2010 pat t4 matematik skema
TRANSCRIPT
JABATAN PELAJARAN MELAKA
PEPERIKSAAN SELARAS AKHIR TAHUN
TINGKATAN 4, 2010
MATHEMATICS
SKEMA PEMARKAHAN
MATHEMATICS PAPER 1
1 A 11 B 21 A 31 B
2 C 12 B 22 D 32 D
3 A 13 D 23 C 33 D
4 B 14 B 24 B 34 B
5 A 15 D 25 C 35 C
6 A 16 C 26 C 36 B
7 D 17 D 27 A 37 A
8 A 18 B 28 C 38 D
9 C 19 D 29 B 39 D
10 C 20 C 30 D 40 C
MATHEMATICS PAPER 2
No Peraturan Pemarkahan Markah
1 (a)
(b)
1
2
3
2 1684 yx or equivalent
33 y or equivalent
OR
oryxory
x 242
48
equivalent K1
33 y or equivalent K1
OR
13
8
24
45
)4)(4()5)(2(
1K2
1
2
y
x
K1
K1
N1
N1
4
Q
P
R
Q
P
R
No Peraturan Pemarkahan Markah
3 < MUN
tan < MUN =
< MUN = 15.640 or 150 39’
Note: NU = 25 seen award 1 mark.
1
2
1
4
4(a)
4(b)
4(c)
False
If x5 = -32 then x = -2If x = -2 then x5 = -32
450
1
11
1
15
5(a)
5(b)
5(c)
5(d)
or
Some
5 is greater than zero
n = 0, 1, 2, …
1
1
1
11
5
6 x2 – 3x = 0x(x – 3) = 0x = 0x = 3
1111
4
No Peraturan Pemarkahan Markah
7(a)
7(b)
7(c)
k = 7
mPQ =
3 = (-2) + c
y = x + 4
0 = + 4
x-intercept = -8
1
1
111
11
7
8 (a) 50x
(b)
60
2
120
y
y
(c)
80
40120120360
12060180
z
z
orQRS
P1
K1
N1
K1
K1
N1
6
910912
2
1
727
22 2
727
2210912
2
1 2
452
K1
K1
K1
N1
4
No Peraturan Pemarkahan Markah
10(a)
3
2
72
)(
Bn
48
(b) 46)(,20)( BnRn
66
20)( RP or
33
10
K1
N1
K1
N1
4
11 (a) 77
222
360
120 or 12
7
222
360
90
5127127
222
360
907
7
222
360
120
52.5721
1157
(b) 777
22
360
120 or 1212
7
22
360
90 or 127
2
1
1272
11212
7
22
360
9077
7
22
360
120
48.12221
10122
K1
K1
N1
K1
K1
N1
6
No Peraturan Pemarkahan Markah
12 (a) 57
Note: 55 – 59 , give P1
(b)
I
II
III
IV
V
VI
VII
VIII
Upper boundary: ( I until VIII )
Cumulative frequency: ( I until VIII )
(c) Graph:
Uniform scale and correct axis
Plot all 9 points correctly
Smooth curve
(d) (i) 166
(ii) 63.5 -52.5
= 11
Note: Do not accept answers without an ogive.
P2
P1
P2
P1
K2
N1
P1
K1
N1
12
Mass (g)Frequency
i
Upper
Boundary Cumulative
Frequency
40 – 44 12 44.5 12
45 – 49 20 49.5 32
50 – 54 32 54.5 64
55 – 59 48 59.5 112
60 – 64 44 64.5 156
65 – 69 26 69.5 182
70 – 74 14 74.5 196
75 – 79 4 79.5 200
No Peraturan Pemarkahan Markah13 (a)
Mass (kg)
Jisim (kg)
Frequency
Kekerapan
Midpoint
Titik Tengah
I35 – 39
0 37
II40 – 44
5 42
III 45 – 49 7 47
IV 50 – 54 18 52
V 55 – 59 13 57
VI 60 – 64 4 62
VII 65 – 69 2 67
VIII 70 – 74 1 72
IX 75 – 79 0 77
Class Intervals: ( III until IX )
Frequency: ( I until IX )
Midpoint: ( I until IX )
(b)50
)172()267()462()1357()1852()747()542(
=50
2670
= 53.4
P1
P2
P1
K2
N1
No Peraturan Pemarkahan Markah(c) Graph:
Uniform scale and correct axis,
Plot all 9 points correctly using midpoint or class interval as x – axis
Correct polygon.
(d) Modal class is 50 – 54
OR
Any correct information from the frequency polygon
Note: Do not accept answer without a frequency polygon.
P1
K2
N1
P1
12
14(a)
14(b)
14(c)
(i) 4n(2m + 3)
(ii) (k – 5)(k – 2)
(i) {23, 29, 31}
(ii) {30, 31, 35}Note: = {20, 23, 25,29, 30, 31, 35} seen award 1 mark
(iii) 2Note: = {23, 29} seen award 1 mark
(i)
(ii) mPQ = -3
6 = -3(1) + c
y = -3x + 9
1
1
1
2
2
2
1
1
112
No Peraturan Pemarkahan Markah
15(a)
15(b)
15(c)
4 tan 260 or 1.951
tan x =
x = 65.920 or 650 55’
<DHJ
Tan <DHJ =
<DHJ = 36.870 or 360 52’
1
1
2
1
2
1
1
2
1
12
44.5 49.5 54.5 59.5 64.5 69.5 74.5 79.5
20
40
60
80
100
120
140
160
180
200
Graph for Question 12
Number of Potatoes
Mass
SELAMAT MAJU JAYA
37 47 52 57 62 67 72 77
2
4
6
8
10
12
14
16
18
20
Graph for Question 13
42
Number of student
Mass