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7/31/2019 MY MATH PRESENTATION.pptx

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7/5/12 11

BELAJARBERKESANBELAJAR BIAR MENJADI

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7/5/12ANDA TIDAK SEHARUSNYA TERSIKSA…..

PERIKSA?

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PENGENALAN

BELAJAR ADALAH AKTIVITI SERIUSBELAJAR BERMAKSUD MEMAHASERTA MENGUASAI MAKLUMAT

BELAJAR PERLU DILAKUKANDENGAN SISTEMATIK DANBERTERUSANBELAJAR PERLUKAN KEJUJURAN

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FOKUS KITA ….

BELAJAR BIAR MENJAD

BELAJAR MESTI ADAKESAN

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ANDA BELAJAR ?

Apa biasanya andalakukan ?Apa bukti andabelajar ?Apa pula kesannya ?

› Boleh dilihat

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Larasan kerja

KESUSAHA ANDA

KERJA

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KEKALKAN KESIHATAN

TIDUR MESTI CUKUP ( 6 – 8 JAM ) JANGAN LUPAKAN RIADAH DANREHATPASTIKAN MAKAN MINUMBERKUALITI DAN MENCUKUPI

JAGA KESIHATAN F/M/E

1

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HADIRIKELAS

KELAS BIASA / TAMBAHANBERIKAN TUMPUAN SEMASAPENGAJARAN

GURU LEBIH TAHU DARIPADA ANDAPANDANG – LIHAT – DENGAR DANTANYA

PASTIKAN ANDA SENTIASA

2

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BELAJAR – TEKUN DANKONSISTEN

DISIPLINKAN DIRI ANDABELAJAR DI MANA-MANA SAJA

BELAJAR BERKUMPULANBIJAK URUS GUNA MASA

PASTIKAN ANDA DAPAT ‘ A

3

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KERJA SMART ~BERJURUSARAH

JANGAN BERTANGGUHSEDIAKAN PERANCANGANSUSUN AGENDA KERJAKERJA SAMPAI SEMPURNA

4

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BANYAKKAN LATIHANSENDIRI

ELAKAN BELAJAR SECARAMENGHAFAL

BUAT LEBIH DARI YANG DISURUHUJI TAHAP MAMPU TERIMAGUNAKAN LAPISAN MAKLUMAT

5

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LAPISAN MAKLUMAT

SUB TOPIK ISI KETERANGAN CONTOH TAMBAHA

1 2 3 4

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BELAJAR SECARABIJAK

BUAT PERSEDIAAN AWALSESUAIKAN MASA DENGAN JENISKERJA

ELAKKAN KEJEMUANGUNAKAN SEMUA SUMBER YANGADA

LAKUKAN AUDITAN HASILAN

6

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PERANCANGAN DANAGENDA

RANCANG AKTIVITI BELAJARANDATAHU APA AKAN DILAKUKAN -

OBJEKTIFTAHU CARA HENDAK BELAJARTETAPKAN MATLAMATSEMPURNAKAN

7

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7/5/12

DOA + USAHA = KEJAYAA

USAHA - MALAS =KEJAYAANRAJIN x MASA = KEJAYAA

MASA ÷ LATIHAN =KEJAYAAN

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STRATEGICANSWERING

QUESTION

MATHEMATICS

FadjilieMatsitumPAPER 1

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DIFFICULT TOUNDERSTAND

WHAT IS GIVEN

WHAT THEY NEED TO FIND

PAPE

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BASICMATHEMATIC

QUIZ1 9 + 5 = 13 6.7 X 6 =

2 9 – 5 = 14 18/6 X 4 =

3 9 X 4 = 15 ¾ X 20 =

4 9 ÷ 3 = 16 Proper fraction 3/7 =

5 9 – 4 + 3 = 17 Simplest form 6/24 =

6 15 + 8 ÷ 4 = 18 1 - 1/8 =

7 (8+4+3)/3 = 19 1 + 1/8 =8 7 X 100 = 20 11/7 = (Nbc)

9 6.7 X 100 = 21 1 2/3 = (PTW)

