8/20/2019 Assisgment Sheet 2- Muhammad Afiq Bin Mohd Zimahdi

1/32

Assisgment Sheet 2

Code / Course :-

KFC 2144 / Network Fundamental

Lecture :-

!"# S"$K%& '&N $"AA# "$S&N

(ro)lem 1

Host IP Address 172.30.1.33Subnet Mask 255.255.255.0Number of subnet bits 8 BitsNumber of subnets 28! 25" Subnet

Number of Host bits Per Subnet 25#Number of usab$e Hosts %er Subnet 28&2 ! 25"&2 ! 25# Host Per SubnetSubnet Address for t'is IP address 172.30.1.0IP address of (irst 'ost on t'is subnet 172.30.1.1IP Address of )ast Host on t'is subnet 172.30.1.25#Broad*ast Address for t'is subnet 172.30.1.255

Ste% 1 + ,rans$ate 'ost IP Address and subnet mask into Binar- natation

172 30 1 33

IP A/SS 10101100 00011110 0000000100100001

Subnet Mask 11111111 11111111 11111111

00000000

255 255 255 0

(irst )ist don t'ese a$ue of Numbers.

 ,ake t'e Host IP Address 172.30.1.30 and Start it' t'e (irst 4*tet * 1+2 ,

IP Address Ansers Binar-

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1+2 / 2 . . / 2 40 40 / 2 21 121 / 2 1 11 / 2

/ 2 2 12 / 2 1 1 / 2 1

So no e kno t'at a e*ima$ Number 172 is 1111 *onerted to Binar-

from.

2 4*tet * 0 , 

IP Address Ansers Binar-0 / 2 1

1 / 2 + 1+ / 2 0 10 / 2 1 11 / 2 1

Binar- Natation for t'e number 0 is 1111

3 4*tet 6 1 

IP Address Ansers Binar-1 / 2 1 1

Binar- Natation (or t'e number 1 is 1

# 4*tet * 00 ,

IP Address Ansers Binar-00 1. 1

1. / 2 / 2 4 4 / 2 2 2 / 2 1 1 / 2 1

Binar- Natation for t'e number 00 is 11

So t'e IP Addressof 1+20100 'as its binar- form euia$ent of +

11111111111

Su)net ask 

/e%eat t'e same %ro*edure used for t'e IP Address to *onert t'e subnet Mask

into Binar- notation.

1 4*tet * 2 , 

IP Address Ansers Binar-2 / 2 12+ 1

12+ / 2 .0 1.0 / 2 01 1

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01 / 2 1 11 / 2 + 1+ / 2 0 10 / 2 1 11 / 2 1

Binar- Notation for t'e number 2 is 11111111

2 4*tet * 2 ,

IP Address Ansers Binar-2 / 2 12+ 112+ / 2 .0 1.0 / 2 01 101 / 2 1 11 / 2 + 1

+ / 2 0 10 / 2 1 11 / 2 1

Binar- Notation for t'e number 2 is 11111111

3 4*tet * 2 , 

IP Address Ansers Binar-2 / 2 12+ 112+ / 2 .0 1.0 / 2 01 101 / 2 1 1

1 / 2 + 1+ / 2 0 10 / 2 1 11 / 2 1

Binar- Notation for t'e number 2 is 11111111

# 4*tet * , 

IP Address Ansers Binar- / 2 / 2 / 2

/ 2 / 2 / 2 / 2 / 2

Binar- notation for t'e number  is 6 sin*e t'ere is no number to

subtra*t for  so automati*a$$- t'e anser is .

 So the &( Addresso3 222 has its )inar 3orm e5ui6alent o3 :

111111111111111111111111

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Num)er o3 Su)net 'its :-

255.255.2998

111111111111111111111111111111

Num)er o3 "ost :-

28

Num)er o3 "ost 'its 7er su)net :-

289925"

Num)er o3 usa)le "osts 7er Su)net :-

28 : 2 ! 25" : 2 ! 25#

&( Address o3 8rst host on this su)net :-

172.30.1.33 10101100 00011110 00000001 11

172.30.1.1 10101100 00011110 00000001 1

&( Addresso3 Last "ost on this su)net :-

172.30.1.1 10101100 00011110 00000001 00000001

172.30.1.25# 10101100 00011110 00000001

1111111

'roadcast Address3or this su)net :-

;se 8 Number of )ast Host

172.30.1.0 10101100 00011110 00000001

172.30.1.255 10101100 00011110 00000001

11111111

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(ro)lem 2

Host IP Address 172.30.1.33Subnet Mask 255.255.255.252Number of subnet bits 1# BitsNumber of subnets 22! # Subnet

