1

3472/1 Additional Mathematics Paper 1

SULIT

Additional

Mathematics

Paper 1

October, 2015

MODUL PENINGKATAN PRESTASI TINGKATAN 4

TAHUN 2015 ANJURAN

MAJLIS PENGETUA SEKOLAH MALAYSIA (KEDAH)

ADDITIONAL MATHEMATICS

MARKING SCHEME

Paper 1

MODULE 3

.

2

3472/1 Additional Mathematics Paper 1

SULIT

PROGRAM PENINGKATAN PRESTASI TINGKATAN 4 TAHUN 2015

Marking Scheme Module 3

Additional Mathematics Paper 1

Question Solution/ Marking Scheme Answer Marks

1

(a) 7

(b) 22

1

1

2

(a) B1 : )2(55)5( 2 h

(b) B1: 12022 tt

(a) 35

(b) t = 10

2

2

3

B2: 1 9

2 2x or x

B1: 2

2 5 4 2 5 4

4 20 9 0

x or x or

x x

1 9

2 2x and x

3

4

(a) B1 : 3 2y x

(b) B1:

22

3

6

y

g y

(a) 1 2( )

3

xh x

(b) 8

( )18

xg x

2

2

5

B2: 3.581 or 0.419

B1: 0382 2 xx

3.581 and 0.419

3

6

B2: 9

52

p or q

B1:

2 18

2 2 2 18 0 22

p or q

95

2p and q

3

3

3472/1 Additional Mathematics Paper 1

SULIT

Question Solution/ Marking Scheme Answer Marks

7

B2 : 0)32)(2(4)10( 2 qp

B1: )32)(2(4)10( 2 qp

4

256

qp

3

8

(b) B2: 36 4(2)( 3) 0m

B1: 042 acb

(a) 6p

(b) 3

2m

1

3

9

3

10

B1: 5232 xy or 7123 2 xxy

a)

5

2

b

a

b) )7,0(M

1

1

2

(2,8)

4

4

3472/1 Additional Mathematics Paper 1

SULIT

Question Solution/ Marking Scheme Answer Marks

11

B2:

or 3

2x , 2x

B1: 2(2 3)( 2) 2 7 6x x or x x

32

2x and x 3

12

B2: 36 = 6x

B1: 6

827

x

3x

3

13

B2: 3 = 27x

B1: 1

39 3

3

xx or

3x

3

14

B2 : 112 kh

B1 : kk OR 3335

2

2

kh

3

15

a) B1: 5log8log 33 or 52log3 33 ogl

b) B1: 9log

8log

3

3

a) nm 3

b) 2

3m

2

2

16

B2: 32

16 xy

B1: 2

1parallelm

152 xy 3

32 2

5

3472/1 Additional Mathematics Paper 1

SULIT

Question Solution/ Marking Scheme Answer Marks

17

B2: 1 2 5y x

B1: 2perpendicularm

2 9y x 3

18

(a) B1: )2.1(6.15 r

(b) B1:

)136.1513)2.1*2

3(2626

(a) 13r

(b) cm4.114

2

2

19

B2: )25.1()12(2

1 2- )25.1(sin)6(

2

1 2

B1 : )25.1()12(2

1 2 OR )25.1sin()6(

2

1 2

72.92 cm2 3

20

B2: 5)2()7( 22 yx

B1: QS = 5

02841422 yxyx 3

21

B2: 5 7x or y

B1: 2 3 5 4 5 9 11 9

610

x y

5 7x and y 3

22

B2: median = 3

2 or

25

4

B1 :

2

215

2

or

93

2

median = 3

2

and

25

4

3

23

B2: 3( 4 )( 2 )

dyv x

dx

B1: 32 4

dv dyx or v

dx dv

325

8

x

x

dx

dy

3

6

3472/1 Additional Mathematics Paper 1

SULIT

Question Solution/ Marking Scheme Answer Marks

24

B2 : 3

12

(7 2 ) 0.02

y

x

B1 : )2()27(6 3 x or 327

12

x

- 0.24

3

25

B2: 8 3dy

dt

B1: dy dy dx

dt dx dt or 2(4 7) 4

dyx

dx

24

3

END OF MARKING SCHEME