solaf 1 - skema pemarkahan math
TRANSCRIPT
SULIT 1449/1&21449/1&2MatematikKertas 1&2PeraturanPemarkahanApril 2011
JABATAN PELAJARAN PERAK
PROGRAM SOLAF
SIJIL PELAJARAN MALAYSIA 2011
MATEMATIK
SOLAF 1
Peraturan pemarkahan ini mengandungi 11 halaman.
[Lihat sebelah
1449/1 SULIT
Jumlah Markah =
SKEMA PEMARKAHAN SOLAF SET 1
MATHEMATICS PAPER 1
1449/1 SULIT
Question Answer
1 D
2 C
3 C
4 A
5 C
6 B
7 D
8 A
9 B
10 D
11 B
12 B
13 A
14 C
15 A
16 C
17 A
18 D
19 A
20 C
Question Answer
21 B
22 D
23 B
24 B
25 A
26 D
27 C
28 D
29 A
30 B
31 A
32 D
33 A
34 A
35 C
36 D
37 D
38 B
39 B
40 C
2
1449/2 SULIT
SKEMA PEMARKAHAN SOLAF SET 1
MATHEMATICS PAPER 2
Section A[ 52 marks ]
No Marking Scheme Marks
1
Straight dashed line x=9 drawn correctly.
Region shaded correctly.
1
2 3
2. 3 x2+10 x−8=0(3 x−2)( x+4 )=0
x=23
,−4
1
1
1, 1 4
3. 3 m−n=18−3 n=9n=−3m=5
1
1
1
14
3
No Marking Scheme Marks
4. (a) ÐEBA
(b) tan ÐEBA =
125
ÐEBA = 67.38 or 67o23’
1
1
1 3
5.(a) False
(b) Converse : If the square of the number is positive, then the number is a negative number. ( False )
(c) PQRS is a square.
1
1 , 1
1 4
6.
(a)
m=7−32−6
m=−1
(b) mAZB = mXY = −1
−2 = (−1)(−3)+c OR y−(−2)=−1 [ x−(−3 ) ]
y=− x−5
(c) x−intercept ; y=0
− x −5 = 0
x = − 5
1
1
1
1
1
1
6
7.
(a)(2 −13 −4 )
−1
= 1(2)(−4 )−(3)(−1 )(−4 1
−3 2 )
=
1−5 (−4 1
−3 2 )=
1−d ( e 1
−3 2 )
d = 5 ; e = −4
1 , 1
4
No Marking Scheme Marks
(b)(2 −13 −4 )(x
y )=(119 )
(xy)= 1
−5 (−4 1−3 2 )(11
9 )
(x
y)= (73 )
x = 7
y = 3
1
1
1
1 6
8.
227
×7×7×15
13×22
7×7×7×6
227
×7×7×15 −
13×22
7×7×7×6
2002
1
1
1
1 4
9.
(a)(i) P( J )=4000
16500
=
833
(ii) P(US )=4500
16500
=
311
(b) Number of tourist of Japan =
833
×33000
1
1
1
1
1
1 6
5
No Marking Scheme Marks
= 8 000
10.
(a)
12×14×14
OR
90360
×227
×21×21
90360
×227
×21×21 −
12×14×14
248.5
(b)
60360
×2×227
×14 OR
90360
×2×227
×21
14 +
60360
×2×227
×14 + 7 +
90360
×2×227
×21 + 21
89.67
1
1
1
1
1
1
6
11.(a) Gradient of RS = - 2
Equation of PQ,
5=−2 (3 )+c
y = - 2x + 11
(b) y – intercept = 11
(c) 0=−2x+11
x-intercept =
112
1
1
1
1
1
1 6
6
No Marking Scheme Marks
Section B [ 48 marks ]
12.(a) y = 13 , 8
(b)
(c) (i) 5 .3≤ y≤5 .7
(ii) x = −2.8, 0, 2.8
(d) Identify equation of y = −2x + 4
Straight line y = −2x + 4 correctly drawn
1, 1
1
1
1
1
x
y
-3 -2 -1 1 2 3
-4
-2
0
2
4
6
8
10
12
14
7
No Marking Scheme Marks
x = 2.4, 0.2, −2.5
Note : Awarded 1 mark for any two correct values.2 12
13.(a) (i) (-3,5)
(ii) (1,5), (-3,3)
(b) (i) M is an enlargement with scale factor 2 at the centre (3,0)
(ii) N is a rotation of 180⁰ about the centre (2,4)
(c) (i)
12
(ii) Area of JKLM = ( 12
)2 x 112
= 28 m2
1
1 , 1
3
3
1
1
1 12
14. (a)Class Interval Midpoint Frequency
15 - 19 17 3
20 - 24 22 5
25 - 29 27 7
30 - 34 32 9
35 - 39 37 7
40 - 44 42 6
45 - 49 47 3
(b) Mean =
3(17 )+5 (22)+7(27 )+9 (32 )+7(37 )+6( 42)+3( 47)3+5+7+9+7+6+3
= 32.25
3
2
1
8
No Marking Scheme Marks
(c)
524742373227221712
9
8
7
6
5
4
3
2
1
0
Payment (RM)
frequency
(d) Number of drivers who paid more than RM34 = 16
5
1
12
15. (a) 47
(b)
Mass (kg) Frequency MidpointUpper
boundary
20 – 29 0 24.5 29.530 – 39 12 34.5 39.5
1
1
9
No Marking Scheme Marks
40 – 49 15 44.5 49.550 – 59 9 54.5 59.560 – 69 8 64.5 69.570 – 79 6 74.5 79.5
(c) (i) 40 – 49
(ii) Mean =12(34 .5 )+15(44 . 5 )+9(54 . 5)+8 (64 .5 )+6(74 .5 )50
= 50.7
(d)
Note: Axes drawn in the correct directions with uniform scales. Upper boundaries/ midpoints/ class intervals correctly used for x-axis
All rectangular with equal width drawn correctly.
1
1
1
2
1
1
1
2 12
16. (a) y = 6 , –8
(b) Axes drawn in the correct directions with uniform scales.
1, 1
1
10
No Marking Scheme Marks
All 8 points and *2 points correctly plotted or curve passes through
all the points. ( 8 or 9 points correctly plotted award 1 mark).
2 smooth and continuous curve without any straight line passes
through all 10 correct points using the given scales.
(c) (i) y = –3.4
(ii) x = –1.2
(d) Identify equation of y=−3 x+1
Straight line y=−3 x+1 correctly drawn
x = −1.8, 2.2
1
1, 1
1
1
1
1
1, 1
12
11
Disediakan oleh:Panel Penggubal SOLAF1 JPNTahun 2011
12