Number of Host bits Per Subnet #Number of usab$e Hosts %er Subnet 22&2 ! #&2 ! #Host Per SubnetSubnet Address for t'is IP address 172.30.1.32IP address of (irst 'ost on t'is subnet 172.30.1.33IP Address of )ast Host on t'is subnet 172.30.1.3#Broad*ast Address for t'is subnet 172.30.1.35

172 30 1 33

IP A/SS 10101100 00011110 00000001

00100001

Subnet Mask 11111111 11111111 11111111

11111100

255 255 255 252

(irst )ist don t'ese a$ue of Numbers.

 ,ake t'e Host IP Address 172.30.1.30 and Start it' t'e (irst 4*tet * 1+2 ,

IP Address Ansers Binar-1+2 / 2 .

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. / 2 40 40 / 2 21 121 / 2 1 11 / 2 / 2 2 1

2 / 2 1 1 / 2 1

So no e kno t'at a e*ima$ Number 172 is 1111 *onerted to Binar-

from.

2 4*tet * 0 , 

IP Address Ansers Binar-0 / 2 1 1 / 2 + 1

+ / 2 0 10 / 2 1 11 / 2 1

Binar- Natation for t'e number 0 is 1111

3 4*tet 6 1 

IP Address Ansers Binar-1 / 2 1 1

Binar- Natation (or t'e number 1 is 1

# 4*tet * 00 ,

IP Address Ansers Binar-00 1. 1

1. / 2 / 2 4 4 / 2 2 2 / 2 1 1 / 2 1

Binar- Natation for t'e number 00 is 11

So t'e IP Addressof 1+20100 'as its binar- form euia$ent of +

11111111111

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Su)net ask /e%eat t'e same %ro*edure used for t'e IP Address to *onert t'e subnet Mask

into Binar- notation.

1 4*tet * 2 , 

IP Address Ansers Binar-2 / 2 12+ 112+ / 2 .0 1.0 / 2 01 101 / 2 1 1

1 / 2 + 1+ / 2 0 10 / 2 1 11 / 2 1

Binar- Notation for t'e number 2 is 11111111

2 4*tet * 2 ,

IP Address Ansers Binar-2 / 2 12+ 112+ / 2 .0 1.0 / 2 01 101 / 2 1 11 / 2 + 1+ / 2 0 10 / 2 1 11 / 2 1

Binar- Notation for t'e number 2 is 11111111

3 4*tet * 2 , 

IP Address Ansers Binar-

2 / 2 12+ 112+ / 2 .0 1.0 / 2 01 101 / 2 1 11 / 2 + 1+ / 2 0 10 / 2 1 11 / 2 1

Binar- Notation for t'e number 2 is 11111111

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# 4*tet * 22 , 

IP Address Ansers Binar-22 / 2 12. 12. / 2 .0 .0 / 2 01 101 / 2 1 11 / 2 + 1+ / 2 0 10 / 2 1 11 / 2 1

Binar- notation for t'e number 22 is 111111 6 sin*e t'ere is no number to

subtra*t for  so automati*a$$- t'e anser is 111111 .

 So the &( Addresso3 22222has its )inar 3orm e5ui6alent o3 :

111111111111111111111111111111

Num)er o3 Su)net 'its :-

255.255.2998

111111111111111111111111111111

Num)er o3 "ost :-

21#

Num)er o3 "ost 'its 7er su)net :-

21#991" 38#

Num)er o3 usa)le "osts 7er Su)net :-

22 : 2 ! # : 2 ! 2 Host subnet

&( Address o3 8rst host on this su)net :-

172.30.1.33 10101100 00011110 00000001 11

172.30.1.32 10101100 00011110 00000001 1

&( Addresso3 Last "ost on this su)net :-

172.30.1.32 10101100 00011110 00000001 0010000

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172.30.1.3# 10101100 00011110 00000001 0010001

