skema kertas 2 mid exam fizik

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PEPERIKSAAN PERTENGAHAN TAHUN 2014SKEMA JAWAPAN FIZIK TINGKATAN 5 KERTAS 2

BAHAGIAN A

QUESTIONSSOALANMARKING SCHEMESKEMA PEMARKAHANMARKMARKAHTOTALJUMLAH

1a (i)Underline or circle correct answer : Y

1

(ii)No parallax error // Eyes perpendicular to the reading1

bState correct volume with correct unit : 34 cm 31

cShows correct meniscus and reading

14

Refraction of lightApparent depth in Diagram 5.1(a) / distilled water is longer (than that in Diagram 5.2(a) / sea water)Density of seawater is higher than distilled water / vice versaDensity increase, apparent depth decreaseRefractive indexGradient of the graph in Diagram 5.2(b) is bigger (than that in Diagram 5.1(b))When apparent depth decreases, refractive index increases // Apparent depth is inversely proportional to refractive indexThe coin appears more closer to the surface // apparent depth decreased

Kg m s-2 Note: also accept if only one T is labelled 1. 2 T sin 200= 8 N 2. T = 8/ 2 sin 200 = 11.7 N (answer with correct unit)

(a) Mengukur tekanan/ To measure pressure 1 (b)(i) Bacaan tolok Bourdon dalam Rajah 5.2 > Bacaan tolok Bourdon dalam Rajah 5.1/ Rajah 5.2 > Rajah 5.1 The reading of Bourdon gauge in Diagram 5.2 > The reading of Bourdon gauge in Diagram 5.1/ Diagram 5.2> Diagram 5.1 1 (b)(ii) Isi padu udara dalam Rajah 5.1 > Isi padu udara dalam Rajah 5.2/ Rajah 5.1 > Rajah 5.2 The volume of air in Diagram 5.1 > The volume of air in Diagram 5.2/ Diagram 5.1 > Diagram 5.2 1 (b)(iii) Suhu udara adalah sama/ Temperature of air is same 1 (c) Semakin tinggi bacaan tolok Bourdon, semakin rendah isi padu udara. The higher the reading of Bourdon gauge, the lower the volume of air. 1 (d) Hukum Boyle/ Boyles law 1 (e) Apabila gelembung-gelembung udara naik ke permukaan, kedalaman berkurang. When the air bubbles move upward to water surface, the depth decreases. Tekanan berkurang apabila kedalaman berkurang menyebabkan isi padu udara dalam gelembung udara bertambah. Pressure decreases as the depth of water decreases causing the volume of air in the air bubbles increases.

Magnitude : same magnitude of atmosphericpressureDirections : atmospheric pressure and mercury arein the same direction // gas pressuredirection against the direction of mercury andatmospheric pressure // atmospheric pressure actsdownwardsPhg + Patm ,// P gasSame / equalGas pressure = atmospheric pressure + mercurypressureMercury level drops and at same level in bothcolumnsSame pressure // atmospheric pressure

(a)(i) Beza keupayaan VLT dalam Rajah 6.2 > Beza keupayaan VLT dalam Rajah 6.1// Rajah 6.2 > Rajah 6.1 The potential difference of EHT in Diagram 6.2 > The potential difference of EHT in Diagram 6.1// Diagram 6.2 > Diagram 6.1 1 (a)(ii) Kekuatan medan elektrik dalam Rajah 6.2 > Kekuatan medan elektrik dalam Rajah 6.1// Rajah 6.2 > Rajah 6.1 The strength of electric field in Diagram 6.2 > The strength of electric field in Diagram 6.1 Diagram 6.2 > Diagram 6.1 1 (a)(iii) Laju ayunan dalam Rajah 6.2 > Laju ayunan dalam Rajah 6.1// Rajah 6.2 > Rajah 6.1 The speed of oscillation in Diagram 6.2 > The oscillation velocity in Diagram 6.1// Diagram 6.2 > Diagram 6.1 1 (b)(i) Semakin tinggi beza keupayaan VLT, semakin tinggi kekuatan medan elektrik. The higher the potential difference of EHT, the higher the strength of electric field. 1 (b)(ii) Semakin tinggi beza keupayaan VLT, semakin tinggi laju ayunan. The higher the potential difference of EHT, the higher the speed of oscillation.

1. Apabila penjana Van de Graaff dihidupkan, cas positif terhasil dan terkumpul di bahagian kubah. 2. Cas-cas positif ini akan menggerakkan cas-cas negatif daripada pili melalui konduktor ke kubah. 3. Apabila wujud pengaliran cas di dalam konduktor, maka arus akan terhasil. 1. When the Van de Graaff generator is turned on, generated positive charges and accumulated in the dome. 2. The positive charges drove the negative charges from water tap through the conductor to the dome. 3. When there is a flow of charges in a conductor, the current will be produced.

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(a) (i) Impulsive force (ii) - Impulsive force, F = m ( v u ) t - Impulsive force, F is inversely proportional to time of collision - In diagram 10.1, the time of collision is long while in diagram 10.2 the time of collision is short

- The impulsive force acting on the first case (diagram 10.1) is smaller than the the impulsive force acting on the second case (diagram 10.2)

- The small impulsive force prevents injury to the player and the large impulsive force causes the spices to be crushed easily (b) - The baseball player should wears a glove which is made of soft material - When catching the ball, the player should moves his hand backward - The both action will lengthen the time of impact between the ball and - the glove and reduces the impulsive force acting on his palm. Hence, it will prevent injury to the player. (c) (i) - Use a big polystyrene box - This is because polystyrene box is lighter

- In the box, Encik Ali should place soft materials such as cloth or cotton - When placing the eggs, Encik Ali should arrange the eggs by layers with cloth or cotton in between the layers

(ii) - A big polystyrene box can accommodate all the 300 eggs and is also lighter. Therefore, it eases the delivery of the eggs. - Soft materials in the box prevent the eggs colliding into the wall of the container with high impulsive forces - This is because, impulsive force, F = m ( v u ) t - Impulsive force is inversely proportional to the time of collision - Soft material increases the time of collision and reduces the impulsive force - Placing cloth or cotton between the layers helps to reduce the impulsive force of the collision between the eggs by increasing the time of colliaion

Distance between optical centre and focal point Correct substitution into formula or correct answer: M =

// 3[Reject answer with unit]

Correct substitution into formula :

Answer with correct unit : f = 15 cm // 0.15 mP = 100 / f = 100 / 15Answer with correct unit : = 6.67DParallel light rays from the hot sun at infinity pass through a convex lens // labelled diagramLight rays are focused after passing through the lens // labelled diagramLight rays are converged onto a very small area called the focal point of the lensAt the point, the intensity of light is great (and the light energy) causes an increases in temperature. When the spot on the paper become hot enough, the paper start to burn // light energy change to heat energy

AspectExplanation / Reason

Power of eyepiece :Low powerFocal length is longer // eyepiece must be more longer focal length than objective lens

Power of objective lens : High powerFocal length is shorter // Objective lens must be more powerful lens than eyepiece // Objective lens must be more shorter focal length than eyepiece

Distance between lenses : > fo + feTo produce bigger image from the eyepiece // to increase the magnification

Position of the specimen : fo < u < 2foTo produce real, inverted and magnified image

The most suitable is : microscope MFocal length of eyepiece is longer than objective lens, distance between lenses is greater than (fo + fe), and the position of the specimen is between fo and 2 fo