koleksisoalanaddmathkertas1-100524205855-phpapp02
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Koleksi Soalan-Soalan
Percubaan add math SPM
kertas 1
Disusun: http://kampungebuku.blogspot.com
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Daftar Isi
Koleksi Soalan-Soalan Percubaan Add Math Kertas 1
1. Peperiksaan Percubaan Sekolah Berasrama Penuh ……1
2. Jawapan Peperiksaan Percubaan SBP…………………. 19
3. Peperiksaan Percubaan Negeri Perak………………….. 25
4. Jawapan Peperiksaan Percubaan Negeri Perak ……… 41
5. Peperiksaan Percubaan Negeri Selangor ……………... 46
6. Jawapan Peperiksaan Percubaan S’ngor ……………. 71
7. Peperiksaan Percubaan Negeri Terengganu…………. 74
8. Jawapan Peperiksaan Percubaan T’gganu …………... 98
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Name : ………………..…………… Form : ………………………..……
BAHAGIAN PENGURUSAN SEKOLAH BERASRAMA PENUH
DAN SEKOLAH KLUSTER
KEMENTERIAN PELAJARAN MALAYSIA
PEPERIKSAAN PERCUBAAN SELARAS SPM 2009ADDITIONAL MATHEMATICS
Kertas 1
Ogos 2009
2 jam Dua jam
3472 / 1
Untuk Kegunaan Pemeriksa
Soalan MarkahPenuh
MarkahDiperoleh
1
JANGAN BUKA KERTAS SOALAN INISEHINGGA DIBERITAHU
2
2 4
3 4
4 3
5 2
6 3
1. Tulis nama dan tingkatan anda pada
ruangan yang disediakan.
2. Kertas soalan ini adalah dalam
dwibahasa.
7 3
8 3
9 410
3. Soalan dalam bahasa Inggeris
mendahului soalan yang sepadan
dalam bahasa Melayu.3
11 3
12 4
4. Calon dibenarkan menjawab
keseluruhan atau sebahagian soalan
sama ada dalam bahasa Inggeris atau
bahasa Melayu.
13 3
14 3
15 3
16 35. Calon dikehendaki membaca
maklumat di halaman belakang kertas
soalan ini.17 4
18 4
19 3
20 3
21 3
22 3
23 3
24 3
25 4
TOTAL 80
Kertas soalan ini mengandungi 18 halaman bercetak
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SULIT 3472/12
The following formulae may be helpful in answering the questions. The symbols given are the ones
commonly used.
ALGEBRA
1
2 4
2
b b ac x
a
− ± −=
2 am × an = a m + n
3 am a÷ n
= a m - n
4 (am)
n = a nm
5 loga mn = log am + loga n
6 loga n
m= log am - loga n
7 log a mn = n log a m
8 loga b =a
b
c
c
log
log
9 Tn = a + (n-1)d
10 Sn = ])1(2[2
d nan
−+
11 Tn = ar n-1
12 Sn =r
r a
r
r ann
−
−=
−
−
1
)1(
1
)1(, (r ≠ 1)
13r
aS
−=∞
1, r <1
CALCULUS
1 y = uv ,dx
duv
dx
dvu
dx
dy+=
2v
u y = ,
2v
dx
dvu
dx
duv
dx
dy−
= ,
3dx
du
du
dy
dx
dy×=
4 Area under a curve
= dx or ∫ b
a
y
= dy ∫ b
a
x
5 Volume generated
= dx or ∫ b
a
y2π
= dy ∫ b
a
x2π
GEOMETRY
5 A point dividing a segment of a line1 Distance =2
122
12 )()( y y x x −+−
( x,y) = ,21⎜⎛
⎝ +
+
nm
mxnx⎟
⎠
⎞
+
+
nm
myny 21 2 Midpoint
( x , y) = ⎜ ,⎝
⎛ +
2
21 x x⎟
⎠
⎞+
2
21 y y
6 Area of triangle
= )()(2
1312312133221 1
y x y x y x y x y x y x ++−++ 3 22 y xr +=
42 2
ˆ xi yj
r x y
+=
+
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SULIT 3472/13
STATISTIC
1 x = N
x∑ 7
1
11
w
I w I
∑
∑=
8)!(
!
r n
nPr
n
−=
2 x =∑∑
f
fx
9 !)!(
!
r r n
nC r
n
−=
3 σ = N
x x∑ − 2)(=
2 _ 2
x N
x−
∑
10 P( A∪ B) = P( A)+P( B)- P( A ∩ B)
4 σ =∑
∑ −
f
x x f 2)(
=2
2
x f
fx−
∑∑
11 P ( X = r ) = , p + q = 1r nr
r
nq pC
−
12 Mean µ = np
13 npq=σ
14 z =σ
− x
5 m = C f
F N
Lm
⎥⎥⎥⎥
⎦
⎤
⎢⎢⎢⎢
⎣
⎡−
+ 2
1
6 1
0
100Q
I Q
= ×
TRIGONOMETRY
9 sin ( A ± B) = sin A cos B cos A sin B ±
10 cos ( A ± B) = cos A cos B sin A sin B m
1 Arc length, s = r θ
2 Area of sector , L = 21
2r θ
11 tan ( A ± B) = B A
B A
tantan1
tantan
m
± 3 sin 2
A + cos 2 A = 1
4 sec2 A = 1 + tan2
A
12C
c
B
b
A
a
sinsinsin==
5 cosec2 A = 1 + cot2 A
6 sin 2 A = 2 sin A cos A
13 a2 = b2 + c
2 - 2bc cos A
7 cos 2 A = cos2 A – sin2 A
14 Area of triangle = C absin2
1
= 2 cos2 A - 1
= 1 - 2 sin2 A
8 tan 2 A = A
A2tan1
tan2
−
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SULIT 4 3472/1
THE UPPER TAIL PROBABILITY Q(z) FOR THE NORMAL DISTRIBUTION N(0,1)
KEBARANGKALIAN HUJUNG ATAS Q(z) BAGI TABURAN NORMAL N(0, 1)
1 2 3 4 5 6 7 8 z 0 1 2 3 4 5 6 7 8 9
Minus / Tolak
.0
.1
.2
.3
.4
0.50000.4602
0.4207
0.3821
0.3446
0.49600.4562
0.4168
0.3783
0.3409
0.49200.4522
0.4129
0.3745
0.3372
0.48800.4483
0.4090
0.3707
0.3336
0.48400.4443
0.4052
0.3669
0.3300
0.48010.4404
0.4013
0.3632
0.3264
0.47610.4364
0.3974
0.3594
0.3228
0.47210.4325
0.3936
0.3557
0.3192
0.46810.4286
0.3897
0.3520
0.3156
0.46410.4247
0.3859
0.3483
0.3121
44
4
4
4
88
8
7
7
1212
12
11
11
1616
15
15
15
2020
19
19
18
2424
23
22
22
2828
27
26
25
3232
31
30
29
.5
.6
.7
.8
.9
0.3085
0.2743
0.2420
0.2119
0.1841
0.3050
0.2709
0.2389
0.2090
0.1814
0.3015
0.2676
0.2358
0.2061
0.1788
0.2981
0.2643
0.2327
0.2033
0.1762
0.2946
0.2611
0.2296
0.2005
0.1736
0.2912
0.2578
0.2266
0.1977
0.1711
0.2877
0.2546
0.2236
0.1949
0.1685
0.2843
0.2514
0.2206
0.1922
0.1660
0.2810
0.2483
0.2177
0.1894
0.1635
0.2776
0.2451
0.2148
0.1867
0.1611
3
3
3
3
3
7
7
6
5
5
10
10
9
8
8
14
13
12
11
10
17
16
15
14
13
20
19
18
16
15
24
23
21
19
18
27
26
24
22
20
.0
.1
.2
.3
.4
0.1587
0.1357
0.1151
0.0968
0.0808
0.1562
0.1335
0.1131
0.0951
0.0793
0.1539
0.1314
0.1112
0.0934
0.0778
0.1515
0.1292
0.1093
0.0918
0.0764
0.1492
0.1271
0.1075
0.0901
0.0749
0.1469
0.1251
0.1056
0.0885
0.0735
0.1446
0.1230
0.1038
0.0869
0.0721
0.1423
0.1210
0.1020
0.0853
0.0708
0.1401
0.1190
0.1003
0.0838
0.0694
0.1379
0.1170
0.0985
0.0823
0.0681
2
2
2
2
1
5
4
4
3
3
7
6
6
5
4
9
8
7
6
6
12
10
9
8
7
14
12
11
10
8
16
14
13
11
10
19
16
15
13
11
.5
.6
.7
.8
.9
0.0668
0.0548
0.0446
0.0359
0.0287
0.0655
0.0537
0.0436
0.0351
0.0281
0.0643
0.0526
0.0427
0.0344
0.0274
0.0630
0.0516
0.0418
0.0336
0.0268
0.0618
0.0505
0.0409
0.0329
0.0262
0.0606
0.0495
0.0401
0.0322
0.0256
0.0594
0.0485
0.0392
0.0314
0.0250
0.0582
0..0475
0.0384
0.0307
0.0244
0.0571
0.0465
0.0375
0.0301
0.0239
0.0559
0.0455
0.0367
0.0294
0.0233
1
1
1
1
1
2
2
2
1
1
4
3
3
2
2
5
4
4
3
2
6
5
4
4
3
7
6
5
4
4
8
7
6
5
4
10
8
7
6
5
.0
.1
.2
.3
0.0228
0.0179
0.0139
0.0107
0.0222
0.0174
0.0136
0.0104
0.0217
0.0170
0.0132
0.0102
0.0212
0.0166
0.0129
0.00990
0.0207
0.0162
0.0125
0.00964
0.0202
0.0158
0.0122
0.00939
0.0197
0.0154
0.0119
0.00914
0.0192
0.0150
0.0116
0.00889
0.0188
0.0146
0.0113
0.00866
0.0183
0.0143
0.0110
0.00842
0
0
0
0
3
2
1
1
1
1
5
5
1
1
1
1
8
7
2
2
1
1
10
9
2
2
2
1
13
12
3
2
2
2
15
14
3
3
2
2
18
16
4
3
3
2
20
16
.4 0.00820 0.00798 0.00776 0.00755 0.00734
0.00714 0.00695 0.00676 0.00657 0.00639
2
2
4
4
6
6
8
7
11
9
13
11
15
13
17
15
.5
.6
.7
.8
.9
0.00621
0.00466
0.00347
0.00256
0.00187
0.00604
0.00453
0.00336
0.00248
0.00181
0.00587
0.00440
0.00326
0.00240
0.00175
0.00570
0.00427
0.00317
0.00233
0.00169
0.00554
0.00415
0.00307
0.00226
0.00164
0.00539
0.00402
0.00298
0.00219
0.00159
0.00523
0.00391
0.00289
0.00212
0.00154
0.00508
0.00379
0.00280
0.00205
0.00149
0.00494
0.00368
0.00272
0.00199
0.00144
0.00480
0.00357
0.00264
0.00193
0.00139
2
1
1
1
0
3
2
2
1
1
5
3
3
2
1
6
5
4
3
2
8
6
5
4
2
9
7
6
4
3
11
9
7
5
3
12
9
8
6
4
.0 0.00135 0.00131 0.00126 0.00122 0.00118 0.00114 0.00111 0.00107 0.00104 0.00100 0 1 1 2 2 2 3 3
Q(z)
z
f ( z)
O
Example / Contoh:
If X ~ N(0, 1), then P( X > k ) = Q
Jika X ~ N(0, 1), maka P( X > k ) =
⎟ ⎠
⎞⎜⎝
⎛ −= 2
2
1exp
2
1)( z z f
π
∫ ∞
=k
dz z f zQ )()(
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SULIT 5 3472/1For
examiner’s
use only Answer all questions.
1 Diagram1 shows a function that maps set A to set B.
Rajah 1 menunjukkan fungsi yang memeta set A ke set B.
x 3− x
Set A Set B
Diagram 1 Rajah 1
It is given that the function that maps set A to set B is .3: −→ x x f
Diberi bahawa fungsi yang memeta set A ke set B ialah .3: −→ x x f
Find
Cari
(a) the value of ,m
nilai m ,
(b) the value of .)3(1− ff
nilai . [2 marks])3(1− ff
[ 2markah]
Answer/ Jawapan : (a) ……………………..
(b).........................................
2 Given that 0,4
: ≠→ x x
xg and the composite function , find
Diberi
2: +→ x xgf
0,
4
:≠→
x x xg dan fungsi gubahan 2:+→
x xgf , cari
(a) ,)( x f
(b) the value of x when 6)( = x fg .
nilai bagi x bila . [4 marks]6)( = x fg
[4 markah]
Answer/ Jawapan : (a) ………......……………..
(b) ......……………………..
2
1
4
2
f
2− 5−
m4
6 3
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SULIT 6 3472/1
3 Given that and px x f −→ 8:5
26:1 x xg
−→−
,
Diberi dan px x f −→ 8:5
26:1 x xg
−→−
,
find
cari
(a) ,)( xg
(b) the value of p if .)()2( x f xg =−
nilai p jika )()2( x f xg =− .
