trial kedah 2014 spm kimia k1 k2 k3 dan skema [scan]

8/11/2019 Trial Kedah 2014 SPM Kimia K1 K2 K3 Dan Skema [SCAN]

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MODULE 2

CHEMISTRY 2014

KEDAH

PAPER 1 ANSWER

Question No. Answer Question No. Answer

1 B 26 A

2 A 27 A

3 D 28 B

4 A 29 A

5 C 30 C6 D 31 B

7 A 32 C

8 D 33 C

9 D 34 B

10 C 35 D

11 D 36 D

12 D 37 A

13 B 38 C

14 D 39 A

15 B 40 B

16 C 41 B

17 C 42 C

18 A 43 C

19 A 44 A

20 C 45 C

21 C 46 B

22 C 47 D

23 A 48 B

24 A 49 D

25 B 50 C


A

B

A

D

D

A


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MARK SCHEME : PAPER 2 MODULE B: CHEMISTRY

Question

NoMark Scheme Marks

1 a) Empirical formula : formula that shows the simplest whole number ratio of atoms ofeach element in a compound 1

b) To allow oxygen from the air to react with magnesium //To prevent fumes of magnesium oxide from escaping 1

d) (i) Mass of magnesium = 19.20 - 18.30 g = 0.9 g

Mass of oxygen = 19.80 - 19.20 g = 0.6 g 1

(ii) Elements Mg : ONo of mole 0.9 : 0.6

24 16

Ratio 0.0375 : 0.0375 // 1 : 10.0375 0.0375

1

1

(iii) MgO 1

(e) (i) Cu // Pb // Sn 1

(ii) To remove all the air in the combustion tube 1

(iii) To dry the hydrogen gas // as a drying agent 1

Total 9

Question

NoMark Scheme Marks

2 (a) Contact Process 1

(b) Oleum 1

(c) SO3 + H2SO4 H2S2O7 1

(d) 450-500OC 1

(e) Air (udara) 1

(f) Nitric acid 1

(g) (i) Acid rain corrodes the buildings made of calcium carbonate/limestone//

Acid rain corrodes concrete building

1

(ii) Reduce combustion of fossil fuels

Channel waste gases from factory through air filtering systems(accept any suitable answers)

1

1

Total 9



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3 (a) Heat released when one mol of water produce from reaction between hydrochoric

acid // acid and sodium hydroxide// alkaline solution. 1

(b) (i)

(ii)

(iii)

Heat change = mc

= 200 x 4.2 x 13

= 10 920 J = 10.92 kJ

No. of mol of H+ = 100 x 0.2

1000

= 0.02 mol

// No. of mol of OH-

= 100 x 0.21000

= 0.02 mol

Heat of neutralisation = 10920

0.02

= 546 000

Heat of neutralization = - 546 kJ mol-1

1

1

1(c)

correct diagram

labelled

1

1

(d) (i) Between -533 kJ mol-1

to 542 kJ mol-1

1

(ii) Ethanoic acid is a weak acid // ionise partially in water to produce hydrogen ion

Some heat is absorbed for ionization of ethanoic acid.

1

1

Total 10

546 kJmol-1


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5 (a) Sulphuric acid[r: H2SO4]

1

(b) H2SO4 + 2KOH K2SO4+ 2H2O

Correct formula reactant and product

Balanced

1

1

(c) (i) Able to calculate the volume of Y(V1) acid used with unit

M1V1= M 2V2

a b

0.1 (V1) = 0.2(25)

1 2

V1= 25 cm3 (r : without unit)

1

1

(ii) Able to calculate the mass of salt formed with unit

Number of mol Y acid = MV1000

= 0.1(25)

1000

=0.0025

Mass of salt formed= 0.0025 x 174

1

4 (a) Strong acid is an acid that ionises completelyin water to produce highconcentration of hydrogen ions.

