kem akademik sept 16
TRANSCRIPT
Mathematics SPM1
BENGKEL KECEMERLANGAN
AKADEMIK
MATEMATIK (1449) SPM 2016
SMK MUKAH20 SEPTEMBER 2016
0900 – 1030 Disediakan oleh: Panitia Matematik
Mathematics SPM2
A B C D E F G H I J K L M N O P Q R S T U V W X Y Z
1 2 3 4 5 6 7 8 9 10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
RENUNG-RENUNGKAN…
Then,KNOWLEDGE = 11 + 14 + 15 + 23 + 12 + 5 + 4 + 7 + 5 = 96%HARDWORK = 8 + 1 + 18 + 4 + 23 + 15 + 18 + 11 = 98% Both are important, but fall just short of 100% But,ATTITUDE = 1 + 20 + 20 + 9 + 20 + 21 + 4 + 5 = 100%
ANALISIS JAWAPAN SPM Tahun A B C D
2005 8 11 11 10
2006 10 10 10 10
2007 6 15 12 11
2008 10 11 9 10
2009 9 10 11 10
2010 10 9 10 11
ANALISIS JAWAPAN SPM Tahun A B C D
2011 11 10 10 9
2012 11 8 10 11
2013 9 10 11 10
2014 10 10 11 9
2015 9 9 11 11
2016 8 – 11
Mathematics SPM5
Question 1KETAKSAMAAN LINEAR
[ 3 marks]
Mathematics SPM6
Symbol Definition Line
> Lebih besar daripada Garis putus-putus------------------
< Kurang daripada
Lebih besar dan sama dengan
Garis solid
Kurang daripada dan sama dengan
Mathematics SPM7
Example 5 : (SPM Nov 2005)On the graph in the answer space, shade the region which satisfies the three inequalities y 2x + 10 , x < 5 and y 10 .
Answer :
x < 5
√ K1
√ K2
Mathematics SPM8
Example 6 : State the three inequalities that satisfied the shaded region in the graph below.
Answer : (i) 3y x + 12 ; (ii) y 2x + 4 ; (iii) x < 2√
N1√ N1
√ N1
Mathematics SPM9
LATIHAN: (SPM Jun 2016)Pada graf tersebut, lorek rantau yang memuaskan ketiga-tiga ketaksamaan y x + 8 , y x and y 6 . (3 markah)
Answer :
Mathematics SPM10
JAWAPAN: (SPM Nov 2016)
Mathematics SPM11
Question 2Persamaan Linear
[ 4 marks]
Mathematics SPM12
Example 7 : (SPM Nov 2015)
Calculate the value of x and of y that satisfy the following simultaneous linear equations:
82445
yxyx
Mathematics SPM13
6366
44104044285)1(int)3(
)3(28:)2()2(82)1(445
yyyyyyosubstitute
yxfromyxyx
Method 1 : Substitution method
√ K1√ N1
4
628:)3(int6
x
oysubstitute
√ N1√ K1
Mathematics SPM14
Method 2 : Elimination method
4123:)1()3(
)1(445)3(1642
2)2(:)2()2(82)1(445
xx
yxyx
fromyxyx
√ K1√ N1
6122824
)2(int4
yyy
oxsubstitute
√ K1
√ N1
Mathematics SPM15
6,4,64
3624
61
85418442
61
84
5142
14251
84
2145
yxso
yx
yx
Method 3 : Kaedah Matriks
√ K2
√ N1 √ N1
Mathematics SPM16
Check answer : Calculator Scientific
MODE 5: EQN 1 : anX+bnY=cn
Mathematics SPM17
Example 8 :
Diberi jumlah 50 tiket telah dijual dengan harga RM 2080 dalam satu konsert. Jika harga satu tiket ialah RM35 ataupun RM50, cari bilangan tiket bagi harga RM35 dan bilangan tiket bagi harga RM50 yang telah dijual.
Penyelesaian :
Katakan x = bilangan tiket bagi harga RM35 y = bilangan tiket bagi harga RM50
2080503550
yx
yx
22,28,2228
330420
151
208050
135150
1355011
208050
503511
yxmaka
yx
yx
Method 3 : Kaedah Matriks
√ K2
√ N1 √ N1
18 Mathematics SPM
Mathematics SPM19
Question 4Lines and Planes in 3-Dimensions
[ 3 marks]
Mathematics SPM20
WON TechniqueExample 12 :Given that V and W are midpoints of UT and PS. Name the angle between line VQ and the base
PQRS.
Mathematics SPM21
WON TechniqueStep 1 : Arrange the line and the plane in two rows. Then draw 3 boxes.
VQPQRSW
Step 2 : Find out the same alphabet. Slash the same alphabet.
VQPQRSW
Mathematics SPM22
WON TechniqueStep 3 : Write V in the first box.
VQPQRSW
Step 4 : Look at V in the diagram. Choose the slash alphabet
nearest to V. Write in the centre box. VQPQRSW
V
V Q
Mathematics SPM23
WON TechniqueStep 5 : Look at V in the diagram. Choose the non-slash alphabet nearest to V. Write in the last box.
VQPQRSW
VQW
V Q W
Mathematics SPM24
LATIHAN : (SPM Jun 2016)Diagram 4 shows a right pyramid with height 7cm. M is the midpoint of AB. Given AB = 4cm and BC = 6cm.
(a)On the diagram, draw the orthogonal projection of the line ME and the base ABCD.