[4 marks]
[4 markah]
Answer/ Jawapan : (a) ………......……………..
(b) ......……………………..
.
4 Given that and2= x3
1−= x are the roots of the equation , find the value of 03 2 =++ cbx x
b and the value of c .
Diberi dan2= x3
1−= x ialah punca-punca persamaan , cari nilai b03 2 =++ cbx x
dan nilai c .[3 marks]
[3 markah]
Answer/ Jawapan : =b ………… ………………=c
exa
u
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SULIT 7 3472/1For
examiner’s
use only5 Find the range of values of x for . x x 9202 <+
Cari julat nilai x bagi . x x 9202 <+[2 marks]
[2 markah]
2
5
Answer/ Jawapan :........... ……..........
6 Given quadratic function has a maximum point . q p x x f +−+−= ]5)6([)(2
)15,3(2nnT −
Diberi fungsi kuadratik mempunyai titik maksimum. . q p x x f +−+−= ]5)6([)(2
)15,3(2
nnT −
Express q in terms p.
Nyatakan q dalam sebutan p.
[3 marks]
[3 markah]
3
6
Answer /Jawapan: ………………………...
.
7 Solve the equation x
x
625
125 2 =+
.
Selesaikan persamaan x
x
625
125 2 =+
.
[3 marks]
[3 markah]
3
7
Answer / Jawapan: …………….…………
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SULIT 8 3472/1
8 Solve the equation 1)2(loglog 33 −=−− x x .
Selesaikan persamaan 1)2(loglog 33 −=−− x x .
[3 marks]
[ 3 markah]
Answer/Jawapan : ……..……...……….....
9 Given and , express in terms of and k .h=2log5 k =3log5 90log12 h
Diberi dan , ungkapkan dalam sebutan dan . h=2log5 k =3log5 90log12 h k
[4 marks]
[4 markah]
Answer/ Jawapan : ……………...………................
10 It is given an arithmetic progression is 5 , 7 , 9 , ………., 87. Find the number of terms of this
progression.
Diberi bahawa suatu janjang aritmetik ialah 5 , 7 , 9 , ………., 87 . Cari ilangan sebutan
dalam janjang itu..
[3 marks]
[ 3 markah]
Answer/ Jawapan: …...…………..…....................
F
exam
use
8
9
1
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SULIT 9 3472/1
11 It is given the first three terms of a geometric series are81
1
27
1
9
1++ + ……….Find the sum to
infinity of the series.
Diberi bahawa tiga sebutan pertama dalam siri geometri ialah81
1
27
1
9
1++ + ……….Cari
hasiltambah hingga sebutan ketakterhinggaan siri itu..
[3 marks]
[3 markah]
Answer/ Jawapan: : ……………...……….....
12 The variables x and y are related by the equation , whereq x px y 522 ++= p and q are
constants.
Diagram 12 shows a straight line graph )2( x y − against .2
x
Pembolehubah x dan y dihubungkan oleh persamaan , dengan keadaanq x px y 522 ++= p dan ialah pemalar .q
Rajah 12 menunjukkan graph )2( x y − melawan .2
x
4
12
3
11
For
xaminer’s
use only
x y 2−
5−
( 4 , 3 )
O2 x
Diagram 12 Rajah 12
Find the value of and of . p q
Cari nilai p dan nilai q .
[4 marks]
[ 4 markah]
Answer : = p ……….… …………………. =q
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SULIT 10 3472/1
13 Diagram 13 shows a straight line with the equationPQ 168
=− x y
.
Rajah 13 menunjukan garis lurus PQ yang mempunyai pesamaan 168
=− x y
.
Diagram 13
Rajah 13
Find the equation of the straight line which is perpendicular to and passes through thePQ
point Q.
Cari persamaan garislurus yang berserenjang dengan PQ dan melalui titik Q.
[ 3 marks]
[3 markah]
Answer/ Jawapan : ……….…………………….
F
exam
use
P•
Q O•
y
x
1
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SULIT 11 3472/1
14 Diagram 14 shows A,B and C are three points on a straight line .
Rajah 14 menunjukkan A , B dan C merupakan tiga titik yang terletak di atas garis lurus.
It is given that 5 AC = AB . Find the coordinates of B.
Diberi 5AC = CB. Cari koordinat B.
[ 3 marks]
[ 3 markah]
Answer/ Jawapan : ………..………..
15 Given and~~
23 y xPQ −=~~
4)1( y xhQR +−= . The points , Q andP R are collinear.
Diberi dan~~
23 y xPQ −=~~
4)1( y xhQR +−= . Titik-titik P , Q dan R adalah segaris.
Find the value of .hCari nilai h .
[ 3 marks]
[3 markah]
Answer/ Jawapan :…………………..…..
For
xaminer’s
use only
Rajah 14
Diagram 14
x
),( y x B•
)3,2(C •
)2,0( A•
y
O
3
14
→ →
→ →
3
15
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SULIT 12 3472/1
16 Solution by graph is not accepted for this question.
Penyelesaian secara graf tidak diterima bagi soalan ini.
Diagram 16 shows OABC is a parallelogram such that OA = 4i + 3 j and OB = 11i + 5 j,
Rajah 16 menunjukan OABC ialah sebuah segiempat selari dengan keadaan OA = 4i + 3j
dan OB = 11i + 5j,
Diagram 16
Rajah 16
Find the unit vector in the direction of .OC
Cari vektor unit pada arah OC .[3 marks]
[ 3 markah]
Answer/ Jawapan:…………………………..…
16
Fo
exam
use
→→
→
y
B
C
A
O
→
→
x
→
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SULIT 13 3472/1
For
examiner’s
use only17 Solve the equation 3 2 o ocos sin 2 0 for 0 360 x x x+ = ≤ ≤
Selesaikan persamaan oo2 3600 02sinkos3 ≤≤=+ xbagi x x
[4 marks][4 markah]
4
17
Answer / Jawapan : ………..……….………
18 Diagram 18 shows a semicircle with center O.PQR
Rajah 18 menunjukkan sebuah semibulatan PQR berpusat O.
RP
Q
Diagram 18
Rajah 18
θ
O
It is given that the arc length PQ is 6.5 cm and the radius of the semicircle is 5 cm.
Diberi bahawa panjang lengkuk PQ ialah 6.5 cm dan jejari semibulatan ialah 5 cm.
[ Use / Guna π = 3.142 ]
Find
Cari
(a) the value of θ in radian ,
nilai θ dalam radian,
(b) area , in cm2 , of sector QOR.
luas , dalam cm2 , sektor QOR. [4 marks]
[4 markah]
18
Answer / Jawapan : (a) …..……..................3
(b).................................
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SULIT 14 3472/1
19 Given that find f ' (2).,)35()( 23 x x x f −=
Diberi cari f ' (2). ,)35()( 23 x x x f −=
[3 marks]
[ 3 markah]
Answer/ Jawapan : .........................................
20 Two variables P and x are related by the equation x
xP2
3 += . Given x increases
at a constant rate of 4 units per second when x = 2, find the rate of change of P.
Dua pembolehubah P dan x dihubungkan dengan persamaan x
xP2
3 += .
Diberi x bertambah dengan kadar malar 4 unit sesaat apabila x = 2, cari
kadar perubahan bagi P.
[3 marks]
[3 markah]
Answer / Jawapan : …...…………..……..…...
exam
us
1
2
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SULIT 15 3472/1
21 Given3)52( −
= x
h y and )( xg
dx
dy= , find the value of if h ∫ =+
3
2
.7]1)([ dx xg
Diberi 3)52( −
= x
h y dan )( xg
dx
dy= , cari nilai bagi h jika ∫ =+
3
2
.7]1)([ dx xg
[3 marks]
[3 markah ]
Answer/ Jawapan: ..…………........……..
22 The mean of a set of data 2m – 3 , 8 , m+1 is 7. Min bagi set data 2m – 3 , 8 , m+1 ialah 7.
Find
Cari
(a) the value of m ,nilai m,
(b) the new mean if each of the data multiflied by 3.
Cari min yang baru jika setiap data didarabkan dengan 3.
[3 marks][ 3 markah]
Answer / Jawapan (a) ..…………........……........
3
21
3
22
For
aminer’s
use only
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SULIT 16 3472/1
(b)..............................................
23 Bag A contains 1 green pen, 2 red pens and 3 blue pens. Bag B contains 2 black erasers
and 3 white erasers. Bag C contains 6 gift cards labeled 1, 2, 3, 4, 5 and 6. An item is
picked randomly from each bag.
Beg A mengandungi 1 pen hijau, 2 pen merah dan 3 pen biru. Beg B mengandungi 2 pemadam hitam dan 3 pemadam putih. Beg C mengandungi 6 kad hadiah yang dilabel
1, 2, 3, 4, 5 dan 6. Satu item diambil secara rawak daripada setiap beg.
Find the probability of getting a blue pen, a black eraser and a gift card with a number
less than 3.
Cari kebarangkalian mendapat satu pen biru, satu pemadam hitam dan satu kad hadiah
yang berlabel nombor kurang daripada 3.
[3 marks]
[3 markah]
2
Answer / Jawapan: ...…..……..……..…....
24 The probability that it will rain on a particular day is5
2.
If X is the number of rainy days in a week, find
Kebarangkalian bahawa hujan akan turun pada sebarang hari ialah5
2.
Jika X ialah bilangan hari hujan turun dalam seminggu, cari
(a) the mean of the distribution of X ,
min bagi taburan X ,
(b) the standard deviation of the distribution of X .
sisihan piawai bagi taburan X .[3 marks]
[ 3 markah]
Answer/ Jawapan: (a)………..……………..
F
exam
use
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SULIT 17 3472/1
(b) ………………….…. For
xaminer’s
use only
4
25
25 Diagram 25 shows a standardized normal distribution graph.
Rajah 25 menunjukkan satu graf taburan normal piawai.
(z)
0.7286
k O-k z
Diagram 25 Ra ah 25
The probability represented by the area of the shaded region is 0.7286.
Kebarangkalian yang diwakili oleh luas kawasan berlorek ialah 0.7286 .
(a) Find the value of k ,
Cari nilai k ,
(b) X is a continuous random variable which is normally distributed with a mean
of μ and a standard deviation of 8. Find the value of μ if X = 70 when the z-score is k .
X ialah pembolehubah rawak selanjar bertaburan secara normal dengan min μ
dan sisihan piawai 8. Cari nilai μ jika X = 70 apabila skor-z ialah k .
[4 mark
[4 markah
Answer/ Jawapan : (a)......……...…..……..…...
(b) ...…………..……..….
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SULIT 18 3472/1
END OF THE QUESTION PAPER INFORMATION FOR CANDIDATES
MAKLUMAT UNTUK CALON
1. This question paper consists of 25 questions
Kertas soalan ini mengandungi 25 soalan
2. Answer all questions.
Jawab semua soalan
3. Write your answers in the spaces provided in the question paper.
Tulis jawapan anda dalam ruang yang disediakan dalam kertas soalan.
4. Show your working. It may help you to get marks.
Tunjukkan langkah-langkah penting dalam kerja mengira anda. Ini boleh membantu anda untuk
mendapatkan markah.
5. If you wish to change your answer, cross out the answer that you have done.Then write down the new answer.
Sekiranya anda hendak menukar jawapan, batalkan jawapan yang telah dibuat.
Kemudian tulis jawapan yang baru.
6. The diagrams in the questions provided are not drawn to scale unless stated.
Rajah yang mengiringi soalan tidak dilukis mengikut skala kecuali dinyatakan.
7. The marks allocated for each question are shown in brackets.
Markah yang diperuntukkan bagi setiap soalan ditunjukkan dalam kurungan.
8. A list of formulae is provided on pages 3 to 5.
Satu senarai rumus disediakan di halaman 3 hingga 5.
9. A booklet of four-figure mathematical tables is provided.
Sebuah buku sifir matematik empat angka disediakan.
10. You may use a non-programmable scientific calculator.
Anda dibenarkan menggunakan kalkulator saintifik yang tidak boleh diprogram.
11. Hand in this question paper to the invigilator at the end of the examination.
Serahkan kertas soalan ini kepada pengawas peperiksaan di akhir peperiksaan.
