Identifying Conic Sections

How do I determine whether the graph of an equation represents a conic, and if so, which conic does it represent, a circle, an ellipse, a parabola or a hyperbola?

Created by K. Chiodo, HCPS

General Form of a Conic Equation

We usually see conic equations written in General, or Implicit Form:

Ax2 +Bxy+Cy2 +Dx+Ey+F =0where A, B, C, D, E and F are integers and A, B and C are NOT ALL equal to zero.

Note: You may see some conic equations solved for y, but if the equation can be re-written into the form above, it is a conic equation!

Please Note:A conic equation written in General Form doesn’t have to have all SIX terms! Several of the coefficients A, B, C, D, E and F can equal zero, as long as A, B and C don’t ALL equal zero.

Dx+Ey+F =0Linear!

If A, B and C all equal zero, what kind of equation do you have?

T H I N K......

So, it’s a conic equation if...• the highest degree (power) of x and/or y is 2 (at least ONE has to be squared)

• the other terms are either linear, constant, or the product of x and y

• there are no variable terms with rational exponents (i.e. no radical expressions) or terms with negative exponents (i.e. no rational expressions)

What values form an Ellipse?

The values of the coefficients in the conic equation determine the TYPE of conic.

Ax2+Bxy+Cy2+Dx+Ey+F =0

What values form a Hyperbola?What values form a Parabola?

Ellipses...

Ax2 +Cy2 +Dx+Ey+F =0

NOTE: There is no Bxy term, and D, E & F may equal zero!

where A & C have the SAME SIGN

For example: 2x2 +y2 +8x=0

2x2 +2y2 +8x−6=0−x2 −2x−3y2 +6y=0

Ellipses...The General, or Implicit, Form of the equations can be converted to Graphing Form by completing the square and dividing so that the constant = 1.

2x2 +y2 +8x=02(x2 +4x+4)+y2 =8

2(x+2)2 +y2 =82(x+2)2

8 +y2

8 =88

(x+2)2

4 +y2

8 =1

This is an ellipse since x & y are both squared, and both quadratic terms have the same sign!

Center (-2, 0)

Vert. Axis = √8Hor. Axis = 2

Ellipses...In this example, x2 and y2 are both negative (still the same sign), you can see in the final step that when we divide by negative 4 all of the terms are positive.

−x2 −2x−3y2 +6y=0−(x2 +2x+1) −3(y2 −2y+1) =−1−3

−(x+1)2 −3(y−1)2 =−4−(x+1)2

−4 −3(y−1)2

−4 =1

(x+1)2

4 +(y−1)2

43=1

Vert. axis = 2/√3

Hor. axis = 2

center (-1, 1)

Ellipses…a special case!

it is a ...

When A & C are the same value as well as the same

sign, the ellipse is the same length in all directions …

2x2 +2y2 +8x−6=02(x2 +4x+2) +2y2 =6+4

2(x+2)2 +2y2 =10(x+2)2

5 +y2

5 =1

Circle!

Center (-2, 0)

Radius = √5

Hyperbola...

Ax2 +Cy2 +Dx+Ey+F =0

NOTE: There is no Bxy term, and D, E & F may equal zero!

where A & C have DIFFERENT signs.

For example: 9x2 −4y2 −36x−8y−4=0x2 −y2 +6y−5=0x2 +10x−4y2 +8y+5=0

Hyperbola...The General, or Implicit, Form of the equations can be converted to Graphing Form by completing the square and dividing so that the constant = 1.

9x2 −4y2 −36x−8y−4=09(x2 −4x)−4(y2 +2y) =4

9(x2 −4x+4) −4(y2 +2y+1) =4+36−49(x−2)2 −4(y+1)2 =369(x−2)2

36 −4(y+1)2

36 =3636

(x−2)2

4 −(y+1)2

9 =1

This is a hyperbola since x & y are both squared, and the quadratic terms have different signs!

