malacca_stpm_trial_maths_t1_2011
TRANSCRIPT
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SULIT*CONIIDENTIAL*954/lMathematics I20113 hours
954/l
MAJLIS PENGETUASEKOLAII MALAYSIACAWANGANMELAKAPEPERIKSAANPERCUBAANSIJIL TINGGI PERSEKOLAHANMALAYSIA 2011
MATHEMATICST.#:trJ,Inrtructionr to candidaterDONOTOPENTIIIS BOOKLETUNTIL YOUARETOLD TO DOSO
Answer ll questiow.Answercmq,beu,rittenn eltherEnglishorMalay.AII necessqrylorking houldbeshown learly.
Non-exaclumecql answersmaybegivenc,oftecto three ignilica rtgwes,or onedecimalplace n thecase fanglesn degrees,nlei a different vel o7oi"'il) i, ,p""t?"d in thequestion.Mqthematicalqbles, list ofmathematicalformutaendgraph qperareptovided,
Arahan pada alontJawabsemtl'aoalan.Jawopan olehditulisdalambahasanggeris taubahasaMelarySemuazrjayangperluhendaklahitunjuk*an enganelss.Jawapanerungkak tupatbolehdib,erikanetulhinggqigqangka eterti,qtausafl, empatperpuluhanalauhes udutdaram @jqh, ecuati raskilitwi yanf riin dttentutan aransoalan.
Sitb mqtematihehqraiumus atematikdankettasgrafdibetwlkan.__Thisquestiotraper onsistsf4 p-intedli!6-( eftassoatanni tedbi dafipado halamsnbercetak)@HakciptaMajlisPengetuaekolahMjaysia Cawanganeleri'iielata 2Of1
STPM95411*Kertqssoalqnni SLILIT ehinggaepefiksaanertasni tamat.*Thisquestionapers CONFIDENTIAL ntil theexarninationsover.[Lihat sebelahSULIT
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if A, B and C arearbitrary sets,show hat A - @ w C ) = ( A - B ) - C. [4 marks]
[4marks]
[6 marks]
[4marks][3ma*s]
[3marks]ll markl[4marks]
[5 ma*s]
[3 marks]
f l . t+11,l"z'.,(a)
(b)
(a)(b)(c)
- I + 2xExpressl-- asa series fascendingowersfx up1o le term n xl.' I (l-x)' [6marksjsrPM 95411*This questionpapers CONFIDENTIAL until the oxaminatiotrs over.
Using he rapeziumute,with live ordinales,uluut" [' )- * ." . /5x-3Detenninehe setofvaluesofx satisfting he nequality 2x - ll < ll_;. [5marks]
If v=x+e*-showhat 4 *-:l-= u' dY' (1+e') '
The tunction fis definedby f(x) =r0.
Find lifn- /(x) and liT. /(.r) .HeNrce,etfininewhether is continuousal x = 0.Sketch hegraphof f .
The complexnumbers l andz2 satisry he equ ior^ t - ziz - 5 = O.Express 1aod 22 n the form a+ bi, wherea andb are ealnumbers.Represent l and 22 in an Argand diagam.Foreachof zl and 22 find the modulusand he argumentn radians.
The differencebetween he distanoe fpoint P ftom thepoint (4 , 0) and hedistancof P ftom thepoint (-4 , 0) is zJio units. Show hat the ocus ofP is. . x ' y ' -he hvnentola'^ 10 6
Showalso hat the ine y = x - 2 is a tangeNto this curve.
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10
lBv takinex- i. find anapproximatioDf Jl20O0 intheformof Z wbereLVqp andq arepositive ntegers.. r - . 1 t2 f --LhtxDleSS
-In me lonn ,{ + +
-Mere A" tt. U zrno ,' ( r - lxr ' + l) x -) ) t ' + lareconstants.
Hence. valuate' ^ ^, ' ar.r ) ( r_ lx-r . +l )
Thepolynomial (x)= ax3 8xt+ bx+ 6, wherea a(Idb are ealconstants,sdrvrslDle y x- -zx -J.Find a and b.For thesevaluesof a andb, factorisep(x) completely.Show hat 2 is a zero ofthe polynomial3xa* l4x3+ llx2 + l6x- 12,Hence, olve heequation x4 14x3 11x2 l6x - 12= 0 by using hepolynomial p(x).