[Lihat sebelah
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BAHAGIAN PENGURUSAN
SEKOLAH BERASRAMA PENUH DAN SEKOLAH KLUSTER
KEMENTERIAN PELAJARAN MALAYSIA
PEPERIKSAAN PERCUBAAN
SIJIL PELAJARAN MALAYSIA 2009
PEPERIKSAAN PERCUBAAN SPM
TAHUN 2009
SULIT
3472/1
Additional
Mathematics
Kertas 1Peraturan
Pemarkahan
August
2009
ADDITIONAL MATHEMATICS
KERTAS 1
PERATURAN PEMARKAHAN
UNTUK KEGUNAAN PEMERIKSA SAHAJA
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Question Working / Solution Marks Total
1 (a)
1 (b)
1
3
1
1
2
2 (a)
2(b)
2,2
4)( −≠
+= x x
x f
0,41 ≠=− x x
g or 2)(
4+= x
x f
3−= x
24
4
+
x
2
B1
2
B1
4
3(a)
(b)
2
56)(
x xg
−=
y x
=−
5
26
p =2
5
px x
−=−−
82
)2(56
2
B1
2
B1
4
4 b = - 5 and c = - 2
b = - 5 or c = - 2
( x – 2) ( 3 x + 1) = 0 OR 03
2
3
52 =−− x x
3
B2
B1
3
5 54 << x
0)4)(5( <−− x x OR
Must indicate the rangecorrectly by shading or other
method
or
4 5
2
B1
2
5x
5x x
4
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Question Working / Solution Marks Total
6 5602 −= pq
5)2(15 2 −= pq
n p 36 −=− or 2155 nq =+
3
B2
B1
3
7
3
2−
4)2(2 −=+ x
x xor
4)2(2 55 −+ OR x225−
3
B2
B1
3
8 1−
3
1
2=
− x
x
⎟ ⎠
⎞⎜⎝
⎛
− 2log
x
x
3
B2
B1
3
9
k h
hk
+
++
2
12
3log2log2
5log2log3log2
55
555
+
++
4
5log2log2log 55
2
5 ++ or or3log2log 5
2
5 +
5log2log3log 12122
12 ++
12log
90log
5
5 or 2 log 5 3 or 2 log52
4
B3
B2
B1
10 n = 4287)2)(1(5 =−+ n
d = 2
3
B2
B1
3
11
6
1
3
11
91
−
3
1=r
3
B2
B1
3
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Question Working / Solution Marks Total
12 p = 2 and 1−=q
p = 2 or 1−=q
04
)5(3
−
−−= p or 55 −=q
q px x y 52 2 +=−
4
B3
B2
B1
4
13
2
9
4
3−= x y
)6(4
30 +−=− x y
P ( 0,8) or Q (-6,0) or4
3−=⊥PQm
3
B2
B1
3
14 (10, 7)
7or10 == y x
25
0=
+ xor 3
5
8=
+ y
3
B2
B1
3
15 h = 7
24 −=λ or 3 = )1(2
1h−−
⎟⎟ ⎠
⎞⎜⎜⎝
⎛ −=⎟⎟
⎠
⎞⎜⎜⎝
⎛
− 4
)1
2
3 hλ
3
B2
3
B1
16
53
27~~ ji+
53=OC
~~~~34511 ji ji −−+
3
B2B1
3
17 90o, 123.69o,270o,303.69o
90o,
270o
or 123.69o, 303.69
o
0)sin2cos3(cos =+ x x x
3 2 x + 2 sin x cosx = 0cos
4
B3
B2
B1
4
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Question Working / Solution Marks Total
18 (a)
(b)
842.1=θ
5.65 =α
23.025
)842.1()5(21 2 * (candidate’s θ from a)
2
B1
2
B1
4
19 60
2213 3)35()3()35(2 x x x x −+−−
23)3)(35(2 xor x −−
3
B2
B1
3
20 10
4232
×⎟ ⎠ ⎞⎜
⎝ ⎛ −
xor 4
2232
×⎟ ⎠ ⎞⎜
⎝ ⎛ −
2
23
xdr
dp−=
3
B2
B1
3
21 h = 3
3]5)3(2[ −
h–
3]5)2(2[ −
h= 7
[ ]32
3
2
3 )()52( xor imit lcorrect thewith x
h
⎥⎦
⎤
⎢⎣
⎡
−
3
B2
B1
3
22 a) m = 5
73
1832=
+++− mm
b) 21
2
B1
1
3
23
15
1or an equivalent single fraction
6
2
5
2
6
3××
6
3or
5
2or
6
2
3
B2
B1
3
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TotalQuestion Working / Solution Marks
31
5
14or 2.8
24(a)
224(b) 1.296
⎟ ⎠ ⎞⎜
⎝ ⎛ −××
521
527 or equivalent B1
425 (a) 1.1 2
0.1357 B1
61.225(b) 2
B11.1*
8
70=
− μ (candidate’s k )
“END OF MARKING SCHEME”
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SULIT
NAMA:. NO.ANGKA GILIRAN:
PEPERIKSAAN PERCUBAANNEGERTPERAK
SIJIL PELAJARAN MALAYSIA 2OO9ADDITIOI\AL MATHEMATICSKertas ISept.2 jam
3472t1
Dua am
ADDITIONAL MATHEMATICS
Paper
Two hours
1 .
7
3.
JANGAN BUKA KERTAS SOALANINI SEHII\GGA DIBERI-IATIU
Tuliskan nama dan nombor kad pengenalananda pada ruangan yang disediaknn.
Kertassoalan ini adalah dalam dtyibahasa.
Soalan dalam bahasa Inggeris mendahuluisoalan yang sepadan dalam bahasa Malaysia.
Calon dibenarkan menjawab keseluruhan atausebahagian soalan sama ada dalam bahaseInggeris atau bahasa Malaysia.
Calon dikehendaki membaca maklumat dihalaman belakang kertas soalan ini.
SoalanMarkah
Penuir
Markah
Diperolehi1 J
2 23 a
J
4 3J
aJ
6 3
I 4
8 aJ
9 .|L
1 0 5
1 1 J
t 2 31 3 a
J
t 4 aJ
1 5 aJ
1 6 4t 7 4
1 8 4t 9 22 0 a
J
2 l 4) ) a
J
2 3 42 4 .+
2 5 +
Jumlah8 0
Kertas soalan ni mengandungi20 halaman bercet:,k.
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For
3
Use
Answer / Jawaoan :
Diagram showshepsaphf the unction(x)=lz-zxl ror ttredomain 3<x<4.
Rajah menunjukkanraf bagiungsi"f x)= i3 - Zxl untukdomain-3 x <4.
State
Nyataknn
(a) the value of i,
nilai h,
Diagram I
Rujah 1
(b) range of flx) corresponding o the given domain.julat flx) berdasarknn domain yang diberi.
6
Answerall questions.Jawabsemuasoalan.
3472/1
[3 marl<s)
13markahl
(a)
(r)
h :
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SULIT 34
For
Examin
UseGiven the function
U'g : x - +
_ _ 3
Diberifungsi s : x -+k
Jika
7
aa
If g(1) =:- , find the valueof 2z
1̂
g(1)=1, carin i la i ) ,z
12marl<sl
12markahl
Answer I Jawapan : )" :
Given he compositeunction fg@)=3x2 5 andfindl-4).
Diberi ungsi gubahan |(x) =3x2 -5 dan ungsi
function 8(x) = 2- *2,
g(x) = 2- x2 ceri A-4).
[3 ntarks]
y3 markahl
Write the quadraticequation 2x2 -4x=3x2 +7x-15 in general orm.using formula. Give your answer correct to 3 decimal places.
Tulis persqmadn kuadratik 2x2 4x=3x2 +7x-75 dalam bentukselesaikan dengan menggunakan rumus. Berikan jawapan tepatperpuluhan.
Then, solve it by
[3 marl<s]
am. Seterusnya,
kepada 3 tempat
[3 markah]
Answer I Jawapan
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SULIT
For
Examiner's
Use
8
Find the rangeof valuesof a if 2x2 .r-15>0.
Cari julat nilai x, jika 2x2- x - 15> 0.
3472t1
[3 marks]
[3 markah]
Answer / Jawapan
Find the coordinates f the maximum point cf the quadraticequation =4x-r2 -9 byusing the method of completing the square. [3 marks)
Cari koordinqt titik maksimumbagi persamaankuadrctik !:4x - 12 -9 dengan
menggttnakan nedahpen))empurnaan ua,sa ua. 13 markohl
Answer I Jowapan :
It is given that
Diberi bahawa
Iogzs +2log5Q 1, express in terms f q.
logzs +2log5Q=7, ungkapkandolam ebutan .
14marks)
[4 markah]
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9SULIT 347
For
Examin
Use
8 x 2 ' - 3Solve he equation 1
[3 marks]
[3 markah]
2 2n3
setesaiknnersamssn:r\'=lt
= t.L
A n s w e r / i a w a p a n : n :
It is given that the first four terms of an arithmeticprogressionare 3,
-8,x and
-30.
Diberi buhswa empatsebutanpertama suatu anjang aritmetik ialah 3, -8, x dan -30.
Find the value of x.
Cari nilai x.
Answer / Jawapan
l0 The third term of a geometricprogression s 16 and its common ratio is '
Find the sum to infinity of the progression.
Sebutan kztiga suatu anjang geometri ialah 16 dan nisbah sepunya ialah
Cari hasil tambah hingga ketakterhinggaan anjang itu.
[2 marks]
12markahl
13marksl
[3 markah]
Answer I Jawapan
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SULIT 347
For
Examin
Use
8 x 2 n - 3Solve he equation
2 2n3
8 x 2 n - 3Selesaikanersamaan -Fr=3-
1 . [3 marksl
13markahll .
A n s w e r l i o w a p a n :n :
It is given that the first four terms of an arithmeticprogressionare 3,Diberi buhowa empat sebutanpertama suatu anjang aritmetik ialah
Find the value of x.
Cari nilai x.
A n s w e r / J a w a o a n : x :
10 The third term of a geometricprogression s 16 and its common ratio is '
Find the sum to infinity of the progression.
Sebutanketiga suatu anjang geometri ialah 16 dan nisbah sepunya ialah
Cari hasil tambah hingga ketakterhinggaan anjang itu.
-8,x and
30.
3,-8, x dan 30.
12marksl
12marknh)
2; .J
[3 marks]
13marknhl
Answer I Jawapan
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SULIT
For
Examinerb
Use
10 3472
1l The first four termsof an arithmetic rogression re 7, -3, l, 5.Empatsebutan ertamasuatuanjang aritmetikadalah -7, -3, l, 5.
Find
Cari
(a) the fifth term of the progression,
sebutankelimaanjang itu,
(b) the sum of next 24 termsafter the fourth term.hasil tambah 24 sebutanberikutnyaselepas ebutankeempat.
[3 marks]
[3 marlcah
Answer lJawapan: (a )
(D)
ThepointsP(2a,a),Q(b,c)
and R(2b,3c)areon a straightine.p dividesPR in the ratio 3 : 4.
Titik-titikP(2a,a), Q(b,c) dan R(2b,3c) erletak adasatugaris urus.
Q membahagiPR dengannisbah3 : 4.
Express in termsof c.Ungkapkan dalamsebutanc.
[3 marks]
13markahl
Answer I Jawapan
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SULIT 1 l
13 The variables andy are elatedby the equation/=2x2 +4x3. A straight ine graph s
obtainedby plotting { againstx, as shown n Diagram2.xo
Pembolehbahx dan y dihubungkan lehpersamoan!=2x2 +4x3.Grafgaris lurus
diperolehdenganmemplotka"+ mebwan x, sepertiditunjukkanpada Rajah 2.x-
Find the value of m and n.
Cari niloi m dan n.
Diagram2
Rajah 2
13marlul
[3 markah)
34
Fo
Exam
Us
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SULIT
For
Examiner b
Use
Answer I Jawapan :
t2
14 Diagram shows straightinepe with theequation
3472t
x v- - +? = |
Rajah3 menunjukkan aris lurus Pe yang mempunyaiersamaan
The point P lies on x-axisand he point e lieson they-axis.TitikP terletakpadapaksi-xdan titik e terletakpada paksi-y.
Diagram3
Rajah 3
Find the equation of the straight line perpendicular o PQ and passing hrough the point p.
[3 mark^s]Carikan persamaangaris lurus yang berserenjongdenganPQ dan melalui titik p.
13markohl
x y r- - = I
3 4
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13SULIT
15
Diagram4
Rajah 4
Diagram showsvectorsOA'=g, OB'=b. OC'and Cd on a grid of equalsquares.
---O C,
a D
J h A\\
B a
Rajah4 menunjukknnehord= g, O?= b, O? aordi di atassatqhgrid segiempatsama.
Express n terms oi q and b.
Ungkapknndalam sebutan g dan 12.
(a)
[3 marks]
13 markahl
347
For
ExamiUs
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t - o r l16I
(Jse I
I
t4
P?RS.trapezium
Diagram 5 shows a trapeziumRajah 5 menunjukkansebuah PQRS,
DiagramRajah5
Given hat hevector d=@+4)L+6 j undTR)= mi+107.Find
DiberivektorPQ=@+4)t_+6 dan SR'=3mi+10. Cari
(a) the valueof rz,nilai m,
(b) the magnitude f ur"ro,V/.)
mognitud bagi vehor PQ'.
Answer I Jawapan :
So l ve heequat ion sec ' x -5 = tanx fo r 0o(x<360. .
Selesaiknnersamcan sek2x-5=tanx bagi 0o(x<360o.
3472t1
[4 marl<sl
[4 markah]
(a)
(b)
[4 marl<s]
14markahl
Answer I Jawaoan :
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SULIT 15
18 Diagram6 shows wo concentriccircles with centreO.Rajah6 menunjukkan ua bulatan denganO sebagai usatnya..
DiagramRajah6
Given that OP : 6 cm, OQ : 3OB and ISOR= 50o. POR and SOQ arestraight ines.
