Download - DATA KELOMPOK
![Page 1: DATA KELOMPOK](https://reader035.vdokumen.net/reader035/viewer/2022062521/56814d58550346895dba953e/html5/thumbnails/1.jpg)
DATA KELOMPOKISTILAH:
Berat (kg) Frek
50 – 56 2
57 – 63 8
64 – 70 5
71 – 77 3
20
Kelas: ada 4
Batas kelas:Pada kelas 57 – 63, batas bawah 57, batas atas 63
Tepi kelas:Pada kelas 57 – 63, tepi bawah 56,5 , tepi atas 63,5
Panjang kelas (interval):= tepi atas – tepi bawah = 57 – 50 , = 64 – 57 = 7
Titik tengah kelas (Xi):
Pada kelas 50 – 56, titik tengahnya 0,5 (50 + 56) = 53
![Page 2: DATA KELOMPOK](https://reader035.vdokumen.net/reader035/viewer/2022062521/56814d58550346895dba953e/html5/thumbnails/2.jpg)
Contoh:
min:jangkauan XXJ maks
nk log3,31:kelasbanyak
kJi :interval
Buatlah menjadi data kelompok:18 24 26 29 3320 24 26 30 3520 25 27 31 3621 25 28 31 3722 25 29 33 37
191837 J661,525log3,31 k
417,3619
i
kelas turus frek17 – 20 III 321 – 24 IIII 425 – 28 IIIII II 729 – 32 IIIII 533 – 36 IIII 437 – 40 II 2
25
n = 25
Data tunggal dapat dibuat menjadi data kelompok dgn aturan Sturges:
![Page 3: DATA KELOMPOK](https://reader035.vdokumen.net/reader035/viewer/2022062521/56814d58550346895dba953e/html5/thumbnails/3.jpg)
Soal: buatlah menjadi data kelompok
kelas turus frek56 – 60 IIIII 561 – 65 IIIII II 766 – 70 IIIII III 871 – 75 IIIII I 676 – 80 IIIII I 681 – 85 IIIi 4
36
log 36 = 1,556
57 63 66 69 74 7857 63 66 70 75 7958 64 66 71 76 8159 64 67 71 76 8160 65 68 72 76 8262 65 68 73 77 82
255782 J613,636log3,31 k
517,4625
i
![Page 4: DATA KELOMPOK](https://reader035.vdokumen.net/reader035/viewer/2022062521/56814d58550346895dba953e/html5/thumbnails/4.jpg)
MENENTUKAN MEAN
Titik tengah:fiXifiX
.
Rataan sementara:fidifiXsX
.
Coding: ificifiXsX ..
![Page 5: DATA KELOMPOK](https://reader035.vdokumen.net/reader035/viewer/2022062521/56814d58550346895dba953e/html5/thumbnails/5.jpg)
Contoh: tentukan Mean dari:
kelas frek fi
50 – 56 5
57 – 63 2
64 – 70 7
71 – 77 4
18
titik tengah Xi
53
60
67
74
fi . Xi
265
120
469
296
1150
89,63181150
x
fi . di
–70
–14
0
28
–56
67Xsdi =
Xi – 67
–14
–7
0
7
89,63185667
x
ci
–2
–1
0
1
fi . ci
–10
–2
0
4
–8
89,637.18867
x
7
![Page 6: DATA KELOMPOK](https://reader035.vdokumen.net/reader035/viewer/2022062521/56814d58550346895dba953e/html5/thumbnails/6.jpg)
Soal: dengan 3 cara, tentukan Mean dari:
kelas frek fi
112 – 120 6
121 – 129 9
130 – 138 12
139 – 147 25
148 – 156 8
60
titik tengah Xi
116
125
134
143
152
fi . Xi
696
1125
1608
3575
1216
8220
137608220
x
fi . di
–162
–162
–108
0
72
–360
143Xsdi =
Xi – 143
–27
–18
–9
0
9
13760360143
x
ci
–3
–2
–1
0
1
fi . ci
–18
–18
–12
0
8
–40
1379.6040143
x
9
![Page 7: DATA KELOMPOK](https://reader035.vdokumen.net/reader035/viewer/2022062521/56814d58550346895dba953e/html5/thumbnails/7.jpg)
MENENTUKAN MODUS
kelas frek fi
50 – 56 5
57 – 63 2
64 – 70 7
71 – 77 4
18
kelas Modus: 64 – 70
tepi bawah: tb = 63,5
idd
dtMo b .21
1
d1 = selisih frek kelas Mo dgn sebelumnya
d2 = selisih frek kelas Mo dgn sesudahnya
d1 = 7 – 2 = 5 d2 = 7 – 4 = 3
875,677.3555,63
Mo
![Page 8: DATA KELOMPOK](https://reader035.vdokumen.net/reader035/viewer/2022062521/56814d58550346895dba953e/html5/thumbnails/8.jpg)
Bagaimana jika ada frekuensi yg sama?
