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ANSWER FOR QUESTION 1

1 (a) (i) [KB0601 - Observation]

Score Criteria

3 Able to state any two observations correctly according to the criteria:

o Sample

o Time taken

o Become colourless

Sample answers:

1. Time taken for methylene blue to become colourless for sample P is 10 minutes.

2. Time taken for methylene blue to become colourless for sample R is 42 minutes

3. Time taken for methylene blue to become colourless for sample Q is 23 minutes

4. Time taken for sample P is 10 minutes that is shorter than time taken for sample R

that is 42 minutes to become colourless

2 Able to state any one observation correctly.

orAble to state any two incomplete observations ( any 2 criteria)

Sample answers:

1. Time taken for methylene blue to become colourless for sample P is

shorter

2. Time taken for methylene blue to become colourless for sample R that is longer

3. Time taken for sample P is shorter than time taken for sample R

4. Time taken for sample P is less 13 minutes from sample Q to become colourless

5. Time taken for sample P/Q/R is 10 minutes/ 23 minutes/42 minutes

1 Able to state any one idea of observation.(any 1criteria)Sample answers:

1. Different sample has different time taken

2. Time taken varied in this experiment

3. Sample P,Q and R has different time taken

4. Methylene blue become colourless

5.

0 Not able to response orwrong response.

1 (a) (ii) [KB0604 - Making inferences]

Score Criteria3 Able to make one logical inference for each observationbased on the criteria

o Sample

o Oxygen concentration

o Duration of time for methylene blue to become colourless

Sample answers:

1. In sample P, oxygen concentration is low, the methylene blue become colourless

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very fast/ less time taken

2. Oxygen concentration in sample R is high, the methylene blue become

colourless slow/ longer time taken

3. Oxygen concentration in sample P is lower than oxygen concentration in sample R,

the time taken for methylene blue to become colourless is shorter.

2 Able to make one logical inference for any one observation.

orAble to make one logical and incomplete inference base on 2 criteria for each

observation.

Sample answer:

1. In sample P, oxygen concentration is low

2. Oxygen concentration in sample R is high

3. When oxygen concentration is low, the methylene blue become colourless very

fast/ take a shorter time4. When oxygen concentration is high, the methylene blue become colourless

very slow/ take a longer time

1 Able to make an idea of inference with one criterion.

Sample answers

1. Oxygen concentration affect the time for the methylene blue to become

colourless

2. different sample has different oxygen concentration3. the longer the time the less oxygen in the water

0 Inference not corresponding to the observation or Not able to response or wrong

response.

(b)(i) [KB0603 Measuring Using Number]

Score Criteria

3 Able to record all the time taken with unit in the boxes given accurately

Sample answers

Sample time

P 10 minutes

Q 23 minutes

R 42 minutes

2 Able to record two reading with unit accurately

1 Able to record one reading with unit accurately

Able to record all the time taken without unit


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(b)(ii) [KB0606 Communicating]

Score Criteria

3 Able to tabulate a table and fill in data accurately base on three criteria:

o Table draw with labeled column.

o Sample

o Time taken with unit.

Sample answers :

Sample Time taken ( minutes)

P 10

Q 23

R 42

2 Able to tabulate a table base on two criteria

1 Able to Able to tabulate a table base on one criterion0 Not able to response orwrong response.

(b) (iii) [KB0607 Interprating Data]

Scor

e

Criteria

3 Able to state clearly and accurately the relationship between:

o time taken

o oxygen content

o BOD level

Sample answer:

1. The shorter time taken for methylene blue to become colourless, less oxygen inthe water and BOD level is high.

2 Able to state clearly but less accurate the relationship base on 2 criteria:

Sample answer:

1. The shorter time taken for methylene blue to become colourless, pollution level

is high.

2. When less oxygen in the water and the pollution level of the water is high.3. The shorter time taken for methylene blue to become colourless, less oxygen inthe water.

1 Able to state the idea of the relationship base on 1 criterion

Sample answer

1. The shorter time taken the more polluted the water

2. Oxygen level shows that the water is polluted

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(c) [KB061001 Controling Variables]

Variables How the variables are operated

Manipulated:

Water sample Water sample is collected from three different locations.

Responding variable

Time taken

Time taken for methylene blue to become colourless is recorded

by a stopwatch.

Fixed variable

Metlhylene blueconcentration / volume/

volume of water sample

o.1% of Methylene blue is used for all experiments/ 1 ml volume/

200 ml of water sample.

(d) [KB0611- Making Hypothesis]

Scor

e

Criteria

3 Able to state a hypothesis to show a relationship between the manipulated variable andresponding variable and the hypothesis can be validated, base on 3 criteria:

manipulated variable

responding variable

relationship

Sample answer :

1. The most polluted water has shortest time for methylene blue to becomecolourless.

2. Sample water P is most polluted has shortest time for methylene blue to

become colourless.