Diberi bahawa OP : 6 cm, OQ : 3OB dan ISOR = 50o POR dan SOQ adalah garis
lurus.
(a ) Find the value of 0, in radians. Use z =3.142)
Cari nilai 0, dalam radian, (Guna n =3.142)
(b) Calculate he area of the shaded egion.
Hitungkan luas kawasan berlorek.
14marksl
14markahl
A n s w e r / J a w a p a n : ( a ) e :
347
ForExami
Use
The curve y= -f(x) is such that I -2px-3, wherep is aconstant.d x
The gradientof curve at x= 4 is -p. Find the valueofp.
Suatu lengkung y= f(x) adalah dengan keadaan !=2pr-3, pd-r
Kecerunan lengkung itu di x = 4 ialah - p . Cari nilai p.
[2 marl<sl
ialah pemalar.
12marknhl
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SULIT
ForExaminer
Use
t6 3472/
wherer isacons tan t .
[3 marl<
x = r, dengankeadaan
[3 markah
20 Thecurve ! = -2x2 +24x+r hasa maximumpointat x = / oFind the valueof r.
Lengkungr = -2x2 +24x + r mempunyaiitik maksimum adar ialahpemalar Cari nilai r.
A n s w e r / J a w a p a n : r =
Givenhat Il, sfrXr =5, find
Diberifl,sftPr=5 , cari
(a)
(b)
r - l
J, sG)dx,
[lr[rrra- rx]d-r
[4 marks)
[4 markah]
(a)Ansrver Jawapan :
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SULIT I7
22 SetX consists f 50 scores, , for a gamewhichhasa meanof 6 andstandard eviation
of 4.5.
SetX mengandungi0 skor,x, bagi suatupermainandenganmin 6 dan sisihanpiowai
4.5.
Calculate
Hitungkan
(a) the sum of the scores, x'
jumlah skon 2x ,
(b) the sum of the squarssof the "o"', It2
hasil tambah kuasa dua skor Lx2 'l-3marksl
13markah)
347
For
Examine
Use
Satu.iawatankuasadengan 4 orang pelqiar harus dibentuk untuk menganjurknnsuatu kuiz'
Ahli-ahli jawatankuori it, aknn dipilii daripada satu kumpulan 6 pelajar lelaki dan 5
pelajar perempuon. Carikan bilangan awatankuasa yang boleh dibentuk ika jawatankuasa
A committeeof 4 studentss to be formedto organisea quiz'
committeewill be chosen rom a group of 6 boys and 5 girls'
committees that can be formed such that the committee consists of
tersebutmengandungi
(a) 3 girls,
3 pelaiarPeremquan,
(b) at least2 boYs.
sekurang-kurangnya pelajar lelaki'
The membersof the
Find the numberof
14marl<sl
14markah)
Answer I JawaPan :
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SULIT
For
Examiner
Use
( b ) n =
18 3472/
24 '40Yoof the carson theroad n Malaysia reMalaysianmade.''40%odaripadakereta-keretai jalan raya di MalaysiaadalahbuatanMalaysia.'
(a) If l0 cars arechosenat random, ind the probability hat exactly7 of themare Malaysianmade.Jikn l0 buahkeretadi pilih secorq awek, cari kebarangkalian ahawa
tepat7 daripadanyaadalahbuatanMalaysia-
(b) If n carsarechosen t ranCom,he probabilityhat all the n carsare
Malaysianmade , * . Find the valueof n.olJ
Jika n buah kereta dipilih secara rawak, kebarangkalian bahawa setnua n
buahkereta tu atlalaltbuatanMalaysiaalah#
. cari nirai n.
[4 marks]
[4 markah]
Answer lJawapan: (a )
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SULIT 19
25 X is a continuous random variable of a normal distribution with mean, p a&d standard
deviation4.2.
X ialah pemboleh ubah rawak selanjar bagi suatu taburan normal dengan min, p dan
sisihanpiawai 4.2.
Find
Cari
(a) the value of p if the z-score s 2.2 when X = 18.4,
nilai 1t jika skor-z ialah 2.2 apabila X : 18.4,
( b ) P ( 1 0 .0 2 < x< 1 2 .2 ) .14marks)
[4 markah]
END OF QUESTION PAPERKERTASSOAILIN TAMAT
347
For
Exami
Use
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| ' .I P+eriksaan crcubaanPM 347211I NeseriPerak 009
MARK SCHEMEFORPAPER ADDITIONALL,TATIIEMATICS
QuestionNo.
Working scheme nd Marks Markallocat
1. (a) 3
(b) 0</(x)s9 or
81: when (x)<9
9>/ (x )>0
or 0< /(x) seen.
I
) 9
ZtL J
) "+3 2I
,)
3. _i J
82: flx):l-3x
Bl: f(2-x27=3v2 5 or g ' (x )= \ lz -x
-]
4. x = 1.227, - 12.23- 12.227) [Bothconect]
r-:--^. - i l i { r1z -40x- is)tszt -__------------1_- [For substitutinghe valuesconectly
2(r)-
into ttre formula]
B l : . r2 1 lx 15 = 0
j
3 -x<-| or x)3 fBoth nequalitiesonect]
82: The correctsections shaded ath '*rex 'raluesshcwnor ind.iceted.
B l : (2x+5) (x -3 )>0
6. (2, s)
R2: =-( r -2) ' -5
t' t: 1,-lxz -4x+(1)z -(-2)21-9or y= - l x z - 4 x+ 4 - 4 + 9
3
L ,
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34' 1PeoeriksaanercubaanPM
NegeriPerak 009
J
B ' 2 : . - n + 3 = 0
91 . 23+n-3-2n+320
-19
Bl : x- (-8)= -8-3 or -30-x -x- (-8)
other quivalentorm
36)
3
87 va :36
{a)(b)
B 1
91320
, r , ,=2]Lr {s) (24- )41 or
sx - s+=|Of-rl * <r8 r)4\-L2eT+ 4 1)41
or -30-x =-8-3 cr
108
S *
, <8 3 : l o g 5P = t o c s \ A ) o r
B2 : log5 p + lcg5 qa =log s52
o' . logsP or los{52 - -
b = - 4 c
8 2 : b = 8 a
- m : 4 , n = 6
8 2 : 1 8 = 2 + 4 ( m )
B l : 1 = 2 + 4 x
n : 2 + 4 ( l )
Y = 2 + 4 X
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3 9V = - - X - -- 4 4
3 ' - . r 9B2: v -0 = -:lx - (-3) or c=---:
4 ' 4
4B l : . m . > - = - l
J
Ie = 3
Bl t -P=2P141-3
r = 6B ,2 :0 = 4 r + 2 4
9 11 9 = - 4 x + 2 4dx
PeperiksaanercubaanPMNegoi Perak 009
347
(a) 3s+!
(b) e-3bRl : g+3BO or q+(4CE)
(a) m= 5
r r2 . +4=im' ( i ) l ( * .+)= im
w: t = | o, t "=J
(6) .fi7 or 3Jil or 10.82or10.817
x= 45o, 46.31',225",326.31" r 45", 45ol9',225",326o19'
x = 45o i id 46.31ooi x=45'and 146o19'
{3tant+2xtanx-1)=03tarfx-tanx -2:0
2.269
72.62 t 72.615 or 72.61 r 72.608
l r
(a)
(b)
rr2,zl:@'Q.26, ta)'(2:?5e)]r equivarent
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34't2/l
PeDeriksaanercubaanSPM
Ne;eri Perak2009
(a)
(5)
B1 :
Ix = 300
Y12 = 2812.5L.
t \ ' - 2
^lLl-_ze=q.sI ) U
Zx' -36=zo.zs50
(a) 60
B ! :s q x 6 q o r 1 0 x 6
(b) 26sBi : uqr tcr+ucrt tcr+uco r
15x10+20x5+15 r 150+100+15
(a) p =9.16
at . 1' t -18'4- Pt a'+.L
(b) 0.1842
,,, o(lWi:J16<zsYl!!!\) r ,t r . . t 4 .2 )\ ' ' -
P(0.204s<70.?238)
(a) -s
(b) -2f ) 1 ? |
B'2, to- l ; - ; )
3x281 : 2x5 o, - ,
(a) 0.04217
/ ? \ t / 1 \ '
Bt : 'oC, l l I ; I o requiva lent\ ) / \ ) /
( b ) n =a
/ a \ u r t a
Bl : l : | == orequ iva ten t\5 / 625
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L v
3; l? / l
l la ,cmat ik' f lmoahan
Kertas2009
Septembcr
2 anr
nrO ANCKA GII- IR, \ \
\+JABATAN PBLAJARAN SELANGOR.
PROCTTANIENINGKATANPRESl'ASISAINS DAN bIATtrMATiK 2OO9
N!A'l'ltDl A'I'l K'L,\lr! BAFLdN
Kei'tas I
L)ua Jam
J;\)iCAll BIIi(A K[]iT/\S S0'\l,AN
iiii li j l i ltt\iCC;\ Dlll ltl:i1"tAI lJ
i. Ti:!i.sicta c:rbcr i, iadpcngr:;ir!an,
ln;;ll:: gllir*n, n]jf ir:rc/,:#;illi l<:t:zn
ant l p t :!ct : .i ! :!.t1 tGnq d sJ ! e k{ ;i.
.1-. crlcs so,-tiun ni t:tlalct.tdaii;tt
dri!.,c1,,:.trt.
I ' / " ; . l t ! : ; ; t , t l : , : ; . t , t . -, , .
t,t iIJL:It.t!|ti ooIJ/;,vaflg :tcl)t't,:|| (!aidn
bu!:. st l '!,:Ia,.,u-
' : . : , . . 1 . . , . , . , . . . - . . . . - . - . . , . . . r .
, , r \ . . . ' i r . ,j ' . i , , /
t r s , , ( . ; , / t : ; < - , ' . . , r' r , r . : r ;
.\.!it1Lt (t!|li lLi!.1m l:ctIu.sct l::ggt't i,'; ttlit:t
!:t i : .t t t ]i.' ! c.,t t.
5. Ct:iot t! kt'itr.t<tnkin'.';itbt:ttt
ontttl;t t!i htLi;nlLn b':Ilka;:i; i;<'rius
\O. K, \D PENGEI{, \LAN
Kod Peme iksa
Soalan lVlarkah
Penuh
Markah
Dipcrolrh
3
2 4
3 3
4 2
5 3
6 3
7 3
it .]
9 2
I O 1
t l 2
12 ..t
l 3 4
l . l 3
l 5 2
f i 3
1 8 .1
l 9 32n . !
2 l1 ) 3
),3 4
21 -i
l ) tl
Ju l l'rl:]h
1." ' : r t rsi i i mcn: : l rdL:a, t i l l hr l l r : : rn Lrc icct : i l :r l I h: t l : l : iuniC k 'o l rcc l ; ,1; .
,ii:::i r:::i::l:r1r
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sut,tl ' 3'472i1
The 1bi1 'wrng l : rn:uhe nl , bc l ; ; lp fu l n ,ns*er ing hequcst ions. hes; ;mbols l \ .n arclhc onescomn.:only sed.
RLtrrtus-ntmus erikut boleh membctntu ndu mt:njawah soalctn.Simbol-sinbol -vangdiberi
aduluh yang bidsa digunakan.
I
2
3
4
5
6
- b r { i 4 *
l d
A - A - A
1og, mn : log. rrt log" n
, mlu& - roR, , rog.,
n
ALGEBR., \
lo:t bg r o g " b = , -
IOg . .J
9 T, : a + ( .n l )d
J , , = - l l a + l n2 '
T,: c t r"I
" , a(r" - l ),
, . u, ) , ; r l -
l r
a \ t - r )
l - r
I
l 0 t ) d l
l l
12
7 log, m"'., n la9um l l
tl; dv r!,.;
rlr ar l.::
{i 1,1-c 1 ,cjs I i:,t !, i;.j.t., J;
,1 .,\.;:r,..ili:r;r cLii..rc
!,t: :,,: d i' <:., t h ! e:ig.l.y,1t
!-- : l , ) . . ^ - l ^ r . ' . , \
:
h
t ,J '
: ./.il',,,.. 3,:iu-':ateii !.siptuiujai:;c;t
f r
I i r , - ' / : ( ) i ( { r / - . l J )J'i,
I r ' ( t \ )J .
2 ,, ,ly'
v ' , ! : t
it, dit d;r-1., - -:- w -.---
3 ck rl;i"
d.,;
citt {;i'v t l
- -crit-..--....c:.n
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ST,I,IT
S1',\TiiJ'l'iC:; I S .4 IIST IX
3172t1
- L f x
) - l
/ \
m : + l = Y - 4 l c\ f . , )
a./: ,:.r- 100
Q,,
, . T w r'
\ - u./- " '
'( n - r ) l
n l
L "-
-\ n r ) ! r !
