com selangor stpm trial 20111 maths t
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8/2/2019 com Selangor STPM Trial 20111 Maths T
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PEPERIKSAAN PERCUBAAN STPM PEPERIKSAAN PERCUBAAN STPM PEPERIKSAAN PERCUBAAN
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PEP. 95011, 95411 'PM PEPERIKsAANPE! STPM (Tr1"al) 2011 INPEP. 'PM PEPERIKSAAN PE! IN
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PEPER!KSAAN PERCUBAAN STPM PEPERIKSAAN PERCUBAAN STPM PEPERIKSAAN PERCUBAAN
PEPERIKSAAN PERCUBAAN STP! pAPER 1 N STPM PEPERIKSAAN PERCUBAAN
PEPERIKSAAN PERCUBAAN STPJ.,, ~ ' ~ " ~ ' " " . , ~ . - ~ ~ - , , , N STPM PEPERIKSAAN PERCUBAAN
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PEPERIKSAAN PERCUBAAN S Three hours {STPM PEPERIKSAAN PERCUBAAN
PEPERIKSAAN PERCUBAAN S { STPM PEPER!KSAAN PERCUBAAN
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PEPERIKSAANPERCUBAAN
SIJIL TINGGI PERSEKOLAHAN MALAYSIA
NEGERI SEMBILAN DARUL KHUSUS 2011
Instruction to candidates:
DO NOT OPEN THIS QUESTION PAPER UNTIL YOU ARE TOLD TO DO SO.
Answer all questions. Answer may be written in either English or Bahasa Malaysia.All necessary working should be shown clearly.
Non-exact numerical answer may be given correct to three significant figures, or one decimal
place in the case of angles in degrees, unless a different level of accuracy is specified in the
question.
Mathematical tables, list of mathematical formulae and graph paper are provided.
Arahan kepada calon:
JANGAN BUKA KERTAS SO ALAN INI SEHINGGA ANDA DIBENARKAN
BERBUAT DEMIKIAN.
Jawab semua soalan. Jawapan boleh ditulis dalam Bahasa Inggeris atau Bahasa Malaysia.Semua kerja yang perlu hendaklah ditunjukkan denganjelas.
Jawapan berangka tak tepat boleh diberikan betul sehingga tiga angka bererti, atau satu
tempat perpuluhan dalam kes sudut dalam darjah, kecuali aras kejituan yang lain ditentukan
dalam soalan.
Sifir matematik, senarai rum us matematik, dan kertas graf dibekalkan.
This question paper consists of 3 printed pages.
(Kertas soalan ini terdiri daripada 3 halaman)
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CONFIDENTIAL */SULJT* 2
I Ex2 - 3x . . I fi .
. xpress m partm ractiOns. [5 marks]x2
-2x+1
5 2
2. By using the substitution x = I + u, find the exact value ofJ( x ~ 1)2 dx.
3. If lzl; .J5, find the modulus of z + ~ , where z' is the complex conjugate ofz.z
[5 marks]
[6 marks]
4. Given the polynomial f{x) ; x4
- 3x3 + kx
2 + 15x + 50, where k is a constant and that
(x - 5) is a factor of f(x). Find the value of k and hence factorise f(x) completely into
exact linear factors. [6 marks]
5. Use the binomial theorem to expand J4 + x as a series of ascending powers of x up to1 - X
and including the term in x2
Find the set of values of x such that the expansion is valid.
[7 marks]
6. Given that function J(x) = 2 •{ll+xl, if x :S 0
x , i f x>O
(a) Sketch the graph ofy = f(x). State the range of f(x).
(b) Hence, find the set ofvalues ofx for which f (x)- I ::: 0 . [7 marks]
7. Find the set of values of x which satisfies ~ + I ::: 4 - _ I _ .x 2 -x
[7 marks]
8. Given that matrices A= and B = r ~ ~ 4 2 1 0
0 5 J1 -7 .
2 -1
(a) Show that A is a non-singular matrix.
(b) Find matrix AB and deduce A- 1•
(c) Given matrix C = ( ~ J , find matrix X in terms ofn ifAX= C. [9 marks]
STPM 950/1, 954/1 Turn over [Lihat Sebelah)
This question paper is CONFIDENTIAL until the examination is over CONFIDENTIAL*
Kertas soalan ini SULIT sehingga peperiksaan kertsa ini tarnal SULIT*
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CONFIDENTIAL */SUL!T* 3
9. A circle touches the straight line 4y =3x- 8 at the point P(4, 1) and passes through
another point Q(5, 3). Find the equation of the circle and show that it touches the y-axis.
