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Teknik Menjawab Matematik Kertas 2OLEH :CIKGU NORHAYATI BT. JAMBARI2/08/2015Yatie @ sinyat1

647ribusa64 0 0 72/8/2-15Yatie Jambari

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32 745 30 000 7/28/2015FAUZIAH AHMAD3

2x 2 = 45x 2 10 =0.47/28/2015FAUZIAH AHMAD4

2.3 kg /2.35 kg7/28/2015FAUZIAH AHMAD5 50 32 4 = ( 1 markah )0.08 4 0.32-03-032-3207/28/2015FAUZIAH AHMAD6

14+1 x 3=14+393 x 399=1797/28/2015FAUZIAH AHMAD7

silinder27/28/2015FAUZIAH AHMAD8

11.43x41722 910102.3001721287/28/2015FAUZIAH AHMAD9

Rajah 3JamMinit815++408557/28/2015FAUZIAH AHMAD10

RM125x 3RM375RM37.5010RM375.00-3075-7050-500-00 30xRM125100=3 x RM12510= RM37510=RM37.507/28/2015FAUZIAH AHMAD11

4.05 m = 4.05 x 100 = 405.00 cm 3 10 405 cm 155 cm 250 cm7/28/2015FAUZIAH AHMAD12

RM5 X 2 = RM10.00RM2 X 2 = RM 4.00RM1 X 2 = RM 2.00 + RM16.00

50 + 20 + 20 = 90 sen RM16.00+ RM 0.90 RM16.907/28/2015FAUZIAH AHMAD13

Purata = 750 g + 3.9 kg + 2.07 kg 3 750 1000 = 0.750 kg 0.750 3.900+ 2.070 6.7202.2436.726761212Purata = 750 g + 3.9 kg + 2.07 kg 3 = 6.720 kg 3 = 2.24 kg7/28/2015FAUZIAH AHMAD14

55571Perimeter = ( 1 + 7 + 6 + 7 + 5 + 5 + 5 ) cm = 36 cm 1 cm 7 cm 6 cm 7 cm 5 cm 5 cm+ 5 cm 36 cm7/28/2015FAUZIAH AHMAD15

1 minggu = 7 hari6minggu745hari-423hari45 hari = 6 minggu 3 hari7/28/2015FAUZIAH AHMAD16

22 cm36 cm 6 02Luas 1 petak = 2 cm x 2 cm = 4 cmLuas kawasan yang tidak berlorek = 4 cm x 6 = 24 cm7/28/2015FAUZIAH AHMAD17

RM2.50 10 x 6 =RM0.2510RM2.50-025-2050-500 1 3 RM 0.25x 6 RM 1.507/28/2015FAUZIAH AHMAD18

2.6 l = 2.6 x 1000 = 2600.0 ml 2600 ml 850 ml 1750 ml 850 ml = 850 1000 = 0.850 l 2.600 l 0.850 l 1.750 lCARA 1CARA 27/28/2015FAUZIAH AHMAD19

2 2 RM 0.65x 4 RM 2.60+ RM 2.00 RM 4.607/28/2015FAUZIAH AHMAD20

Kawasan berlorek = 5Kawasan tidak berlorek = 5 Seluruh rajah = 10Peratus kawasan berlorek=5x100 % 10=50%7/28/2015FAUZIAH AHMAD21