0,68211428
x 0,687.212476
x
kelas fi52 - 58 359 - 65 566 - 72 673 - 79 680 - 86 1 21
Xi5562697683
f . Xi16531041445683
1428
ci fi.ci-3 -9-2 -10-1 -60 01 1 -24
ci fi.ci-2 -6-1 -50 01 62 2 -3
0,687.21369
x
Kelas Mo: 66 – 72 d1 = 1 , d2 = 0 5,727.0115,65
Mo
Kelas Mo: 73 – 79 d1 = 0 , d2 = 5 5,727.5005,72
Mo
![Page 9: DATA KELOMPOK](https://reader035.vdokumen.net/reader035/viewer/2022062521/56814d58550346895dba953e/html5/thumbnails/9.jpg)
Bagaimana jika ada frekuensi yg sama?
88,67251697
x 88,677.252976
x
kelas fi52 - 58 359 - 65 866 - 72 573 - 79 880 - 86 1 25
Xi5562697683
f . Xi16549634560883
1697
ci fi.ci-3 -9-2 -16-1 -50 01 1 -29
ci fi.ci-1 -30 01 52 163 3 21
88,677.252162
x
Kelas Mo: 59 – 65 d1 = 5 , d2 = 3 875,627.3555,58
Mo
Kelas Mo: 73 – 79 d1 = 3 , d2 = 7 6,747.7335,72
Mo
![Page 10: DATA KELOMPOK](https://reader035.vdokumen.net/reader035/viewer/2022062521/56814d58550346895dba953e/html5/thumbnails/10.jpg)
MENENTUKAN KUARTIL
if
fn
tQK
b .41
if
fn
tQK
b .22
if
fn
tQK
b .43
3
![Page 11: DATA KELOMPOK](https://reader035.vdokumen.net/reader035/viewer/2022062521/56814d58550346895dba953e/html5/thumbnails/11.jpg)
Contoh: tentukan Q1, Q2, Q3 dari: if
fn
tQK
b .41
Letak Q164
244 n
13 – 17
24132-28827-23522-18717-13312-8fikelas
24132-28827-23522-18717-13312-8fikelas
64,145.7365,121
Q
Letak Q2122
242 n
18 – 22
50,195.510125,172
Q
Letak Q3184
24343
n
23 – 27
375,245.815185,223
Q
![Page 12: DATA KELOMPOK](https://reader035.vdokumen.net/reader035/viewer/2022062521/56814d58550346895dba953e/html5/thumbnails/12.jpg)
Soal: tentukan Q1, Q2, Q3 dari:
Letak Q194
364 n
65 – 73
50,739.5495,641
Q
Letak Q2182
362 n
83 – 91
0,849.1216185,822
Q
Letak Q3274
36343
n
83 – 91
75,909.1216275,823
Q
368100-92
1291-83782-74573-65464-56fikelas
368100-92
1291-83782-74573-65464-56fikelas
![Page 13: DATA KELOMPOK](https://reader035.vdokumen.net/reader035/viewer/2022062521/56814d58550346895dba953e/html5/thumbnails/13.jpg)
Nilai UH Math IPA 5:
c. Jika KKM = 69, 0 berapa siswa yg lulus?368100-92
1291-83782-74573-65464-56fikelas
368100-92
1291-83782-74573-65464-56fikelas
a. Jika peringkat 10 besar akan dapat bonus, berapa batasan nilainya?
b. Peringkat 12 terkecil harus ikut Remed. Jika nilai Rio 77, apakah ia ikut Remed?
