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SIJIL PELAJARAN MALAYSIA 2019 MATHEMATICS 1449/2 Kertas 2

Peraturan Pemarkahan

Ogos

PERATURAN PEMARKAHAN

PROGRAM GEMPUR KECEMERLANGAN

SIJIL PELAJARAN MALAYSIA 2019

Question Solution and Mark Scheme Mark Total

1

P1

P1

P1

3

2 (a)

(b)

RSCCSR or

equivalentor 12

6tan

or 612

12cosor

612

6sinor

12

6tan

1

2222

26.570

or 260 34’

P1

K1

N1

1

2

3

3

( )( ) OR )1(2

)120)(1(422 2

Note :

award N1

K1

K1

N2

4

4

or equivalent

or equivalent

or equivalent

K1

K1

K1

N1

4


5

12

equivalentor 412747

22

2

17)86(

2

1

equivalentor 747

22

2

1

equivalentor 7)86(2

1

2

2

l

l

Note :

1. Accept for K mark 2. Accept correct value from incomplete substitution for K mark 3. Correct answer from incomplete working, award Kk2

K1

K1

K1

N1

4

6 (a)

(b)

(c)

(i) 43 is a multiple of 3 and a prime number

(ii) False

If √ + k = 12, then k = 9

3 n2 – 2, n = 1, 2, 3, 4, …

Note :

3 n2 – 2 award K1

P1

P1

P1

K2

2

1

2

5

7

32

2)4(

5

OR

3or )4(25

2

*

*

21

xy

x

y

cc

mm

2

3or

2

3

)3(2 OR 2

)4(

50 OR 320or 320 ****

kx

kkkx

P1

K1

N1

K1

N1

3

2

5


8 (a)

(b)

(c)

30

equivalentor 5025

030

–1 2 or 5

6

30)5025(2

1 + 15)30(

2

1u = 1260

48

Note :

K1 awardseen 15)30(2

1or 30)5025(

2

1 u

P1

K1

N1

K2

N1

1

2

3

6

9 (a)

(b)

Appel

Epal (A)

Banana

Pisang (B)

Watermalon

Tembikai (W)

1 (1 , A) ( 1, B) ( 1, W )

2 (2 , A) ( 2, B) ( 2, W )

3 (3 , A) ( 3, B) ( 3,W )

4 (4 , A) ( 4, B) ( 4, W )

5 (5 , A) ( 5, B) ( 5, W)

Note :

1. Accept correct combination 2. Allow 2 mistake for P1

(i) (1 , A) ( 1, W ), (1, B ), (2, A), (3, A), (4, A), (5, A)

15

7

(ii) (2, B), (3, B),(5, B)

15

3

Note :

Accept correct answer without working from correct listing for K1N1

NOTE : 1. Accept listing without brackets

2. Accept using alphabets only

P2

K1

N1

K1

N1

2

4

6


10

(a)

(b)

14

3

157

7

222

360

1202

7

222

360

120

rr

r

9

1694or 188.22or

9

2188

777

22

360

40 1414

7

22

360

120

777

22

360

40 1414

7

22

360

120

or

K1

K1

N1

K1

K1

N1

3

3

6

11 (a)

(b)

14

5

7

114

3

7

2

52

34

14

1or

Note :

52

34

2345

1seen award P1

16

26

42

35

y

x

=

52

34

620

1

16

26 or

matrix

inverse

16

26

Note : Do not accept

10

01or

42

35

matrix

inverse

4x

2y

Note :

2

4.1

y

xas a final answer, award N1

2. Do not accept any solution solved not using matrix method.

P2

P1

K1

N1

N1

2

4

6

*


12 (a)

(b)

(c)

(d)

8

17

Axes drawn in correct directions with uniform scale for –5 ≤ x ≤ 3

and 2511 y .

All 7 and *2 points correctly plotted or curve passes through all the

points for –5 ≤ x ≤ 3 and 2511 y .

A smooth and continuous curve without any straight line passes

through all 9 correct points using the given scale for –5 ≤ x ≤ 3 and

2511 y .

(i) 5554 y

(ii) 2202 x

Straight line y = –3x – 5 is drawn correctly.

(Check any two points are plotted or the straight line passed through

( 5 ,10), ( 4 ,7), ( 3 ,4), ( 2 ,1), (0, 5 ), ……)

Note:

Identify equation y = –3x – 5 award K1

Values of x:

903703 x

8060 x

Note: Values of x obtained by calculation, award N0

6794.3 , 6794.0 x

K1

K1

P1

K2

N1

P1

P1

K2

N1

N1

2

4

2

4

12

Graph for Question 12 / Graf untuk Soalan 12

-4 -3 -1 0 1 2

-15

-10

- 5

-2

5

10

15

20

x

y

3 -5

-20

25


13 (a)

(b)

(i) (2, 1)

Note:

(2, 1) marked on the diagram or 2 4, seen or (4, 2) marked on the diagram, award P1.

