mohd tabish, b14 ,banking system

8/2/2019 Mohd Tabish, B14 ,Banking System

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PROJECT REPORTOF

BANKING SYSTEM

Submitted in the partial fulfillment of the Degree

of Bachelor of Technology (Integrated)In

Civil Engineering

SUBMITTED BY:- GUIDED BY:-Name:MOHD TABISH Mr.HARJEET SINGHRegd. No : 11106249Rollno : B14Section : C1R12Course Code : CSE 101


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ACKNOWLEDGEMENTI take this opportunity to present my votes of thanks to

all those guidepost who really acted as lightening pillarsto enlighten our way throughout this project that has led

to successful and satisfactory completion of this study.

We are really grateful to our subject teacher for

providing us with an opportunity to undertake this

project in this university and providing us with all the

facilities. We are highly thankful to Mr.Harjeet Singh for

his active support, valuable time and advice, whole-

hearted guidance, sincere cooperation and pains-takinginvolvement during the study and in completing the

assignment of preparing the said project within the time

stipulated.

Lastly, We are thankful to all those, particularly the

various friends , who have been instrumental in creating

proper, healthy and conductive environment and

including new and fresh innovative ideas for us duringthe project, their help, it would have been extremely

difficult for us to prepare the project in a time bound

framework.

Name Mohd Tabish

Regd.No 11106249

Rollno. C1R12B14


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TABLE OF CONTENTS

1. Introduction2. Proposed system

i. Descriptionii. System requirements

3. Requirement Analysis4. System Design5. Source code6. Testing7. Future scope of project


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INTRODUCTION

In the existing system, most of the records are maintained on paper. It becomes very

inconvenient to modify the data. In the existing system, here is a possibility that the samedata in different registers may have different values which means the entries of the same

data do not match. This inconsistent state does not supply the concrete information which

poses a problem in the case information related to particular search record.Our project is very useful. User is no longer required to check his register in search of

records, as now it can be searched over the software by choosing some options. The user

need not to type in most of the information. He/she is just required to enter the desired

options. On the whole it liberates the user from keeping lengthy manual records. In anutshell, it abates the work load of an organization.

In todays world, no one likes to perform calculations on calculator or manually when

computer is there. Every one wants his/her work to be done by computer automatically

and displaying the result for further manipulations.

This term paper project is just an application of the language C in developingsoftwares.This is the program for keeping records of the bank ,that is the entire details of

the customer ,savings ,how much money he/she can deposit and withdraw from the bank,

to open the new account ,create a new account ,display all account holders, balanceenquiry etc.


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PROPOSED SYSTEM

The following documentation is a project the BANKING SYSTEM . It is a detailed

summary of all the drawbacks of the old system and how the new proposed systemovercomes these shortcomings. The new system takes into account the various factors

while designing a new system. It keeps into the account the Economical bandwidth

available for the new system. The foremost thing that is taken care of is the Need andRequirements of the User.

DESCRIPTION

Before developing software we keep following things in mind that we can developpowerful and quality software

PROBLEM STATEMENT

o Problem statement was to design a module:o Which is user friendlyo Which will restrict the user from accessing other users data.o Which will help user in viewing his data and privileges.o Which will help the administrator to handle all the changes.

FUNCTIONS TO BE PROVIDED:The system will be user friendly and completely menu driven so that the users shall have

no problem in using all options.

o The system will be efficient and fast in response.o The system will be customized according to needs.o Create new accounto Search ,edit and display customer detailso Display account holderso Deposit moneyo Withdraw moneyo Balance enquiry

