spm jawapan [ 1449/1 ] [ 1449/2 ] 2008 mathematics … 2008 soalan ulangkaji spm 2008 jawapan s...

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SPM 2008 SOALAN ULANGKAJI SPM 2008 [ 1449/1 ] [ 1449/2 ] Mathematics 1. 2. 3. 4. 5. 6. 7. 8. 9. 10. 11. 12. 13. 14. 15. 16. 17. 18. 19. 20. 21. 22. 23. 24. 25. 26. 27. 28. 29. 30. 31. 32. 33. 34. 35. 36. 37. 38. 39. 40. B C D C C B B A A A D B B C A D C A B C B B A D C B C D D C D B C A B A A C D A Kertas 1

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Page 1: SPM Jawapan [ 1449/1 ] [ 1449/2 ] 2008 Mathematics … 2008 SOALAN ULANGKAJI SPM 2008 Jawapan S Kertas 2 Soalan Jawapan Markah 15 (a) 15 (b) i) ii) Soalan Jawapan Markah 16 (a) 16

SPM2008

SOALAN ULANGKAJI SPM 2008

JawapanSoalan Ulangkaji

[ 1449/1 ] [ 1449/2 ]

Mathematics

1.2.3.4.5.6.7.8.9.

10.11.12.13.14.15.16.17.18.19.20.

21.22.23.24.25.26.27.28.29.30.31.32.33.34.35.36.37.38.39.40.

BCDCCBBAAADBBCADCABC

BBADCBCDDCDBCABAACDA

Kertas 1

Page 2: SPM Jawapan [ 1449/1 ] [ 1449/2 ] 2008 Mathematics … 2008 SOALAN ULANGKAJI SPM 2008 Jawapan S Kertas 2 Soalan Jawapan Markah 15 (a) 15 (b) i) ii) Soalan Jawapan Markah 16 (a) 16

SPM2008

SOALAN ULANGKAJI SPM 2008

JawapanSoalan Ulangkaji

Soalan Jawapan Markah

1

2

3

4 (a)

4 (b)

4 (c)

5

6

7 (a)

7 (b)

8 (a)

8 (b)

9 (a)

9 (b)

10 (a)

10 (b)

10 (c)

x = - , x = 1

p = 1 , q = - 2

i ) trueii) false

Implication 1 : If 3k 2 – 5 > 7 then k > 1Implication 2 : If k > 1 then 3k 2 – 5 > 7

Conclusion : n² + 3, n = 1,2 ,3,4,…….

18 cm

UW = 10 cm

tan 0 = , 0 = tan 1

= 36.87º or 36º52’

8 x 7 = 414 13 13

x + x =

k = 3

x = 1, y = -1

y = x-12, x-intercept = 8

25 - 15 = 10 s

= 2 ms 1

= 2 , d = 60

4

4

3

Kertas 2

13

Soalan Jawapan Markah

11 (a)

11 (b)

12 (a)

12 (c)

13 (a)

13 (b)

14 (a)

14 (b)

14 (c)

58 cm

56 cm²

i) 24.5ii) - 2.3, 2.4

x³ - 15x + 10 = 0x³ - 15x + 10 + 10x 10 = 0 + 10x + 10 x³ - 5x + 20 = 10x + 10 y = 10x + 10Draw a graph y = 10x + 10 x = 0.7 , 3.5

i) (0,1)ii) (3,-1)iii) (-2,-2)

i) (a) A or (-3,1) i) (b) k = 3

ii) 64 unit²

Draw a graph 7 plotted points, joining points, A curve line from point (9.5,0) to point (39.5,48)

i) The third quartile = 27.5ii) 36 participants are 27.5 years old or less.

Q R

Q R

P

68

68( )

411

710

711

410

2255

32

14

10 - 025 - 30

d30

xy

-38

218

Age Frequency upper boundary

cummulative frequency

5-9 0 9.5 010-14 6 14.5 615-19 8 19.5 1420-24 14 24.5 2825-29 12 29.5 4030-34 5 34.5 4535-39 3 39.5 48

Mathematics[ 1449/1 ] [ 1449/2 ]

Page 3: SPM Jawapan [ 1449/1 ] [ 1449/2 ] 2008 Mathematics … 2008 SOALAN ULANGKAJI SPM 2008 Jawapan S Kertas 2 Soalan Jawapan Markah 15 (a) 15 (b) i) ii) Soalan Jawapan Markah 16 (a) 16

SPM2008

SOALAN ULANGKAJI SPM 2008

JawapanSoalan UlangkajiKertas 2

Soalan Jawapan Markah

15 (a)

15 (b) i)

ii)

Soalan Jawapan Markah

16 (a)

16 (b)

16 (c)

16 (d)

HL is the diameter of the parallel of latitude 60º SH ( 60º S, 40º E),L ( 60º S, 140º W) , Longitude of L = 140º W

Shortest distance = ( 180 – 60 – 60 ) x 60 = 3600 n.m

H ( 60º S, 40º E), K ( 60º S, 30º W)Distance = ( 40 + 30 ) x 60 x Cos 60 = 2100 n.m

Average speed = distance/time , 480 =

Distance = 480 x 5 = 2400 n.m

= = 40

Latitude of M = 60-40 = 20º S6 cm

2 cm

8 cm

3 cm

D/P

A/Q

T/S

U/RB

C

W/T V/U

K/S/P L/R/Q

C/D B/A

3 cm

3 cm

4 cm

7 cm

7 cm

2 cm8 cm

3 cm

T

S

W

K

D

P

C

Distance5

Distance50

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Mathematics