3. Sample water R is less polluted has longest time for methylene blue to becomecolourless,

2 Able to state less accurate hypothesis to show a relationship between manipulated

variable and responding variable base on 2 criteria.

Sample answer

1. The most polluted water is sample water P

2. Sample water R is least polluted3. The shorter time taken, the less oxygen in the water

4. The longer time taken, the more oxygen in the water

5. The different water sample has different time taken for methylene blue to

become colourless

1 Able to state idea of hypothesis to show a relationship between manipulated variable

and responding variable base on 1 criterion.

Sample answer

1. Time taken depends on oxygen level

2. Oxygen level affect the time taken for methylene blue to become colourless3. The less oxygen in the water, the more polluted the water.

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4. The more oxygen in the water, the less polluted the water


(e) [KB0608 Space and Time Relationship]

Score Criteria

3 Able to state clearly and accurately the relationship between increasing the time and

the level of pollution in the water base on criteria:

o Time taken

o Pollution level

o relationship

Sample answer:

1. The longer the time taken for methylene blue to become colourless the less

polluted water is been used.2. The shorter the time taken for methylene blue to become colourless the more

polluted water is been used.

2 Able to state clearly but less accurate the relationship between increasing the air

movement speed with the rate of transpiration base on 2 criteria

Sample answer:

1. The time taken for methylene blue to become colourless the shows the

pollution level

2. Water pollution affected the time taken methylene blue to become colourless

1 Able to state the idea of the relationship base on 1 criteriaSample answer:

1. Different time taken is recorded from different types of water used

2. Level of pollution can be detected by different time taken


(f) [KB0609 [Define operationally]

Score Criteria

3 Able to explain BOD base on experiment correctly according to the criteria:

o Amount of oxygen in the water sample

o used by microorganisms

o shown by time taken

Sample answer:

1. BOD is amount of oxygen in the water sample that used by microorganisms and canbe shown by time taken of methylene blue to become colourless.

2 Able to state BOD base on experiment:

Sample answer:

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1. BOD is amount of oxygen in the water and can be shown by time taken by methyleneblue to become colourless

1 Able to state the idea of BOD or the theoretical definition of BOD

1. Biological Oxygen Demand (BOD) is a measure of the oxygen used by

microorganisms to decompose waste2. BOD is amount of oxygen in the water


(g) [KB0605 Predicting]

by using water sample from chicken farm area

Score Criteria

3 Able to predict the result accurately.

o Expected time

o Compare to which

o Reason

Sample answer:

1. The time taken for methylene blue to become colourless is 5 minutes, less than watersample P, because chicken farm water can be contaminated with chicken faeces/ or any

other answer.

2 Able to predict the result less accurate:

Sample answer:

1. The time taken for methylene blue to become colourless is 5 minutes, because chickenfarm water can be contaminated with chicken faeces

2. The time taken for methylene blue to become colourless less than water sample P,because chicken farm water can be contaminated with chicken faeces

3. The time taken for methylene blue to become colourless is 5 minutes, less than watersample P.

1 Able to give idea of the result

1. time taken is shorter

2. water from this area is polluted


(i) [KB0602 Classifying]

Score Criteria

3 Able to arrange the 3 level of polluted water

Sample answer:

Types of water PollutedP Most

Q Moderate

R Least Most polluted least polluted

P Q R


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ANSWER FOR QUESTION 2

Problem statement

Score Criteria

3 Able to state the problem statement of the experiment correctly that include

criteria:

C 1: Manipulate variables

C 2: Responding variables

C 3: Relation in question form and question symbol [?]

Example :

Problem statement:

1. What is the population size / percentage coverage / density / frequency of

Mimosa pudica andImperata cylindrica in the school field?

2 Does the type of plant species affects the population size / percentage

coverage / density / frequency of the plants?

3. Which type of the plant species/ species Mimosa pudica orImperata

cylindrica has the highest percentage coverage/ population size?

2 Able to state the problem statement of the experiment with two criteria;

Example:

Problem statement:

1. Species Mimosa pudica andImperata cylindrica have different population

size/ percentage coverage/ density.

2. What is the percentage coverage/ population size / density of plants?

1 Tick Able to state the of problem statement with one criteria.

Example:

Problem statement:

1. Which plant is dominant?

0 No response or wrong response.

Aim

Score Criteria

Tick To estimate/ determine / study the population size / percentage coverage /

density / frequency ofMimosa pudica andImperata cylindrica in the school

field using the quadrat sampling technique.

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Hypothesis

Score Criteria

3 Able to state the hypothesis correctly according to the criteria:

C 1: Manipulate variables

C 2: Responding variables

C 3: Relationship of the variables

Example

1. The population size / percentage coverage / density / frequency of

species Mimosa pudica plant is higher than species Imperata cylindrica

in the school field.