10 9/100 = 22 3/8 - 1/8 = =

11 7.6/100 23 3/8 + 1/8 = =

12 10 + 9.8 =

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24 1.5 l = ml 37 3 minutes = second

25 1.5 kg = g 38 5 minutes 5 second = second

26 1.5 km = m 39 10 % of RM 20 =

27 400 ml = l 40 1 - 80% =

28 400 g = kg 41 RM1 – 80 sen =RM

29 400 m = km 42 K=RM9 ,U=90sen,J=

30 50 cm = m 43 K=RM10,J=RM12,U=

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NUMBERS

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NUMBERS

1) 0.507 millions =

a) 57

b) 507c) 50700d) 507000

0 . 5 0 7__ __ __ __

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The sum of three numbers equals to 20.8.The first and the second number are 7.6 and

3 7/ 100. What is the third number?

A.16.27B. 13.2C. 10.67D. 10.13

3. 07

20.807.60

13.20

10. 13

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example

A. 3 5 – 8 B. 1 3 – 8

D. 1 – 4C. 5 – 8

1 3 _____

8=

= 5 – 8

2 – =3 – 413 – 8 2 – 3 – 413 – 8 X 2X 2

_______ 8 + 3 – 68

=

SOLUTION

– 6

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EXAMPLE

A. 3 7 – 9 B. 2 7 – 9

D. 7 – 9C. 1 7 – 9

2 9 – 9

– 2 – 9

=

= 1 7 – 9

3 – =2 – 91 3 – =2 – 91

1

SOLUTION

EXAMPLE

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EXAMPLES

A. 2 1 – 5 B. 1 1 – 5

D. 2 – 5C. 3 – 5 = 3 – 5

1 – =4 – 52 – 5

+ 2 – 4 _______ 5

=

1 – =4 – 52 – 5

SOLUTION

5

The information below shows the selling price of

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The information below shows the selling price of a television set.RM669

Aziz gets a profit of RM763 from the sale of 7 sets othe television. How much is the cost of each set?

A. RM 560 B. RM 658 C. RM 728 D. RM

= RM 109763

7

RM 669-RM 109

RM 560

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Example

The incomplete bill above showsthree types of items . How muchis the price for each eraser?

A. 30 sen B. 40 sen

C. 50 sen D. 60 sen

i. RM 7.60 x 4 = RM

ii. RM 30.40 + RM 4= RM 74.90

iii. RM RM 77.30 + R= RM 2.40

vi. RM 2.40 6= 40 sen

Soluti

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Example

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+23

12

50

100

2+ 50 % =3

B. 710

D.1 3

1C.

1 61

A.5

3

1

2

46

+ 3

176

16=

2

3 +

Example

The diagram shows the length of

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c) The diagram shows the length of rope

P,Q,R and S

16 cm

P Q R S

RS is 2 times the length of PQ . The lengthof QR is 39 cm more than PQ. The lengthof PQRS in cm is

A. 71B. 87C. 91

39+16=55 16+16=32

16+55+32= 103

WXYZ is a rectangle

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WXYZ is a rectangle.

The area of the shaded region isA. 51 B. 45 C. 36 D . 24

7cm

3cm

xW

y z

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a) X 3 x = 12 12 x

= 12 x 2 3 = 8

b) 12 X 8 = 96 + 12

= 108 cm 2

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Diagram shows a cube

What is the volume of the shaded region?.A. 700 B. 490 C. 300 D. 210

7 cm

10 cm

DATA HANDLING

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DATA HANDLINGThe pictograph below shows the number of bicycles sold byWong’s company in three month.

1. Each bicycle is sold for RM89. How much does Mr. Wong getsfrom the sold of all the bicycles for 3 months?

2. What is the average number of bicycles sold for 3 months?

MEI

JUN

JULAI

Each bicycle represents 15

a) 14 X 15 = 2b) 210 x RM = RM 18690

2. 210 : 3

DATA HANDLING

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DATA HANDLINGThe incomplete graph below shows the amountmoney saved in 4 months .