P(AIB) = P(A)+ P(B) - P(A \8)
P ( X : r ) :
n C , p r q 4 - ' ,
p + q : 1
Mcan Min , p: np
o =^["ps
v - l t
\- r':
> f
l 0
l l
t 2
I J
l 1
\ ' - 2
I Dlsl::rce -/rr.";;i,r
: 'l('r, - x,)' + 0z - Yt)'
r , , ,1 , : f r t , . i i : r\ , 2 2 )
J A poini rliviriial3 sr,-g;ncitt1' a ine
T k yt : ;1 *: en!; d: c,: .s a u t eii:b c e ng,tll r s
( ' ' , " " " t t , - ' : : t ,)- . - l
't : t t r t t l t l n , 1
C,"tOivlE-I;iV / 6 ?.8':ii,L-triTJ
4 A:ea ol trter';\e LucssryiiiglI:r) (
r:t , t- r.y.'i' -r.y, - (;r.1, + ;r.,y, - r,y, j
I l )i . ' r t i . i /
" r i + _ y j
1 2 2\ ' ; J I
l l i i : : : r ; l : l : I
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5UT-tT' i172i l
TRIGO' Ot1U' l \ I TRIGA"\O.vERt
Arc length,s r 0
Panjang engkok, :j 0
._ -LArc f , o l sec to r . I = r -
t ^Luas sektor,:
; i' e
s i n 2 1+ . o . 2 l : 1
sitt2A + kcs2 I -"1
, . " 2 . 1 l u r r n 2
, " k 2 1 : l ' + - t " , r 2
a n r " . 2 l - l + c o i 2 l
k o s i : k 2 l - . I + k o t t /
:;in?"1 ) si;r ccs
sin 2l ?-sil I kos
sc:;2.': l ,:,,:,t 1 ::":, '
- 2. cost ,4 |
- . , I 2 | r '12 I
ki:s 2.,1 kt;s2 -,'1 sirr2 ,1
: 2 k o s 2 , , 1
== 2 st.t't
sin (.4 L|9) - sin,.:l os B I cos.,l sin B
sin (l + B) : sin .1 os B I kos si n I
co s l 1 A ) : c o s l c o s - B s r n , 1 i n B
ko s (l + B) = kos.,l kos B T sin sin B
1 a n ( l + B ) = a n A + t a n j
I + lfn /4 te;l 1J
A
I
t 0
l l
12.
t l n 2 A :I - tan2 ,1
srn ,1 sin rf si nC
,. . ,t2 + c2 .2l l r 'cos, ,1
. - h? ' , , ) 2bt l :ot I
I . l , , t
, r 2
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sul .t ' I 11
Anslve r all qucjt i t lns.
J uuu h sctr'ltJas t lun.
I G r cn he unctionl(- t) r- l -rJ, i r thedornain 2!.r i l '
Diheri.limgsil.t)=11
3.q, untukdomuin 2 5x< I'
(6 ) state he rangeof/(-t) correspondingo thc givendomain.
nyatu*tn julat flx) berdusurkandomain yang diberi.
Answcr / Jawopan :
(" )
(rz) sketch hc graphofthe function./(-t) n the axcs n the answerspace,
l akLt ktn graf untuk.fungs flr) pttda pakt i-pttk i daktm ntat:i;,m.iawapan,
3172t1
[3 marks)
13narkah)
(b)
( . n )
Ci;rn tlrc r:nction:;./t(") = 3, - 2 ord r{,r)'= i: r - 3, 1l;:d
iliiti:r! ; irg::i ./'( 'r) - 3, t z dat:2;i1' l t; 3, cari
/(;r),, , , t t t t l - . 7 .
|.:: tsttr I .ltto1;ct:t : (t;)
i " i , ' : : - / , t "
I-L *. .. i I.t
| 1 - " - I : - - l l . , 1
( i )
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Diagrarn shows n: r :rv diagrarr hat eprtsentshe 'rnc:icn/ (-r)= ?-L,, * *.: . Y - l
Rajah I menunjui&cn sualu gambtrajah antk panah vang mewakili.t'itng.si
I t x \ = l J . x - m .
l r - l
, f x -px + 2x l
3172.'l
13mcrk;j
13narkchl
Dia;.;am
Rcjoh 1
Find the valut cf
Cari nilai
\a) m,
(b) p.
!,:-;.:,,:t: / ,!::',,;:".:.:;:t (rN :r--
(r))p '-
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5 i, iLiT 31 12tl
F i n u t h c v l l u e o 1 ' f t i l ' r h c q i r a d : a t i c e q u a t i c n / r - r : . 1 . r + 3 = 0 h a s t l v o e q u a lo o t s .
[2 marks]
Curi nilai h iktr persdmdanquddrutic h.t? 4.r+3-0mempun.suipuncu-punc'a
!"ungsama.
[2markahl
Ans'wet / Jawcpun :
Fir:d hc rangeof valuesofp if t i :egr:ph of tl:equadraticdnctlon
JG).- "'-Zpx +2Jt +3 clces ot intrrsect he x-axis. f3 ncrk:l
Ccri juk:t niini p .jika graf .fing.si kuudratik ./(-r) = rt ' 2 px + 2p + 3 titi;tlt bt:r:;i!ang
de;1qL:rittr:tsr-r. 13n:it:i;cltj
l . i l ^ * - . ! . ^ ' - " ,
An:s';ver Ja',r't:1:::in
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s 1,1.1-r
6
3 34121t
Diegr-rm2 sl'ows hc gilph oiir r;Lratlratic;::ction 'r(r)= t it - ')r ' rvi.rcrcr ald I
3r c conslSnls.
Rajah2 mattuniukkttngral bttgi /ungsikLratlrttik 1\r): ft (r + 5f ' tlengunkeadcan
h dun k iulutt Pcmular.
Ir-f'
StateI'
I\ lyar,k tt :
(.r) thc vr.lueof l l,
niliii lt,
(b) thc valr.ic i ' l ',
nilti i t,
(,J tl c r:r-lu:it ionf fi:e:ui:; o! slj)li:lc y'
p,.' ,;a:ntx:r Pt:ks .sj;'tt' i'
lgra:l 2
'tjeit 2
13n:arks)
13n::;rk.4)
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St r -IT
7
3112i1
13marks)
t3 markchl
l i o i ' c ihe cquat ic i :
S , t:s u i kun St rs a maun :
1 l u c . . R t
Ans'Ner Jav,apan: x:
Given hat ogl -r1+ 5 logt r 2
Diberi ogtxy 5 log:x: 2.
lixpress.y n tcrr:rsof ,r.
Uxgkapkun cltlan sehuton .
[3 mcrks)
13markahl
I i , i i : : :r t : : ]11:.1:
Ans',1..: ix.gc,r
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5U - lT 1{)
( j iven hc i r rcc onscc ivc tcnnsofa gctr l t tc l r icrogrcs i io ' l rc 6. \ a: ]d
rvhere > 0.
Irind the value of-r.
Diberi ligo sebuldn bertitrul-lurul dulum unjung gconrt'lri itiith 6, r and
dengan cadaunr>0.
Cari nilui x.
A s,,n r /.,/..rrt l , rrr i l : r :
- t - l , ; / I
12mark.sl
d
3 '
12mcrkahl
3
3
t 0 Given the sccond enn and h. tenth riL
rc pectively.
Diltcri bahcwt sebult:n ktditt t.lrutsebt;
nos!t;74-mttsir:gak:lt 12.d,-:i 52
Find
L.Gf I
(l) t ir: cori:n';cr"riiici'lrcr,
bztt sepu:yt,
(6) l ire ltii;t tcr:n.
:;th||:{:ti perIul;0.
o ian ai i lhnet icprogressionre12and52
. t l:t s p u i .s tii anj ctn ori tnrl i );
(,,)
\ t )
li nurtu)
l ' , i ls ' l ; t / .-/cr: i;r.. :
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_
sul-t 'r 1t)
(iiven :l]c lirrceconsecrtivg cr-]lnsf a qatilllclfc progressitl ' l rc 6. \ Nild
rvhere > 0.
F nd the valuc of -r.
Diberi tigo seburdn bertitrut-lltntt &tlum lun ung l1conn'lri iriitth 6. r 'tntl
dengankeadaanx>0.
C.arinilui s.
A: 'swcr/Jat '^apun:x:
- l l ; l / l
12murlcsl
d
3
12markahl
fi
3
t 0 Given the sccond enn ard t|e lenth rir
rc pectively.
Diltcri bohawa schulr:n kt'tli:t dr:rts:abt.;
nic:;it;g-nos rg it:lch 12 Ci;:i 52.
Iiind
Cari
(l) 1i.ie onr.rl(. jn i iii lrrr,
h:tt sei,tu:iu:,
(5) tire il;t tcnn.
:rhuiutt perla;t;tt.
ol-ar a;ilhmcticprogression re l2 and 52
:n l:cs 'Jtt.tiil r .:;tttiltt onj ct;tgoritrutli);
(,,')
\ t ]
] r,l.:orks)
,. i i lsi ' r;t /.-/r. ' r:o;:. ; :
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St . - ' I r r
I I A gcorxc{ricprogrcssi!,n,.is 0 tcrms. iivcn that hc lirst tcrrn is I an,.lhe)
3112i1
lsst crm
is 156, flnd thc conrnon ratio ol'this progrcssion. 12nrark.sl
Sutrttrttttjtmg gconrctr i tttt,ttntrntui 10 .yehuttn.Dihti sebtrturt ertrtnta iulah ! t lanI
scbulan t'rukhir itt lul:256, turi nishuh septnt;ubagi ujuktn in t [2 markah)
At:..t;t, lJultcpan
i 2 lJiagianr3 shousparl of a strf,ight rncgrtp
Rttjah 3 ntenunjuiiltun sahaht:giun raf gtri.
. 1t:tcl i t:vtttt ; .
r irl,
trirprt:i l ; in i lrir,s ol -r.
U)1 k{tl *! n,l' .lu {;rt,ycbit t n .r.
obtrined y plotting ryagairst .x
urtt.s,angdiperolchclengtnnempkst y
l r : i t : : i i ; ; t -1
l!ult:it 3
[4 r:rir, l ;.]
1.1 tr.lith)
tl
/"(3,6)
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SUI"I'I l 2 3,r?:i l
!3 Diagram4 showsa strarght in e '{B vith the equation ] - f- - f .-1 6
Rajah 1 menunjukl<tngaris lurus AB yang mernpun;;ai ersamacn
Diagram .i
Rojah 4
(a) Exprcss hc ccuatjonofthe straight ire.,18 in grarl icnt onl.
Unglicpkanper.;,:;:itt:: gcri.s urus AB daian ltcntuk ltaceruntn.
(6) I.ind the cqn:-i lon f ttr: sir-:i i;; irtin ; 1-';ri:cndicui:r l l3 airCpr.ssinghioughth e point B.
Curi perst;mtz::t i4:iri,s t;r::,t 1clt itt:r.t!:ren ir4! (1":t1!lr!n B all:'lr
nc!sl:ti titlli [.
-Y _t
3 6
(j )
(i-,)
14nrcrlisl
14nn;'!tal)
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SU -IT t3 3172i1
Given that hc points (1, 4) , B(2h r l, 2) and ti(5,'1) arc coil inear, ind th e
value cf h. L3mcsrks)
Diber i t i t ik - t i t ik (1, 1) .8(2h+1,2)danC(5 ,4)ddalahsegar i .s ,car in i la ih.[3 markahl
l . l
15 GivenOP= 7 i-. i and 'Q=9i+3 i , f ind i : : : ocrr" l inttsf p.
Diheri bdi:ava OF =l i- .i .l.r,r ! - 9 it-3 , c,trik,;ttrt\lnt;t .
[ I , i i : : t r i . r ; i :h
12matlrch)
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l 6
SLr- ]' l-l J 1 , : t I
l) iarr:rnr5 sho.rsa :r'ar)e;riLrnt'pr!.! *lrcr.,: r(.) s parallcj o S,R.
Rafuh 5 ;nenunjukkn.yahtiu[r trap(.:itltn PQttS dcngan keltluun pO.selori dengun .SR.
J,r
P
l );,,-qral. l t
I :jtih 5
Given p-3.., Cri 2), 1t. 'd),[ 'O tl .
Di l ' t r i l ,u i t . r \ , t P() I r . ( ) . : 2 r . , , i ' ; " ) l . t i .
I lxL,rc"*'-
teri:i:; of .r a::d1
:
Un;;kepkn dilatn scll',tir;:t .r ditn ;'
i ':t.
| , 1 , , - . , - : . . \
t l , .^ , l r , r
1r..,:i;t f /,.1t|r.;;)a:ti :(c)
(1,)
( r r )
(r.)
:i.i'
;rt
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sr ; t_ lT 31't2il
l i ( . ivcn hat tanf)- , '? , hcre I is a constant nd C". 0<9! l ' ' .
Dibt'ri tan}- Ji , di.rrrn t tkth panrular t)oLz0"< 0 < 90".
Find. n termsof
l :
Cari, clulant \chutan .
