ fy =

1100√ 320 = 61,49 mm

a=

150 cm(asumsi

) = 1500 mm

Kn =5 + 5

(ah)2

=5 + 5

(1500220 )2

= 5,11 mm

K#at n minal g r

h

tw = 1,1 √kn×Efy22 = 1,1 5,11 x200000320

22 = 62,16 : ?$;&n = 0,6 x fy x Aw

= 0,6 x 3200 x .28x1= 53760 $g%cm2

@&n &'0,9 x 53760 46989,3948384 $g 46989,39 $g : $;

b K ntr l $#at m m n l nt#r

cal b#c$lingB !aya)

bf

2 tf =95

2 x15 = 3,17 mm > C) =170

√ 320 = 9,5 mm

B Dadanh

tw =22010 = 22 mm > C) =

1680√ fy =

1680√ 320 = 93,91


= .95x15 .280B15 10.G280B15 .G280B15= 533875 mm= 53387,5 cm

"n = ")= Ex x fy= 3200 x 53387,5= 170840000 $g%cm

at ral D#c$ling

) nam)ang$ m)a$


10/24

b = 150 cm

) = 1,76 x iy√ Efy= 1,76 x 2,74 √20000003200= 120,56 cm

(y = 3200 Kg%cm 2

(r = 700 Kg%cm 2

(l = (yB(r = 3200B700= 2500 $g%cm2

H = J bt 3

= ((1

3 ×bf ×tf 3

) x2

) (1

3×h×tw 3

)= ((13 × 9,5 × 1,5 3) x2) (13 × 22 × 1 3)= 21,375 7,333= 28,71 cm 4


11/24

= 2,68 x 10 B7 $g%cm2

r = iy( X 1fy− fr )√ 1 +√ 1+ x2 × fl 2

= 2,74 (244920,212500 )√ 1+√ 1 +2,68 × 10 −7 × 2500 3

= 435,78 cm) L D > M

120,56 cm L 150 cm > 435,78 cmBentang Menengah


= 448,57 .3200B700= 1121425 $g%cm"y= fy x !x

= 3200 x 448,57= 1435424 $g%cm

") = 1,5 x "y= 1,5 x 1435424= 2153136 $g%cm

") = fy x Ex = 3200 x 53387,5= 170840000 $g%cm

/b = 12,5 Mmax2,5 Mmax +3 Ma +4 Mb+3 Mc ≤ 2,3

=

12,5 x93978,77

2,5 x 93978,77 +3 x 14

x93978,77 +4 x 12

x93978,77 +3 x 34

x93978,77≤ 2,3

= 1,67 ≤ 2,3


= 1,67 (1121425 +(2153136 − 1121425 )( 435,78 − 150435,78 − 120,56 ))= 3434821,363 $g%cm L 170840000 $g%cm


12/24

@"n "#0,9x 3434821,363 93978,773091339,23$g %cm 93978,77 $g%cm: $;

4.1.1.4 Gording A-Bll = 100 $g dl = 116,99 $g%mll = - .100 $g x / .35 x 6 m

=122,87 $g%m= 1,2 dl 1,6 ll= 1,2 x 116,99 1,6 x 122,87= 336,98 $g%m= 3,37 $g%cm

K ntr l nd#tan

i in =

L

360 =

600

360 = 1,67 cm

t r adi =5 ×q× L 4

384 × E × I =5 × 3,37 × 600 4

384 × 2000000 × 6280 = 0,46 cm

i in y t r adi1,67 cm 0,46 cm : $ ;

o K ntr l K $#atan + r< = d 2 .tf r

= 280 2 .15 15 = 220 mm = 22 cm

h

tw =22010 = 22 mm >

1100√

fy =

1100√

320 = 61,49 mm

a = 150 cm(asumsi ) = 1500 mm

Kn =5 + 5

(ah)2

=5 + 5

(1500220 )2

= 5,11 mm

K#at n minal g r

h

tw =1,1

√kn×E

fy

22 = 1,1 √5,11 x20000032022 = 62,16 : ?$;&n = 0,6 x fy x Aw

= 0,6 x 3200 x .28x1


13/24

= 53760 $g%cm2

@&n &'0,9 x 53760 46989,3948384 $g 46989,39 $g : $;

