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3472/1 © 2011 Mid Year Exam F5 Hak Cipta SBP
3472/1
Matematik Tambahan Kertas 1 2 jam Mei 2011
BAHAGIAN PENGURUSAN SEKOLAH BERASRAMA PENUH DAN SEKOLAH KECEMERLANGAN
KEMENTERIAN PELAJARAN MALAYSIA
PEPERIKSAAN PERTENGAHAN TAHUN TINGKATAN 5
2011
ADDITIONAL MATHEMATICS
Paper 1
Skema Pemarkahan ini mengandungi 6 halaman bercetak
MARKING SCHEME
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3472/1 © 2011 Mid Year Exam F5 Hak Cipta SBP
PERATURAN PEMARKAHAN- KERTAS 1
No. Solution and Mark Scheme Sub Marks
Total Marks
1(a)
(b)
{2, 4, 6, 10} One to many
1
1
2
2(a) g1 (x) = 3
2
x
1
3 (b) 1
B1 : 2
31
2
3
21446)( xxxg
B2 : 2
73 4
2
x
B1 : 1 7( )
2
xg x
3 3
4
37.5,372.0
B2 : )1(2
)2)(1(4)5(5 2 x
B1 : 0252 xx
3
3
5
25
2h
B2 : ( 10 )2 – 4(2)(h) 0 B1 : 2x2 – 10x + h = 0
3
3
6
x < - , x > 2
B2 : (2x + 11)(x – 2) > 0 or B1 : 2x2 + 7x - 22 > 0
3
3
7(a) (b)
(c)
4
3
B1 : - 8 = - a(0 – 2)2 + 4
x = 2
1 2
1
4
2
11 2
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3472/1 © 2011 Mid Year Exam F5 Hak Cipta SBP
8 2
3 hk
B3 :
B2 :
B1 : 25log
125log
5
5
a
b
4
4
9 n =
B2 : 3462 nn
B1 : 32(n + 3) = 3- n - 3n + 3 or )1(33
2
1)3(4
3.3
13
n
n
3
3
10(a)
(b)
6p
B1 : )13(8)82(13 pppp
nTn 323
B1 : )3)(1(20 nTn
2
2
4
11(a)
(b)
B1 :
12.2 or 5
112or
6
61
B1 : or 2
5
45
5
455
2
2
4
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3472/1 © 2011 Mid Year Exam F5 Hak Cipta SBP
12 x
xy
52
B2 : 51
21
xy or equivalent
B1 : cxy
12
1 OR c = 5 or 15 = 2(5) + c
3
3
13 a = 10 and b = 100 (both) B2 : a = 10 OR b = 100 OR 1log2log 1010 aandb (both)
B1 : bxay 101010 logloglog OR gradient, m = 202
15
OR 2log10 b OR 1log10 a
3 3
14 (4,5) B2 : x = 4 and y = 5
B1 : 13
)2(3)1(10
or 13
)4(3)1(8
or equivalent
3
3
15 049802255 22 yxyx or equivalent
B2 : 2222 ))1(()5(2)4()1(3 yxyx
B1 : 3
2
PB
PA or equivalent
3
3
16(a)
(b)
5
B1 :
3
4or34 jiOR
(b) or
2
1
3
17(a)
(b)
yx 66
yx 3
B1 : )66(2
1yxMK
1
2
3
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3472/1 © 2011 Mid Year Exam F5 Hak Cipta SBP
18(a)
(b)
rad or 1.047 rad
37.70 cm2 or 37.69 cm2
B1 : or )094.2()6(2
1 2
1
2
3
19 60o , 131.81o or 131o49’ , 228.19o or 228o11’ , 300o
B3 : ,
B2 :
B1 :
4 4
20 16
1
B2: or equivalent
B1:
3 3
21 (a)
(b)
363
4 3 x
3
1
036
3
4:1B 3 x
1
2
3
22 n = -3 and p =
B2 : n = -3 or p =
B1 : )2)(1(
)21( 1
n
x n
3 3
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3472/1 © 2011 Mid Year Exam F5 Hak Cipta SBP
23 (a) (b)
4
B2 : 51
24
kx
B1 :
2
1
2
1
5)( kdxdxxf
1 3
4
24 7.43
B2 : 1025
32-2
80
40.5median
B1 : lower boundary, L = 40.5 or 32 or 25
3 3
25 3.428
B2 : 222222222
2 (7) - 8
1411765553
B1 : 8
56
N
x or x =7
3
3
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