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1 MODUL PENINGKATAN PRESTASI TINGKATAN 5 TAHUN 2016 MAJLIS PENGETUA SEKOLAH MALAYSIA (KEDAH) MODUL 1 FIZIK Kertas 2 Peraturan Pemarkahan

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Page 1: Skema Fizik Percubaan K2 F5 - SKORMINDAskorminda.com/wp-content/uploads/2016/10/Skema-Fizik-Percubaan-… · MODUL PENINGKATAN PRESTASI TINGKATAN 5 ... 4 2(a) Refraction 1 (b)

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MODUL PENINGKATAN PRESTASI TINGKATAN 5

TAHUN 2016

MAJLIS PENGETUA SEKOLAH MALAYSIA (KEDAH)

MODUL 1

FIZIK

Kertas  2  

Peraturan  Pemarkahan  

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BAHAGIAN A

Soalan Cadangan Jawapan Markah 1(a)

Base quantity Derived quantity Distance Mass Time

Speed

Note: All correct – award 2 marks 2 – 3 correct – award 1 mark

2

(b) v = !""!.$%

= 80 km h-1 // 22.22 m s-1

1

1 4

2(a) Refraction 1 (b)

Correct direction (towards normal) Wavelength decreases

1 1

(c) &'&(

=  *'*(

= +,.%

v1:v2 = 6: 5

1

1

5 3(a) The rate of change of momentum in a collision or explosion

A strong impact force produced in a short ime when collision occurs 1

(b) F =

%"" " -%""  ($,.,/)!

= -13890 N

1

1 (c) (i) Decreases 1

(ii) Time of impact increases / longer impact time 1 (d) Air bag // seat belt // padded dashboard //crumple zone 1

6 4(a) n-p-n transistor 1 (b) To limit base current / to control base current 1 (c) Resistance changes with brightness 1

(d) 12!".%3  12

x 6 ≥ 1.5

RQ ≥ 3.5 kΩ Minimum RQ = 3.5 kΩ

1

1 (e) Resistance of Q increases // Base voltage increases

Base current, IB flows / Transistor switches on

1 1

Glass block/ Bongkah kaca

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7

Soalan Cadangan Jawapan Markah 5(a) (i)

F Coil F Both direction correct – award 1 mark

1

(b) (i) Diagram 5.2 > Diagram 5.1 1 (ii) Diagram 5.2 < Diagram 5.1 1

(iii) Diagram 5.2 < Diagram 5.1 1 (c) (i) The smaller the thickness, the smaller the spring constant / vice versa 1

(ii) The greater the angle of deflection of pointer, the smaller the spring constant / vice versa

1

(iii) Diagram 5.2 1 (d) Use stronger magnet // increase number of coils 1

8 6(a) Incompressible liquid 1 (b) (i) Diagram 6.1 = Diagram 6.2 1

(ii) Diagram 6.1 < Diagram 6.2 1 (iii) Diagram 6.1 < Diagram 6.2 1

(c) (i) The smaller the cross sectional area of output piston, the smaller the force exerted / vice versa

1

(ii) Pascal 1 (d) (i) No change / same 1

(ii) No change in input pressure 1 8

7(a) (i) Total internal reflection 1 (ii) Incident angle is greater than the critical angle // light propagates from denser

medium to less dense medium 1

(b) 2.42 = !

456 7

c = 24.4 o

1

1 (c) (i) Higher / more / bigger / larger

Reason: Bent easily 1 1

(ii) Higher / more / larger Reason: More data/energy can be transmitted

1 1

(iii) Higher / more Reason: Less signal/energy loss

1 1

10 8(a) Unstable isotope 1 (b) (i) Shorter

Reason: Water will not be contaminated for a longer period 1 1

(ii) Beta Reason: Moderate penetrating power // Can penetrate the ground to a certain range only