o

K ntr l $#at m m n l nt#r cal b#c$lingB !aya)

bf

2 tf =95

2 x15 = 3,17 mm > C) =170

√ 320 = 9,5 mm

B Dadanh

tw =22010 = 22 mm > C) =

1680√ fy =

1680√ 320 = 93,91

mm

Ex = .b x tf .F B tf tw.GF B tf .GF B tf= .95x15 .280B15 10.G280B15 .G280B15= 533875 mm= 53387,5 cm

"n = ")= Ex x fy= 3200 x 53387,5= 170840000 $g%cm

at ral D#c$ling

b = 150 cm

) = 1,76 x iy√ Efy= 1,76 x 2,74 √20000003200= 120,56 cm

(y = 3200 Kg%cm 2

(r = 700 Kg%cm 2

(l = (yB(r

= 3200B700= 2500 $g%cm2

H = J bt 3

= ((13 ×bf ×tf 3) x2) (13 ×h×tw 3)

) nam)ang$ m)a$


14/24

= ((13 × 9,5 × 1,5 3) x2) (13 × 22 × 1 3)= 21,375 7,333= 28,71 cm 4

M 120,56 cm L 150 cm > 435,78 cmBentang Menengah


= 448,57 .3200B700


15/24

= 1121425 $g%cm"y= fy x !x

= 3200 x 448,57= 1435424 $g%cm

") = 1,5 x "y

= 1,5 x 1435424= 2153136 $g%cm") = fy x Ex

= 3200 x 53387,5= 170840000 $g%cm

/b =12,5 Mmax

2,5 Mmax +3 Ma +4 Mb+3 Mc ≤2,3

=

12,5 x93978,77

2,5 x 93978,77 +3 x 14

x93978,77 +4 x 12

x93978,77 +3 x 34

x93978,77 ≤2,3

= 1,67 ≤ 2,3


= 1,67 (1121425 +(2153136 − 1121425 )( 435,78 − 150435,78 − 120,56 ))= 3434821,363 $g%cm L 170840000 $g%cm

@"n "#0,9x 3434821,363 93978,773091339,23$g %cm 93978,77 $g%cm: $;

4.1.1.5 Gording A-Cll = 100 $g dl = 99,295 $g%mll = - .100 $g x / .35 x 6 m

=122,87 $g%m= 1,2 dl 1,6 ll= 1,2 x 99,295 1,6 x 122,87= 315,75 $g%m= 3,16 $g%cm

K ntr l nd#tan

i in = L

360 =600360 = 1,67 cm


16/24

t r adi =5 ×q× L 4

384 × E × I =5 × 3,16 × 600 4

384 × 2000000 × 6280 = 0,43cm

i in y t r adi1,67 cm 0,43 cm : $ ;

o

K ntr l K $#atan + r< = d 2 .tf r = 280 2 .15 15 = 220 mm = 22 cm

h

tw =22010 = 22 mm >

1100√ fy =

1100√ 320 = 61,49 mm

a = 150 cm(asumsi ) = 1500 mm

Kn =5 + 5

(ah)2

=5 + 5

(1500220 )2

= 5,11 mm

K#at n minal g r

h

tw = 1,1 √kn×Efy22 = 1,1 √5,11 x200000320

22 = 62,16 : ?$;&n = 0,6 x fy x Aw

= 0,6 x 3200 x .28x1= 53760 $g%cm2

@&n &'0,9 x 53760 46989,3948384 $g 46989,39 $g : $;

o K ntr l $#at m m n l nt#r cal b#c$ling

B !aya)

bf

2 tf =95

2 x15 = 3,17 mm > C) =170

√ 320 = 9,5 mm

B Dadanh

tw =22010 = 22 mm > C) =

1680√ fy =

1680√ 320 = 93,91


= .95x15 .280B15 10.G280B15 .G280B15= 533875 mm

) nam)ang$ m)a$


17/24

= 53387,5 cm"n = ")

