JABATAN PENDIDIKAN NEGERI PERAK

MOCK TEST 1SIJIL PELAJARAN MALAYSIA (SPM)

KIMIATINGKATAN 5

MARKING SCHEME

SKEMA PEMARKAHAN

SULIT 2 4541

No Explanation Mark ∑ mark1 (a) (i) Able to state the energy conversion

AnswerChemical Electrical 1 1

(ii) Able to state the negative terminal & reasonAnswer(1) Magnesium / Mg (2) Magnesium / Mg is more electropositive // higher

position in Electrochemical Series // higher tendency to release electron

1 1 2

(iii) Able to write the half equationAnswerMg Mg2 + + 2e 1 1

(iv) Able to state the observationSample answerBrown solid deposited // copper electrode becomes thicker

1 1

(b) (i) Able to state the ions presentAnswerCl -, OH – // chloride ion, hydroxide ion 1 1

(ii) Able to name gas Y collectedAnswerChlorine 1 1

(iii) Able to calculate the mass of gas collected

1. No. of mole of gas = 12 / 24 000 // 0.0005 2. Mass of gas = 0.0005 x 71 g // 0.0355 g

11 2

Total 9

Skema-Mock Test 1 – Kimia SPM

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SULIT 3 4541

No Explanation Mark ∑ mark2 (a) (i) C4H8 1 1

(ii)

Choose : 2 structural formula

without name

1

1

1

Maks 2

(b) (1) Butene is an unsaturated hydrocarbon/ has double bond between carbon atoms(2) Butane is a saturated hydrocarbon/ has single bond

1

1 2

(c) C4H8 + H2 C4H10

- correct reactants and products1 1

(d)

- Functional diagram- Labelled diagram 1

1 2

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Glass wool soaked in butanol

SULIT 4 4541

(e) Percentage of carbon by mass in hexane, C6H14

= 6(12) x 100% 6(12) + 14(1)

= 83.72%

Percentage of carbon by mass in hexene, C6H12

= 6(12) x 100% 6(12) + 12(1)

= 85.71%

Hexene contains higher percentage of carbon by mass than hexane//Hexene burnt in air produces more soot compared to hexane.

1

1

1 3

Total 11

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SULIT 5 4541

No Explanation Mark ∑ mark

3 (a) (i) Soluble salts – sodium chlorideInsoluble salt – lead (II) sulphate*Note – accept any correct soluble and insoluble salt.

11

4

(ii) Pb(NO3)2 + Na2SO4 PbSO4 + 2NaNO3

- correct reactants and products-balanced equation

11

(b) 1. Add 10 cm3 of distilled water into the beaker containing 1 spatula of magnesium nitrate crystal and stir.

2. Pour 2cm3 of magnesium nitrate solution into a test tube

3. Add 2cm3 of sulphuric acid 1.0 moldm-3 into the test tube

4. Add 2cm3 of freshly prepared of iron(II) sulphate solution 1.0moldm-3 into the test tube

5. Add a few drop of concentrated sulphuric acid into the slanted test tube.

6. Brown ring is observed.

1

1

1

1

1

1 6(c) Procedures:

1. Measure and pour 50cm3 of zinc sulphate solution 1.0 moldm-3 into a beaker

2. Measure and add 50cm3 of sodium carbonate solution 1.0 moldm-3 into the beaker

3. Stir the mixture, filter and wash the residue4. Measure 50cm3 of nitric acid 2.0 moldm-3 into

another beaker (and warm the acid)5. Add zinc carbonate formed (from Pt 1 – 3) bit by

bit into the acid until in excess.6. Stir the mixture and filter 7. Heat up the filtrate in an evaporating dish until

one-third of original volume left and cool the solution

8. Dry the zinc nitrate salt formed between two filter papers.

Chemical equtions:9. ZnSO4 + Na2CO3 ZnCO3 + Na2SO4

10. ZnCO3 + 2HNO3 Zn(NO3)2 + CO2 + H2O

1

1

11

1

11

1

11 10Total 20

~END OF MARKING SCHEME~

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