4. math paper 1 upsr

7/27/2019 4. Math Paper 1 UPSR

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1.

Ain 84

Zuidayana

849

= 75

Ilyani

75 + 15= 90

Average84 + 75 + 903

= 83 B


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2Mokhtar = 180

Jelani = 180 x 2 = 360

Ghani = 360150 = 210

A. Meng = 75 x 3 = 225

Left

(180 + 360 + 210)225

= 750225 = 525

B


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Rajah 6, menunjukkan petak-petak segitiga

sama kaki yang sama besar bagi mewakili

bilangan jagung yang dijual kepada 4 orang

pekedai iaitu Ali, Baba, Chin dan Dali.

BabaBabaBaba

Ali

AliDali

Dali

Chin

Diberi jumlah jagung yang

diterima oleh Baba ialah1350 biji.

3

A 2700

B 2250

C 900

D 450

Hitungkan jumlah jagung yangditerima oleh 3 orang pekedailain.


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Baba

Baba

Baba

Ali

AliDali

Dali

Chin

Baba = 3 bahagian= 1 350

450 450 4503 pekedai lain = 5 bahagian5 x 450 =


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4

37 76812

A 276

B 2 076C 2 706D 2 760

37+ 37

74

74

2

2

x

8

0


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81 49005

A 65B 605C 6 005

D 6 050

6x

20058

x


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35 119270

A 34725B 347C 3 40725

D 3 407

3

200735

35+ 35

70+ 35105

105

14

xx

4

2

+ 35140

14027

0

0

7

+ 105

245

245


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20097

12 369612

A 3 081B 3 801C 30 801

D 30 810

3

x

12+ 12

24+ 1236

36

x

9

0

6

8

+ 1248+ 48

96

961

0


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5 5 000 107 x 23 =A 2 539B 3 461C 112 539D 117 461

107X 2321

145000

2461

- 2461XX 9


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6. 7 27

4 12

23

14211 33

14311

=7 414

4 714=3 414 714 =21814 714

xx

=21114


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71

23 2

16

y

216A

21

3B

212C

22

3D

146 1

56 1

66 2 2

26 2

36

23

6= 2

1

2

C


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8. 4180X Y 421035 of the total ofXandYis

Y(4210 4180) 2= 30 2 = 15= 4180 + 15= 4195

X

4180 (15 x 4 )=4180 60=4120

A 4120B 4195

C 4989D 8315

x


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9

11.200+ 17.075A 27.071B 23.415C 23.135

28.27528.275 5.140

5x 3C


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10 + 705.38 = 1 025

A 319.62B 320.38

C 324.62D 1 730.38

1025.00

705.38

x

4 9 10

2x 6.

10

9

Answer A


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11hours + 3 hours 50 minutes =

910

jam + 3 jam 50 minit =910

A 3 jam 59 minit

B 4 jam 4 minitC 4 jam 40 minit

D 4 jam 44 minit


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11jam + 3 jam 50 minit =

910

A 3 jam 59 minitB 4 jam 4 minit

C 4 jam 40 minitD 4 jam 44 minit

j m

3 5054+

1043x

60 -+ 144


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12. Diagram 3 shows the timeEncik Halim returned fromthe night market.

1 hour 25 minutes later,he watched television.

State the time, in the 24-

hour system, he started to

watch television.


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12. Returned from the night market.11.15 pm = 2315 hrs

1 hour 25 minutes

later

watch tvhours minutes

23 15+ 1 25 +4024

A 0040 hrsB 0950 hrsC 1240 hrsD 2150 hrs 24 0000 40


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13 Mula

14 June7.45

- 257.20 pm

=1920 hours

Tamat

hour minutes

19 2010 45

29 65+ 1 60 -

30 05

- 246 05

15 June, 0605-hours D


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14

I usually drink 10

glasses of water

everyday

Kebiasaannya saya

minum 10 gelas air

sehari

Which of the following measurementsuits the statement.

Antara sukatan ber ikut, yang manakah amat

bersesuaian dengan pernyataan di atas.

A 3 ml

B 30 ml

C 300 ml

D 3000 ml

X

X

X

0 75


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150.75 l 38

0.75 l

=

750ml

Left83

8

=5

8

3

8 = 750ml

1

8 = 250ml

= 250x5 =

1250ml

DA 1.25

B 2.5

C 125D 125O

X

X


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16

21.15 l

40% of the aquarium had notbeen filled with water.