( a ) c o t0 ,
k o t 0 ,
( r ) s in (180" 0).[3 mark l
13n:ctrkahl
t i i : , , . r , , - - r .I
L l l I l ' , i .. . ] l :
l-i
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SUI.IT
1 3
l 6
I)iaqrlrn 6 showsa scctr:rGP(] with ccnrreO
Rujih 6 mcnun;ukfutnvbuuh ';ektorOFQ dengonpusat L)'
lliagam 6
liuiah 6
Given that OT - TP -.8 cnr,a:T I Q{.}I 'I radian, i ir, i
Dibcri bnl:uwtt OT -- T'P-'U ctt:, !t:': I {}C{':Lrar!icn' cari
CP, in crn,
Oi',ttttldn cm,
thc arcx, i;: c:rr, of l, ' - : thir;:r-i i ' i l j l Ji '
! : : : . , ,d , : ! . : t ( , r ' . . . . ' : ' ' ' r ' / ' i i '
3412t1
14 :;critsl
14ncrkr:it)
(.t
(r)
( r i
(r)
3472i15lJ -!-1 1
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' , 1 3nzr i
l9 lrlo va, a'lies, r anC 1', e relatedby the equalion.r' .r(3 -r)r.
Civen that r increases t a constant ate of4 unitspe r sccot l, iind the ratcofchang:
13mark';l
13mcrkahl
Ii,ii r:t s':l;11:.or
of-r whcn r - 2.
Dua pcmbolehubah, r r)any, dihubungl<an .tleh e rutmoctny=
r(J r)r.Diberi y herlarnbahpadu kadar malar I unit sesaat,cari fudar perubahun x
apabila r : 2.
.Lrt riet I .Jl',rapun:
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: 0
ST'T,tT l 3 t472i1
The gradient irnctionofa curve s p"t + 3, wherep is a constant. he straight ine
"v- 5 2-r s a tangent o ihe curve at the point ( 2, I ).
Fung.sikecentrutn lenglung ittLth px + 3, di nana p arlalahpemalar. Caris lurus
;,: 5 - 2x ialah tcngen kepuda lenglotngpada titik ( 2, 1).
Find
Cari
(a) the value ofp,
nilai p,
(b) the equationofthe curve.
J)?rsamaan engkung iiu.
[3mar,L,sl
13markahl
I,t;
(I)J
,,'",ii rr;ci I . :;,".. t :;, t :
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SUt,Tf
7 l
i t
Givcn that | ---1- - a .= , tln,l the ralue of k.'i (a .r)' 5
t n lJ
D i b t r i | . 1 . , . / r ' , t a r i n i l , t i .
'1 '1 r)- 5
3472t1
13marks)
13markahl
A setof dalarvhicllccnsistsof l2 n:rni1-'ersesa meanof rur nr-l'arianceof 4.
Thr su n of tl:c ni::::bcrs s 360
Stii:t sel tlgla 1'cr:g cnliri dot ipath 12 notnbnr metnptutl,:ri ;tin m dan yaricns 4.I!c.;il t:t,,,ish br:;qi onbor- nonLar iiu cC,slch360.
Ir r: .i(i t i i
(l) tL:;; : iu:: ol 'r;r,
(5) thc sLln of sr;urrrsolithi nulirbris.
!t:i:;i! tcn:i;t:lt bagi kt:a.'t:<!iianonl;or-itortbor ilu.
[3 r::i;l;11
13n,arkr:i:l
l I i L + t r , 1 . , - l r
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SULTT 2i i
A tea( tcr wants o ch0ose5 dit.furi:ntrophicsasprizes br a birdnli l t lrl l tournment.
l wo t,ithe trophiesarc madeofpeu'ter and he oti ier hreeare nladeofpiastic The
teachcrcan choose he 5 trophies io m 6 tlpes of pewlcr rcphiesand 8 1lpcsof
p ,lstio rophies.
Seorangguru ingin nemilih 5 trttJiscbagai httdiah untuk suatuperlantlingctn
batlminton. Dua dar:pada troft adalah enis pewter dun tigd )'ang lain adalah enis
pla.;tik. Guruboleh memilih5 trof itttdaripada 6 enis trof pewter danS jenis trof
plastik.
Find
Cari
(a) the numberofdifTerentways the eachcr an choose he rophies,
bilangcn cttra yt;ng herlainon grtnt ilu boleh ntemilih trofilro/i ilu,
(/ ') the tumberofways thc trophies an be arralged n a row on a table f
th e pewtcr trophicsmustbe placcd lext o eachother.
bilongan sitsunan troii-tr"oJi lu boleh di:;usunclalamsualu bcris di atas meja
.jika lro/i-troJi pewtenne sli C!!cic'!tCi scbck:h-ntctyebeluh
14nar!<sl
14markrih)
l":'-:;* l: / .,Ic 'l ;irl,r: (a)
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SLI IT
21
l {7: , ' !
ln a iurvey conducleC,:n ollegesrudents,r is ibund thai 129,i,.r f hc collegestudcn,s o not own a computer. n a san:pleof 10 collegesnrdenls hosen andoml.l.find
I)ulum :uatu soul selidik yang dijalankan ke ataspelar"t kolej, terdapat 12 9'o elajarkolel :idak memptnfai komputer.Dalam saiu sutnpelyang terdiri daripadtt l0 orangpelcltr kole.jyang dipilih secara rawuk, cari
(r.r) the probabil i ty hat at leastoneof them doesno t own a computer,
keburangka an bahau.,a ekurang-kuntng sctu doripada mereka titlukntmpunyai komTtr!tr.
(b) the total nun:bcrofcollcgc studentswho doesnot own a computer f the coilcgeha s 1200studcnts.
.junit:h pelajar kolej ycng tidak mempun.yui cs:;puterika kotej itu terdiridariTudrt 20t)orang 1t.l. lor.
14narlcs)
11mcrkahl
ll,il::t slLtir: i :
2 i
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st.. -r
25
:2
Diasrrm 7 sho* s a standard onnal distributiongraph.
R.;jah 7 nt' nunjukkan sun gritf iuhurun normal piatvci.
3472;1
Diagram
Rajdr T
The probabil i tyrepresented y the areaofthe shaded egicn s C 7416.
Kebarcngktliun yang diu;akili clah l:s:s }.,{tva:;cn erlorgk iclch 0.1416.
(o) Find thc valuc offt.
Ct:ri nilai k.
(6) X is a coi'l t inuousnnClnrvr:: ' i :: l ; l ::hich il n*rnally tl:11:i 'r:utedilh a mi3r
cf 85 :rnda. lsda:d dcvi:r1-:;:n-,'1.
Filil fir* vah:e c|Xrvl:.:r il '::z :co;,.. s .. ( .
X iaLlr p:tni;o!el: i :h t r: ' ,:t: ' , .:::!:,r: .1tr l ;e; ' !t:, i ;t.t: ' {:;;i tt:(:; ' ! :!ui}t ' t i icl d::;t;;.:.,, ,: i ; i ' . . i5
dnit si:; i:'yt i,'!ttw:i 3.
gnrl 7711;;1)( 1;;:rlt;!u *.c,r-: i,tj,:i: ii. ['1r;;;rlr]
i4 r : ' ' ' ' ' : "
l .,f. i :-i :] l- : l i l '.! l : i ::11illi;ii i [.: i T.'l,li,\. .',..,r,..ii ;'.,i '..1
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,' !,
t: i{ ,LIT3472t1
BLANK PAGEH,'IL,IMAN }IOSONG
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S i i . 1 '
I i . - t)Rl l . \ l ' Io\ r {)R c.\5DID.\TES
3172t1
i . Thisqutst ion aper onsists f25 quest ions.
2. .,\nswer llqucstions.
3. Writc ,vouranswers n thc spaccs rovided n this qucstionpaper.
'1. Shox your,'vorking. t nray help yo u to ge tmarks.
5. I1 - ou wish to cirange oui answcr,crossou t thc answer h atyou haveCone.Then
write down the new aniiwcr.
6.'l 'he
diagrams n thequcstions rovidedar enot dra',vno scaleunless tated.
7.'Ihe
marks allocated or eachqucstionare shown n blackcts.
8. A list of f ormulac s providedon pages2 to 4.
9. Fr.rur-figure athcnatical lrbles roallowed.10. You may usc r non-piograntrnabiecienlificcalculator.
I 1. LI3nd n this questionpilr,. i to the n.rigileiorat tl te end of the examination.
NiAKi,Ul,lr^'I ' UNTI]i{ Cr'"i.(;ii l
1 Fkrlus scctktn ini n,'ngati:!::;:11i 25 soalt;tr.
2. Jsv uh simul sacll i l .
3. .Jgu'llsn uittto ht:irkkici: r.!!rt!i.spt;tlri niar:l )tc::g t! .t,:t!iukr''t r.!ulum k:rics:;att!::t ini.
4. Tusijukksn lu; t;',keh- t:t1].,';:tt lr.j'::j:iE L:Jl'Yt l;::;ji: ir;:tt71itu r;:t:h. Itti I'tt!el; r:t:nbcttitt
a n ltt t tt k r:te lJ: : t 'fu 't :i: t 'it,::lt.
5. -tikt ntrlu hcnit!1 ntuit*c:.j,::,,":a:ltr.rs!, ;t,'ti.-;;t.i r!t'i:,.;::;tkc:t:t::; jo.+apr:n ri:itg tt!u!t
dibu::t. Xenuditi1 l!t!;:; j 't',:ii;i:,tr-(:n.: ':,':i:nt.
6. litju);1.r.:i'tg r;:tn,qiri::;1i sr.tui::rt i:!ti; dilirl:it ;i.ti',;;"::tI sku!t; l;:':u,;li clitt's !:;.itttt.
8. !'u!:.t :;cruirtLi tit :ii.t diskii! .!.1.r,t,:!i ijcrtfi:.tn ?, it:.,11:: 4.
().B:.iktt sil)r rtda,'rttiik tt,:i;::: rt.':g)it i!hrn,::ri;ut'.
IA. .,1nilLr iii;cttitrit:t't t,-tt:r;:.,,;i:i:':.1;i)1ti:!:i;!!i!r s6:,tlif'l .t :.'t;7 idu.L bo!tit r!t;;;o"1;r;;n.
12. S:rc!:kt;tt k!r:t1,\ so{rldtl in! lt,:;:,-;1,!ti1.ttt:1:,r;',;'0,:;)t'Stt'rii::;t;r;:t italt tl.:h;r ra;),..ril:c{r:1.
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+progrlnr peringkatan
i I'ltltti{s'!! !lq1!"nt,1t
r]
(.1)-uraphssh,trvnit(r_,1
I
\ l . ,
. \ . .shapcd
Ii. - i ''lr''rrrh----l---->
(b ) 0 < . l l r ) < 7
t
( h ) k - i I2 l s
4 k 3 - j I
/ ' ( 2 ) = c l B z
4 - p
I
2
B )
4(rx3) 0
-l r. , -l
(p -3)(p t) o
(-2!,)t 4(2p l) (_)
Pres la r i a ins l l : r r cn r r r t i k1009tc r l : r r k i l g \ t .hc r r :e p : rpc rI
l ( n )n 5
' ( t) r t 5
91 " .
lo-1, -r6y iogr g
Iog.,11 - lo-g; j
/ , 4 I
7r r t l -5
t l 12nxi a
rlI
I
logr9
I
B 1
I
-)
B2
B I
3
B2
B ]
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t i
i i
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SULIT 3472tr
NAMA:
TINGKATAN:
.IABATAN PT),AJARANTERENGGANU
SPM2OO9 347211EPERIKSA"dNPERCUBA,{NADDITIONAL MATHBMATICSKertas1Sept20092 iam
JANGAN BUKAKERTAS SOALAN INI
SEHINGGA DIBNRITAHU
| . Tuli.t Nama dar Tingkatxn pada ruong,yong
disediakan.
2. Kertas soalan ini adalah dalatr dwibahasa
3. Soalandalamhahasa nggerismendohuhti
soalanyang sepadandalam hahasaMelayt.
4. Calondibenarkannenjawab keseluruhan
atou sebahagiunsoalan samaada dalamhahasa nggeris atau dalam bahasaMelayu.
5. Calon dikehendakimembacamaklumstdi
halamanbelakanskzrtassoalan ni'
UntukKewnaan Pemeriksa
SoalanMarkahPenuh
MarkahDiperoleh
22 J
3')
4 3
5 36 37 3
8 39 4l 0 2
I L 3l 3 4
l 4 3t ) 3
l 6A
l 8 2l 9 +
20 32 l 4
22LJ 324 4
25 3
Jumlah 80
Di.\!,ll kln ol(h;
AKIIAi\ I NEGERI TNR[N(;( ;AN ti
l ) i h ia ] / ] i [ t h :
KNRA, 'AAN NO(; ERI TI]RI]N(;(iA Nt J
Di etuk olch
P!rcetqkan ytJ'atu, lsln. Terenggunu Sln' Bhl.
lit|: 60Q-b66 l6 |I 6(t-\2 I6t)| f-ukt: 6t)Q-6(6(t6| .00()l
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3472/lULIT
The ollowing ormulaemaybehelpful n answeringhequestions.hesymbols ivenare heones ommonly sed.
Rumus-runus erikut bolehmembantu ndamenjawob oalan.Simbol-simbolangdiberiatlalahyangbiasadigunakan.
ALGABRA
l . . r =- b !
