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MODUL PENINGKATAN PRESTASI TINGKATAN 5
TAHUN 2016
MAJLIS PENGETUA SEKOLAH MALAYSIA (KEDAH)
MODUL 1
FIZIK
Kertas 2
Peraturan Pemarkahan
2
BAHAGIAN A
Soalan Cadangan Jawapan Markah 1(a)
Base quantity Derived quantity Distance Mass Time
Speed
Note: All correct – award 2 marks 2 – 3 correct – award 1 mark
2
(b) v = !""!.$%
= 80 km h-1 // 22.22 m s-1
1
1 4
2(a) Refraction 1 (b)
Correct direction (towards normal) Wavelength decreases
1 1
(c) &'&(
= *'*(
= +,.%
v1:v2 = 6: 5
1
1
5 3(a) The rate of change of momentum in a collision or explosion
A strong impact force produced in a short ime when collision occurs 1
(b) F =
%"" " -%"" ($,.,/)!
= -13890 N
1
1 (c) (i) Decreases 1
(ii) Time of impact increases / longer impact time 1 (d) Air bag // seat belt // padded dashboard //crumple zone 1
6 4(a) n-p-n transistor 1 (b) To limit base current / to control base current 1 (c) Resistance changes with brightness 1
(d) 12!".%3 12
x 6 ≥ 1.5
RQ ≥ 3.5 kΩ Minimum RQ = 3.5 kΩ
1
1 (e) Resistance of Q increases // Base voltage increases
Base current, IB flows / Transistor switches on
1 1
Glass block/ Bongkah kaca
3
7
Soalan Cadangan Jawapan Markah 5(a) (i)
F Coil F Both direction correct – award 1 mark
1
(b) (i) Diagram 5.2 > Diagram 5.1 1 (ii) Diagram 5.2 < Diagram 5.1 1
(iii) Diagram 5.2 < Diagram 5.1 1 (c) (i) The smaller the thickness, the smaller the spring constant / vice versa 1
(ii) The greater the angle of deflection of pointer, the smaller the spring constant / vice versa
1
(iii) Diagram 5.2 1 (d) Use stronger magnet // increase number of coils 1
8 6(a) Incompressible liquid 1 (b) (i) Diagram 6.1 = Diagram 6.2 1
(ii) Diagram 6.1 < Diagram 6.2 1 (iii) Diagram 6.1 < Diagram 6.2 1
(c) (i) The smaller the cross sectional area of output piston, the smaller the force exerted / vice versa
1
(ii) Pascal 1 (d) (i) No change / same 1
(ii) No change in input pressure 1 8
7(a) (i) Total internal reflection 1 (ii) Incident angle is greater than the critical angle // light propagates from denser
medium to less dense medium 1
(b) 2.42 = !
456 7
c = 24.4 o
1
1 (c) (i) Higher / more / bigger / larger
Reason: Bent easily 1 1
(ii) Higher / more / larger Reason: More data/energy can be transmitted
1 1
(iii) Higher / more Reason: Less signal/energy loss
1 1
10 8(a) Unstable isotope 1 (b) (i) Shorter
Reason: Water will not be contaminated for a longer period 1 1
(ii) Beta Reason: Moderate penetrating power // Can penetrate the ground to a certain range only
1 1
(iii) Liquid Reason: Dissolve well / easily with water
1 1
(c) S 1 (d) (i) When the ratemeter reading increases abruptly 1
(ii) GM tube 1 (e) 100% à 50% à 25% à12.5%
3 T !$ = 3 x 5.27
1
4
= 15.81 tahun 1 12
BAHAGIAN B
Soalan Cadangan Jawapan Markah 9(a) Pressure 1 (b) Temperature of air in air tight container in Diagram 9.1 < Diagram 9.2
Length of air in air tight container in Diagram 9.1 < Diagram 9.2 Reading of Bourdon gauge is the same. The lower the temperature of air in the container, the shorter the length of air in the container // vice versa Charles’ Law
1 1 1
1 1
(c) Reading of Bourdon gauge increases Friction between tyre and the road produces heat // Heat is absorbed by the air molecules in the tyre Kinetic energy // Velocity of air molecules in the tyre increases Rate of collision between air molecules and the walls of the tyre increases // Air molecules hit the walls of the tyre more frequently
1
1 1
1 (d) (i) Specific heat capacity of the liner is bigger
Good insulator 1 1
(ii) Use oil to fill up air space Able to transfer heat more efficiently
1 1
(iii) High sensitivity of thermometer Gives more accurate reading
1 1
(iv) Higher rated power of the electrical heater Able to supply more power / heat
1 1
(v) Wrap aluminium block with thick cloth Reduce heat loss to the surrounding
1 1
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Soalan Cadangan Jawapan Markah 10(a) Current 1
(b) (i) The ammeter reading in Diagram 10.1 is lower / vice versa The cross-sectional area of wire PQ is smaller / vice versa The resistance of wire PQ is higher / vice versa
1 1 1
(ii) The smaller the cross-sectional area, the lower the reading of the ammeter / vice versa The smaller the cross-sectional area, the higher the resistance / vice versa
1
1
(c) When the Van de Graaff generator is switched on, plate X is positively charged. Electrical force is produced. The ping pong ball is attracted to / touches plate X. The surface of the ping pong ball is positively charged. Like charges repel and the ping pong ball swings to plate Y.
1 1 1 1 1
Max: 4 (d) (i) The density is lower
The power bank is lighter / easier to carry 1 1
(ii) The capacity is higher Able to recharge repeatedly / supply more power / can be used for a longer time
1 1
(iii) Shorter charging time Able to save time
1 1
(iv) Rate of power loss is lower Able to save energy
1 1
(v) Higher number / more USB ports Able to recharge more devices at once
1 1
5
BAHAGIAN C
Soalan Cadangan Jawapan Markah 11(a) Rate of change of displacement 1
(b) AB : Velocity increases uniformly / Constant acceleration BC : Constant velocity // Zero / No acceleration CD : Velocity decreases uniformly / Constant deceleration Moving in opposite direction
1 1 1 1
(c) Larger diameter of tyre Wheelchair can move faster Narrow tyre Less contact with the ground / Easier to move Low seat More stable / Lower centre of gravity Bigger angle of camber Increases stability Best choice: R Big diameter, narrow tyre, low seat and bigger angle of camber
1 1 1 1 1 1 1 1 1 1
(d) (i) EP = mgh = 95 x 10 x 10 = 9500 J
1 1
(ii) EP = EK = ½ mv2 9500 = ½ (95) v2 v = 14.1 m s–1
1 1
(iii) No energy loss to the surrounding 1 20
Soalan Cadangan Jawapan Markah
12(a) Sources which vibrate at the same frequency and in phase / * Accept: same wavelength
1
(b) (i) λ = &8 =
9""!$""
= 0.25 m
1
1 (ii) x = *:
;
= ".$% (%.")$."
= 0.625 m
1
1 1
(c) At night, temperature of air decreases Density of air is higher Wavelength decreases // Velocity decreases x is directly proportional to λ
1 1 1 1
(d) Radio wave Longer wavelength // Easy to diffract Higher frequency Faster transmission // More energy // Can go further Greater number of antenna Transmit more signals at one time // Stronger signal transmitted Higher position Less obstacle // Less signal loss Best choice: Q Radio wave, higher frequency, greater number of antenna and placed at higher position
1 1 1 1 1 1 1 1 1 1
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