(ii) (3 , - 1)

Note:

(3, - 1) marked on the diagram or 0 5, seen or (5, 0) marked on the diagram, award P1.

(i) (a) V = Reflection in the line x = 7 or equivalent Pantulan pada garis x = 7

Note:

Reflection // Pantulan award P1

(b) U = Enlargement of scale factor 2 with centre F (8, 3)

or equivalent

Pembesaran dengan faktor skala 2 pada pusat F (8, 3)

Note :

1. Enlargement of scale factor 2// Enlargement with centre F (8,3) award P2

Pembesaran dengan faktor skala 2 // Pembesaran pada pusat

F (8, 3)

2. Enlargement // Pembesaran award P1

OR

(a) U = Enlargement of scale factor 2 with centre B (6, 3) or equivalent ( P3 )

Pembesaran dengan faktor skala 2 pada pusat F (8, 3)

(b) V = Reflection in the line x = 7 or equivalent ( P2 ) Pantulan pada garis x = 7

(ii)

equivalentor

204812

20or 18

6

20or 203or 20220

2*

Note:

2*220 seen, award K1

60

P2

P2

P2

P3

K2

N1

4

5

3

12


14 (a)

(b)

(c)

(d)

(i) 80 - 89

(ii)

Titik

tengah

Midpoint

Sempadan

Atas

Upper

Boundary

Kekerapan

Longgokan

Cumulative

frequency

54 5 59 5 0

64 5 69 5 8

74 5 79 5 20

84 5 89 5 40

94 5 99 5 55

104 5 109 5 66

114 5 119 5 76

124 5 129 5 80

Midpoint

Upper boundary

Cumulative Frequency

Min =

410111520128

45124105114105114

115104155942058412574)8564(

Note : 1. Allow two mistakes in frequency or *midpoint for K1

2. Allow two mistakes for multiplication for K1

3891or8

391or

8

731.

Note :

Correct answer from incomplete working, award Kk2.

Ogive

Axes are drawn in the correction directions with uniform scales for

5.1295.59 x and 800 y

1 point and *7 point are correctly plotted, or the line passes through

all the points

Correct and continuous ogive using the given scale.

Note : 6 or 7 points are correctly plotted award K1

7538*

10080

49*80

Note:

1. Do not accept answer without ogive

P1

P1

P1

P1

K2

N1

P1

K2

N1

K1

1

3

3

4

1

12

Graph for Question 14 / Graf untuk Soalan 14

59 69 79 89 99 109

0

10

20

30

40

50

60

70

Speed ( )

Laju ( )

Cumulative Frequency

Kekerapan Longgokan

80

90

119 129


15 (a)

(b)

Correct shape with hexagon ABKLGF. All solid lines.

AB > AF = LK > GL > BK = GF

Measurements correct to 2.0 cm (one way) and all angles at vertices = 90 1 .

Correct shape with rectangles EJKF and EFGH, triangles HMG,

JMH, KMJ and GMK. All solid lines.

FK > KJ = JH = EF > EH = FG

Measurements correct to 2.0 cm (one way) and all angles at vertices = 90 1 .

K1

K1

N1

K1

K1

N2

3

4

8 cm

6 cm

6 cm

4 cm

2 cm

A B

F G

K

L

E

F G/L

H/I J

K

M

6 cm 2 cm

6 cm


15 (b) (ii)

Correct shape with rectangles AFED and isosceles triangles PMQ.

All solid lines. Ignore dashed line.

PJ, JK and KQ joined by dashed line to form trapezium PJKQ.

AF = FE > EJ > EP = QF = JD

Measurements correct to 2.0 cm (one way) and all angles at vertices = 90 1

.

K1

K1

K1

N2

5

12

6 cm

6 cm

2 cm

4 cm

2 cm

3 cm 3 cm

A D

F E

K J

M

P Q


16 (a)

(b)

(c)

(d)

( 40º N//U, 145º W//B)

Note : 145º E // T or º W//B award P1

(180 – 40 – 40) 60

6000

97or 605820

57or 4097

Sº57

40 cos6025

Note : cos 40 correctly used award K1

600

5820071149*

62.11

P1P2

K1

N1

K1

K1

N1

K2

K1

N1

3

2

3

4

12

sijil pelajaran malaysia 2019 mathematics 1449/2 › wp-content › uploads › 2020 › 09 ›...

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