2 . f x t = { " ^
{ + d = { - '
({y = {'
5. log mn= log,m + log, n
. mlo & ._ =logE'..m-logltn
log, mn= n log, m
los b̂log- D : --=-:-
Iog. a
T , = a . t \ n ' l ) d
J' *. I
r3.r-fr, ,,t.
ro.s,=i\za+tn-\al
l l . T" = 1v'-l
a(r" * l )
8.
-t .
o.
7 .
- 4sc
CALCULUS KALKULUS
l . y : w
dv dv
dx dx
- d v d v d u-J. -:- = ---:- x --
dx du dx
^ uv
. d uJ' r,.. -
dx
du dv, v ..-- - u--'
a Y , d x d x
d,- **7-
4- Areaundera curveLuasdi bawah engkung
:)Y dx or alau
b-
)x d.r '
5. VolumegeneratedIsipaduanaan
b= lf i v- f i t or I alau
b=
l | t x - dy
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ST]LIT 3
STATISTICS/ STATISTIK
3172/l
l .Y y
N
LlxL f
l ] .v-r)5 . m = L + | - * l Ct f l\ '/ l,r )
n,6 . y = E ! v l [ S
Qo
7,
8.
- \ W . I' - -F r { /
/ , ' i
' l != -
\ n - r ) l
, 1 |
7 . L - -' ( r - r) l r!
t0. P(AvB)= P(A)+P(Bt-P(.4^B)
f l . P ( X = r )=n C ,
P ' q ' - ' P + q= |
12. Mean Min = np
13.o =.,lnpq
rl t ', - " r '
i _ , ,-'.=-
r o=, /n f i .L= f r : "1; r ,
@mmmmmm=w;I : r \ J : /
CEOMETRIGEOMETRY)
1. DistanceJaraL
( x , + x . v , + v .( r -u l= I , '
- : r - - ,1- : Il 1 1 t
A pointdividing segmentfa line
Titik angnenbahagi uatuembereng
gans(nx ,+mx , nv , my , \
(x.-Y)l - . - I\ m + n m + n )
4. Areaoftriangle Luassegiigat ,i ,
l { " , -u , t r t , +xr } r ) - (x?.vr xry , +r ,y3) l
6 . i =
2.
3 .
= J1x ,- x2 )21y1 - !2 \2
Midpoint Titik engah
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S]TJLIT
i. Arc length,s = rO
Panjang engko( s -70
TRTGONOMETRY TRIGONOMETRI
3472t1
8. sin(l t.B) = siM cos8 * coM sin8
sin(,4 * A) = sinl kos.BJ kos,4sinj
2. Areaofsector = ! rz, 9. cos(l + B) = coMcos6 T siM sinjz
Luassektor,f: ! i2gkos(l t B) = kos,e os.BT siM sinB
2 '
3 . s i n2A+cos2 A : Ito . tan ( l t B ) = tsn l t t anB
s in2 , {+ kosz r = rI + tan l tanB
4. seczl = I + tan?A 11. tan2A=
,",u 1 ,L * t a n ' A
sek2l - I + tan2,4
2 . - ! - = b . , - '
s rn l s inB s inC5. cosec2l = I + cot2l
kosek2l = I + kor2l1 3 .d : h " + c ' - 2 b c c o s A
6. sin24 = zsiM cosld = b2+t-2bckosA
sin 2,4 = 2 sinl koM14. Area of triangle lna.r se8 iga
7. cos2l = coszl - sin2 = I aDsin C
= 2 c o s e l - l2
= l - 2 s i n 2 l
kos 2l = kos2l * sin2
= 2 k o s z l - l
* I *2 s in2 l
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SULIT
Answer ll questions.
Jawabsemuasoalan.
Diagram showshe unction/thatmaps to/ and he unction thatmapsyto z.
Rajah I menunjukkanungsi yangmemetakan kepada danfungsig yangmemetakany kepada .
Diagram1RajahI
DetermineTentuktn
(a)c
'(6)
(b) d(4)
3472t1
[2 narks]
12narkahl
AnswerlJawapan:(a)
(b)
ForEtamlner't
Use
I
r-:I l 2
{
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ST]LIT 3472t1
[3 marksl
[3 markahl
For
FJarninet's
Use
2
t;
The unctions/and aredefined y f: x --+ - 3x andg : x -t x2+ 3.
Fungsi-fungsidan g ditatviJkanolehf : x -+ | - 3xtlang: x -+ x2+ 3.
Find I Cari
(a) d2}
(b) I 'd2).
3
r-:I l 2 l
r--)
Answer Jawapan.(a)
Find he ange fvaluesofp such hal heequation * -, =p *2 hasno real oots.
12narl<sl
Cari ulat nilaip dengan eadaan e samaan xz x =p - 2 tidak mempunyai uneanydtd. [2 narkahl
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Stn,IT
4 Given hatoneofthe rootsofthequadraticquation '* ir + 8= 0 istwice heother.Find he values f ft.
3472tr
[3 marks]
Diberi bahawasatu daripada punca-punca persdmaankuadratik t' - k + 8 = 0 adalahdua kali ganda yang satu lagi. Cari nilai-nilai k. 13markahl
Answer/Jawapan:k=
ForExominer's
Use
4
T_:I t 3
Find he ange f valuesf / for (/-4) > l8-t.
Cariulat nilai bagi t(t*4) > 18-/.
[3 narles]
[3 markahl
5
G1 \
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$nlT
ForFtqmlner's
Use
6
m
3472tr
Diagram showshegraphofa quadraticunction/(x)= 9 - 2(x- l)2 and he
maximum oint s(r, &),where and tareconstants.
Rajah6 menu4iukkanraffungsi kuadratikflxl = 9 -2O - h)2yangmempunydii,ikmalrsimumh,k), dengan eadaan dan k adalahpemalar.
DiagramRojah6
State Nyataknn
(a) thevalueof*,nilei k,
(b) thevalueofi,nitaih,
(c) theequation f the axisof symmetry.persamaan aksi simetfi
13narksl[1martahl
Answer Jawapan (s) ,t =
(b) h=
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ST]LIT3472/r
7 The erticesf a rian leare (7;.3.),e(_1,5)and (,L_t). Givenhat hearea f theriangles 19unit2,inl thepossiblirlu". oit.
- --''-
[3narksl
Bucy;buc.ulb.u7lysttigaalh.l(7,3),
gl_1,5)danR(k, t). Diberibahawauassegitigatu iatah 9 unit2,artnilai-niiiliri ^ung*iiiogi i.-' '- '- .ii
^**on
ForErominer's
Us
I JI t 3 lAnswerJawapan: k=
SofveheequarionZ't(Blb) = Jj .
SelesatkanersamaanZ7(g1b)- Jj .
Answer Jawapan
{3narksl
13narkahl
I
r:lI t 3 l
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ForIianiner's
Use
9
t--:I t 4 l
l o
Diagram9 shows wo sectorsOpP and 0lt8 with centreO.
Rajah9 menunjukkanua sektar,OQPdan ORS, erpusatO.
DiagramRajah9
Given hatOQ= 16cm and heperimeterf sectorOOP s 42 cm.
Diberi bahawaOQ= 16cm danperimeter ektorOQP alah42 cm.
(a) Find hevalue f d, n radians.
Cari nilai 0, dalam radian.
(6) If the atioO]t I RQ= 3 : I , findthearea f sectorORS.
Jika nisbahOR : Rg = 3 : 1,cari uassektorORS.
Answer/Jawapan:(a)
(r)
e =
3472t1
f4 narkr)
[4 narkah]
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SL]I.IT u
Answer / Jawapan : k-
11 The irst hree ermsof a geometric rogrcssionre36 , 12,4.
Tiga rebutan ertamasudlu aniang geometri qldh 36, lZ, 4.
Find I Cari
(a) the fourth term,sebutankeempat,
(b ) thesum o infinity,ofthe geometric rogression.
hasil tambuh hingga sehutanketakterhinggaan,bagi ianjong itu.
AnswerJawapun:(a)
(,5)
3472/r
10 Givenhe hree onsecutiveerms f an arithmetic rogre.ssionrewhere is a constant.ind hevalue f k.
Diberi iga rebutan erturatan uatuianiang arilhetih ialah rz,3k - 2 daa4 + t,d€..ga..kesdaan adalahpemalar.Cari nilai k.
12markahl
1 2 , 3 k - 2 a n d 4 + k ,
[2 narks]For
Erominer'sLlse
l 0
I --lI t ? l
| |l
[4 marks]
14markah\
l l
t--:I l 4 l
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SIJLIT
Givenhat =! a,ld/r 3q, xpr€ss'"r[+J'"
terms fp and .
Diberi bahawa = 3pdank= 3q ungkapka, 'rgr(t!\aolamsebutan danq.- t
e J
t 2 3472t1
[3 marlcsl
[3 markah]
ForExaminer's
Use
t2
r-----]t - JI l ? l Answer / Jqwaoan :
Given hat ogtQ. logeP = -1, express in terms f 0.
Diberi bahawa ogzQ- logeP2 = -1, ungkapkan dalam ebutanQ.
Answer Jawapan :
[4 narksl
[4 markoh]
l3
T-;lI t 4 l
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STJLIT
14 Table 4 showsmarksobtainedyagroupofstudentsn a monthly est.
Jadual 14menunjukkanmarkah angdiperolehsekumpulanelajar dalamsatuujian
bulanan,
MarksMarkah
l - 2 0 2 l -40 4 l - 6 0 6 l - 80
Numberof studentsBilanganpelaiar
o 9 l 3 t2
Tabte4Jadual14
Withoutdrawinganogive, ind he hirdquartilemark.Tanpamelukisogif, cari markahhnrtil ketiga.
t3 3472t1
[3 narks]
13markahl
l-orExaniner's
Use
l 4
t;
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SL,'LIT
E a iher's
Use
l5
tG
t 1 3472t1
15 Given hat heequation f a curvewhichpasseshrough ointP isy : 12r I )2 .
Thenormalgradiento the curveat pointP is -; . Find hecoordinatesfP.I
[3 marlcs]
Diberi bohawapersamaan uatu engkung ang melalui titik,P ialahy = (2x * 112.
Kecerunannormal kepada engkung itu pada titik P ialah *- . Cari koordinat P.
13narkthl
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S{JLIT t 5
GivenhatIS@a,
= 7, ind hevalue fI
4f
utDcrt bahawa I RG) dx = 7 car! nilui bagiI
I
(4 ) | .S(-r) r .
(D) z f I l l s ( " r ) - n l dx = 25 . ) " " '
P l tKo l l2 (x l - D l dx - 25.J ' " -l
Answer/Jrn,apon:(a)
(h )p :
3472t1
l 6
[4marksl
[4 narkah]
16
t__I l
a)
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s'utxT
ForExaminer's
Use
l 7
T-:I l 4 l
3472t1
17 A curvewhichhasgradientunction tx 2, where is a constant, asseshroughpoints0, 0) and 2,0) .Satu engkung angmempunyaiungsi kccerunan a -2, dengan eadaan adalahpemalar,melalui itik-titik 0, l0) dan 2,0),
Find Cari
(a) thevalueof ft,nilai k,
(6) theequation fthe curve.persamaanengkung tu.
14narlcsl
14narknhl
Answer/Jowapant(a) :
(b)
l o
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ST]LIT l 7
--t
Diagram 18 showssquaregridswhere OP = a andOO = b.
Rajah 18 menunjukkangrid-grid segiempatsama dengan keadaan--'
dan Og =6.
3472t1
18-+O P = a
-+(a) Express R
Ungkapkan
Diagram18Rajah 18
in termsof a and b.-+OR dalam sebutan dqn b.
-+(D) In heanswerpaceiven, lotandabelhe oint where S=b*2a.
Pada ruangjawapan, tanda dan labelkan titik S dengan keadaan RS= b - 2a.
AnswerJawapan:(a)
(b)
[2 marksl
12marlcahl
-)
O.ie=
.tt
\
P
; l at \ A
(, t
R
\
P
\ \ 0a \ Ao
ForExaniner
Use
1E
t-tI l 2
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SUI,IT
Fbr
E atniner's
Use
t 9
T;I l 4 l
r-)
3172t1l l
19 Diagram 9 showsa parallelogrampR.S ndMis themid pointof Q,R.
Rajah 19 menunjukkan egiempat elari PQRSdan M ialah titik tengahQR.
Diagram 9
Rajah 19
--t
Given hat PQ=4i+ j and PM : 5i + 4j, whefe and areunit vectors arallelo x-axis
andy-a,xis espectively.-+ -+Diberi bahawo PQ = 4i + i dan FM '=Ji + 4j, ctengan zadoan dan masing-masing
aclalah vektor unit selari denganpaksi-x danpaksi-y.
Find I Cari
-+(a) QM in termsof i and ,
-)
QM dalamsebutan dan ,
-)
(b) D tPst,(ii) the unit vector n thedirection f * .
veklor uni! dalam oroh 1S .
14marksl[4 markah]
-+Answer Jawapan (a) QM =
(D) i) lPs =
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3172t19UI,IT
20 Diagram 0 showsa straightinegraph f log royagainstog ro:r.
Rajah 20 menunjukkan raJ'garis urus log rcymeluwan og nx.
