spm percubaan 2007 sbp mathematics paper 2 marking scheme

8/14/2019 SPM Percubaan 2007 SBP Mathematics Paper 2 Marking Scheme

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SULIT 1449/2

1449/2

Matematik

Kertas2

Peraturan

PemarkahanOgos

2007

SEKTOR SEKOLAH BERASRAMA PENUH

BAHAGIAN SEKOLAH

KEMENTERIAN PELAJARAN MALAYSIA

PEPERIKSAAN PERCUBAAN

SIJIL PELAJARAN MALAYSIA 2007

MATEMATIK

Kertas 2

PERATURAN PEMARKAHAN

Peraturan pemarkahan ini mengandungi 12 halaman.

[Lihat sebelah

1449/2 SULIT

Jumlah Markah =1 2

100%140

Kertas Kertas


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Section A[ 52 marks ]

No Marking Scheme Marks

1 8x2 14x 3 = 0( 4x 1 ) ( 2x 3 ) = 0

x =1

4or x =

3

2

K1K1

N1 N1 4

2 5x + 2

5y = 25

2

11y = 33

y = 6

x = 2

P1

K1

N1N1 4

3

y = 1

2 =x - 4

y = 2x + 1

O

y

Draw the straight line y = 1

Region shaded correctly

Notes :

1. Region that satisfies any two inequalities : P1

2. Deduct 1 mark from K1P2 if the straight line y = 1 drawn insolid line

K1

P2 3

2


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4 Identify JSM orMSJ or angle marked on the diagram correctly

tan JSM=12

8orequivalent

563o or 56o 19

P1

K2

N1 4

5 (a)

(b)

y = 3

Gradient ofJK=1

2or the gradient being used

1

2 32

c or

2 1

3 2

y

x

1 1

2 2y x or equivalent

yintercept =1

2

P1

P1

K1

N1

P1 5

61

6 7 83

1 22 7 76

2 7 2 2

16 7 8

3

+1 22 7 7

6

2 7 2 2

227.5

K1

K1

K1

N1 4

7(a)

(b)

5.37

222

360

60 or 7

7

222

360

180

7 + 3.5 + 3.5 +22 +11

3

239

3or 39.67

277

22

360

180 or 27

7

22

360

60 or

25.37

22

360

180 or 25.3

7

22

360

60

277

22

360

180 - 27

7

22

360

60 -

25.37

22

360

180 + 25.3

7

22

360

60

= 382

1cm2 or 38.5 cm2

K1

K1

N1

K1

K1

N1 6

3


4/12


8(a)

(b)

(c)

Statement

Implication 1: If P R then P R = P

Implication 2 : If P R = P then P R

Conclusion : 4n + n3 , where n = 1,2,3,4, ..

P1

P1

P1

P1P1 5

9(a)

(b)

64

200

8

25

60 59

120 119

59

238

K1

N1

K2

N15

10(a)

(b)

1 1

4 6 2 42 2

v v

v = 12

12 4

6 0

1

13

or 1.33

K2

N1

K2

N1 6

4


5/12


11 p =3 , k = 10

1 3 6

2 4 3

m

n

4 3 61

2 1 34 6

m

n

3

2

3

2

m

n

m =3

2 , n =3

2

Notes:

1.

3

2

3

2

m

n

: N1

2. Solution without using matrices method cannot be accepted.

P1P1

P1

K1

N1,N1 6

5


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Section B

[48 marks]


12(a)

(b)

(c)

(d)

7.6

2

Graph

Axes are drawn in the correct direction, uniform scale for

2.5 x 4 and 2.5 y 46

6 points and 2 points* plotted accurately

Smooth and continuous curve without straight line(s) and passes

through all the 8 correct points for 2.5 x 4

Notes : (1) 6 or 7 points plotted correctly, award K1

(2) Other scale being used, subtract 1 mark from the KN

marks obtained.

2.5


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13 (a)

(b)

i) (5 , 6)

ii) (10 , 3)

Notes :1. (6, 1) : P1

2. Accept answers without bracket.

i) (a) Q : Rotation 90o anticlockwise about (0,6)

(b) M : Enlargement with scale factor 3 centered at point (4, 9).

Notes:

1. Rotation 90o anticlockwise or Rotation about (0,6) : P2

2. Rotation only : P1

3. Enlargement, scale factor 3 or Enlargement, at point ( 4, 9) : P2

4. Enlargement only : P1

ii) 32 343

32 343 343

2744Notes :

1.343

283.5

or equivalent : P2

2. Without calculation, K0N0

P1

P2

P3

P3

K1

K1

N112

14(a)Number of

telephone callsUpper

BoundaryFrequenc

yCumulativeFrequency

6 - 10 10.5 0 0

11 - 15 15.5 1 1

16 - 20 20.5 3 4

21 - 25 25.5 6 10

26 - 30 30.5 10 20

31 - 35 35.5 11 31

36 - 40 40.5 7 38

41 - 45 45.5 2 40

7


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(b)

(c)

Column I (all class interval correct)

Column II (all upper boundary correct)

Column III (all frequency correct)

Column IV(all cumulative frequency correct)

Note : Allow two mistakes in column III for P1

Ogive

Axes are drawn in the correct direction, uniform scale for

10.5 x 45.5 and 0 y 40

The horizontal axis labeled with upper boundary or

use the values of upper boundary for plotting

Plot 7 points*

Smooth and continuous curve without straight line(s) and

passes through all the 8 correct points for 20.5 x 55.5.

Notes : (1) 5 or 6 points* plotted correctly, award K1

(2) Mark(s) for plotting can be given to a curve which

passes through 7 points* and point (10.5, 0)

(3) Other scale being used, subtract 1 mark from the KNmarks obtained.

First Quartile = 25.5 or Third Quartile = 35 0.5

Interquartile range = 35 25.5

= 9.5 0.5

P1

P1

P1

P1

K1

K1

K2

N1

K1

K1

N1 12

8


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15 (a)

(b)

The shape must be correct in quadrilateral form for RSTU and

RSNM.

R and S are linked by dotted lines

UT = MN > UM = TNUR = TS < RM = SN

The measurement is accurate to 0.2 cm. (one way ) and the anglesat all verticals of the rectangle are 90 1

The shape must be correct in quadrilateral form for JKWG and

GFNW . TSPN is a trapezium. All lines must be drawn in full.

JK = GW = FN < JF = KN

JG = KW > GF = WN

KT < SP < TW

The measurement is accurate to 0.2 cm. (one way ) and the anglesat all verticals of the rectangle are 90 1

K1

K1

K1

N1

K1

K1

N2

9

L K

M

T

SR

P

G

F

S

J


10/12


11/12

Graph for number 12

Graph for number 14

11

0

5

10

15

20

25

30

35

40

15.5 20.5 25.5 30.5 35.5 40.5 45.510.5


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spm percubaan 2007 sbp mathematics paper 2 marking scheme

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