SYSTEM REQUIRMENTS

Operating system: MS Windows XP or Windows Vista

Language: C LanguageProcessor: Pentium IV Processor

RAM: 512 MBHard disk: 5 GB


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REQUIREMENT ANALYSIS

This process is adopted when management of the system development, Personnel decidethat the particular system needs improvement. The system development life cycle is the

set of activities, carried out by the analyst, designers and users to develop and implement

a system. The systems that are present in the nature follow common life cycle pattern.For example consider the raining system. Initially the rain falls into the river, river flows

into sea, the sea water evaporates to form vapors, the vapors form clouds which again

bring rain. Similarly consider a man made system initially a system is analyzed, designedand made operational by the efforts of system analysis. After successful operation or a

number of users, the system becomes less and less effective by change in the

environment. So these changes have to be incorporated in to the system by minor

modifications. So the general activities from the life cycle of the system are given below:

Select ion and identification of the system to be studied

Preliminary study Defining the system Design and development of the system Implementation of the system


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SYSTEM DESIGN

Then we began with the design phase of the system. System design is a solution, a HOW

TO approach to the creation of a new system. It translates system requirements intoways by which they can be made operational. It is a translational from a user oriented

document to a document oriented programmers. For that, it provides the understanding

and procedural details necessary for the implementation. Here we use Flowchart tosupplement the working of the new system. The system thus made should be reliable,

durable and above all should have least possible maintenance costs. It should overcome

all the drawbacks of the Old existing system and most important of all meet the user

requirements.

Welcome to the project on banking

Enter

yourchoice

Create account Customer details De osit withdraw

Do you want to

continue?

START

STOP

Balance en uir


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SOURCE CODE

# include

# include

# include # include //library header file

int dmenu(); //main menu

void dadd(); //add to list

void dfind(); //search from the listvoid dedit(); //edit the record

void ddel(); //delete from the list

void ddisp(); //display all

void ddisp1();//display1void ddisp2();//display2

void dwith();

void ddepo();void dcurrent_with();

void dcurrent_depo();

void deposit();void withdrawal();

struct dnode {

int num,bal,check;

char dlname[20], dfname[20], dtel[15];

struct dnode *dnext;};

typedef struct dnode node;node *dstart, *dtemp;

int i=5000,chk=1,j=15000;

int dmenu()

{int dch;

gotoxy(30,5);

printf(" BANKING DATABASE ");

gotoxy(30,6);

printf(" ================ ");gotoxy(3,24);

gotoxy(27,10);printf(" 1. Create a new account");

gotoxy(27,11);

printf(" 2. Search customer details");gotoxy(27,12);

printf(" 3. Edit customer details");


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gotoxy(27,13);

printf(" 4. Delete a customer");gotoxy(27,14);

printf(" 5. Display all account holders ");

gotoxy(27,15);

printf(" 6. Deposit money");gotoxy(27,16);

printf(" 7. Withdrawal money");

gotoxy(27,17);printf(" 8. Balance Enquiry");

gotoxy(27,18);

printf(" 9. Exit ");gotoxy(27,21);

printf(" Enter your choice(1-9):");

gotoxy(55,21);

scanf("%d", &dch);

return dch;}

void dadd(){

int type;

node *dptr,*dprev;dtemp=(node *)malloc(sizeof(node));

printf("\nWhich type of account you want to create?\n1->Savings\n2->Current\nenter

your choice : ");

scanf("%d",&type);if(type==1)

{

do{

printf("\nYour Account No:");dtemp->num=i;

printf("%d",dtemp->num);

i++;}while(i>10000);

printf("\nFirst name: ");

scanf("%s", dtemp->dfname);printf("Last name:");

scanf("%s", dtemp->dlname);

printf("Telephone No.: ");

scanf("%s", dtemp->dtel);a:

printf("Deposit Sum:");

scanf("%d",&dtemp->bal);if(dtemp->bal


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goto a;

}dtemp->dnext=NULL;

if(dstart==NULL) dstart=dtemp;

else {

dprev=dptr=dstart;while(strcmp(dtemp->dfname,dptr->dfname)>0){

dprev=dptr;

dptr= dptr->dnext;if (dptr == NULL) break;

}

if(dptr==dprev) {dtemp->dnext=dstart;

dstart=dtemp;