= Ex x fy= 3200 x 53387,5= 170840000 $g%cm

at ral D#c$ling

b = 150 cm

) = 1,76 x iy√ Efy= 1,76 x 2,74 √20000003200= 120,56 cm

(y = 3200 Kg%cm 2(r = 700 Kg%cm 2

(l = (yB(r = 3200B700= 2500 $g%cm2

H = J bt 3

= ((13 ×bf ×tf 3) x2) (13 ×h×tw 3)=

((13 × 9,5 × 1,5 3) x2

) (13 × 22 × 1 3)

= 21,375 7,333= 28,71 cm 4


18/24

= 244920,21 $g%cm 2

2 = 4 ( SxG× J )2

× Iw Iy

= 4

( 448,57

800000 × 28,71 )2

×70049,44

399

= 2,68 x 10 B7 $g%cm2

r = iy( X 1fy− fr )√ 1 +√ 1+ x2 × fl 2

= 2,74 (244920,212500 )√ 1+√ 1 +2,68 × 10 −7 × 2500 3= 435,78 cm

) L D > M 120,56 cm L 150 cm > 435,78 cmBentang Menengah


= 448,57 .3200B700= 1121425 $g%cm

"y= fy x !x= 3200 x 448,57

= 1435424 $g%cm") = 1,5 x "y= 1,5 x 1435424= 2153136 $g%cm

") = fy x Ex = 3200 x 53387,5= 170840000 $g%cm

/b =12,5 Mmax

2,5 Mmax +3 Ma +4 Mb+3 Mc ≤2,3

=

12,5 x93978,77

2,5 x 93978,77 +3 x 14

x93978,77 +4 x 12

x93978,77 +3 x 34

x93978,77≤ 2,3

= 1,67 ≤ 2,3


19/24


= 1,67

(1121425 +(2153136 − 1121425 )

( 435,78 − 150

435,78 − 120,56 ))= 3434821,363 $g%cm L 170840000 $g%cm@"n "#0,9x 3434821,363 93978,773091339,23$g %cm 93978,77 $g%cm: $;

4.2BIDANG TARI 4.2.1 !da- !da

Profil!i$# = 150 x 150 x 15N# = 9844,03 $g

(y = 320 ")a = 3200 Kg%cm 2

(# = 1,3 x 320

= 416 ")a= 4160 Kg%cm2

Ag = 42,74 cm 2

= 4274 mm 2

tw = 15 mm

tf = 15 mm

r = 14 mm

F = 150 mm

4.2.1.1 "a#$!ngan

O = 20 mm

= 2 cm .b r

Ol#bang= @ ba#t 1,5 mm

= 20 1,5 = 21,5mm = 2,15 cmAb = - P .2,15 2

= 3,63 cm 2

4

7

7

7,5

d = 2.15

x = 7.5 1 5

15 1

, 5


20/24

Q bal )lat = 1,5 cmK#at + r @Mn = @ x r1 x f# x Ab x t)

