anstruk47
TRANSCRIPT
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8/18/2019 Anstruk47
1/2
3:3010
I:CD
5:306
I
12
I2:BC
2:3015
I:AB
×
×=
×
•> Kekakuan relatif :
•> MUT :
Rentang AB :
Rentang BC :
ftki36M
ftki36!12"
!6!"6!"2#"M
ftki$2%25!15"
!$!"6!"12"M
ftki2&%1'!15"
!6!"$!"12"M
(CB
2
2
(BC
2
2
(BA
2
2
(AB
−−=
−==
−−=
−
=
−==
•> )arga R relatif :
BBCCB
CBCBBC
BABBA
BBAAB
D
5C1036!2"536M
51036!2"536M
R ##$2%25!R 22"2$2%25M
R #22&%1'!R 22"22&%1'M
0*0:Diket
θ−θ−−=θ−θ−+−=
θ−θ−=θ−θ−+=
+θ−−=+θ−θ−+−=
+θ−=+θ−θ−+=
=θ=θ→Α
R 3:3010:R
0:0:R
2:3015:R
CD
BC
R AB
×∆
×∆
•> +er,- .l/e Defleti/n :
: 2# K 6 6
6
12k
2 IB
I
I
C
D
A
10
$
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8/18/2019 Anstruk47
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R $3!R 32"30M
R $6!R 32"30M
CCDDC
CDCCD
+θ−=+θ−θ−+=
+θ−=+θ−θ−+=
•>.4arat .a5ungan :
7/int B :
7/int C :
8e,eran: 0))12
0MM0MM
DA
CDCB
BCBA
=−−
=+
=+
!10"
MM)*
!15"
MM
!15"
!6!"12") DCCDD
BAABA
+=
++=
0!
10
MM"!
!15"
MM&%#"12 DCCDBAAB =
+−
++−
30
0
10
!R $3"!R $6"
!15"
!R ##$2%25"!R #22&%1'"&%#"12 CCBB =
+θ−++θ−−
+θ−−++θ−+−
'6%''R 3
'0$# CB −=−θ+θ→
•> +er,a5aan .i5ultan :
→
−=−θ+θ+
=+θ−θ−
−=+θ−θ−
'6%''R 3
'0$#
36R $165
0&%10R #51#
CB
CB
CB
2'$#%3R
03$1%1C
02&1%2B
=
−=θ
=θ
!2'$#%3"$!03$1%1"3M
!2'$#%3"$!03$1%1"6M
!02&1%2"5!03$1%1"1036M
!03$1%1!"5"!02&1%2"1036M
!2'$#%3"#!02&1%2"#$2%25M
!2'$#%3"#!02&1%2!"2"2&%1'M
DC
CD
CB
BC
BA
AB
+−−=
+−−=
−−−−=
−−−=
+−−=
+−=
•> M/5en U9ung :
ftki632%32
ftki'50%35
ftki'50%35
ftki$15%20
ftki$1#%20
ftki3#2%26
−=
−=
−−=
−=
−−=
−=