}

else if(dptr==NULL)

dprev->dnext=dtemp;else {

dtemp->dnext=dptr;dprev->dnext=dtemp;

}

}ddisp1();

}

else if(type==2)

{do{

printf("\nYour Account No:");

dtemp->num=j;

printf("%d",dtemp->num);j++;

}while(j>20000);

printf("\nFirst name: ");scanf("%s", dtemp->dfname);

printf("Last name:");

scanf("%s", dtemp->dlname);printf("Telephone No.: ");

scanf("%s", dtemp->dtel);

m:

printf("Deposit Sum:");scanf("%d",&dtemp->bal);

if(dtemp->bal


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if(dptr->num==no)

{printf("\n\t\tHELLO %s WELCOME TO OUR BANK", dptr->dlname);

printf("\n\t\tYou are a SAVINGS account holder of our bank");

printf("\n\t\tAccount number: %d",dptr->num);

printf("\n\t\tFirst name: %s", dptr->dfname);printf("\n\t\tLast name:%s", dptr->dlname);

printf("\n\t\tTelephone No.: %s", dptr->dtel);

printf("\n\t\tYour Balance: %d",dptr->bal);printf("\n\t\t------------------------------\n");

}

}else{

printf("\n\n");

printf("\t\t------------------------------\n");

if(dptr->num==no)

{printf("\n\t\tHELLO %s WELCOME TO OUR BANK", dptr->dlname);

printf("\n\t\tYou are a CURRENT account holder of our bank");printf("\n\t\tAccount number: %d",dptr->num);

printf("\n\t\tFirst name: %s", dptr->dfname);

printf("\n\t\tLast name:%s", dptr->dlname);printf("\n\t\tTelephone No.: %s", dptr->dtel);

printf("\n\t\tYour Balance: %d",dptr->bal);

chk=1;

printf("\n\t\tCheque nos:%d to %d",chk,chk+19);printf("\n\t\t------------------------------\n");

}

}

}else

{

printf("No Matching Records Found .......\n");}

getch();

}void deposit()

{

int no;

node *dptr,*dprev;if(dstart==NULL) {

printf("\n\t\t\tNO ACCOUNT DATABASE....\n");

getch();return;

}

printf("Enter your account no : ");


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scanf("%d",&no);

dptr=dstart;while(dptr->num!=no)

{

dptr= dptr->dnext;

if (dptr == NULL) break;}

if(dptr!=NULL){

if(dptr->num>=5000 && dptr->numdlname);

printf("\nAccount No:%d \n",dptr->num);

printf("First Name : %s\n",dptr->dfname);printf("Last Name : %s\n",dptr->dlname);

printf("Phone Number : %s\n",dptr->dtel);

printf("Your Balance : %d\n",dptr->bal);printf("Deposit Amount:");

scanf("%d",&bal);

dptr->bal+=bal;printf("Your New balance:%d",dptr->bal);

getch();

}

void dcurrent_depo(){

node *dptr;

int bal,ch;printf("\t\t\n-----------------------------------------------\n");

printf("\n\t\tHELLO %s WELCOME TO OUR BANK", dptr->dlname);



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printf("First Name : %s\n",dptr->dfname);

printf("Last Name : %s\n",dptr->dlname);printf("Phone Number : %s\n",dptr->dtel);

printf("Your Balance : %d\n",dptr->bal);

printf("\nHow do you wish to deposit?\n1->cash\n2->cheque\nEnter your choice : ");

scanf("%d",&ch);if(ch==1)

{

printf("Deposit Amount:");scanf("%d",&bal);

dptr->bal+=bal;

printf("Your New balance:%d",dptr->bal);}

else if(ch==2)

{

do{

printf("\nYour Check No:");dtemp->check=chk;

printf("%d\n",dtemp->check);chk++;

}while(chk>21);

printf("Deposit Amount:");scanf("%d",&bal);

dptr->bal+=bal;

printf("Your New balance:%d",dptr->bal);

}getch();

}

void withdrawal()