[3marks]
[5 marks]
[4 marks]
[5 marks][2 marks][2 marks]14marksl
[8 marks]
[5 marks]
[4marks][2ma*s][5marks]
(a)(b)(c)
11 (a) (zt to zz\ (a 7 -13)I fP=14 -8 4l .O=1, -5 c I and Q 72I .vheres he
t t - t t -[4 I t2) (-2 | r t )3 x 3 idqrtity matrix, determine the values ofa, b and c.Hence, uld r _.Using he esult n (a),solvehe system f linearequations
x.-2Y+z=0,x+ 2y+ 32:1080,6x+1Oy+82=4500.12 Thegradientofthe tangent o a curve at anypoint (x , y) is givenby
+ = -j--,- *ho""+ f . P (2 , 9 ) is apont or the curve.dx (2x-1)' 2(a) Find the equationofthe curve(b) Sketchhe cuwe.(c) Find the coordinates fthe mid-point ofQR ifthe normal o the curve atP
meetshey-axisand he x-axis atQ and R rcspectively.STPM 954ll*This questionpaper s CONFIDENTIAL until the exanriqations over.
(b)
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(d) A point (x , y) movesalong he curve n such a way tlat t1lex-coordinateinqeasesat a constantmte of0.03 uaitspersecond.Fiud the rute ofalrangeofthe y-coordinateat the nstantwhen hepoint passesbrcughP. [3 narks]
STPM 954/I*This questionpapers CONFIDENTIAL until the examinations over.
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MARKING SCITEME TRIAL EXAMINATION STFNI VIELAKA 2011MATHEMATICS T/S:PAPEROdestion Answers Rema.rksI LHS=A-(BuC),= A. (BuC)
-An(B'^C')=(AnB')^C'=(A-B)^c'=(A-B)-c
BIB1B1B1
DifferenceD MorganAssociativeDill'ercnceI41z xn: I Yo 0.7071 |x' : l .5 ve0.4114 lxr= 2 lyr=0.3780 _ ]x' :2.5 I vz:0.3244x4=3 ly4=0.2887 I
h=0.5J' J5r_3- ! ro.sro,zortz(o4i 4-o3'7Bo0.3244) .288?}2= 0.836
I)
B1
B1
MIA1 t4l
3 t2x-11
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Question Remarks-dxlaom l ' dy 1+e't l+ex):: '+ - _-:0Jy' ( l+e' ) '
cl"x e- -., ,-+-=uy' (1+e') '
AIA1
t6l5 (a, *tqXrtx)="ll11r+lt *o=lim /(r) = lim e-'z. 1
li l /(x) =1, t(o)zBut 14 (x) + "f(o). . f snotcontinuouslx= 1
'MlAI
MIAI
(b) R1R1RI
Modulusgaphexponential$aphclose ointat(0,2),-1,0).openpointat(0,1).Mustbelabelled
6 (a) 2i t2 ix4.| , 24=2 +i22=*2+r
+40x5) MIAI
AIa)zrcr. t) \
Im axis
,,41e,r)z---->Real axis
D1
(c) lzr l=F+t=./slzrl {5,r.,g"' =,*'' []J= 0.464adiane.eo: o.'l- zl]* 'r- 2.68adian
M1AIBIB1
Apply formulaofmodulus.Forbothans
Uol.noh( t tSt lnt t f , t ) l V" la|a l t l4R^t\ .S.HLML )
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An(wers
'7 Jr. ' r+y ryr \ ' ( "-4) ' -Y' -2 ' / l { )(J( . ' - -4) ' ) / - (2Vlo" ' r ( r -4r ' ' v t7rox +o + rq1"-+1' 1't| ---- lr4x rof= l l totr-+t ' ' l16x28ox+ 1oo: lo( x'?-8x+ 16+ f )3* - 5f =3010 63x'?sl = 30.. . . . . . . . . . . . . . (1)v=x-2. , , , . ' (2)3ubst.2) nto 1) 3* - 5(x-z)2
=30x2*1ox+25=o(x'-5)'? ox= 5,y-3Point f oontact5,3).. y = x - 2 is a angento thecurve
BIMI
M1A1
A1
MI
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MlA1 J1"3termsI correcl]4,PryI corroclMlAl I As above
MI musthavetrms 10
A1
l--:--I t+ zx
I(1+2t)'z
-1+l(2r)+2'=1+x-] . t '?+2(1 - x)-t
l ,_fvr,r , l , -1, - 1y2r),2. 2"-" , + 2' 2 2. +..-26l "2
r-r\/-1I= l+(-2X-x)+-(-jr)-= I+2x+3x2+4x3+'I(1+2r) t 1 x) '
* (-2X-JX-q)1_ry. ...
= I + 2x+ 3x2+4x3+x+ x2+ xt f,* -11+113+. .