= 0,75 x 0,5 x 4160 x 3,63 x 1,5= 8494,2 $g

K#at Q#m)# @Mn = @ x 2,4 x d x t) x f#

= 0,75 x 2,4 x 2 x 1,5 x 4160= 22464 $g

n = u

!"n

=9844,038494,2

= 1,2 R 3 ba#t

@M#' = u

n

=9844,03

3

= 3281,34 $g@Mn @M#'8494,2 $g 3281,34 $gQn = 0,75 x f# x Ab

= 0,75 x 4160 x 3,63= 11325,6 $g

4.2.1.2 Perhit!ngan Tari% 1& Ag'( Agt( An'( dan Ant )$lo*% +hear&Ag' = 18 x 1,5

= 27 cm 2

Agt = 7,5 x 1,5= 11,25 cm 2

An' = .18 .2,15 x 2,5 x 1,5= 18,94 cm 2

Ant , .7,5B . 2,15 x 0,5 x 1,5= 9,64 cm 2

2& P!t!+ Tari% dan P!t!+ Ge+er

N#t# tari$ = f# x Ant= 4160 x 9,64= 40102,4 $g

N#t# + r = 0,6 x f# x An'= 0,6 x 4160 x 18,94= 47274,24 $g

N#t# g r )#t# tari$ Mn =.0,6 x f# x An' fy x Agt


21/24

=.0,6 x 4160 x 18,94 3200 x 11,25= 83274,24 $g

@Mn N#0,75 x 83274,24 9844,0362455,68 $g 9844,03 $g

3& eleh dan P!t!+l


22/24

Kc = )it )it N# = 11157 $gAg = 42,74 cm 2 d = FB2 .tf rix=iy = 4,56 cm = 150 2.15 14

bf = 150 mm = 15 cm = 92 mmtb=tf = 15 mm = 1,5 cm < = d 2 .tf r

r = 14 mm = 92 B 2 .15 14fy = 320 ")a = 3200 $g%cm = 34 mm1& ontrol Pena# ang

!aya) =bf

2 tf =150

2 x15 Cr =250

√ 320

= 5 mm > = 13,98 mm

Dadan =h

tw =3415 Cr =

665√ 320

= 2,27 mm > = 37,17 mmHadi ) nam)ang tida$ lang ing

2& Anali+a elang+ingan = 1088,61 cm

Uilai $c #nt#$ )itB )it = 0,65

C =kcxL

i

Cx =kcxL

ix

=0,65 x 1088,61

4,56

= 155, 17

Cy =kcxL

iy

=0,65 x 1088,61

4,56

= 155, 173& Menghit!ng *

Cc = #π

× √ fy E =

155,173,14

× √ 32002000000 = 1,98 .batang )an ang

V = 1,2 x Cc 2

= 1,2 x 1,98 2


23/24

= 4,74& Menent!%an Pn

Nn = Ag xfy$

= 42,74 x3200

4,7

= 29099,57 $g@Nn N#0,85 x 29099,57 1115724734,63 $g 11157 $g $;

4.3.2 /DA 0 /DA BA AProfil!i$# = 150 x 150 x 15Kc = )it )it N# = 11157 $gAg = 42,74 cm 2 d = FB2 .tf rix=iy = 4,56 cm = 150 2.15 14

bf = 150 mm = 15 cm = 92 mmtb=tf = 15 mm = 1,5 cm < = d 2 .tf r r = 14 mm = 92 B 2 .15 14fy = 320 ")a = 3200 $g%cm = 34 mm5& ontrol Pena# ang

!aya) =bf

2 tf =150

2 x15 Cr =250

√ 320

= 5 mm > = 13,98 mm

Dadan =h

tw =34

15 Cr =

665

√ 320

= 2,27 mm > = 37,17 mmHadi ) nam)ang tida$ lang ing

& Anali+a elang+ingan = 827,53 cm

Uilai $c #nt#$ )itB )it = 0,65

C =kcxL

i

Cx =

kcxL

ix

=0,65 x 827,53

4,56

= 117,96

Cy =kcxL

iy


24/24

=0,65 x 827,53

4,56

= 117,966& Menghit!ng *

Cc = #π × √ fy E =

117,963,14

× √ 32002000000 = 1,5 .batang )an ang

V = 1,5 x Cc 2

= 1,2 x 1,5 2

= 2,77& Menent!%an Pn

Nn = Ag xfy$

= 42,74 x32002,7

= 50654,81 $g@Nn N#0,85 x 50654,81 1115743056,59 $g 11157 $g $;

laporan baja 2

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