'roadcast Address3or this su)net :-;se 8 Number of )ast Host

172.30.1.32 10101100 00011110 00000001 1

172.30.1.35 10101100 00011110 00000001 111

Su)net Address

Perform a bit&ise AN 6 $o

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1" > 8 > # > 2 ! 0

0rd !ctet

1

4

th

!ctet02

 ,'erefore t'e subnet Address is 1+20102

etermine 'i*' bits *ontain netork information and 'ost information

aor #i6ide * #, Su)net #i6ide

* S# ,

"ost &(

Address

10101100 00011110 00000001 00100001

Su)net

ask 

11111111 11111111 11111111 11111110

Su)net

Address

10101100 00011110 00000001 00100000

ra t'ema?or iide 6 M. Asa a*- $ine 'ere t'e 1@s in t'e ma?or

netork mask 6 t'e 1" $eft&most Bits nd and t'e subnet diide 6 S. as

a Strai

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First "ost 11111111111

12 .4 02 1. 4 2 11 1 1 1 1 1 1 1 1 1 1

(or t'e 1st !ctet

IP Address Ansers Binar-1+2 / 2 . . / 2 40 40 / 2 21 121 / 2 1 11 / 2 / 2 2 12 / 2 1 1 / 2 1

2 4*tet * 0 , IP Address Ansers Binar-

0 / 2 1 1 / 2 + 1+ / 2 0 10 / 2 1 11 / 2 1

3 4*tet 6 1 

IP Address Ansers Binar-1 / 2 1 1

Binar- Natation (or t'e number 1 is 1

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# 4*tet * 00 ,

IP Address Ansers Binar-00 1. 1

1. / 2 / 2 4 4 / 2 2 2 / 2 1 1 / 2 1

 ,'erefore t'e (irst Host Address is 1+20100

Last "ost 11111111111

12 .4 02 1. 4 2 11 1 1 1 1 1 1 1 1

1 1

(or t'e 1st !ctet

IP Address Ansers Binar-1+2 / 2 . . / 2 40 40 / 2 21 121 / 2 1 11 / 2 / 2 2 12 / 2 1 1 / 2 1

2 4*tet * 0 , 

IP Address Ansers Binar-0 / 2 1

1 / 2 + 1+ / 2 0 10 / 2 1 11 / 2 1

3 4*tet 6 1 

IP Address Ansers Binar-1 / 2 1 1

Binar- Natation (or t'e number 1 is 1

# 4*tet * 04 ,IP Address Ansers Binar-

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04 / 2 1+ 1+ / 2 1 / 2 4 4 / 2 2 2 / 2 1

1 / 2 1 ,'erefore t'e $ast Host Address is 1+20104

Broadcast Address 10101100.00011110.00000001.00100011

(or t'e 1st !ctet

IP Address Ansers Binar-1+2 / 2 .

. / 2 40 40 / 2 21 121 / 2 1 11 / 2 / 2 2 12 / 2 1 1 / 2 1

2 4*tet * 0 , 

IP Address Ansers Binar-

0 / 2 1 1 / 2 + 1+ / 2 0 10 / 2 1 11 / 2 1

3 4*tet 6 1 

IP Address Ansers Binar-1 / 2 1 1

Binar- Natation (or t'e number 1 is 1

# 4*tet * 0 ,

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IP Address Ansers Binar-0 / 2 1+ 11+ / 2 1 / 2 4 4 / 2 2

2 / 2 1 1 / 2 1

 ,'erefore t'e Broad*ast Address is 172.30.1.35

(ro)lem 0

Host IP Address 1F2.1F2.10.23#Subnet Mask 255.255.255.0Number of subnet bits 8 BitsNumber of subnets 28! 25" SubnetNumber of Host bits Per Subnet 25#Number of usab$e Hosts %er Subnet 28 & 2 ! 25" & 2 ! 25# Host Per SubnetSubnet Address for t'is IP address 1F2.1F2.10.0IP address of (irst 'ost on t'is subnet 1F2.1F2.10.1IP Address of )ast Host on t'is subnet 1F2.1F2.10.25#Broad*ast Address for t'is subnet 1F2.1F2.10.255

Ste% 1 + ,rans$ate 'ost IP Address and subnet mask into Binar- natation

1F2 1F2 10 23#

IP A/SS 11000000 11000000 00001010

00100001

Subnet Mask 11111111 11111111 11111111

00000000

255 255 255 0

(irst )ist don t'ese a$ue of Numbers.