0

2

4

6

8

0

The average saving for 4 months isRM 550. What is the amount saved in the month

a) 500 + 400 + 600 = 1500b) 550 x RM 4 = 2200

c) RM 2200– RM 150= RM 700

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HIGH LEVEL QUESTIONS

A shop sold 630 blue and yellow T-shirts. The blue T-shirt sold are 124more than the yellow one. Find thenumber of the yellow T-shirts sold?

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IQ QUESTION

10 BANANA TREES ARE PLANTED INONE ROW. THE DISTANCE BETWEENEACH PLANT IS 5.8 m.WHAT IS THE DISTANCE FROM THEFIRST PLANT TO THE TENTH PLANT

QUESTION DEALING WITH

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QUESTION DEALING WITHCONCEPT

ZIANA BUYS SOME EGGS.SHE USED 20% OF THE EGGS TO MAKE

CAKES. SHE KEEPS 120 EGGS. HOW MANEGGS DID SHE BUY?

A. 140 B. 150 C. 480 D. 600

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UNITS

THE AVERAGE MASS OF 4 BOXES IS 62ONE OF THE BOXES WHICH WEIGHS 3IS TAKEN OUT OF THE GROUP.WHAT IS

THE AVERAGE MASS,OF THE BOXES INNOW?A. 0.715 B. 0.755 C. 7.15 D. 8.55

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MAThematic UPSR

PAPER 2

Solving problem in number

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1. 195 mango are dividedequally among 5 pupils . Howmany mango does each pupils

get ? 195 ÷ 5= 39

Solving problem in number

MIXED OPERATION

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A) 56 + 12 x 3 =

B) 76 9 x 5 =

C) 24 + 76 4 =

D) 88 56 8 =

E ) 236 x ( 12 + 8 ) =

92

31

43

81

4720

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TIMES

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1 WEEK = 7 DAYS1 YEAR = 12 MONTHS

1 DAY = 24 HOURS1 HOUR = 60 MINUTES

TIMES

B) Convert units in times

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5 x 12 =6060 + 7 = 67

8 x 7 =5656 + 5 = 61

i) x AND x …+a) 6 hours to minutesb) 6 hours 35 minutes to minutesc) 3 days to hoursd) 3 days 13 hours to hours

e) 5 years to monthsf) 5 years 7 months to monthsg) 8 weeks to daysh) 8 weeks 5 days to days.

6 x 60 = 360

360 +353 x 24 = 72

72 + 13 = 85

a)56 days to weeks and days

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b)43 months to years and months

c)85 hours to days and hours

d)145 minutes to hours and minutes

56 ÷ 7 = 8 weeks

43 ÷ 12 = 3 years 7 months

85 ÷ 24 = 3 days 13 hours

145 ÷ 60 = 2 hours 25minutes

TOPIC: TIMES

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Convert to 24 hours system.a) 4 .04 morning

b) 9 .25 night c)8 .40 a.m.

d) 10 .55 p.m

0404 hours

2125 hours

0840 hours

2255 hours

FRACTION

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FRACTIONe) State 4 to improper fraction.

f ) State 16/5 to mixednumbers

2

33X4+23

3 1/3

5 16-- 15

1

= 143

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EYa) Airis saves 30 sen everyday . How much does she save

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30 x 7 = 210 sen = RM 2.10

165 ÷ 3 = RM 55

93.70 - 58.50 = RM35 .20

for a week ?

b) RM165 is divided equally to Ahmed , Adlan dan Murat .How much will each of them get?

c)

RM58.50 RM93. 70The difference between the two amounts is

d)

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)

10sen

10sen

5sen20sen

RM1

50

sen

10

5

2

1

g)

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g)

80sen RM1.80Emelda bought 3 books and apiece of diskette . How muchshould Emelda pay ?

80x 3 = 240 sen = RM2.40 RM1.80RM4.20

+

Search the total amount for two items

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e) Food Price per kg

Crab RM12 .50meat RM8.00

Jeff buys 2 kg of crabs and 1 kg of

meat. What is the total amount that Jeff has to pay?12.50 x 2 = RM25.00

8.00

To search for the balance

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h) Murat has RM60 . He bought 4shirts for RM7.80 each . What is thebalance after paying for the 4 shirts ?