(b) Calculate the angle between the line ME and the plane ABCD. (3 marks)
Mathematics SPM25
JAWAPAN : (SPM Jun 2016)
Mathematics SPM26
Question 7Gradient and Area under a Graph
[ 5 ~ 6 marks]
Mathematics SPM27
(I) Distance-time Graph(a) Find distance or period of time, when object
stationary
(b) Gradient = Speed = Rate of change of distance
(c) Average speed =
Mathematics SPM28
(II) Speed-time Graph(a) Find speed or period of time, when object at ‘uniform
speed’
(b) Gradient = Acceleration = Rate of change of speed
(c) Average speed =
* (d) Total distance travelled = Area under the graph
Mathematics SPM29
LATIHAN : (SPM Jun 2016)Diagram 9 shows a speed time-graph for the movement of two particles, A and B, for a period of 30 seconds. The graph PR represents the movement of particle A and the graph PQR represents the movement of particle B. Both particles start at the same point and move along the same route.
Diagram 9
Mathematics SPM30
Example 15 : (SPM Jun 2016)(a) State the uniform speed, in ms-1, of particle B.
(b) Calculate the rate of change of speed, in ms-2, of particle B.
12 ms-1
2
2124
12306012
ms
Particle A
Particle B
(6, 12)
(30, 0)
√ N1
√ K1
√ N1
Mathematics SPM31
Example 15 : (SPM Jun 2016)(c) Find the difference between the distance, in m, travelled by particle A and particle B for the period of 30 seconds.Distance travelled by particle A = Area under the
graph PR =
12
30
m180
123021
√ K1
Lakarkan bentuk geometri
Mathematics SPM32
Example 15 : (SPM Jun 2016)(c) Find the difference between the distance, in m, travelled by particle A and particle B for the period of 30 seconds.Distance travelled by particle B = Area under the
graph PQR =
12
30
m216
12)306(21
6
The difference = 216 – 180 = 36 m
√ K1√ N1
Lakarkan bentuk geometri
Mathematics SPM33
Question 8Solid Geometry ( Volume )
[ 4 marks]
Mathematics SPM34
Example 16 : (SPM Nov 2007)Diagram 6 shows a solid, formed by joining a cylinder to a right prism. Trapezium AFGB is the uniform cross-section of the prism. AB = BC = 9 cm. The height of the cylinder is 6 cm and its diameter is 7 cm.
Diagram 6
Calculate the volume, in cm3, of the solid.[Use ]7
22
9 cm
9 cm
6 cm 7
cm
Mathematics SPM35
Example 16 : (SPM Nov 2007)
(i) Volume of cylinder
231
627
722 2
2
hr(ii) Volume of prism
756
9812921
Ah
(iii) Volume of the solid = 231 + 756
= 987 cm3
√ K1
√ K1
√ N1
√ K1
Mathematics SPM36
LATIHAN : (SPM Jun 2016)A container contains 1386 cm3 of water. Then of the water is poured into the right prism container as shown in Diagram 3. Trapezium ABCD is the uniform cross section of the prism.
Find the depth, in cm, of the water. (3 marks)[Use ]
722
43
Mathematics SPM37
JAWAPAN : (SPM Jun 2016)
Mathematics SPM38
Question 10Matrices
[ 6 marks]
Mathematics SPM39
Inverse matrix
Let , then .
dcba
A
No Inverse matrix If a matrix has no inverse, then ad – bc = 0 .
ad – bc = 0
acbd
bcadA 11
Mathematics SPM40
LATIHAN: (SPM Jun 2016)
(a) It is given that is the inverse matrix of .
Find the value of p and of q.
;
q
p5
3
3547
p = 4 q = 7√
N1√ N1
Mathematics SPM41
Example 18 : (SPM Jun 2016)(b) Write the following simultaneous linear equations as a matrix form :
7x + 4y = 55x + 3y = 3
Hence, using matrix method, calculate the value of x and of y.
Answer :
43
37553453
35
7543
54371
35
3547
yx
yx
yx
yx
x = 3 , y = 4
√ K1
√ K1
√ N1
√ N1
Mathematics SPM42
Question 11Probability II[ 5 ~ 6 marks]
Mathematics SPM43
LATIHAN: (SPM Jun 2016)Diagram 11 shows two boxes, P and Q. Box P contains five tokens labelled with letter and box Q contains three tokens labelled with number. Two tokens are picked at random. The first token is picked from box P and the second token is picked from box Q.
Diagram 11
Mathematics SPM44
JAWAPAN: (SPM Jun 2016)(a) List all the elements in the sample space.
6 8 9K (K , 6) (K , 8) (K , 9)E (E , 6) (E , 8) (E , 9)L (L , 6) (L , 8) (L , 9)A (A , 6) (A , 8) (A , 9)H (H , 6) (H , 8) (H , 9)
n(S) = 15 √
P2
Mathematics SPM45
JAWAPAN: (SPM Jun 2016)(b) By listing down all the possible outcomes of the event, find the probability that (i) a token labelled with letter A and a token labelled with an even number are picked,
X = { (A, 6), (A, 8) }P(X) =
152
√ K1√ N1
6 8 9K (K , 6) (K , 8) (K , 9)E (E , 6) (E , 8) (E , 9)L (L , 6) (L , 8) (L , 9)A (A , 6) (A , 8) (A , 9)H (H , 6) (H , 8) (H , 9)
√
√
Mathematics SPM46
JAWAPAN: (SPM Jun 2016)(b) By listing down all the possible outcomes of the event, find the probability that (ii) a token labelled with a vowel or a token labelled with number 9 is picked.
6 8 9K (K , 6) (K , 8) (K , 9)E (E , 6) (E , 8) (E , 9)L (L , 6) (L , 8) (L , 9)A (A , 6) (A , 8) (A , 9)H (H , 6) (H , 8) (H , 9)
X = { (K, 9), (E, 6), (E, 8), (E, 9), (L, 9), (A, 6), (A, 8), (A, 9), (H, 9)}
P(X) = 159
√ K1√ N1
√ √ √ √ √
√ √
√ √
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