 ,ake t'e Host IP Address 1F2.1F2.10.23

 and Start it' t'e (irst 4*tet * 1;2 ,

IP Address Ansers Binar-1;2 / 2 ;. ;. / 2 4 4 / 2 24

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24 / 2 12 12 / 2 . . / 2 0 0 / 2 1 11 / 2 1

So no e kno t'at a e*ima$ Number 1;2 is 11 *onerted to Binar-from.

2 4*tet * 1;2 , 

IP Address Ansers Binar-1;2 / 2 ;. ;. / 2 4 4 / 2 24 24 / 2 12 12 / 2 . . / 2 0

0 / 2 1 11 / 2 1

So no e kno t'at a e*ima$ Number 1;2 is 11 *onerted to Binar-

from.

3 4*tet 6 1 

IP Address Ansers Binar-1 / 2 / 2 2 12 / 2 1 1 / 2 1 1

Binar- Natation (or t'e number 1 is 11

# 4*tet * 204 ,

IP Address Ansers Binar-204 / 2 11+ 11+ / 2 1 / 2 2; 2; / 2 14 114 / 2 + + / 2 0 1

0 / 2 1 11 / 2 1 1

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Binar- Natation for t'e number 204 is 11111

So t'e IP Address of 1;21;21204 'as its binar- form euia$ent of +

11111111111

Su)net ask 

/e%eat t'e same %ro*edure used for t'e IP Address to *onert t'e subnet Mask

into Binar- notation.

1 4*tet * 2 , 

IP Address Ansers Binar-2 / 2 12+ 1

12+ / 2 .0 1.0 / 2 01 101 / 2 1 11 / 2 + 1+ / 2 0 10 / 2 1 11 / 2 1

Binar- Notation for t'e number 2 is 11111111

2 4*tet * 2 ,

IP Address Ansers Binar-2 / 2 12+ 112+ / 2 .0 1.0 / 2 01 101 / 2 1 11 / 2 + 1+ / 2 0 10 / 2 1 11 / 2 1

Binar- Notation for t'e number 2 is 11111111

3 4*tet * 2 , 

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IP Address Ansers Binar-2 / 2 12+ 112+ / 2 .0 1.0 / 2 01 101 / 2 1 1

1 / 2 + 1+ / 2 0 10 / 2 1 11 / 2 1

Binar- Notation for t'e number 2 is 11111111

# 4*tet * , 

IP Address Ansers Binar- / 2 / 2 / 2 / 2 / 2 / 2

/ 2 / 2

Binar- notation for t'e number  is 6 sin*e t'ere is no number to

subtra*t for  so automati*a$$- t'e anser is .

 So the &( Address o3 222 has its )inar 3orm e5ui6alent o3 :

111111111111111111111111

Num)er o3 Su)net 'its :-

255.255.2998

111111111111111111111111

Num)er o3 "ost :-

28

Num)er o3 "ost 'its 7er su)net :-

289925"

Num)er o3 usa)le "osts 7er Su)net :-

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28 : 2 ! 25" : 2 ! 25#

&( Address o3 8rst host on this su)net :-

1F2.1F2.10.23# 11000000 11000000 00001010

11111

1F2.1F2.10.1 11000000 11000000 00001010

1

&( Addresso3 Last "ost on this su)net :-

1F2.1F2.10.1 11000000 11000000 00001010

00000001

1F2.1F2.10.25# 11000000 11000000 00001010

1111111

'roadcast Address3or this su)net :-

;se 8 Number of )ast Host

1F2.1F2.10.0 11000000 11000000 00001010

1F2.1F2.10.255 11000000 11000000 0000101011111111

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(ro)lem 4

Host IP Address 172.17.FF.71Subnet Mask 255.255.0.0Number of subnet bits 1" BitsNumber of subnets 21" ! "553"

Number of Host bits Per Subnet "553"Number of usab$e Hosts %er Subnet 21" ! "553" : 2 ! "553# Hosts Per

SubnetsSubnet Address for t'is IP address 172.17.FF.0IP address of (irst 'ost on t'is subnet 172.17.FF.1IP Address of )ast Host on t'is subnet 172.17.FF."553#Broad*ast Address for t'is subnet 172.17.FF.255

Ste% 1 + ,rans$ate 'ost IP Address and subnet mask into Binar- natation

172 17 FF 71

IP A/SS 10101100 00010001 01100011

01001101

Subnet Mask 11111111 11111111 00000000

00000000

255 255 0 0

(irst )ist don t'ese a$ue of Numbers.

