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    0. Introduction

    physical chemistry establishes and develops the

    principles of chemistry

    concepts used to explain and interpret observations

    on the physical and chemical properties of matter

    central theme:

    systems states

    processes

    topics of physical chemistry:

    (1) the study of the macroscopic properties of sys-

    tems of many atoms or molecules

    (2) the study of processes which such systems can

    undergo

    (3) the study of the properties of individual atoms and

    molecules

    PChem I 1.1

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    states: ice (solid) 32F

    water (liquid)212F

    vapor (gas)

    processes: heat the system; sharp transition from iceto water at 32

    F and from water to vapor at 212

    F

    macroscopic properties change, no change in the

    molecules or the forces between them!

    Can we understand these changes? Can we pre-

    dict the transition temperature, i.e., the melting tem-perature Tm and the boiling temperature Tb, or the

    macroscopic properties of the different phases, e.g.,

    the molar volumes, or the dependence of the transi-

    tion temperatures on pressure P, on impurities (e.g.

    salt), etc.

    Can two or more different phases exist for the same

    external conditions?

    carbon: 1) diamond: transparent, colorless, hard;

    2) graphite: black, slippery, soft; 3) buckminster-

    fullerene: ?

    properties: topic (1)

    processes (transformations, reactions): melting ice,

    evaporating water, burning methane, . . .

    PChem I 1.3

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    Tobacco Mosaic Virus (TMV)

    2130 identical subunits in protein coat, closelypacked in a helical array around a single-stranded

    RNA molecule (6390 nucleotides)

    TMV can be dissociated by acetic acid into coat sub-

    units and RNA

    spontaneously reassemble under suitable con-

    ditions into virus particles

    indistinguishable from original TMV in structure and

    infectivity

    self-assembly

    process

    1) Can it occur?

    2) Will it occur spontaneously?

    3) How fast will it occur?

    thermodynamics: 1) and 2); kinetics: 3)

    How can we influence a process?

    applications: reactor design, catalysts, corrosion,. . .

    PChem I 1.4

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    toluene+methanol

    mxylene 0.50oxylene 0.25pxylene 0.25

    pxylene oxidized terepthalic acid

    ethylene glycol

    polyester (Dacron)

    How can we increase the yield of p-xylene?

    zeolite: crystalline aluminosilicate framework, exten-

    sive 3-D network of SiO44

    and AlO45

    ions and Si4+

    andAl3+ ions

    ZSM-5: channels and chambers 1 nm

    PChem I 1.5

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    Thermodynamics

    large systemstwo types of variables:

    intensive extensive

    T,P, . . . V,m, . . .

    historically: empirical observations concerning rela-

    tions between such variables

    example: PV= nRT

    origins of thermodynamics:

    practical interest: heat generates motion

    evolved into a theory that describes transformationof states of matter in general

    thermodynamics is particular good in dealing with

    complex systems, since the exact nature of the con-

    stituents and microscopic processes is irrelevant

    two conceptual innovations of thermodynamics

    First Law: conservation of energy

    Second Law: entropy

    PChem I 1.6

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    1. The Properties of Gases

    Notation: (i) I use an overbar to denote molar quan-

    tities; the textbook uses a subscript m. Example: mo-

    lar volume, these notes V, textbook Vm. (ii) I use a

    capitalPfor pressure; the textbook usesp.

    simple system to learn the concepts and methods ofthermodynamics

    gas: fills any container

    dilute gas; chemically pure

    macroscopic description

    state of pure gas: V volume of container, T temper-

    ature of the gas, Ppressure of the gas, n amount of

    the gas = number of moles

    assume no electric or magnetic properties

    pressure P= FA

    PChem I 1.7

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    Fforce perpendicular to area A

    units: Pa=Nm2

    ,1 N= 1 k g m s2

    1bar 100.kPa= 105 Pa= P standard pressure1atm 101.325kPa1atm 760torr= 760mmHg

    hydrostatic pressure P= g h; density of fluid; ggravitational acceleration;hheight of fluid column

    temperature

    gas A gas B

    diathermic wall

    diathermic wall: thermal contact between the twocompartments, flow of energy (heat) possible

    ast: thermal equilibrium

    PChem I 1.8

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    mechanical properties of each compartment, e.g., P,

    do no longer change with time!

    fortsufficiently large: PA(t) PA,PB(t)PBfor a fixed, rigid wall, in general PA = PB

    Zeroth Law of Thermodynamics

    If A is in thermal equilibrium with B andif B is in ther-

    mal equilibrium with C, then A is in thermal equilibri-um with C.