Diagram 0Rejah20
Civen hat y= 1000x?,alculatehevalue fp andof4.
Diberi hahav,a l= 1000x2,itungkan iloip dannilai 11.
Answer Jawapan p:
"'
l 0 *
13marksl
f3 markahl
lo8ro
( l l , q )
Ilaminer's
Use
z$
T-:I l 3 l
n
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ForEiquiner's
Use
2 l
T_:I t 4 l
20 3472t1
Solvehe rigonometricquation in2x- 2sint=0 for0" <x < 180o. [4marksl
Selesaikanersamaanligonomerri in2.r-2sinx=0 untuk oSxS 180o. 14markahl
Theprobabilityor Raihan, ichellendAmira oqualifyor he inalof a schoolevel' ' I 1*a ! resDect ive lv .ublrc peaKrngontest re .
5 g
Kebarangkalian ahawaRaihan,Michelle danAmira layak keperingkatakhirpertandingan
syarahaneringkatset<olahdalahmasing-masing*,i
*"*
Cafculateheprobabilityhat Hitungkan ebarangkalianahawa
(a) onlyoneofthemwill qualify,hanyaseorangdaripadamerekaakan ayak,
(6) Raihan r Michelle ill qualifo.RaihanatauMichelle akan avak.
14marksl
14markahl
Answer/Jawapan:(a)
)',
T_:]I l 4 l
t l (r)
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SUI,IT
Answer/Jawapan:(a)
(r)
21 3472/l
E M t r E t r H t rDiagram 3Rajah23
23 Diagram 3 shows ive letters nd wo digits.How manypossible ayscanall the ettersand hedigitsbearrangedf
Rajah23menunjukkanima hurufdandua angkt. Berapabanyakbilangancara,semuahurufdanangkndapat disusunjika
(a) none fthe letters nddigits s repeated.tiadl huruf dan angkadiulengi.
(b) thedigitsareseparatediom each ther.angku-angfuidaraherpisah ntara atusdma ain.
13marksl
[3 markah]
Exsniner'sUse
t l
l--JI l 3
\
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Fot
FJaniner's
Use
24
r-:I l 4 t
ST]LIT 3472/l
A teamof 6 playersare o be selected andomly rom 7 girls and4 boys.
Find thenumberof ways the teamcan be formed f
Satupasukan terdiri daripada 6 orang pemain akan dipilih secara rawak daripada
7 orangperempuandan 4 orang elaki. Cari bilangancarapasukan tu tlibentukjika
(a) there s no restriction,tiada syarot dikenakan,
(b ) the number f girls s more han he number f boys n the eam.
pemainperemputn lebih ramai daripadapemain elaki dalampasukan tu.
22
24
14marksl
14narkahl
Answer Jawapan (a) . .
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SUIIT
Diagram 5 showsa standard ormaldistribution raph'
Raiah 25 menuniukkan raftaburan normalpiu*'ai.
Diagram 5
Rajah25
Theprobability epresentedy he area fthe shadedegion s0 7648'
Kebarangkalian ang tliwakili oleh uas kawasanberlorek ulah 0'7648'
Find / Cari
(a) P(z > i),
(b ) thevalueof ft.
nilai bagi k.
Answet/,lau,upan
HNDOF QT]ES]ON PAPER
IiERT'AS OAI.ANTAMAT
23 3472t'l
[3 marks]
13markahl
t q
(a) P(z
(b ) k=
L\amLner's
L'se
25
t--:I t r l
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21
INFORMATTONFOR CANDIDATESMAKLUMAT UNTAKCALON
3472t1SLII,IT
2.
) .
l . Thisquestion aper onsists f25 questions.
Kertassoalon ni mengandungi 5 soalan.
Answeral l questions.
.Iawab sernuusoalen.
Write your answersn the spaces rovided n the questionpaper'
Tulis awapan anda dalan ruang yang disediaktn dalam kprtassoalan'
Showyour working. t mayhelpyou o getmarks.
Tunjukkan angkahJangkah enling dalamkefa mengiraanda. a bolehmembanlu
anda untukmendaPslkanmarkah.
lfyou wish o change ouranswerr ross ut heanswerwork thatyouhavedone'
Thenwrile downthe new answer.
Sekiranya nda hendakmenukarawapan, batalkanau'apanyang telah dibuat'
Kemudian tulis jawaPan Yangbaru
The diagramsn the questions rovidedarenot drawn o scaleunless tated.
Rajahyung nengiringi soalan tidak dilukis nengikut skala kecuali dinyatakan'
The marksallocated or eachquestionare shown n brackets.
Markahyang diperuntukkanbagi setiapsoalanditunjukkandalam kurungan'
A list of formulaes provided npages to 4.
Satusenarairumusdi,sediakan i halaman2 hing.ga .
A bookletoffour-figure mathematicalables s provided.
Buku sifir matematikempatangkadisediakan.
7 .
10. Youmayuse non-programmablecientificalculator'
Andadihenarkan enggunakanalkulator aintifik ang idakbolehdiprogram'
ll. Handn thisquestionapertohe nvigilator t heendof theexamination'
Serahkan ertassoalun ni kepoda engowaseperiksaan i aLhirpeperiksaan'
8 .
9.
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74SULIT 3472t1(.PP)
JABATANPELAJARAN ERENGGANU
PEPERIKSAANPERCUBAANSPM2OO9 34721I
ADDITIONAL MATHEMATICSKertas1
PeraturanPemarkahan
Sept2009
Perllturallpeilrarkahan ni ntengalrdLrlrgi halamitttbcrcstak
34721\(PP) .rr 009 RIAL Ptvl akCipto abatan elajamnegeri efengganir [Lihat sebelah
SULIT
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stn-lT'3412t1(l>P)
INSTRUCT IONS FOR F]XAMIN F]RS
I, MARKINGGUIDII
1 I Mark all th eanslvers.
1.2 Do not mark vorking answer hal hasbecncancelled
l. i Answerwritten n the answer pace r at the endofthe working s considercdhe inal
allswer.
1.4 lull mark s given i, 'r hecorrect ns\\erwithout eferringo theworking'
1.5 If the linal answer s wrong, award he corrcspondingmaximunlmark as stated n the
tnarking scheme.
l .6 l fmoret l renonef inalanswer isgiven'c l roosethcanswerwi ththehighestmarkUnless
statedotherwise n the marking schenre'
1. 7 lf tlre inal answer scoffect,but statedwrongly n the answer pace'ull mark s not
au'arded.
2. NOTATION
2.1 lu l l mark br eacl r uest ionn thispaper s e i the 2, u 4
2.2 If full mark s not awarded,he ollowingsystetns used
83 - 3 marks s awilrdedf theanswerat his stagc scorre t'
B2 - 2 tnalks s awardedl'theanswer t this stages concct'
ts t - 1 mark sawtrrdedf theanswera1 hisstages correcL
2.3 Onlyoneoulof83, 82 olBl is awart . let lbr each uest ion rpadofa qucst ion '
3.Acceptanswerscofrect to4signi f icant f iguresunlessstatet lotherr ,v iseint | remark ingschenre.
4. Acceptothercorrectmethodsvhichar enot given rr hemarking cheme'
5. Acceptansrversn BahasaMelayrt
6. CalculatingotalnlatKs
Ser)rcor 'upur I f sc"re { ' r ' i r l )cr ,^^ , , ,
I {0
317211{PP) io20osRIAL PMHa k ipta abatanelaiaranegerietengsanu llihat seb,clah
SI]LIT
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3 347?/1(Pt)STILIT'
Mark Scheme
(a)
(b)
3
(l
(a)
(b )
7 (r)
2 {2)
| - 3 x : 7 o r B1
, . \ - o r p < I t l 7 5' 8
( l 1 2 - 4 ( l ) ( 2 , ) 0 ((iive B0 lbr othcr than< 0)
(2 )
tll
k :6 . 6 (3 )
d+ 2a=-k , a (2a ) :8 (bo th )
, t ' 2 u k t l r t , t ( 2 n ) 3
a ld o : !2(acccpt : 2)
B I
OR
k : 6 , 6 ( 3 )
-k= 3a, 2l :8 ( bo tl r) a n d c = t 2 B 2
(accept l- 2)
" t 2 m , a r + 2 i - 0(r - aX.{ 2/ l :0 xnd
I < 3 , 1 > (J) ({iive li 2 tbr othet }ran1)
E Marks
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ST]I,IT '3.1?2/rPP
Mark Scheme
(a ) 9
(b) |
( c ) r = I
( l )
( 1 )
( l )
4, 42 (borh) t3)
II t r r 5 ) . ( x l ) , { l ) I I ( l r ' k t 5 t ] t l } l - l { )1
;IJ 1 7 1 5 1( I x r ) , ( l ) - t l ( l ) - { ( 5 r 7 ( l r l J ' l 9'
tfor82 thcre s rroatrsoluteign)
l
, J I r 7 ( 5 )( r X l , , l ( t ) I I ( t ) * l ( 5 ) 7 r I ) l)
i- or -0.11 25 (3 )1 6
-
- i a(ZrI
or cqui r l . t t B2' ) -
I
3: 13+i2-')1 :r Bl for any two out of thme rrdiccsvithbase3
( a )
( b )
0.625or
l 0= r 6 '
s l 0( 2 1 { d on ( , 1 ( c r p t . . )
l l lo
or cqLrivaent
antl PQ - 10 cr n(value 0 seen nywheren
rvorkingsPace) Bl
45 cnt' (2) i igrroreLrnit)
l -
Aroa =. : ( l?l' +f/ + krl lorv irr0' l l l
t l
I L
sebclah
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SI,ILIT 3472!t(1'P)
Marl< Scheme
k : 4
3 k - 2 1 2 1 + k , ( 3 k 2 ' )
(21
{tr
0 )- o rl -
unal , : ,l3
accept
(a l i .3 :l
accept 3.997 U!na1 i.99
36
i - .0 . 3 3 1 3
0.3333
Z p - r q - 2 ( 3 )
2 l o g s z + o g r , t l o g 3 I l z
lll fol either using log.,nn or log,, An
347211 Pl'') @r 009 RIAL
t h I 5 /
J O
, r! -
3
a : 3 6
(3)
l
I
I
I Marks
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R
PI
,l
\ \a\ A
sUt. l '
. - 1 ( 3 )
, : l l l - - ) y t ) 0' 2
PXv- -. - zx l c'' 2
? -r , -a-r ' - 2x-r 0' ? ,
( a ) 2 a + b
(ignore+r' fo r 81)
gg equivalenl (l)
3412tr..|PP)
lLihat scbclah
/ ' tt J
t -\ 4
1 t)
;
(al
(b)
r \
. - j4 )
r - l
Mark Schcme
or (0'75,0 5) (3)
3X 2 ) - 2 9 r ' : t o r
2x - 1)(7) or equivalent
equlval9l l i
ul l ignore)
-7 ( l )
-6(3)
1 l l r(4) P(l ) l -25 82 (subsl i tutc)
I [r . t l , ' ]5 Rl lor ntegration
ta,
(b)
82
BI
( 1 ) for corrcctlYsPotted
and abelled
egeri erengganil
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stJI t' f
( i i )# ( i i3 i )
2: i l + J t ) o r
V'+{l
3172/1(vPJ
(a)
(b)
Mark Schcme
i + 3 i ( l )
(i) .,/a0or 6 i25 or 2Jt 0 (2 )
-)P^9 2( i | 3j ) q! cquivalent Il1
I
J+o(2 i + 6j )
2-i , j : i sr 0'3162i+3i)
J40 J40
0 . 1 5 8 12 i 6 j ) o r 0 i l 6 2 i + 0 9 4 8 6 i ( 1 )
p : 3. q -- 25 both) (3 )
- r t , t )( ' o r n p r r ( ' : f I ! I l
t l
82
n - 2 o r c - l o g , , ,0 0 09 1 c : 3
From : log,u ': logro 000+ 2 ogr)x
; r= 0' ,90",180" (4)
_t 0.. I80" or _r. '90.
s i n :0 9g cos - i 82
? s i r . t ( c L r s . r) - 0
2 sin.tcc,sr 2 sirl r ={l
B1
ll l
IIl
I
i
X Marks
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3472/t(PPl
X Marks
SUI , IT
Mark Schcme
n , ' ' . ' l " , l . . 5 l B r\ r5 r j / l r 5 8 /
R1t 4 3 )
o r J x - x I \ 2 5 8 )
(r)
(2)
ta)
(b)
l(a)
1Ql
( t I r )
l 2 ' a ' n . J
o ) ; e )
( t r r )l , t ' ; " * J
IJI: { .61.2l)
5040
3600
"P., t.
(a)
ib )
(a)
(b)
( I )
(3)
'1.62
i 0 1
- ( . , , ' ' ( ' , ,I
' c ' . r ( '
tc 'ut
' ' f - 'oor
' ( ' r ,
rt{-'o
xt{',
Bz
' tc ,( | , r ' t : , * t { . . ' . ,
B l
0 . 1 0 i 8
1 . 2 6
B Il i 14 or 0 8962 or 0 i0-18 or 0 ?352
ENt) ()F Nl.{Rh. S(' tll lMlL
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