jawapan add. maths t4 kertas 1 [2010]

8/7/2019 JAWAPAN ADD. MATHS T4 KERTAS 1 [2010]

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3472/1Form 4Additional MathematicsPaper 12010

PEPERIKSAAN AKHIR TAHUN 2010

TINGKATAN 4

ADDITIONAL MATHEMATICS

Paper 1

MARKING SCHEME

This marking scheme consists of 6 printed pages


2/6

2

Number Solution and marking scheme Submarks Full marks

1

( a ) -1 x 2

( b ) One-to-one

1

12

2 a = 2

b = 4

1

1

2

3

( a ) k = 2

( b ) f 2 ( x ) =x

x

21

)2(3

, x

2

1

B1 : ff( x ) =

)2

3(2

3

x

1

2

3

4 k = -4

p = 12

B1 : 3 2 + 3 = p

1

23

5 X

3

- 3x -10 = 0

B1 : ( x + 2 ) ( x - 5 ) = 0

Or x2- ( -2 + 5 )x + (-2)(5) = 0

2 2


3/6


4/6

4

11. 3 + x y

3 3 3

3 3 3

3log 3 log log

log 27 log log

m n

m n

3

B2B1

3

12. X = 2

3 9x

3 (9) 3 (3) 54x x

3

B2

B1

3

13.

2

4 2

2

1

9

log 9 1

4 log 3 3

log 2 log 3 3

x

x

x

x

4

B3

B2

B14

14. y = 7x 15

6 = 7(3) + c

m = 7

3

B2

B1

3

15. t = -2 , 14

18 3t = 24

1(38 2 4 2)

2t t

4

B2

B1

4

16h =

4

k

h =4

2)6/1(3 h

g =6

k

k =4

36 kg

4

B3

B2

B1

4


5/6

5

17a) x = 96b) p = 26

5

96 p

= 14 @ 96 p = 70

1

2

B1

3

18a) 14

b) 6

214

8

1856

1

2

B1

3

19 a) m = 4

85

127

m

b) 16.8

285

404

2

B1

2

B1

4

20 a) = 1.2 rad

b) S = r = 5 [ 2 - 1.2 rad ]= 5 [ 5.084 ]= 25.4

1

1

1

3

21(a) = 0.6 rad

(b) 13

Arc of PR = 3

2

B1

2

B1

4

22(a) 39 cm

(b) 343.55

1

3

B2 4


6/6

6

or

B1

23 3x 6 2

B13

2420

20[ 5(1) 4 ]

20(5x4 )

3

B2

B1

3

25 -2 units s-1 3

B2

B1

3

jawapan add. maths t4 kertas 1 [2010]

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