 ,ake t'e Host IP Address 172.30.1.30 and Start it' t'e (irst 4*tet * 1+2 ,

IP Address Ansers Binar-

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1+2 / 2 . . / 2 40 40 / 2 21 121 / 2 1 11 / 2

/ 2 2 12 / 2 1 1 / 2 1

So no e kno t'at a e*ima$ Number 172 is 1111 *onerted to Binar-

from.

2 4*tet * 1+ , 

IP Address Ansers Binar-1+ / 2 1

/ 2 4 4 / 2 2 2 / 2 1 1 / 2 1

Binar- Natation for t'e number 1+ is 11

3 4*tet 6 ;; 

IP Address Ansers Binar-;; / 2 4; 14; / 2 24 124 / 2 12 12 / 2 . . / 2 0 0 / 2 1 11 / 2 1 1

Binar- Natation (or t'e number 1 is 1111

# 4*tet * +1 ,

IP Address Ansers Binar-+1 / 2 0 10 / 2 1+ 11+ / 2 1 / 2 4 4 / 2 2 2 / 2 1 1 / 2 1 1

Binar- Natation for t'e number +1 is 1111

So t'e IP Addressof 1 'as its binar- form euia$ent of +

11111111111111

Su)net ask 

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/e%eat t'e same %ro*edure used for t'e IP Address to *onert t'e subnet Mask

into Binar- notation.

1 4*tet * 2 , 

IP Address Ansers Binar-

2 / 2 12+ 112+ / 2 .0 1.0 / 2 01 101 / 2 1 11 / 2 + 1+ / 2 0 10 / 2 1 11 / 2 1

Binar- Notation for t'e number 2 is 11111111

2 4*tet * 2 ,

IP Address Ansers Binar-2 / 2 12+ 112+ / 2 .0 1

.0 / 2 01 101 / 2 1 11 / 2 + 1+ / 2 0 10 / 2 1 11 / 2 1

Binar- Notation for t'e number 2 is 11111111

3 4*tet * , 

IP Address Ansers Binar- / 2 / 2 / 2 / 2 / 2 / 2 / 2 / 2

Binar- notation for t'e number  is 6 sin*e t'ere is no number to

subtra*t for  so automati*a$$- t'e anser is .

# 4*tet * , 

IP Address Ansers Binar-

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/ 2 / 2 / 2 / 2 / 2

/ 2 / 2 / 2

Binar- notation for t'e number  is 6 sin*e t'ere is no number to

subtra*t for  so automati*a$$- t'e anser is .

 So the &( Addresso3 222 has its )inar 3orm e5ui6alent o3 :

111111111111111111111111

Num)er o3 Su)net 'its :-

255.255.2998

111111111111111111111111

Num)er o3 "ost :-21"

Num)er o3 "ost 'its 7er su)net :-

21"99"553"

Num)er o3 usa)le "osts 7er Su)net :-

21F : 2 ! "553" : 2 ! "553"

&( Address o3 8rst host on this su)net :-172.17.FF.71 11000000 11000000 00001010

11

172.17.FF.1 11000000 11000000 00001010

1

&( Addresso3 Last "ost on this su)net :-

172.17.FF.1 11000000 11000000 00001010 1

172.17.FF.25# 11000000 11000000 00001010

1111111

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'roadcast Address3or this su)net :-

;se 8 Number of )ast Host

172.17.FF.0 11000000 11000000 00001010

172.17.FF.255 11000000 11000000 00001010 1

11111111111111

(ro)lem

Host IP Address 1F2.1"8.3.21FSubnet Mask 255.255.255.0Number of subnet bits 8 Bits

Number of subnets 28! 25" SubnetNumber of Host bits Per Subnet 25#Number of usab$e Hosts %er Subnet 28 & 2 ! 25" & 2 ! 25# Host Per SubnetSubnet Address for t'is IP address 1F2.1"8.3.0IP address of (irst 'ost on t'is subnet 1F2.1"8.3.1IP Address of )ast Host on t'is subnet 1F2.1"8.3.25#Broad*ast Address for t'is subnet 1F2.1F2.10.255

Ste% 1 + ,rans$ate 'ost IP Address and subnet mask into Binar- natation

1F2 1"8 3 21F

IP A/SS 11000000 10101000 00000011

11011011

Subnet Mask 11111111 11111111 11111111

00000000

255 255 255 0

(irst )ist don t'ese a$ue of Numbers.

