1.panduan menjawab biologyspm, 2009
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PERKONGSIAN ILMU
(Latihan dalam perkhidmatan) 2009
RADZIAH BINTI MOHD YAMIN
GURU CEMERLANG SAINS
SMK BUKIT SAUJANA PORT DICKSON
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Program Kecemerlangan
BIOLOGY SPM 2009
BIOLOGY WORKSHOP
Paper 2 (4551/2)
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EXAM FORMAT FOR SPM BIOLOGYDURATION
OF TIME
FORMAT OF PAPER TOTALITEM
MARKs %
1 Section A : Simple Multiple Choice Qn 25(1 h) Section B : Moderately difficult MCQ 15 50 25
Section C : Difficult MCQ 10
2 Sec. A : Compulsory structured item 5 60
(21/2h) Sec. B : Limited response item [Essay] 1/2 20 50: Open-response item [Essay] 1/2 20
3 Structured Item 1 33
(11/2h) Open-response item 1 17 25
4 PEKA & Persijilan - - -
100
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Paper 2 (4551/2)
Section A ( 5 structure questions )
*answer all
*score : 60Section B
(4 essay questions)
*answer any two*score : 40
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Biology ..
Understanding not memorising
Biological concepts are related , not
stand aloneMore exercise to get use the different
type of questions
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Test your understanding
Detect your weakness
Get use the exam format
Acquire answering skill
Practice makes perfect
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Use mind mapping / concept mapping to:
Prepare short notes
Recall back
To fast revision
Link up concept
See whole concepts
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1) Stimuli (S) :
Diagrams, Tables, Graphs, Statements
2) Command words (C):
Draw.., Describe.., Explain, Justify why, Differentiate,
Complete., What conclusion, Compare, Define,Statethe meaning.., Discuss , Suggest.., Estimate
3) Task (T) :
Statements to be written as responses to the items// Concept
4) Marks (M) :
Shows how many points must be written.
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Sample Question to identify . S-C-T-M
Example 2 (SPM 2004 / Paper 2 / Section A / No 3d) :
Blood Vessel Volume / cm3 Pressure /kPa
X 100 13.3
Y 300 0.3
d (i) Based on the table 3.2, What conclusion can you make about
the rate of blood flow in the blood vessels X and Y?
Explain your answer. [2 marks]
S : C : . T : . M : ..
Table 3.2
F : The rate of blood flow in the blood vessels X / aorta is higher than
blood vessels Y / vena cava.E 1 : X/ aorta carried blood with high pressure from heart whereas Y /
vena cava carried blood with low pressure from body cell / tissue
E 2 : Lumen size of X / aorta is smaller than lumen size of vena cava/Y
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Name..
Require thespecific
answer.Example:
Nameone
organ wherecell Q is found Cell Q
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The answer is ..
Gonad
Reproductive organ Testes
ovary
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Diagram 3.1 shows three stages of mitosis, P, Q and R, in an animalcell.
Name the stages P, Q and R in the spaces provided in Diagram 3.1.
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Diagram 3.1 shows three stages of mitosis, P, Q and R, in an animalcell.
Name the stages P, Q and R in the spaces provided in Diagram 3.1.
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State.
More general..
Example :
State thefunction of
organelle S S
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The answer
To generate energy
To generate cellularrespiration
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State the chromosome behavior at the following stages.Stage PStage R
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DRAW..
Constructa pyramid of.
Sketch a diagram..
Draw a cross section of
Illustrate the above
statements .
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Using the information in figure 6,
construct a pyramid of energy for
that ecosystem.
FIGURE 6
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The answermust start withProducer
carnivore
herbivore
ProducerProducer 6 x104 kJ
Herbivore
5x103kJ
Carnivore30 kJ
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Grasshopper, Paddy plant, Caterpillar ,Frog , Owl , Snake , Rat
Based on the above organisms ,construct :
A food web showing theinteraction of all organisms
A pyramid of numbers consisting
of four trophic levels
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Sketchadiagram to show the movement ofthe substance across plasma membrane byosmosis
Things to be considered :
Plasma membrane, water, sucrose
An arrow to show direction ofmovement
Size of water and sucrose molecules
Number of water and sucrosemolecules
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Suggested diagram
Early situation
Final situation
Plasmamembrane
Watermolecule
Sucrose molecule
19 8
15 15
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In the space below, draw a sectionthrough the ovule, showing all cells inS. label the cells involved infertilization.
S : embryo sac
Able to draw the cellsand show thepositions of 8 nucleus
Label polar cells and
egg cells
S
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Diagram
Polar cellsEgg cell
*Labelling for diagrammust have connectinglines
Di 5 h h l i f ifi
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Diagram 5 shows the regulation of specifichormones towards the development in theovary
Indiagram5, draw
thechangethatoccurs tostructureT on 26thday.