    (empirical observations)

    [Figure: Thermal equilibrium and the Zeroth Law; Atkins 9th ed., Fig. 1.3]

    = existence of a property common to all systemsthat are in thermal equilibrium with each other: tem-

    perature

    PChem I 1.9

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    thermodynamic temperature scale:

    C, melting

    point of ice: 0

    C at 1 atm; boiling point of water:

    100C at 1 atm

    T

    K C+273.15

    thermodynamic equilibrium

    = thermal equilibrium,TA = TBand

    mechanical equilibrium,PA = PB

    thermodynamic equilibrium states

    P=f(n,V,T)

    ideal gas

    PV= nRTSI units:Vm3,PPa,TK: R= 8.314JK1mol1

    PChem I 1.10

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    1 J= 1 N malternative units:

    VL, (

    1 L = 1 dm3

    = 103

    m

    3)

    Patm:

    R= 8.206102 LatmK1mol1

    consider a system withn= constisotherm: T= const,P V= const,P1/V, hyperbolas

    [Figure: Ideal gas isotherms; Atkins 9th ed., Fig. 1.4]

    PChem I 1.11

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    isobar: P=const,V T

    [Figure: Ideal gas isobars; Atkins 9th ed., Fig. 1.6]

    PChem I 1.12

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    isochore:V= const,PT

    [Figure: Ideal gas isochores; Atkins 9th ed., Fig. 1.7]

    PChem I 1.13

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    surface of equilibrium states

    [Figure: Ideal gas: surface of possible states; Atkins 9th ed., Fig. 1.8]

    standard temperature and pressure (STP): =0 C,P=1atm = V= RT/P=22.414dm

    3

    mol1

    = 22.414Lmol1

    standard ambient temperature and pressure (SATP):

    PChem I 1.14

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    T= 298.15 K, P= 1 bar = V= RT/P= 24.789dm3mol1

    mixture of ideal gases

    Daltons law P=P1+P2+ . . .=j Pj, Pj=njRT

    V

    mole fraction xj=nj

    n, n=

    j

    nj

    Pj= xjP

    for nonideal gases: Pj xjP

    Real Gases

    deviations from ideal gas law: due to intermolecular

    forces

    PChem I 1.15

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    [Figure: Potential energy between two molecules; Atkins 9th ed., Fig. 1.13]

    attractive: dipole-dipole forces, H-bonds, dispersion

    forces

    repulsive: repulsion of electrons

    measure for deviations

    compression factor Z= PVRT

    PChem I 1.16

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    ideal gas (superscript

    ) V = RT

    P Z 1

    Z= VV

    [Figure: Compression factor; Atkins 9th ed., Fig. 1.14]

    Z> 1V> V repulsive forces dominateZ< 1V< V attractive forces dominate

    PChem I 1.17

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    equation of state for real gases? no general form!

    Try: PV= RT f(P), f(P)to be determinedf(P) 1for ideal gasesas P0, all gases follow the ideal gas law= f(P)1asP0

    try power-law ansatz for f(P), i.e., expand f(P) in

    powers ofP

    PV= RT[1+B(T)P+C(T)P2+ ...]

    virial expansionorvirial equation of state

    B(T) second virial coefficient (depends only on pair

    interactions), C(T) third virial coefficient (note: the does not denote a derivative; it is simply used to

    distinguish these coefficients from those in the alter-

    native form)

    alternative, but equivalent form of the virial equation

    of state

    ideal gas law is valid for dilute gases, i.e., small or

    V large ( =m/V=M/V or 1/V)

    PChem I 1.18

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    PV= RT f(V), f(V) 1 for ideal gas

    expand f(V)in powers of1/V

    PV= RT

    1+B(T) 1V+C(T) 1

    V2+ . . .

    left as an exercise to show that

    B(T)= B(T)RT

    , C(T)= C(T)B(T)2

    (RT)2

    Z= 1+B(T)P+C(T)P2+ . . .dZ

    dP=B(T)

    +2C(T)P

    +. . .

    PChem I 1.19

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    Boyle temperatureTB: B(TB)= 0orB(TB)= 0

    P 0: if T= TB then Z 1 and dZ/dP 0 extended range of ideal behavior

    [Figure: Boyle temperature; Atkins 9th ed., Fig. 1.16]

    Boyle temperatures for some gases: H2 109 K,

    CH4 510 K, C2H4 720 K, NH3 1030 K [Estrada-Torres,

    R.; Iglesias-Silva, G. A.; Ramos-Estrada, M. & Hall, K. R., Boyle temper-

    atures for pure substances, Fluid Phase Equilib., 258, 148154 (2007),

    http://dx.doi.org/10.1016/j.fluid.2007.06.004]

    PChem I 1.20

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    real gas isotherms: exampleCO2

    [Figure: CO2 isotherms; Atkins 9th ed., Fig. 1.15]

    phase transition: condensation, gas liquidcritical point: critical temperature = maximum tem-

    perature at which a gas can be liquefied

    PChem I 1.21

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    phase diagram

    critical temperature Tc, critical pressure Pc, critical

    molar volumeVc: critical constants

    as the critical point is approached along the vapor

    pressure curve: (l)(g) 0orV(g)V(l) 0

    PChem I 1.22

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    [Figure: Approaching the critical point; Atkins 9th ed., Fig. 4.6]

    critical opalescence: strong density fluctuations near

    the critical point, (l) (g); characteristic length of

    fluctuations on the order of the wavelength of visible

    light = strong scattering = milky appearance

    law of rectilinear diameter (Cailletet and Mathias

    1886)

