skema matematik ppt tingkatan 3 perak 2010

10
SULIT JABATAN PELAJARAN PERAK PEPERIKSAAN PERTENGAHAN TAHUN 2010 TINGKATAN 3 MATHEMATICS 50 Mei / Jun 2010 MATHEMATICS PERATURAN PEMARKAHAN

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SULIT

SULIT

JABATAN PELAJARAN PERAK

PEPERIKSAAN PERTENGAHAN TAHUN 2010

TINGKATAN 3

MATHEMATICS 50

Mei / Jun2010

MATHEMATICS

PERATURAN PEMARKAHAN

ANSWER

MATHEMATICS PAPER 1

1D21B

2C22D

3D23B

4B24C

5B25C

6A26D

7B27A

8D28C

9B29A

10C30B

11C31A

12B32B

13C33C

14A34B

15D35D

16A36A

17D37A

18B38D

19A39D

20A40B

MARKING SCHEME

MATHEMATICS PAPER 2

NoSolution and Mark SchemeSub MarkFull Mark

1 or

K1N12

2(a)

(b) 10 + 27 or 10 or 27

37

N1

K1N13

3(a) 13.59 + 10.59 or 6.48 + 3.48 3

(b) 7 ( 3 ) or 3

10

K1N1

K1

N14

NoSolution and Mark SchemeSub MarkFull Mark

4

All points are plotted correctly and image is drawn completely

Note : 1. 2 points plotted correctly and image drawn completely P1 2. Only plotted all points correctly but the image is not drawn

completely P1 3. Dont accept sketch the image

4. Ignore labelP22

5

All sides are drawn correctlyNote: 1. 4 or 5 sides are drawn correctly P1 2. Dont accept sketch the image

3. Ignore labelP22

NoSolution and Mark SchemeSub MarkFull Mark

6

All points are plotted correctly and image is drawn completely.

Note : 1. 4 or 5 points plotted correctly and image drawn completely P1 2. Dont accept sketch the image

3. Ignore labelP22

7(a) (0, 1)

(b) Reflection // Pantulan y-axis as a axis of reflection // paksi-y sebagai paksi pantulanP1

P1

P13

8a2 = b + 25

K1

N12

9(a) y = 5 (b)

k = 4 N1K1

N13

10(a) 4b(a 2 )

(b) m2 2m m + 2 6

(m + 1)(m 4)N1

K1

N13

NoSolution and Mark SchemeSub MarkFull Mark

112(m 3) = 5n

or 2m = 5n + 6

or

K1

K1

N13

12(a) 3m + mn(b) 25x2 10xy 10xy + 4y2 25x2 20xy + 4y2

N1K1

N13

13 or equivalent

or equivalent

K1

K1

N13

145(u2 16)

5(u + 4)(u 4)

K1

N12

15(a) Uniform scale

All points are plotted correctly

Note: 3 or 4 points are plotted correctly P1

Line is drawn to join the points

Note: Dont accept sketch the line(b) Monday

K1P2

N1

N15

NoSolution and Mark SchemeSub MarkFull Mark

16(a) 100o 0.1(b)

Construct line segment AD

Construct line segment CD

Completely parallelogram ABCD

Construct arc to cut line AB

Construct perpendicular DE to ABN1

K1

K1

K1

K1

K16

17(a) Line POR or Line PR

Note : Only line drawn in the diagram P1 (b)

Draw locus L Draw locus M

( correctly markedP2

K1

K1

N15

NoSolution and Mark SchemeSub MarkFull Mark

1832x -1 = 33x = 2K1

N12

19(a) 4a10b2(b) or

6N1

K1

N13

2012 8 or SQ = 12

4K1

N12

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