skema jawapan matematik ar1(k2)

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  • 8/17/2019 Skema Jawapan Matematik AR1(K2)

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    015/2 PRA UPSR 1/AR1

    SKEMA JAWAPAN

    Soalan Markah Jumlah

    markah1. (i) 102 247

    (ii) 102 247 = 100 000 + 2000 + 200 + 40 + 7

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    2. (i)2

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     X = 4 ( lor!k mana"mana 4 #aha$ian)

    (ii)2

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     X 100% = &0%

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    '. (i) 20 &1' 20 &0 = &P = 20 &1' + (' X &)  = 20 &1' + 1&  = 20 &220 &2 4 + '0 & = '& 720

    (ii) S!$i !m*a !*a

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    4. (i) '00m  

    (ii)2

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     =1. = (1. X 1000) = 1 &00 5 5 m m    Kaakan #ilan$an #ikar ,an$ -i*!rlukan = 

    X '00 = 1 &00m m    

      = 1 &00 '00m m      = & #uah #ikar

    (iii) /i *a-u air -i -alam /!#uah k!lalan$ kon  1 &00 = 2&0m m    

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    &. Wan$ kui*an M!i in$ -an 3aa3M2.&0 + 3M0.50 = 3M'.40

    Wan$ kui*an ulon$6 M!i in$ -an 3aa3M2.&0 + 3M'.40 + 3M'.40 = 3M5.'0

    Wan$ kui*an Johan3M12.00 3M5.'0 = 3M2.70

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    . (i) '.&m

    (ii) min *anan$ r!#!n ,an$ -i$unakan ol!h

    /!ia* muri-

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    015/2 PRA UPSR 1/AR1

    '.&m 7 = 0.&m

     7. (i) '26 '26 '26 '46 '46 '6 '6 '6 '6 '

      M!-ian

    M!-ian =2

    3634 +

     = '&k$

    (ii) Jula i/im = 40k$ '2k$ = k$

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    . (i) mur En. 3u--, /!ma/a -ia #!r/ara20'2 157 = & ahun

    (ii) 8!m*oh En9ik 3u--, #!rkhi-ma

    20'2 2000 = '2 ahun'2 ahun =' -!ka- 2 ahun

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    5. (i) Jumlah #ilan$an rakan /!k!la/ :li;ia ,an$

    m!m#!lanakan

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    015/2 PRA UPSR 1/AR1

    Ko/ unuk *a$ar #au"#aa= 11m > 3M20 = 3M2 '20

    (iii) Pa$ar ka,u 1

    11.(i) :r!n

    (ii) 50$ = (50$ 1000)k$  = 0.5k$

     Jumlah i/im #uah"#uahan1.22k$ + 0.5k$ = 2.20k$

    (iii) Jumlah 3M2 = 3M4.40

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    12.(i)5

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    12

    km = 12.2km Jarak -i anara SK 8!li*ok -!n$an P!kan 8uaran0km 12.2km = 47.km47.km = (47. > 1000)m = 47 00m

    (ii)10

    72

    km = 2.7km Jarak -i anara SK 8!li*ok -!n$an SK P!kan

     8uaran

    47.km 2.7km = 4&.1km

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    1'.(i) ku#oi-

    (ii) /i *a-u #!nuk i$a -im!n/i.= 9m > 29m > 49m = 49m'

    (iii) Jumlah i/i *a-u #a$i 24 #ii k!k ,an$ /ama= 24 > 49m'

    = 11&29m'

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    14.(i) ilan$an k!r!a ,an$ -iual -alam #ulan M!i= 110 (2& + 20 + '0 + 1&)

    = 110 50 = 20

    (ii)

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    015/2 PRA UPSR 1/AR1

     Januari ?!#ruari Ma9 A*ril M!i 

    M! &0 = 20 Jumlah #ilan$an manik *uih -an #iru= &0 + 20 = 70

    (ii) ilan$an manik *uih ,an$ in$$al

    =5

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     > &0 = '0ilan$an manik m!rah ,an$ in$$al

    = 100% " 40% = 0%

    =100

    60

     > '0 = 1ilan$an manik ,an$ in$$al= '0 + 1 + 20=

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