'm:rr3x+:t ' - t j . 'r'**=rMalhemtict Tl/sl 20ll bial - Meldlia " MAPKNG SCIIEaE 3
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RemarksF;,1,rlr 'l \1ol 12000 {'?9sq8lJ'?t00*r , r , I r -ar l l 11,1, ,
l l l l0 2lo 2 lo= 4032000
....h2000- 2189432000
B1
IvI
AI
Subst : 1l0
tel9 x' -2x- l
( '- l)('z
+1)-r-r)().-+ ,- B . Cx+D(.x-lX.Y'+1)' x-| x2 +1
x2 2x -l = B ( x, +1)+ (Cx+D) x-Whenx=1,8=-1Whenx=0,D=0.Compareoeffof x'', C=2
l )
.12xx-l r" +1,)(x '?+1)T dx(x- l )(r '?+1)
=1'11-1+f; . rx4 -r- l .x- t l= [x - ln (x - 1)+ ln(x'+1)]], , 10= (J -2) - ln(:)+ ln(;)
BI
BI
MI
AI
M1A1M1A1
(Longdivisior)
l0 (a)
(b)
p(x)= (x' - 2x 3)Q(x)= (x-3X + 1)Q(x)l i i l i r to- t=o 11qt l v L9a+b= 22.. . . . . . . . . . . . . . . . . . . . . . . . . . . . . ( i )p(-1)= oa-8-b+6=0a+b =-2.. . . . . . . . . . . . . . . . . . . . . . . . . . . . . ( i i )a=3 b=-5p(x):3x3-8x2-5)(+6=(x,-2x-3)(3x-2)=(x-3Xx+1X3x-2)
BIM1A1MIA1M1AI
FactorizeForm2 eqn aa&bBoth corect
Solving heqnForbothanswe$Findthe linearfactor(cAo)
Mokenot:B Tl/S1 20IIftiol Melokr -- MARKINGSCHEME
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Rsmarks
(c) Let(x)-3xa- 14xrr . 1x2+ 6x- 12t(2)= 2(2)4 14(2)1 11{2)2 16x - 12=0..2 isazerooff(x)3x4- 14x3+lx2 + l6x- 12:o(x - 2)(3xr 8x'z-5x1 6)= 0( x-2) (x-3Xx+ 1X3x-2)- 0. ' .x:2,x=3,x= 1,x= 2i3
MIAI
MlAIM1AILongdivide oobtain (x),Factorize[13]
l l (4,
(b)
PQ=72r(24 40 32)(a z -r:l]4 -8 4l i b 5 c l=72t\4 8 12)\-2 | t I )(2aa a,b 64. 168-200+32| 4a-8b-B 28+40+I qa+8b-2c 28-40+12(72 o oll0 72 0l[0 0 12)4a+ 8b 24= 0.. . . , , . . . . , . . . . . ( i )4a 8b 8= 0 . . . . . . , . . , ( iD-312+40c+352=0 c=-1. . .a=4 b= 1c=-1PQ=72rl-po =t'72 -
l^P-t=iu
- 312+ 0c 3521-s2-Bc+441=-5r+R.+1l t I
(LL18 72I I -s=l i il l a\36 '72f' -, rlf/)l1 2 3 ly l[e ro s.J['J(24 40 32\(la -r al ll4 s rz][
iti ),01080.4500t;
II)000120
M1
AIAIMlAI
MI
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B1
Solving or a,b&c
Transform oreq. form
Matheha .tTI/Sl 20ll tml Melala MA?rJ:tC SaFEMa
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Ouestion ,Answers Rsrnarkst"'l1l, r l(22a| 1e0u60220^
'llJt'lt'li'j
8000.l0lt320)'18000
04320(4 7 - r3lf rsoou)l ' -5 - ' l l 0 l\-2 r rt ) \ 4320.)I
;),y= 190,2 160
M1
AI
Multiply(his)inverse
l2 (a)
(c,
(b)
dv6d.x (2t -t)'zn= [--i- a,- t 12x r).6' -2(2x-t)3
, . -1
ArP(2.9).9= i rc' 2(2)-1..c=10Theequation f thecu*" i, u = - J- n19
YI l ,x=r /2| / l") / :_i l , i . . ._____._l i / ' -l r /---*-**nffi
| : /I t ll i lGmdientoftangentat P= -Gradient fnormalat P : -i 2Ecn f normal tP s v- g : -],*- Z,"2
v: -1x + 12-2
AIRI
MIA1M1
B1B1MI
R1
For 2 brarlchesof ourve
All corett
MathematicsTlSl 2All Tial- Melaka , MAP,XINGSCHEME 6
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Answers
(d)
Q:(0, 12),R=(8,0)Mid-pointofQR = (4 , 6): = 0.03dt:a = : x(0.01)dt3
- 0.02 unit per second
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MIAl
ilatrmqtics TlA j 2011Trial- Mehkt - MARtuNGSC.{EME 'l