1 1

(iii) Liquid Reason: Dissolve well / easily with water

1 1

(c) S 1 (d) (i) When the ratemeter reading increases abruptly 1

(ii) GM tube 1 (e) 100% à 50% à 25% à12.5%

3 T !$ = 3 x 5.27

1

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= 15.81 tahun 1 12

BAHAGIAN B

Soalan Cadangan Jawapan Markah 9(a) Pressure 1 (b) Temperature of air in air tight container in Diagram 9.1 < Diagram 9.2

Length of air in air tight container in Diagram 9.1 < Diagram 9.2 Reading of Bourdon gauge is the same. The lower the temperature of air in the container, the shorter the length of air in the container // vice versa Charles’ Law

1 1 1

1 1

(c) Reading of Bourdon gauge increases Friction between tyre and the road produces heat // Heat is absorbed by the air molecules in the tyre Kinetic energy // Velocity of air molecules in the tyre increases Rate of collision between air molecules and the walls of the tyre increases // Air molecules hit the walls of the tyre more frequently

1

1 1

1 (d) (i) Specific heat capacity of the liner is bigger

Good insulator 1 1

(ii) Use oil to fill up air space Able to transfer heat more efficiently

1 1

(iii) High sensitivity of thermometer Gives more accurate reading

1 1

(iv) Higher rated power of the electrical heater Able to supply more power / heat

1 1

(v) Wrap aluminium block with thick cloth Reduce heat loss to the surrounding

1 1

20

Soalan Cadangan Jawapan Markah 10(a) Current 1

(b) (i) The ammeter reading in Diagram 10.1 is lower / vice versa The cross-sectional area of wire PQ is smaller / vice versa The resistance of wire PQ is higher / vice versa

1 1 1

(ii) The smaller the cross-sectional area, the lower the reading of the ammeter / vice versa The smaller the cross-sectional area, the higher the resistance / vice versa

1

1

(c) When the Van de Graaff generator is switched on, plate X is positively charged. Electrical force is produced. The ping pong ball is attracted to / touches plate X. The surface of the ping pong ball is positively charged. Like charges repel and the ping pong ball swings to plate Y.

1 1 1 1 1

Max: 4 (d) (i) The density is lower

The power bank is lighter / easier to carry 1 1

(ii) The capacity is higher Able to recharge repeatedly / supply more power / can be used for a longer time

1 1

(iii) Shorter charging time Able to save time

1 1

(iv) Rate of power loss is lower Able to save energy

1 1

(v) Higher number / more USB ports Able to recharge more devices at once

1 1

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BAHAGIAN C

Soalan Cadangan Jawapan Markah 11(a) Rate of change of displacement 1

(b) AB : Velocity increases uniformly / Constant acceleration BC : Constant velocity // Zero / No acceleration CD : Velocity decreases uniformly / Constant deceleration Moving in opposite direction

1 1 1 1

(c) Larger diameter of tyre Wheelchair can move faster Narrow tyre Less contact with the ground / Easier to move Low seat More stable / Lower centre of gravity Bigger angle of camber Increases stability Best choice: R Big diameter, narrow tyre, low seat and bigger angle of camber

1 1 1 1 1 1 1 1 1 1

(d) (i) EP = mgh = 95 x 10 x 10 = 9500 J

1 1

(ii) EP = EK = ½ mv2 9500 = ½ (95) v2 v = 14.1 m s–1

1 1

(iii) No energy loss to the surrounding 1 20

Soalan Cadangan Jawapan Markah

12(a) Sources which vibrate at the same frequency and in phase / * Accept: same wavelength

1

(b) (i) λ = &8 =

9""!$""

= 0.25 m

1

1 (ii) x = *:

;

= ".$% (%.")$."

= 0.625 m

1

1 1

(c) At night, temperature of air decreases Density of air is higher Wavelength decreases // Velocity decreases x is directly proportional to λ

1 1 1 1

(d) Radio wave Longer wavelength // Easy to diffract Higher frequency Faster transmission // More energy // Can go further Greater number of antenna Transmit more signals at one time // Stronger signal transmitted Higher position Less obstacle // Less signal loss Best choice: Q Radio wave, higher frequency, greater number of antenna and placed at higher position

1 1 1 1 1 1 1 1 1 1

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