{node *dptr;

int no;

if(dstart==NULL) {printf("\n\t\t\tNO ACCOUNT DATABASE....\n");

getch();

return;}

printf("Enter the account No : ");

scanf("%d",&no);

dptr=dstart;while(dptr->num!=no){

dptr= dptr->dnext;

if (dptr == NULL) break;}

if(dptr!=NULL)

{


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if(dptr->num>=5000 && dptr->numdlname);


printf("First Name : %s\n",dptr->dfname);printf("Last Name : %s\n",dptr->dlname);


printf("Your Balance : %d\n",dptr->bal);

b:printf("Withdrawal Amount:");

scanf("%d",&bal);

if((dptr->bal-bal)bal-=bal;


getch();}

void dcurrent_with()

{

node *dptr;int no,bal,ch;

printf("\t\t\n-----------------------------------------------\n");

printf("\n\t\tHELLO %s WELCOME TO OUR BANK", dptr->dlname);printf("\nAccount No:%d \n",dptr->num);


printf("Last Name : %s\n",dptr->dlname);


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printf("Your Balance : %d\n",dptr->bal);printf("\nHow do you wish to deposit?\n1->cash\n2->cheque\nEnter your choice : ");

scanf("%d",&ch);

if(ch==1)

{b:

printf("Withdrawal Amount:");

scanf("%d",&bal);if((dptr->bal-bal)bal-=bal;


}else if(ch==2)

{do{

printf("\nYour Check No:");

dtemp->check=chk;printf("%d\n",dtemp->check);

chk++;

}while(chk>21);

c:printf("Withdrawal Amount:");

scanf("%d",&bal);

if((dptr->bal-bal)bal-=bal;


}getch();

}

void dedit()

{node *dptr;

int no,bal;

if(dstart==NULL) {printf("\n\t\t\tNO ACCOUNT DATABASE....\n");

getch();

return;


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}

printf("Enter number to Edit : ");scanf("%d",&no);

dptr=dstart;

while(dptr->num!=no){


}

if(dptr!=NULL) {printf("\t\t\n-----------------------------------------------\n");

printf("\n\t\tHELLO %s WELCOME TO OUR BANK", dptr->dlname);

printf("\nOld First Name : %s", dptr->dfname);printf("\nNew First Name : ");

scanf("%s", dptr->dfname);

printf("\nOld Last Name : %s", dptr->dlname);

printf("\nNew Last Name : ");

scanf("%s", dptr->dlname);printf("\nPhone Number : %s", dptr->dtel);

printf("\nNew Phone Number : ");scanf("%s", dptr->dtel);

printf("\nOld Balance : %d", dptr->bal);

m:printf("\nNew Balance : ");

scanf("%d", &bal);

if(balbal=bal;}

else {

printf("No Matching Records Found .......\n");}

getch();

}void ddel()

{

node *dptr,*dprev,*dtemp;

int no;char dyn='n';

if(dstart==NULL) {

printf("\n\t\t\tNO ACCOUNT DATABASE....\n");getch();

return;

}


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printf("Enter your account no to delete : ");

scanf("%d",&no);dprev=dptr=dstart;

while(dptr->num!=no){

dprev=dptr;


}

if(dptr!=NULL){printf("\nDeleting Record.....Confirm [y/n]: ");

dyn=getch();

printf("\n\n---------------------------------------------------------");printf("\n\t\tHELLO %s WELCOME TO OUR BANK", dptr->dlname);

printf("\nAccount No : %d\n",dptr->num);


printf("Last Name : %s\n",dptr->dlname);

printf("Phone Number : %s\n",dptr->dtel);printf("Balance : %d\n",dptr->bal);

printf("---------------------------------------------------------");if(dyn=='y') {

if (dptr==dstart) {

dtemp=dstart->dnext;free(dstart);

dstart=dtemp;

}

else {dtemp=dptr->dnext;

free(dptr);

dprev->dnext=dtemp;