(10 marks]
I 0. Find the coordinates of the stationary points on the curve y = e-'x'
nature. Sketch the curve.
and determine their
[11 marks]
2
II. Sketch on the same coordinate axes, the curve y = 2x 2 and the ellipse x2 +L = 1.9
(a) Calculate the area of the region bounded by the curve y =2x2
and the line y = 1..:'..2
(b) Find the volume of the solid formed when the region bounded by the curve and the
ellipse is rotated through 180° about they-axis. [12 marks]
12. (a) Express ( X ) n partial fractions. Hence, obtain an expression for3k- 2 3k+ 1
n 1 .sn = "" X ) and find 11m sn.
L... 3k-2 3k+1 n->®k=1(8 marks]
(b) Find the least value ofn for which the sum of the first n terms ofthe geometric series
I+ 0.75 + (0.75/+ (0.75)3+ .. .
is greater than ~ o f its sum to infinity. [7 marks]4
STPM 950/1, 954/1 Turn over [Lihat Sebelah)
This question paper is CONFIDENTIAL until the examination is over CONFIDENTIAL*
Kertas soalan ini SULIT sehingga peperiksaan ke1tsa ini tamat SULIT*
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Skema Pemarkahan Mathematics T 1/S l Pepcriksaan Percubaan STP:Vl 2011
x 2- 3x . . .
l. Express m parllal fracttons. [5 marks]
x2 -2x+1
x2 -3x x+1---- . :1
x2
-2x+1 . x2 -2x+1Ml
X +1 A 8
Let (x -1Xx -1)"' x- 1 + (x -1)281
x+ l =A (x - l ) +B Ml
X = 1, B = 2; X= 0, A = I Ml
x2
-3x "' 1__
_x2 -2x+1 x-1
2 AI(x -1)2
5 2
2. By using the substitution x = 1 + u, find the exact value of f. ~ , - d x . ' (x- '
x = 1+ u, u = x - 1, du = dx,
X = 2, ll = ] ; X = 5, ll 4
[,,
= 4 - + 21n u u,
Bl
Ml
= 4[(- 21n4 +4)- (- 1 + 21111+ :)l= 15+161n7.
AI
I\11
AI
[5]
[5 marks]
[5]
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2
3. If jz[= 15. find the modulus u t ' z + ~ , where z' is the complex conjugate ofz.z
[6marks]
Let z =a+ bi
/zl = .Ja':b2 151 . 1
z + = a + b1 +---z' a -bi
. a +bi=a+bi+--
a2 + b 2
= a+ bi + -1
(a+ bi)5
= El_(a + bi)
5
Bl
Ml
Ml
AI
Ml
Al [6]
4. Given the polynomial f(x) = x4
- Jx3
+ kx2
+ 15x + 50, where k is a constant and that
(x -· 5) is a factor of f(x). Find the value of k and hence facto rise f(x) completely into
exact linear factors. [6 marks]
f(5)=0 :=:, (5)4. J , s / + k(5)
2 + 15(5) +50= o:::;> k=-15
f(-2) = (-2)4
-3(-2)3
- 15(-2/ + 15(-2) +50= 0
:. x + 2 io a factor of f(x)
f(x) = (x + 2) (x - 5)(x2
- 5)
•= (x + 2) (x - 5)(x - --/S)(x + -iS)
MlAI
Ml
AI
MlAI [6]
5 Use the binomid theorem to expand ~ L \ + x as a series of ascending powers of x up· 1-x
to and including the term in x2
. Find the set of values of x such that the expansion isvalid. [7 marks]
1
(4+x)l =2(1+)(l)z\ 4
1 r ~ y _ q ]= i , + i ( ~ } i ' l ; : _ 2 2 ( ~ r + ..
I .L
Ml
1
+ - X ~ ~ - X2 -i . A!
64
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3
M1
A1
M1
5 55 2" '2+-X+-X AI
4 64
. . Set of values of x for the expansion to be valid is { x: -I < x < I} A I [7]
( ){
11 + xj, if x :<:: 06.
Given that functionf x
= , .x- , zf x > 0
(a) Sketch the graph ofy = J(x). State the range of f(x).
(h) Hence, find the set of values ofx forwhichf(x)-1?: 0. [7 marks]
(., \")
y
y = [1 + x[D1 y =[ I+ x[
y =_L_ __ -----].
D 1 all correct
Range off= {y: y 2': 0) Bl
f(x)-1::>0 =:>f(x)::>1
Solving y = I andy= -(x + I) =:>X= -2 M1
. 'So!vmg y = I and y = x- => X= 1 Ml
Tl'" set of values of x. is {x: x:::; -2 or x ::> 1 or x = 0) AI [Tj
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4
7. Find the set of values of x which satisfles2 +I:: 4- _I
2(2- x) + x - 3x(2- x) >0
x(2- x)
3x2
- 7x + 4 ;::0
x(2- x)
(3x- 4)(x- 1) > 0x(2- x) -
0 + I - 4 +
3
x 2-x
Ml
Ml
Ml
Ml
X
2 - Ml
The solution set is { x: 0 < x S I or i > x < 2} AI
[7 marks]
AI [7]
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5
8. Given that matrices A= [ ! and B = [
(a) Show that A is a non-singular matrix.
