add maths 3
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TRIAL SPM 2010TRANSCRIPT
mcis zurich spmrg - copy.indd 63 8/4/2010 5:33:29 PM
Bachelor of ACCOUNTINGwww.unirazak.edu.my
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mcis zurich spmrg - copy.indd 64 8/4/2010 5:33:30 PM
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mcis zurich spmrg - copy.indd 65 8/4/2010 5:33:31 PM
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mcis zurich spmrg - copy.indd 66 8/4/2010 5:33:32 PM
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mcis zurich spmrg - copy.indd 67 8/4/2010 5:33:32 PM
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mcis zurich spmrg - copy.indd 68 8/4/2010 5:33:33 PM
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mcis zurich spmrg - copy.indd 69 8/4/2010 5:33:33 PM
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mcis zurich spmrg - copy.indd 70 8/4/2010 5:33:34 PM
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mcis zurich spmrg - copy.indd 71 8/4/2010 5:33:34 PM
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mcis zurich spmrg - copy.indd 72 8/4/2010 5:33:35 PM
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mcis zurich spmrg - copy.indd 73 8/4/2010 5:33:35 PM
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SOALAN ULANGKAJI SPM 2010 305 SOALAN ULANGKAJI SPM 2010
JawapanAdditional Mathematics[3472/1] [3472/2]
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Additional Mathematics Paper 1(3472/1)
2
2
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306 SOALAN ULANGKAJI SPM 2010
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3 4
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SOALAN ULANGKAJI SPM 2010 307 SOALAN ULANGKAJI SPM 2010JA
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308 SOALAN ULANGKAJI SPM 2010
Additional Mathematics Paper 2(3472/2)
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b) 0 ≤ 4x (x-2) OR (2x - 5)(2x + 1) ≤ 0
x ≤ 0, x ≥ 2 OR 1 x 5 2 2
1 5 2 2
1M
1M
1M,1M
≤ ≤
≤ x ≤ 0 and 2 ≤ x ≤
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SOALAN ULANGKAJI SPM 2010 309 SOALAN ULANGKAJI SPM 2010JA
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ATH
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310 SOALAN ULANGKAJI SPM 2010
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3m
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SOALAN ULANGKAJI SPM 2010 311 SOALAN ULANGKAJI SPM 2010JA
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312 SOALAN ULANGKAJI SPM 2010
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SOALAN ULANGKAJI SPM 2010 313 SOALAN ULANGKAJI SPM 2010JA
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314 SOALAN ULANGKAJI SPM 2010
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1 m
0
0
5
5
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SOALAN ULANGKAJI SPM 2010 315 SOALAN ULANGKAJI SPM 2010JA
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x(4 - t2 ) dt = q 4t - r
use limit x or x Answer = 15.54 cm
t3
3 3
2 2
0
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316 SOALAN ULANGKAJI SPM 2010
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5 5
30
0
5 0
00
0
2x + 1.5y ≤ 3000
x ≥ y
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SOALAN ULANGKAJI SPM 2010 317 SOALAN ULANGKAJI SPM 2010JA
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2000
1800
1600
1400
1200
1000
800
600
400
2000 200 400 600 800 1000 1200 1400 1600 1800
(c) (i) 400 < x ≤ 1200
(ii) (500,300)50 2(500) + 1.5 (300) RM15
y
R
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