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Q
R
S
T
U
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Diagram shows the human blood circulatory system
Mark the following
flow of blood toillustrate thecirculations R and S:
Oxygenated bloodwith arrow
Deoxygenated
blood with thearrow
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Complete Diagram 4.2 to show a DNA molecule.
Part of one of the nucleotide chains has beendrawn.
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P Q
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Cross diagram..
Parental phenotype Parental genotype
Key
Gamete formation Meiosis
Fertilization
Offspring genotype
Offspring phenotype
Phenotype ratio
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Mendel`s First Law : A characteristicof an organism is determined by a pair
of genes located at the same locus of apair of homologous chromosomes.Only one of the pair of genes can be
present in a gamete
Illustrate the above statements usingthe following cross :
female x male
Parent black mouse black mouse
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Cross DiagramKey :
B : black mouse , dominant alleleb : white, recessive allele
parental phenotype : black x black
parental genotype : Bb
Bb
gamete : B b B b
Fertilization :
meiosis
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Offspring genotype BB Bb Bb bb
Offspring phenotype black, black, black, white
Phenotype ratio 3 black : 1 white
Phenotype ratio 3 : 1
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Correct and Complete the Cross Diagram
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Difference
State aspects for bothsubject
Use or relate the twosubject with the sameaspect with but /
meanwhile / where as
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State one difference between lymphand the blood
Subject : LYMPH vs BLOOD
Aspect : COMPONENT in both fluids
Suggested Answer :
Lymph has no red blood cells but blood hasred blood cells
//
Lymph has no plasma protein meanwhileblood has plasma protein.
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Comparetwo structures
Similarity and differences Examples :
Compare two structuresof a afferent neurone anda efferent neurone .
1. .2.
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afferent
efferent
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Location of cell body = aspectafferent n efferent = subject
1. Similarity :
Both neurones have myelin
sheath, cell body, and dendrite
2. Difference :
Location of Cell body of Afferent
neurone is at the side of the cell
but cell body of efferent neurone is
at the end of the cell.
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Explain ..
Facts (F) = the mainpoint from the question
Explanation (E) = why /reason based on the ourbiology knowledge
. Relate F and E byusing because / for / that
is / to.. Explain how leaves are adapted to be
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Explain how leaves are adapted to beefficient at absorbing carbon dioxide from theatmosphere.
Adaptation
Structure /feature
function
they have(structure).
To (function).
at absorbingcarbon dioxide
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answer
(F)Has many
stomata
(P) Allowing theexchange of
gases betweenthe internalpart of leaf
and theenvironment.
(F) Spongy
mesophyll arelooselyarranged
betweeneach cell are air
space
(P) Allow easydiffusion ofcarbon dioxide
through leaf
Figure 10 shows a plant cell immersed in
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Figure 10 shows a plant cell immersed indifferent concentrations of sucrosesolution
Explainwhat
happen tothe cell in
situation 2
21
3
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F = what happen to the cell inthe diagram
E1 : state the different
osmotic concentrationsbetween internal and external ofthe cell
E2 : state the correct directionof water movement byosmosis.
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The answers
Cell becomes flaccid
The sucrose solution ishypertonic to sap cell
Water molecules diffuse
out from the cell byosmosis
Explainthe similarities and
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p a t e s a t es a ddifferences in the formation of twopairs of twins
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SIMILARITY
Both
explanation
DIFFERENCE
but
explanation
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Similarities..
(F) BOTH involve Onesperm fuses with oneovum/secondaryoocyte to form a zygote
(P) Zygote undergoes
mitosis to form ablastocyst
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Differences
F = One blastocyst divides into twobut incomplete division in twins Pand complete division in twins Q
P = causing the formation of aSiamese twin sharing an organ in
any part of body in P and a pair ofidentical twins in Q.
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Explain base on the situation
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Pieces
Unripe papaya
40oC
enzyme
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Explain WHYthe housewife carriesout step 1 and step 2
Step 1
(unripe papaya): contains
papain enzymes / protease(pieces ofmeat & strips of
papaya ) : increases TSA
To tender / soften the meat
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Step 2(Temperature 40C)
To increase rate ofenzyme reaction
Because 40C is optimumtemperature for enzymeaction
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Explain why all of the offsprings haveblack fur .
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Parent
Homozygous black
Homozygous white
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1. allele for black fur is dominant
2. each gametes carries one allele for
the fur color from parents // each
offspring receives one allele from
each parent.
3. each offspring produced is
heterozygous // carries one dominantallele and one recessive allele.
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Based on diagram.
Explain the changes that occurred in the
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double helix of the DNA strand during stage
I.
1. Fact :
double helix of DNAopen
2. Explanation :RNA strand isproduced
State two differences between the structure
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of the protein polypeptide molecule and the
DNA molecule.