40%

Calculate in litre, the amount of

water needed to fill up the tank.


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16

21.15l

40%

Calculate in litre, the amount of

water needed to fill up the tank.

60%

A 8.46B 14.10

C 20.75D 32.25x

=

= 21.15 l1

5 =

21.15

3= 7.05 l

3

5

=

2

5

25

=7.05 l

+ 7.05 l. 0 l


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17. Which of the following is theheaviest ?Antara ber ikut, yang manakah paling

berat ?

A 5 12

kg

B 5 14

kg

C 5 35

kg

D 5 310

kg


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A 51

2kg

B 51

4kg

C 53

5kg

D 53

10kg

= 5 500 g= 5 250 g= 5 600 g

= 5 300 g Answer

Always look at where you're


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Always look at where you'regoing...


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18. Mr. Rajesh sold 24 papayas toPuan Rohaya. The mass ofone papaya is between 300 gto 600 g.

Estimate in kg, the mass of allthe papayas bought by PuanRohaya.

Encik Rajesh menjual 24 bij i buah betik kepada PuanRohaya. Berat sebij i buah betik adalah di antara 300 g

hingga 600 g.

Anggarkan berat, dalam kg, semua buah betik yang dibeli

oleh Puan Rohaya.


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18.

PAPAYAminimum maximum

300 g 600 g

300 gx 24 600 gx 24A 17.7B 14.1C 7.04D 6.9

7200 g 14400 g= 7.2 kg = 14.4kg


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19Total = 3 x 2kg = 6kg

= 6000 g

325 g

x 18

5850 0

A 150

B 250

C 1675

D 5850

Balance

6000

5850

x

x

150


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2 kg

Tepung

Kek

5 850 g18 peket x 325 g =

3 box = 6 000 g

6 000 g 5 850 g

150g A

19

20


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20

kg

1

23

4

pumkin4.8 kg = 4800 g

Balance4800 1710

= 3090Second

80Third

80 = 3010

= 3010 2 = 1505= 1505


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21 35 m 8 cm 4

A 8.77 cmB 87.7 cmC 877 cm

3500 35088xx C


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221800m = 1.8 km

34 x 1.8 km

A 0.45

B 1.35

C 450

D 1350

x

x

5.4 km

4=

1

B

1


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23Total

20.6

30.8

+ 45.496.8

A 72.6

B 51.4

C 24.2

D 21.2

Left =1

4

Sudah

=

3 x 96.8

4

=

290.4

4 = 72.6A


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MONEYMains Skills- Value of RM and sen, andconversion of units- Involving quantity, number ofobjects and total- The four operations & quantity- Calculation involving fractions &percentage- Selling & buying concept & profit

and loss

24


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24Money Amount

RM5 7RM1 13

50 sen 7

20 sen 1310 sen 15

Total

A RM55.60B RM54.10C RM11.12

D RM10.92

35.0013.00

3.50

2.601.50 +

.60

XX A


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Kuantiti Alat Tulis Harga

seunit RM

Harga

RM

4 btg Pen 1.60

3 kotak Warna Air5 kotak Pensil 3.00 15.00

Jumlah 46.90

Kuantiti Alat Tulis Harga

seunit RM

Harga

RM

10 biji Pemadam10 kotak Pensil

Warna

Jumlah 97.00

6.4025.50.50

8.50 85.0012.00.20

25


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26

RM1100

Discount

15%

15xRM1100

100

= RM165D

27


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27

RM450Encik Lokman sold 8 samebicycles and earned aprofit of RM600What is the cost pr ice for 11

bicycles ?

27


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27 RM450

A RM825B RM4125

C RM4950D RM6600

Price= RM450

Profit8 bicycles

1 Profit= RM6008= RM75

RM600

Cost price= 450 75

= 375Cost price11 bicycle= 375 x 11

= 4125B


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2 & 3 DIMENSIONAL SHAPEMain Skills- Characteristics 2-D and 3-D.

- Able to use formula of area,perimeter & volume

- Calculation of area, perimeter &

volume from diagram- Conversion of units and

measurements

28


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28 The perimeterof the shadedregion is 28 cm.