 ,ake t'e Host IP Address 1F2.1"8.3.21F

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 and Start it' t'e (irst 4*tet * 1;2 ,

IP Address Ansers Binar-1;2 / 2 ;. ;. / 2 4 4 / 2 24 24 / 2 12 12 / 2 . . / 2 0 0 / 2 1 11 / 2 1

So no e kno t'at a e*ima$ Number 1;2 is 11 *onerted to Binar-

from.

2 4*tet * 1. , 

IP Address Ansers Binar-

1. / 2 4 4 / 2 42 42 / 2 21 21 / 2 1 11 / 2 / 2 2 12 / 2 1 1 / 2 1

So no e kno t'at a e*ima$ Number 1. is 111 *onerted to Binar-

from.

3 4*tet 6 0 

IP Address Ansers Binar-0 / 2 1 11 / 2 1 1

Binar- Natation (or t'e number 0 is 11

# 4*tet * 21; ,

IP Address Ansers Binar-21; / 2 1; 11; / 2 4 14 / 2 2+

2+ / 2 10 110 / 2 . 1

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. / 2 0 0 / 2 1 11 / 2 1 1

Binar- Natation for t'e number 21; is 111111

So t'e IP Address of 1;21.021; 'as its binar- form euia$ent of +

11 111 11 111111

Su)net ask 

/e%eat t'e same %ro*edure used for t'e IP Address to *onert t'e subnet Mask

into Binar- notation.

1 4*tet * 2 , 

IP Address Ansers Binar-2 / 2 12+ 112+ / 2 .0 1.0 / 2 01 101 / 2 1 11 / 2 + 1+ / 2 0 10 / 2 1 11 / 2 1

Binar- Notation for t'e number 2 is 11111111

2 4*tet * 2 ,

IP Address Ansers Binar-2 / 2 12+ 112+ / 2 .0 1.0 / 2 01 101 / 2 1 11 / 2 + 1+ / 2 0 1

0 / 2 1 11 / 2 1

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Binar- Notation for t'e number 2 is 11111111

3 4*tet * 2 , 

IP Address Ansers Binar-2 / 2 12+ 1

12+ / 2 .0 1.0 / 2 01 101 / 2 1 11 / 2 + 1+ / 2 0 10 / 2 1 11 / 2 1

Binar- Notation for t'e number  is

# 4*tet * , 

IP Address Ansers Binar- / 2 / 2 / 2

/ 2 / 2 / 2 / 2 / 2

Binar- notation for t'e number  is 6 sin*e t'ere is no number to

subtra*t for  so automati*a$$- t'e anser is .

 So the &( Address o3 22 has its )inar 3orm e5ui6alent o3 :

1111111111111111

Num)er o3 Su)net 'its :-

255.255.991"

1111111111111111

Num)er o3 "ost :-

28

Num)er o3 "ost 'its 7er su)net :-

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21"9925"

Num)er o3 usa)le "osts 7er Su)net :-

21" : 2 ! "553" : 2 ! "553#

&( Address o3 8rst host on this su)net :-

1F2.1"8.3.0 11000000 10101000 00000011

1F2.1"8.3.1 11000000 10101000 00000011

1

&( Addresso3 Last "ost on this su)net :-

1F2.1"8.3.1 11000000 10101000 00000011

000000011F2.1"8.3.25# 11000000 10101000 00000011

1111111

'roadcast Address3or this su)net :-

;se 1" Number of )ast Host

1F2.1"8.3.0 11000000 10101000 00000011

1F2.1"8.3.255 11000000 10101000 00000011

11111111

(ro)lem .

