skema jawapan percubaan pmr maths 2010 sarawak
TRANSCRIPT
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JABATAN PELAJARAN SARAWAK
PEPERIKSAAN PERCUBAAN PMR 2010
Answers For Mathematics Paper 1
Question Answer Question Answer
1 C 21 B
2 A 22 C
3 B 23 A
4 B 24 C
5 B 25 C
6 C 26 D
7 D 27 C
8 B 28 D
9 B 29 B
10 A 30 D
11 B 31 D
12 C 32 D
13 A 33 A
14 B 34 C
15 B 35 C
16 A 36 A
17 D 37 A
18 A 38 D
19 B 39 D
20 D 40 A
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JABATAN PELAJARAN SARAWAK
PEPERIKSAAN PERCUBAAN PMR 2010
Marking Scheme For Mathematics Paper 2
Question Scheme Marks
1 9 1 1
14 5 4
9 4 514 20 20
9 9
14 20
9 20
14 9
10=
14
10=
7
3=1
7
+
= +
=
=
1
1
1 3
2 7.38
0.2 0.3
7.38
0.06
738
6
123
=
=
=
1
1 2
3 (a) 0.493
2
3
3
1( ) 2
8
14
8
1
2
18
b
=
=
=
1
1
1 3
Note :
See
4 5
20
+
or
9
20 award 1 mark
Note:
See 0.06 or738
6award 1 mark
Note:
see1
2, award 1 mark
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Marking Scheme For Mathematics Paper 2
Question Scheme Marks
48 2
5
2 8 5
40
2
20
PR
PR=
PR=
PR
=
=
1
1 2
5(a)
5
12
5 13
6
13 5 6
30
13
42
13
bDE
DE =
DE =
DE
( ) =
=
1
1
1 3
6 (a) 90o clockwise direction 2
1 3
Note : Also accept
PR = 4 5}PR=20
1 mark8 2 = 4
1 mark
Note:
Also accept 2.3 .
(b) The point Kplotted correctly.
K
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Marking Scheme For Mathematics Paper 2
Question Scheme Marks
7 (a)
S as seen or any 2 or 3 intersecting lines at S
(b) (10,10 )
1
1 2
8 (a) 3p + 6
(b) 4 ( 2p 3 ) + (p 2 )
= 8p 12 + (p 2 ) ( p 2 )
= 8p 12 + p 2 2p 2 p + 4 or 8p 12 + p 2 4p + 4
= p2 + 4 p 8
1
1
1 3
9 (a) 6 ( 3 2t)
(b) 3 ( 25p2
4 )
= 3 ( 5p + 2 )( 5p 2 )
1
1
1 3
R Q
CB
AP
0x
108642
2
4
6
8
10
y
S
Note :
See 8p 12 or p2
4p + 4 award 1 mark
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Question Scheme Marks
10
1
1
1
1 4
11 (a) 70o 1o
(b)
30A
B
C
1
1
1
1
1 5
Construct a 30o
angle atA correctly
Construct point Ccorrectly.
Construct the triangleABCcorrectly..
Construct the perpendicular line BD fromB toACcorrectly.
BD = 3.0 ( 0.1) cm
J
N R
M
S
L
T
K
P
Q
(a) The straight line PN(b) (i) Locus Ydrawn
Correctly(ii) LocusZdrawn
Correctly
(c) Intersection of locus YandlocusZmarked correctly ( )
locus Y
locus Z
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Marking Scheme For Mathematics Paper 2
Question Scheme Marks
12 4 1
3 12
4( 4) (1)
12
x
xy y
x x
xy
+
+ =
=
4 16
12
x x
xy
+
=3 16
12
x
xy
+
or
12 ( 4) 3 (1)
3 (12 )
y x xy
xy y
+
=2
12 48 3
36
xy y xy
xy
+
=2
9 48
36
xy y
xy
=2
3 ( 3 16 )
36
y x
xy
=3 16
12
x
xy
+
1
1
1 3
13
+ =
= +
+ =
=
=
q
pp q
q p
q p
q p
3
2 22 4 3
3 2 4
2 3 4
2 7
1
11
3
14 (a)x 2 = 3x = 2 3
x = 11
1
1 3
Note : See 2p 4 award 1 mark
1 mark
1 mark
1 mark
4b 23
3 6 4
3 6 4
2 10
x+x =
x =x+
x x
x
x=5
= +
=
( )
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Marking Scheme For Mathematics Paper 2
Question Scheme Marks
15 (a) 8k9
5 3
4
5 3 4
5 3 4
6
b bb
b
b
b
b
( ) ( )
( )
+
+
=
=
=
1
1
1 3
16(a)
1
2
(b) 3n+1
= 81
3n+1
= 34
Hence,n+1 = 4
n = 4 1
n = 3
1
1
1
3
17 4 1 7y 4 7 1y +
4 8y
8
4
y
2y
y = 2 , 4 , 6 , 8
1
2 3
18
2
2
Note :
Any three integers correct, award 1 mark
Image draw correctly
Note :
3 or 4 sides drawn
correctly, award 1
mark
c m c m
c m c m
c m c m
11 2 0 0 6
2 0 0
14 0 0 2
2 0 0
18 0 0 4
2 0 0
=
=
=
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Marking Scheme For Mathematics Paper 2
Question Scheme Marks
19
1
1
1 3
20 The y-axis is drawn with the correct scales.
All the points plotted correctly.
The curve is drawn correctly. ( Passing through all the points )
1
2
1 4
Note :
5 or 6 points plotted correctly, award 1 mark
(a) 2x = 120 5 20 30 25 or 80 + 2x = 120
2x = 40
x = 40
2
x = 20
(b)20
360120
= 60o
(c) Reading
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Answer for question 20
y
-2-3 x0 2 31
5
5
10
15
20
25
30
35
-1