Calculate theperimeter, incm, of theunshaded

region.A 72B 68

C 64D 60

28


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28

A 72B 68

C 64D 60

Perimeter shadedregion = 28 cm1 side

287= = 4 cm

Perimeterunshaded region= 4 cm x 18

= 72 cmA

29


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29

J K

L

Q

M

NOP

8cm4cm

4cm

6cm

6cm

5cm

5cm4cm

4cm

A

Area A 6 x 82= 24cm

2=

B

Area B 11 x 42= 22cm2=

C

Area C = 20cm=5 x 4

Shaded Region= (24+22+20) cm2

= 66 cm2A

30 K L Volume


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30 K L

MN 7cmcmVolume

= 210cm3?

Area KLMN

= 21035 = 6

6cm

LM

= 5 x 6

= 30 cm2 C

31 Diagram 13 shows a rectangle PQRT a


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31 Diagram 13 shows a rectangle PQRT, asquare STUV and a tr iangle of equal

sides PQW.

P

Q R

T

4 cm

S

U

V4 cm

4 cm

W6 cm

The length ofTU isthe length ofPT.

13

Calculate thearea, in cm2,of the shadedregion.A 56

B 48C 24D 16

31


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31 The length of TU is the length of PT.3

P

Q R

T

4 cm

S

U

V4 cm

4 cmcmArea PQRT

12 x 8 = 96Area STUV4 x 4 = 16W6 cm Area STUV8 x 6

214

= 24Area shadedregion = 96 16 24 = 56


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AVERAGEMain skills

- Very good in the four operations

- Formula average =

- Very good with calculation ofquantity or objects

Total number

Number of groups

32


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32. X 180 Y 255 175

A 610 C 310

Total= 215 x 5= 1075

X + Y= 1075 (180+255+175)= 1075 610 = 465

xY = 2X Y = 465 3

= 155

S b i 900


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33 Sabrie = 900Haziq = 900150 = 750

3 = 800 x 3 = 2400

Average =900+750+2400

5

=4050

5= 810 A

C


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PERCENTAGE

Convert percentage to fraction ordeciamal

Finding percentage (% : x 100% )

Calculating quantity Concept of discount, cut of price

Profit

34


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34Spectacles 25% =

14

Non-spectacles

34

= 105

1053

= 35

UPSRcandidates

35 x 4= 140

A

14

1414

35 35

14 3535

35 Indian


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35.

TAMAN

BAKAWALI

2500 people

Chinese

20%

Indian

Malay

55%

Sikh

10%

What is the total of Indians population

of Taman Bakawali.

35 What is the total of Indians


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35. What is the total of Indianspopulation of Taman Bakawali.

A 1375 C 375

Indian

100% - 20% - 55% - 10%

= 15% 15 x 2500

100=

= 15 x 25

= 375

36


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36 TotalChairs12 X 45 = 540Red Chairs = 75%

Blue Chairs = 25%A 135B 180C 405D 540

=14

= 1 x 5404= 135X


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DATA HANDLINGMain Skills

- Skilful reading information &

pictograph

- Skilful with the four operations

- Skilful at making comparison

and adding- Skilful at finding information

and average

O 5 5


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37One pipe = 5.5m

P = 16

Q = 20

R = 10

S = 22

To = 68

Total pipes

x

5.5m

6804400

33000374.00 =

0.374 km

38


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38. IS RK Represents 20 books

Selasa

20 x 6

= 120

Khamis

20 x 4

= 80

Remainder

760-120-80

= 560 Isnin Rabu

80

560

4802

=560-80

2= 240

24020

= 12


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ANALISA JAWAPAN 2005 - 2010

A B C D

2005

20062007

2008

2009

2010 11 10 9 10

9 10 11 10

9 11 10 1010 10 11 9

10 10 9 1110 11 10 9


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10 A!

17A!

18A!

18A!

14A!

17A!


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10A!17A!


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17A!

18A!

17A!

18A!

14A!


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NewStraitsTimesTuesday,March13,20

07

18A!

15A!


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BUANG BAYI


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BUANG BAYI


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BUANG BAYI


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BUANG BAYI


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BUANG BAYI


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BUANG BAYI


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BUANG BAYI


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BUANG BAYI


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MURID YANG ..


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Dreamwhat you want to dream;Go where you want to go;

Be what you want to be,

Because you have only one lifeand one chance to do all the things

you want to do


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4. math paper 1 upsr

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