(b) Find matrix AB and deduce A_,.
(c) Given matrix C = [ l ind matrix X in terms of n if AX = C.
(a) de tA=J ( l - 6 ) - 2 (2 -12 )+ 1 (4 -4 )=5 Ml
Since IAI i ' 0, :. A is a non-singular matrix. AI
~ ] [ ~ ~ 2 I 0 2
-1 0 11 7
= 25 5
02 1-5 5
( c )X=k1
C
-1 0 11 72 -- l ~ l
02--n51-n5
52--5
51
5
5 j rs a oJ-7 = lo s o- ] 0 0 5
Ml
Ml
AI
Ml
Ml
AI
AI
[9 marks]
[9]
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7
I0. Find the coordinates of the stationary points on the curve y = e-' x' and determine
their nature. Sketch the curve. [I I marks]
dy 2 -X -X 2- = xe - e xdx
=xe-x(z-x)
Let dy = 0, xe -x (2- x) = 0dx
x = 0 or x = 2
MI
MI
4y= 0 or y= - MI
e '
:. the stationary points are (0, 0) and (2, 4) A Ie
d'y = e-x(2- 2x)- e-x(zx- x2 ) MIdx2
= e·x(2- 4x + x2)
X= 0 _c:i_'y - 2 > 0' dx 2 -
d2 y 2x=2, --=--" <0 MI
dx 2e"
:. (0, 0) is a minimum point and (2, ~ - ) is a maximum point.Y e
X -7
+oo, y -7 0
tX -7 - W, y -7 + W
AI AI
DI (shape)
01 (critical points)
(2, 4/e2) D 1 (all correct)
---4-L.________· ~ = - - - = - - o _ ; , , X [II]·)I
l I
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8
"ll . Sketch on the same coordinate axes, the curve y = 2x 2 and the ellipse x2 + y_·_ = 1.
9
(a) Calculate the area of the region bounded by the curve y = 2x 2 and the line y = 11_2
(b) find the volume of the solid formed when the region bounded by the curve and
the ellipse is rotated through 180° about the y-axis. [12 marks]
y2 4x 4 .[3 3
X +-=1=>X=±--=>y=-9 2 2
Ml AI
D I (parabola)
Dl(ellipse)
-1
1-
(a) y'X=-123 1 1 1
Area =f 12 y2 jdy Ml
3
2 [2 T Ml- -Y '12 30
4(3[3_ \=12 22 --
0J Ml
=13 AI
3
(b) Volume= fn(±y fY + H ~ - ~ - } y Ml
2
3 J3' ' r Y3'Ml[-ny] +l{y---1
4 , L 21; "2
[( 9 , r 3 ( 3 r Jl--0 +l3-1- -+ i ·:.:· +2716 j 2 \ .L ;
MJ
19AI ['-1 t [ Lj
16
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9
112. (a) Express (:lk-=2X:Jk +
1) in partial fractions. Hence, obtain an expressron for
" 1 .s, =L( X ) and find lrm S,. [8 marks]k=l 3k - 2 3k + 1 HW '
(b) Find the least value of n for which the sum of the first n terms of the geometric
series
1+ 0.75 + (0.75)2
+ (0.75i + ...
is greater than 2of its sum to infinity.4
1 A B
(a) Let (3k-2X3k+1) 3k-2 + 3k+1
=> I = A(Jk + J) + B(Jk- 2)
1 1 1
(3k- 2XJk + 1) = 3(3k- 21 3(3k + 11
" 1
s. =6 3k- 2X3k + 1)
"1[ 1 1 J=6 3k - 2 - 3k + 1
M1
Ml
Al
Ml
= _311(1--41)+ (-41- _71) +-71 - 11o) + ...(-1-- ~ _ 1 _ __ ) + ( ~ L ____1 _ ~ 3n .. 5 3n - 2) 3n -· 2 3n + 1 /
= H- 3 n ~ 1 J = 3nn+1lim S =im[·!J1--
1 ) ] = ~ n--+w n n--+aJ 3l 3n + 1 3
(b) S = 1(1-0.75") Ml
" 1- 0. 75
1- 0.75"
0.25
a 1s =-=-w 1 - r 1-0.75
= ~ 1 ~ = 4 0.25
s. > ~ ( 4 ) => 1-0.75"
0.25
AI
Ml
Al
>3
=> 1- 0.75" > 0.75
=> 0.75" < 0.25
n > 4.819
The least value ofn is 5.
AI
Ml A I
M1
Ml
AI
[7 marks]
Ml
[8]
[7]
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