}printf("\n\n1 Record Deleted....");

}

elseprintf("\n\nRecord not Deleted....");

}

else {printf("\nNo Matching Records Found .......");

}

getch();

}void ddisp()

{

node *dptr;if(dstart==NULL) {

printf("\n\t\t\tNO ACCOUNT DATABASE....\n");

getch();


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return;

}clrscr();

printf("\t\t------------------------------\n");

for(dptr=dstart; dptr!=NULL; dptr=dptr->dnext) {

printf("\n\t\tHELLO %s WELCOME TO OUR BANK", dptr->dlname);printf("\n\t\tAccount number: %d",dptr->num);

printf("\n\t\tFirst name: %s", dptr->dfname);

printf("\n\t\tLast name:%s", dptr->dlname);printf("\n\t\tTelephone No.: %s", dptr->dtel);

printf("\n\t\tYour Balance: %d",dptr->bal);

printf("\n\t\t------------------------------\n");}

getch();

}

void ddisp1()

{printf("\n\n");

printf("\t\t------------------------------\n");printf("\n\t\tHELLO %s WELCOME TO OUR BANK", dtemp->dlname);

printf("\n\t\tYou are a SAVINGS account holder of our bank");

printf("\n\t\tAccount number: %d",dtemp->num);printf("\n\t\tFirst name: %s", dtemp->dfname);

printf("\n\t\tLast name:%s", dtemp->dlname);

printf("\n\t\tTelephone No.: %s", dtemp->dtel);

printf("\n\t\tYour Balance: %d",dtemp->bal);printf("\n\t\t------------------------------\n");

getch();

}

void ddisp2(){

printf("\n\n");

printf("\t\t------------------------------\n");printf("\n\t\tHELLO %s WELCOME TO OUR BANK", dtemp->dlname);

printf("\n\t\tYou are a CURRENT account holder of our bank");

printf("\n\t\tAccount number: %d",dtemp->num);printf("\n\t\tFirst name: %s", dtemp->dfname);

printf("\n\t\tLast name:%s", dtemp->dlname);

printf("\n\t\tTelephone No.: %s", dtemp->dtel);

printf("\n\t\tYour Balance: %d",dtemp->bal);chk=1;

printf("\n\t\tCheque nos:%d to %d",chk,chk+19);

printf("\n\t\t------------------------------\n");getch();

}

void main()


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{

int dch;dstart=(node *)malloc(sizeof(node));

dstart=NULL;

do{

clrscr();dch=dmenu();

clrscr();

switch(dch) {case 1: dadd();

break;

case 2: dfind();break;

case 3: dedit();

break;

case 4: ddel();

break;case 5:

ddisp();break;

case 6:

deposit();break;

case 7:

withdrawal();

break;case 8:

dfind();

break;

}}while(dch!=9);

}


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Deposit Sum:1000

------------------------------

HELLO TABISH WELCOME TO OUR BANKYou are a SAVINGS account holder of our bank

Account number: 5001

First name: MOHD

Last name:TABISH

Telephone No.: 2251218

Your Balance: 1000

------------------------------

SECOND TYPE OF OUTPUT:-

BANKING DATABASE================

1. Create a new account

2. Search customer details

3. Edit customer details

4. Delete a customer

5. Display all account holders

6. Deposit money

7. Withdrawal money8. Balance Enquiry

9. Exit

Enter your choice(1-9): 7

Enter the account No : 5001

-----------------------------------------------

HELLO TABISH WELCOME TO OUR BANKAccount No:5001

First Name : MOHD

Last Name : TABISH

Phone Number : 2251218

Your Balance : 1000

Withdrawal Amount:300

Your New balance:700


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FUTURE SCOPE OF THE PROJECT

Our project will be able to implement in

future after making some changes and

modifications as we make our project at a

very low level. So the modifications that can

be done in our project are:-

This project can be implement only at small

bank branches. It cannot be used for large

scale bank purposes.

mohd tabish, b14 ,banking system

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