asam borat

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Penentuan kelarutan dan ∆H H 2 C 2 O 4 Pada suhu 27°C = 300,15 K V 1 .N 1 = V 2 .N 2 4,25 mL.1,11 N = 10 mL. N 2 N 2 = 4,175 N 10 N 2 = 0,4715 N M 2 = 0,4715 2 = 0,2358 M S = M = 0,2358 M T1 = 40°C + 273,15 = 313,15 K T2 = 27°C = 273,15 = 300,15 K ∆H = log | S 2 S 1 | 2,303 R + T 2T 1 T 2. T 1 = log | 0,2358 0,23581 | 2,303x8,314 + 300,15313,15 300,15 x 313,15 = log 0,3085x 19,1471 – 0,000138 = -9,7794 J/mol Pada suhu 37°C = 310,15 K V 1 .N 1 = V 2 .N 2 5 mL.1,11 N = 10 mL. N 2 N 2 = 5,55N 10 N 2 = 0,555 N

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asam borat

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Penentuan kelarutan dan H H2C2O4Pada suhu 27C = 300,15 KV1.N1 = V2.N24,25 mL.1,11 N = 10 mL. N2N2 = N2 = 0,4715 NM2 = = 0,2358 MS = M = 0,2358 M

T1 = 40C + 273,15 = 313,15 KT2 = 27C = 273,15 = 300,15 KH = log || 2,303 R + = log || 2,303x8,314 + = log 0,3085x 19,1471 0,000138 = -9,7794 J/mol

Pada suhu 37C = 310,15 KV1.N1 = V2.N25 mL.1,11 N = 10 mL. N2N2 = N2 = 0,555 NM2 = = 0,2775 MS = M = 0,2775 M

T1 = 40C + 273,15 = 313,15 KT2 = 37C + 273,15 = 310,15 KH = log || 2,303 R + = log || 2,303x8,314 + = log 0,3840x 19,1471 0,0000308 = -7,975 J/mol