7.80 x 4 = RM31.20

RM60.00RM 31.20

RM 28 80

MONEY

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i)

Razi have RM50 . He bought 3 boxesof soap as shown above . How much isthe balance after paying?

BREEZZ

RM12.90

A) 12.90 x 3 = 38.70 B) RM 50.00

- 38.70

RM 11.30

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20 is the total amount for

three numbers . when 16 isadded , what is the average of the new number?

20 + 16 = 3636 ÷ 4 = 9

Th f h b i

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The average of three numbers is9 . When 21 is added, what is the

average of the new number?

9 + 9+ 9 + 21 = 4848 ÷ 4 = 12

@9 x 3 = 27+21 =4848 ÷ 4 = 12

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example

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solution

Find the percentage of theshaded region.

68 = 3

4X 100

= 75%

Table of length, mass ,volume,times and percentage

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p g

length Km 500 250 750

mass Kg 500 250 750

Volume of liquid Liter 500 250 750

percentage 100% 50 25 75

times hour 30 15 45

times year 6 3 9

12

14

34

LENGHT AND MASS

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1

a) 3 75 km x 4 =Give the answer in meter .

b) 2 47 kg 0 06 kg =Give the answer in gram.

2470 g- 60 g

15000 M

3750 M

X 4

2410 g

Length and volome

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1

c) 5 03 l + 0 65 l=

Give the answer in ml ?

d) 67 2 m 8 =Give the answer in cm ?

67.2 m ÷ 8 = 8.4 x 100

@

6720 ÷ 8 = 840 cm

5030

+ 650 5680 ml

b)

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The water is poured into 6 jars. Howmuch is the volume, in ml , for each

jar ?

4 32 l

4.32 l ÷ 6 = 0.72 l x 100

= 720 ml4320 ml ÷ 6 = 720

@

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EXAMPLE

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7 8 1

8 5 6

7 5

7 1

8.56 m – 75 cm = ____cm

SOLUTION

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ii) Mass in gram

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The cake above is divided equally

among5 pupils . What is the mass of thecake each pupil gets ?

250

500

750

0g

850 g

850g ÷ 5 = 170 g

iii) ESTIMATION IN MASSWhat is the best estimation of the

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0kg 1

234

What is the best estimation of themass in gram from the diagram

shown.

The answer between 1.25 kg to

1i) LENGHT

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2

3

4

The wire is divided equally into

3 . Find the length in mm of eachpart?

4 . 8 x 1 0 = 4 8 m m

48 mm ÷ 3 = 16 mm

SHAPE AND SPACE

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A)

SPHERE , CUBE , CUBOID, PYRAMID CONE AND CYLINDER

B)SQUARE, RECTANGLE, ISOSCELES

TRIANGLE, EQUILATERAL TRIANGLE TRIANGLE AND RIGHT-ANGLED

3 Dimensional

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Vertex Edges Flat face Curve Face

CUBOID 8 12 6 0

CUBE 8 12 6 0

CONE 1 1 1

SPERE 0 0 0

CYLINDER 0 2 2

PYRAMID 5 8 5

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12 cm

5 cm

5 cm + 12 cm + 5 cm + 12 cm = 34 cm

(5 cm + 12 cm ) x 2 = 34 cm

3 cm

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5 cm

12 cm

5 cm

12 + 3 = 15cm

5cm + 12cm + 5cm + 3cm + 10 cm + 15cm =

P IS Square and Q is equilateral triangle. What isth i t f h l di g ?

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the perimeter for whole diagram?

pQ

96cm

9 – 6 = 3cm

99966

+ 3

42 cm

Perimeter shaded region

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1) Perimeter shaded region

3cm

2

cm34 cm

3 x 6 = 18

2 x 8 = 16

x

P is a square. What is the perimeter of the shaderegion in cm?

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12 cm

P

5 cm

1297

55

+ 4

42 cm 12 – 5 = 7 cm

9 – 5 = 4cm

xx 5 cm

5 cm

3) Perimeter

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1) Perimeter for whole diagram is21

543

6

4cm

2

cm

36 cm

2 x 6 = 12

4 x 6 = 24

THANK YOU

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ALL THE BEST TO YOU." A " FOR MATHEMATICS

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