2. Different plant species have different population size / percentage

coverage / density / frequency.

3. Plant species Mimosa pudica is more dominant than speciesImperata

cylindrica in this habitat.

2 Able to state the hypothesis with two criteria

Example:

1. Plant species affects population size / percentage coverage / density /frequency.

2. Species Mimosa pudica /Imperata cylindrica has the highest

population size / percentage coverage/ density / frequency.

3. Species Mimosa pudica is more dominant in the habitat.

1 Tick Able to state the idea of the hypothesis.0 No response or wrong response.

Variables

Score Criteria

Tick Able to state the three variables correctly

Example:

Manipulated variable:

Type of plant species/ species Mimosa pudica andImperata cylindrica / twoexample of plant species.

Responding variable:

Population size / percentage coverage / density / frequency of plants

Controlled variable : Quadrat size, school field.

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Materials and apparatus

Score Criteria

3

Tick

Able to state all functional materials/ 2 materials and 4 apparatus for the

experiment .

Materials : Plant species Mimosa pudica andImperata cylindrica B.

Apparatus : Plastic quadrat, marker pen, A4 Paper, graph paper.

2 Able to state 1 material and 2 apparatus for the experiment

1 Able to state 1 material and 1 apparatus for the experiment.

0 No response or wrong response

Bonus marks:technique and data = 2 marks

Technique :

Score Criteria

Tick

Bonus1

Able to state the action on responding variable with an apparatus.

Example:

Measure and record the area of each type of species using a quadrat 1m x 1m// Calculate the percentage coverage of plant // species Mimosa pudica and

Imperata cylindrica using the formula:

Total area covered by the species X 100%

Number of quadrats X area of one quadrat

// Calculate the density of plant species using the formula:Total number of organisms in all quadratsNumber of quadrats X area of one quadrat

// Calculate the frequency of plant species using the formula:No. of quadrat containing the species X 100%

Total number of quadrats

Procedure (Refer to procedure in example)

Score Criteria

3 Able to state fiveprocedures P1,P2,P3,P4 & P5 correctly:

P1 : How To Set Up The Apparatus

P2 : How To Make Constant The Control Variable

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P3 : How To Manipulate The Manipulated Variable

P4: How To Record The Responding Variable

P5 : Precaution

2 Able to state three of any procedures correctly

1 Tick Able to state two of any procedures correctly


Data

Score Criteria

Tick

Bonus

1

Able to tabulate the correct table with units

Example:

Plant

species

Number/ area of plant species

in the quadrat

1 2 3 4 5 6 7 8 9 1

0

Total

number/areaof plant

species(m2 )

Density/

percentagecoverage

area (%)

M.pudica

I.cylindrica

Conclusion

Score Criteria

Tick Able to rewrite the hypothesis correctly.

Example:and

1. The percentage coverage// population size of species Mimosa pudica

plant is higher than speciesImperata cylindrica in the school field? or

2. Different plant species have different percentage coverage// population

size . or

3. Plant Mimosa pudica is more dominant thanImperata cylindrica in this

habitat.Hypothesis is accepted.

Planning the experiment

Score Criteria

3 Able to plan the experiment based on 8-9 of the following criteria :

Statement of identified problem

Objective of study

Variables

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Statement of hypothesis

List of materials and apparatus

Technique used

Experimental procedures

Presentation of data

Conclusion

2 Able to plan the experiment based on 4-7 of the criteria :

1 Able to plan the experiment based on2-3 of the criteria :


Example of Procedure.

1 School field was chosen as the field study (P1)

2 Quadrats of size 1m x 1m was used. (P2)

3 Two plants species Mimosa pudica and Imperata cylindrica was identified (P3)

4 The quadrats were thrown at random in the school field (P1)

5 The area of (coverage) each plant species was counted// the number of

individual plant species in each quadrat was counted.

(P4)

6 If more than half of the squares in the quadrat are covered, the area of plant

species will be counted. The area is not counted if only less than half is

covered.

(P5)

7 Steps 5 to 7 was repeated for nine quadrats (P1)

8 The area covered by plant species / species Mimosa pudica and speciesImperata cylindrica / number of individual plant species studied in each

quadrat were recorded and tabulated in a table.

(P4)

9 The percentage coverage / density / frequency of plant species / speciesMimosa pudica and species Imperata cylindrica were calculated by using

this formula:

(P4)

Percentage coverage of plant species :

= Total area covered plant species in all quadrats X 100%

Total number of quadrats X area of a quadrat

// Frequency of species = Number of quadrat containing plant species X 100%Total number of quadrats

// Density of plant species = total number of individual species in all quadrats

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Total number of quadrats X area of a quadrat

PERATURAN PERMARKAHAN TAMAT

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bio p3 sbp 2008

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