    12

    ((l)+(g))= A+BT[Figure: rectilinear diameter]

    PChem I 1.23

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    continuity of states: the substance changes from

    liquid-like to gas-like in the supercritical region with-

    out ever changing phases

    virial equation of state good for quantitative work,

    B(T), C(T), . . . are tabulated for gases, but it does

    not provide understanding of the above phenomena

    of real gases

    find a general model; best known and most widely

    used: van der Waals gas

    repulsive interactions: hard spheresexcluded vol-ume,V Vnb

    bis a material constant, equal to the volume of 1 molof densely packed gas particles

    P(Vnb)= nRT

    or

    P= nRTVnb

    PChem I 1.25

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    attractive forces: diminish pressure; pressure is the

    result of collisions of the gas particles with the walls;

    as a particle is about to hit the container wall, it is

    held back, and its impact is diminished, by the at-

    tractive forces from surrounding gas particles; this is

    a pair effect number of pairs of particles (n/V)2 =

    2

    P= nRTVnba

    n

    V

    2

    van der Waals equation

    ais a material constant;aand bare tabulated for real

    gases

    P+ a

    V2

    Vb

    =RT

    compare van der Waals equation with virial equation

    B(T)= b aRT

    PChem I 1.26

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    How good is the van der Waals model?

    (Vb)V2P=RT V2a(Vb)

    V3

    PV2bP=RT V2aV+ab

    V3

    b+ RT

    P

    V

    2+ aP

    V abP= 0

    cubic equation for fixed T and P, three real rootsor one real root and two complex conjugate roots

    isotherms for the van der Waals equation for ammo-

    nia

    PChem I 1.27

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    T< Tc: between the minimum and the maximum ofthe isotherm we have

    dPdV

    > 0, and since dPdV

    =

    dVdP

    1

    we have

    dV

    dP>0

    = unstable!!

    replace the unphysical van der Waals loop by the

    Maxwell equal area construction

    PChem I 1.28

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    branch BB and AA are metastable states

    AA: fast compression: supersaturated gas, cloud

    chamber

    BB: fast expansion: superheated liquid, bubble

    chamber

    critical point = coalescence of minimum and maxi-mum= disappearance of van der Waals loop

    minimum or maximum: first derivative vanishes

    PChem I 1.29

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    between a minimum and a maximum is an inflection

    point (curvature changes): second derivative vanish-

    es

    critical point: at (Tc,Pc,Vc)

    dddP

    dddV= 0 and ddd

    2P

    dddV

    2= 0

    there are three critical constants, need one more

    equation: equation of state

    P=RT

    Vba

    V2 (1)

    dP

    dV= RT

    (Vb)2+ 2a

    V3= 0 at critical point (2)

    d2P

    dV

    2= 2RT

    (V

    b)3 6a

    V

    4= 0 at critical point (3)

    equation (2)RTc=2a(Vcb)2

    V3

    c

    (4)

    PChem I 1.30

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    insert this result into equation (3)

    4a(Vcb)2

    V3

    c(Vcb)3 6a

    V4

    c

    = 0 (5)

    2

    Vcb 3

    Vc= 0

    2Vc=

    3Vc

    3b

    Vc=3b

    insert into equation (4)

    RTc=2a(3bb)2

    (3b)3 = 2a4b

    2

    27b3

    Tc= 8a27bR

    insert into equation (1)

    Pc=

    8a27b

    3bba

    9b2 =8a

    2 27b2 a

    9b2

    Pc=a

    27b2

    PChem I 1.31

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    critical compression factor:

    Zc= PcVcRTc

    =a

    27b2 3b8a

    27b

    Zc=3

    8

    independent of the material constants aandb

    ZvdWc = 0.375; compare with experimental datarange: 0.12 HF 0.47N2O4

    mode: 0.27; 27% of all organic and inorganic sub-

    stances have this value ofZc

    61% Zc in [0.26, 0.28]; 77% Zc in [0.25, 0.29]; 90%

    Zcin [0.23, 0.31]

    van der Waals gas: simple model that captures the

    essential aspects of real gases

    critical point is a very characteristic point for real gas-

    es

    use critical constants as units

    reduced variables Pr=P

    Pc, Vr=

    V

    Vc, Tr=

    T

    Tc

    PChem I 1.32

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    P= RTV

    b a

    V

    2

    PrPc=RTrTc

    VrVcb a

    V2

    rV2

    c

    Pra

    27b2=

    8a27b

    Tr

    3bVrb a

    V2

    r9b2

    Pr=8

    3Tr

    Vr 13 3V

    2

    r

    material independent

    law of corresponding states

    universality

    PChem I 1.33

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    [Figure: Law of corresponding states; Atkins 9th ed., Fig. 1.21]

    PChem I 1.34

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