90,0
77,4
29
![Page 14: DATA KELOMPOK](https://reader035.vdokumen.net/reader035/viewer/2022062521/56814d58550346895dba953e/html5/thumbnails/14.jpg)
Nilai fi
51 - 58 14
59 - 66 12
67 - 74 20
75 - 82 16
83 - 90 28
90
Soal, tentukan:a. batas nilai 20 besar
b. batas 45 siswa terbaik
c. KKM 69, berapa yg lulus?
![Page 15: DATA KELOMPOK](https://reader035.vdokumen.net/reader035/viewer/2022062521/56814d58550346895dba953e/html5/thumbnails/15.jpg)
SIMPANGAN RATA-RATA
kelas fi42 - 48 649 - 55 756 - 62 763 - 69 570 - 76 3 28
ci-10123
fi ci-60710920
Hitung Mean dulu.
0,577.282052
x
Xi4552596673
12 5 29
16
xXi
7235 144548
214
xX. i fi
64,728214
SR
![Page 16: DATA KELOMPOK](https://reader035.vdokumen.net/reader035/viewer/2022062521/56814d58550346895dba953e/html5/thumbnails/16.jpg)
Soal
kelas fi50 - 59 360 - 69 870 - 79 980 - 89 190 - 99 4 25
ci–2 –1 012
fi ci-6–8 018
–5
Tentukan Simpangan Rata-rata dari:
Xi54,564,574,584,594,5
18 8 2
1222
xXi
5464181288
236
xX. i fi
44,925236
SR5,7210.2555,74
x
![Page 17: DATA KELOMPOK](https://reader035.vdokumen.net/reader035/viewer/2022062521/56814d58550346895dba953e/html5/thumbnails/17.jpg)
RAGAM/VARIANS & SIMPANGAN BAKU
kelas fi42 - 48 649 - 55 756 - 62 763 - 69 570 - 76 3 28
ci–10123
fi ci–60710920
Xi4552596673
–12 –5 29
16
xXi
864175 28
405768
2.240
2i xXfi.
80282240
Var 94,880 SB
0,577.282052
x
![Page 18: DATA KELOMPOK](https://reader035.vdokumen.net/reader035/viewer/2022062521/56814d58550346895dba953e/html5/thumbnails/18.jpg)
Soal
kelas fi50 - 59 360 - 69 870 - 79 980 - 89 190 - 99 4 25
ci–2 –1 012
fi ci-6–8 018
–5
Tentukan Simpangan Baku dari:
Xi54,564,574,584,594,5
–18 –8 2
1222
97251236
1441.9363.600
5,7210.2555,74
x
xXi 2i xXfi.
144253600
Var 0,12144 SB
![Page 19: DATA KELOMPOK](https://reader035.vdokumen.net/reader035/viewer/2022062521/56814d58550346895dba953e/html5/thumbnails/19.jpg)
HISTOGRAM
kelas fi42 - 48 649 - 55 756 - 62 763 - 69 570 - 76 3 28
2
4
6
41,5 48,5 55,5 62,5 69,5 76,5
![Page 20: DATA KELOMPOK](https://reader035.vdokumen.net/reader035/viewer/2022062521/56814d58550346895dba953e/html5/thumbnails/20.jpg)
Soal: buatlah tabel distribusi frekuensi dari:
4
8
12
52,5 60,5 68,5 76,5 84,5 92,5
40292-85884-77
1476-69668-61
1060-53fikelas
40292-85884-77
1476-69668-61
1060-53fikelas
Latihan soal, dari buku Mandiri