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Host IP Address 1F2.1"8.3.21FSubnet Mask 255.255.255.22#Number of subnet bits 5 BitsNumber of subnets 25! 32 SubnetNumber of Host bits Per Subnet 32

Number of usab$e Hosts %er Subnet 25

& 2 ! 32 & 2 ! 30 Host Per SubnetSubnet Address for t'is IP address 1F2.1"8.3.0IP address of (irst 'ost on t'is subnet 1F2.1"8.3.1IP Address of )ast Host on t'is subnet 1F2.1"8.3.25#Broad*ast Address for t'is subnet 1F2.1F2.10.255

Ste% 1 + ,rans$ate 'ost IP Address and subnet mask into Binar- natation

1F2 1"8 3 21F

IP A/SS 11000000 10101000 00000011

11011011

Subnet Mask 11111111 11111111 11111111

11100000

255 255 255 22#

(irst )ist don t'ese a$ue of Numbers.

 ,ake t'e Host IP Address 1F2.1"8.3.21F

 and Start it' t'e (irst 4*tet * 1;2 ,

IP Address Ansers Binar-1;2 / 2 ;. ;. / 2 4 4 / 2 24 24 / 2 12 12 / 2 . . / 2 0 0 / 2 1 11 / 2 1

So no e kno t'at a e*ima$ Number 1;2 is 11 *onerted to Binar-

from.

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2 4*tet * 1. , 

IP Address Ansers Binar-1. / 2 4 4 / 2 42 42 / 2 21 21 / 2 1 11 / 2 / 2 2 12 / 2 1 1 / 2 1

So no e kno t'at a e*ima$ Number 1. is 111 *onerted to Binar-

from.

3 4*tet 6 0 

IP Address Ansers Binar-

0 / 2 1 11 / 2 1 1Binar- Natation (or t'e number 0 is 11

# 4*tet * 21; ,

IP Address Ansers Binar-21; / 2 1; 11; / 2 4 14 / 2 2+ 2+ / 2 10 110 / 2 . 1

. / 2 0 0 / 2 1 11 / 2 1 1

Binar- Natation for t'e number 21; is 111111

So t'e IP Address of 1;21.021; 'as its binar- form euia$ent of +

11 111 11 111111

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Su)net ask 

/e%eat t'e same %ro*edure used for t'e IP Address to *onert t'e subnet Mask

into Binar- notation.

1 4*tet * 2 , 

IP Address Ansers Binar-2 / 2 12+ 112+ / 2 .0 1.0 / 2 01 101 / 2 1 11 / 2 + 1+ / 2 0 10 / 2 1 11 / 2 1

Binar- Notation for t'e number 2 is 11111111

2 4*tet * 2 ,

IP Address Ansers Binar-2 / 2 12+ 112+ / 2 .0 1.0 / 2 01 101 / 2 1 11 / 2 + 1+ / 2 0 1

0 / 2 1 11 / 2 1

Binar- Notation for t'e number 2 is 11111111

3 4*tet * 2 , 

IP Address Ansers Binar-2 / 2 12+ 112+ / 2 .0 1.0 / 2 01 101 / 2 1 11 / 2 + 1

+ / 2 0 10 / 2 1 11 / 2 1

Binar- Notation for t'e number 2 is 11111111

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# 4*tet * , 

IP Address Ansers Binar-224 / 2 112 112 / 2 . . / 2 2 2 / 2 14 14 / 2 + + / 2 0 10 / 2 1 11 / 2 1 1

Binar- notation for t'e number  is 6 sin*e t'ere is no number to

subtra*t for  so automati*a$$- t'e anser is .

 So the &( Address o3 222224 has its )inar 3orm e5ui6alent

o3 :

1111111111111111 11111111111

Num)er o3 Su)net 'its :-

255.255.2224995

111111111111111111111111111

Num)er o3 "ost :-

25

Num)er o3 "ost 'its 7er su)net :-

259932

Num)er o3 usa)le "osts 7er Su)net :-

25 : 2 ! 32 : 2 ! 30

&( Address o3 8rst host on this su)net :-

1F2.1"8.3.2 11000000 11000000 0000001111111

1F2.1"8.3.1 11000000 11000000 00000011

1

&( Addresso3 Last "ost on this su)net :-

1F2.1"8.3.1 11000000 11000000 00000011

00000001

1F2.1"8.3.255 11000000 11000000 00000011

11111111

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'roadcast Address3or this su)net :-

;se 8 Number of )ast Host

1F2.1"8.3.0 11000000 11000000 00000011

1F2.1"8.3.255 11000000 11000000 00000011

11111111