Center (2,-1)

y-axis=3x-axis=2

Hyperbola... In this example, the signs change, but since the quadratic terms still have different signs, it is still a hyperbola!

x2 −y2 +6y−5=0x2 −(y2 −6y) =5

x2 −(y2 −6y+9) =5−9x2 −(y−3)2 =−4x2

−4 −(y−3)2

−4 =−4−4

(y−3)2

4 −x2

4 =1

Center (0,3)x-axis=2

y-axis=2

Parabola... A Parabola can be oriented 2 different ways:

Ax2 +Dx+Ey+F =0

A parabola is vertical if the equation has an x squared term AND a linear y term; it may or may not have a linear x term & constant:

Cy2 +Dx+Ey+F =0

A parabola is horizontal if the equation has a y squared term AND a linear x term; it may or may not have a linear y term & constant:

Parabola …Vertical

x2 −4x−y+7=0

The following equations all represent vertical parabolas in general form; they all have a squared x term and a linear y term:

4x2 +8x+y=0x2 −y−7=0

x2 +y=0

Parabola …VerticalTo write the equations in Graphing Form, complete the square for the x-terms. There are 2 popular conventions for writing parabolas in Graphing Form, both are given below:

Vertex (2,3)

0=x2 −4x−y+70=(x2 −4x+4)−y+7−40=(x−2)2 −y+3y=(x−2)2 +3

ory−3=(x−2)2

Parabola …VerticalIn this example, the signs must be changed at the end so that the y-term is positive, notice that the negative coefficient of the x squared term makes the parabola open downward.

Vertex (-1,4)0=4x2 +8x+y0=4(x2 +2x+1)+y−40=4(x+1)2 +y−4

−y=4(x+1)2 −4y=−4(x+1)2 +4

ory−4=−4(x+1)2

Parabola …Horizontal

y2 +8y−2x+18=0

The following equations all represent horizontal parabolas in general form, they all have a squared y term and a linear x term:

x+y2 −3=03y2 −6y+x−2=0

y2 −x=0

Parabola …HorizontalTo write the equations in Graphing Form, complete the square for the y-terms. There are 2 popular conventions for writing parabolas in Graphing Form, both are given below:

0=y2 +8y−2x+180=(y2 +8y+16) −2x+18−160=(y+4)2 −2x+2

2x=(y+4)2 +2

x=12(y+4)2 +1

or0=(y+4)2 −2(x−1)

2(x−1) =(y+4)2

Vertex (1,-4)

Parabola …Horizontal

0 =x+y2 −30 =y2 +x−3

−x=y2 −3x=−y2 +3

or(x−3) =−y2

In this example, the signs must be changed at the end so that the x-term is positive; notice that the negative coefficient of the y squared term makes the parabola open to the left.

Vertex (3,0)

What About the term Bxy?

Ax2 +Bxy+Cy2 +Dx+Ey+F =0None of the conic equations we have looked at so far included the term Bxy. This term leads to a hyperbolic graph:

4xy−8=0

y= 84x =2

x

or, solved for y:

Summary ...General Form of a Conic Equation:

Ax2 +Bxy+Cy2 +Dx+Ey+F =0where A, B, C, D, E and F are integers and A, B and C are NOT ALL equal to zero.

Identifying a Conic Equation: Conic Equation Stats

A = 0 or C = 0, but not both. Parabola If A = 0, then the parabola is horizontal.

If C = 0, then the parabola is vertical.

Circle A = C Ellipse A & C have the same sign. Hyperbola A & C have different signs.

Practice ...Identify each of the following equations as a(n):

(a) ellipse (b) circle (c) hyperbola

(d) parabola (e) not a conic

See if you can rewrite each equation into its Graphing Form!1) x2 +4y2 +2x−24y+33=02) 4x2 −4y2 −9=03) x2 −4x−y=04) x2 +y2 −2x−8=05) 9x2 +25y2 −54x−50y−119=06) x2 −x=07) y2 −8y−9x+52=08) x2 −2x−y2 +4y−7=0

Answers ...

1) x2 +4y2 +2x−24y+33=0 - -- > (a) (x+1)2

4 +(y−3)2

1 =1

2) 4x2 −4y2 −9=0 - -- > (c) x2

94−y2

94=1

3) x2 −4x−y=0 - --> (d) (y+4) =(x−2)2

4) x2 +y2 −2x−8=0 - -- > (b) (x−1)2 +y2 =9

5) 9x2 +25y2 −54x−50y−119=0 - - > (a) (x−3)2

25 +(y−1)2

9 =1

6) x2 −x=0 - --> (e) not a conic7) y2 −8y−9x+52=0 --- > (d) 9(x−4) =(y−4)2

8) x2 −2x−y2 +4y−7=0 - -- > (c) (x−1)2

4 −(y−2)2

4 =1

(a) ellipse (b) circle (c) hyperbola (d) parabola (e) not a conic

Conic Sections !CE

Created by K. Chiodo, HCPS

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