1. The polypeptideconsists of amino acidwhile DNA consists ofnucleotide units/ nitrogenous bases
2. the polypeptideis in the form of asingle chain but DNAis a double strand
3. polypeptideconsists linear chainbut DNA consists ofhelix chain
Diff i b h f
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Differentiate between the structures ofDNA and RNA
1. DNA consists oftwo nucleotidechains while RNAconsists of a single
nucleotide chain 2. DNA is longer
than RNA
3. DNA consists of
helix chain butRNA consistslinear chain
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Explain how mutation affect.
1. glutamic acid is replaced by
valine in the polypeptide
2. the properties of the polypeptide/ protein changes
3. different enzyme / protein // protein
changes is produced // the trait shows adefect
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( c ) Explain one feature of thoracic
vertebra which is related to themechanism of respiration.
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Describe
Do not require anysupportive statement
Involved mechanism orsteps in particular process
D ib th h i
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Describe the process shown infigure
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Tell the story.
D1: name of the process :Spermatogenesis
D2: spermatogonium cell
undergoes mitosis to form twoprimary spermatocyte.
D3: one primary spermatocyteundergoes meiosis 1 to form twosecondary spermatocytes
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Continue your story
D4 : secondary spermatocytesundergoes meiosis 11 to formspermatids
D5 : spermatids undergoesdifferentiation to form sperms
D6 : the number of chromosomesdecrease by half the original
number // the diploid chromosomesbecome haploid
D ib th t f t iti i P
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Describe the type of nutrition in Pand Q
PQ
http://www.kids-coloring-pages.net/Rabbit-picture.jpghttp://www.kids-coloring-pages.net/Rabbit-picture.jpg -
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Organism P ( papaya tree)
1. Autotroph nutrition //photosynthesis
Synthesize / produce its own food /glucose / starch
From carbon dioxide, water and light
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Organism Q (Rabbit)
Heterotroph nutrition
Obtain its food source /organic substancesfrom the surroundings
GRAPH based on the graph explain
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GRAPH..based on the graph, explain
the differences.
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Divide graph into small parts
At (time , X-axis.) ,
(y-axis), % of dissolved oxygen.. And % of dissolved carbondioxide is
Because .. (biology knowledge
about respiration andphotosynthesis )
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Inaccurate answer
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Evaluation
State / explainadvantages and
disadvantages
Give the reasons oropinion
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Task Words .
Give an evaluation
Explain the above
statement to justifyDiscuss the good and badeffect
State your opinion andexplain both statement
Multicellular organisms like humans,
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gneed specific transport system ascompared to unicellular organisms like
Amoebasp., which do not need atransport system.
Give an evaluation of the above
statement based on the physicalfeatures of the organisms with thefollowing physiological process :
Respiration
Nutrition
excretion
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Respiration (Amoeba vs Human)
Multicellular organisms :Needs specific gas exchange
surface / organ / lungs toexchange oxygen for carbondioxide
Needs transport system toget gasses in and out oftissues
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Answers
Unicellular organisms :No specific organ /
surface for gas exchangeAs the gases exchangecan takes place by simple
diffusion through theplasma membrane
Balanced diet :
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Balanced diet :
Meat-base fast food
Excess of mineralsalt
Excess fat
Excess protein Insufficient fibre
Presence of foodpreservatives,
flavouring andfood colouring.
Discuss the effectsof consumingmeat-base fast
food for long time.
Figure shows an activity carried out near a
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Figure shows an activity carried out near aresidential area with the intention to develop thearea. However, the residents are worried about
the bad effects of the activity.If you were
a resident of
the area,discuss thegood and
bad effectsof theactivity.
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State the activitycarried out
Effects of deforestation
Consequences of theeffects
The good purpose ofland development
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Samples answer :
1. causes land to be exposed toagents of erosion
Flash flood / landslides / shallowingof rivers / infertile soil / loosen soilstructure
2. Causes increase in carbon
dioxide contentGreen house effect
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3. destroy natural habitats oforganisms.
No natural habitat /extinction of organisms /migration
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The good purpose
1. Develop residence / industry toaccommodate the increase inpopulation
2. Increase the job opportunities
3. Develop road system to shortentravelling time
4. Restructuring of infrastructurefacilities.
Diagram 9.2 shows an ecosystem in
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Malaysia
Based onthediagram9.2, discusswhy theecosystemhas to bemaintained.
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Question 1
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1(a)(i)P:Pulmonary vein
S:Septum
(ii) Diagram
(iii) Oxygenated blood is blood which containoxygen that is picked up by the capillaries
(b) Explain
F: Facts: Q pump blood out from heart to all parts ofthe body(1 mark)
P: To withstand the high pressure of blood flowingthrough them. Function (1 mark)
(c) (i) Diagram
(ii) ExplainF: Facts: (1 mark)
P: Function (1 mark)
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