1

(b) (i) Ethanoic acid 1

(ii) Ionise partially in water //produce low concentration of hydrogen ions. 1

(c) (i) 2 1

(ii) 10 x X = 250 x 0.02X = 0.5 mol dm

-3

11

(d) (i) water 1

(ii) H+ 1

(iii) Zn +2 HClZnCl2+ H21.correct formula and reactant

2.balancing

1

1

Total 10


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TOTAL 11

Section B

7 (a) (i) 1.No of mole of helium atoms= 4 mol //1 mol

42. No of mole of hydrogen atoms = 2 x 2mol //2 mol

2

1

1

(ii) 1.No of atom of hydrogen is double/twice than helium2.because no of mole of atom of hydrogen is double/twice than helium

11

(b) (i) Empirical formula = C5H7NMolecular Formula = C10H14N2

C5H7N C10H14N2

both contain element carbon,hidrogen and nitrogen

Contain 5 carbon atoms,7hidrogen atoms and 1 nitrogen

atom

Contain 10 carbon atoms,17hidrogen atoms and 2 nitrogen

atom

Shows simplest whole numberratio of atom of each element

Shows actual number of atom ofeach element

11

1

1+1

1+1

(ii) 1.brown bromine water decolourises2.nicotine undergoes addition reaction with bromine//c=c react with bromine

11

(c) (i) Wrong formula

1. AgCl22. Mg NO3

11

(ii) 2AgNO3 + MgCl2 2AgCl + Mg(NO3)2

1.correct formula of reactant and product2.correct balancing

11

(iii) 1. silver nitrate and magnesium chloride are reactants and silver chloride andmagnesium nitrate are products

2. silver nitrate , magnesium chloride and magnesium nitrate are in aqueoussolution but silver chloride in solid form

3. 2 mole of AgNO3react with 1 mole of MgCl2to form 2 mole of AgCl and1mole of Mg(NO3)2

(Note : point 3 ecf from (c)(ii))

1

1

1

Total 20



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(a) (i) 2H2O22H2O + O2

Correct formulabalanced

11

(ii)

Correct curve

axis and unitslabel expt(A,B) and time (20,40)

1

1

1

(iii) i) Increase the concentration of hydrogen peroxide 1

ii) 0.1 mol dm-3

/ any suitable higher concentration 1

iii) Volume 25 cm3/ any suitable volume to get that match the

concentration

1

iv) Any suitable application of concentration. 1

v) How the application is used. 1

(iv)

functional diagram

Labelled

1

1


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c) (i) 1. Rate of reaction of experiment B is higher 1

2. The presence of catalyst in experiment B 1

3. the reaction through the alternative path // lower activation energy 1

4. more colliding particle can achieve the lower activation energy 1

5. frequency of effective collision is higher. 1

c) (ii)

Correct graph

Label experiment (A,B)

Label activation energy

1

1

1

Total 20

Section C

9 a) i. Ionic: Y and X// Y and Z// Y and W

Covalent: W and X//W and Z //X and Z

1

1

ii Ionic:

Between Y and X



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ii.

or

Between Y and Z

Covalent

Correct no of shells and electron for each atoms involved


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Correct no of atoms// charge for each compund

1x2

1x2

ii Explain:Between element Y and X(sample for ionic)

Atom Y has 1 valence electron and atomX has 6 valence electron2 Atomof Y donate 1 electron each to form 2Y

+ion // 2Y2Y

+ + 2e

AtomX accept 2 electron to form X2-

ion // X + 2eX2-

To achieve stable octet electron arrangement2 ion Y

+and ion X

2-attract each other by a strong electrostatic forces

// Y2X ionic compound is formed

Between element W and X (WX2)(sample for covalent)

Oneatom W contribute 4electronsFour atom Z contribute 1electron to share.

One atom W share 4 pairs electron with four atom Z

Four single covalent bondare formedWZ4covalent compound is formed

1

111

11

11

1

11

Maximum mark 12

b)

Covalent Compound Ionic Compound d

Low melting and boiling points High melting and boiling points

Held by weak intermolecular

forces

Held by strong electrostatic

forces

Need more energy to overcome

the forces

Need less energy to overcome

the forces

or

1+1

1+1

1+1

Covalent Compound Ionic Compound

Cannot conduct electricity in

any state

Cannot conduct electricity in

solid state 1+1


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10 (a) Metal R: magnesium//zincReason: Metal R is more electropositive than iron// Iron nail does notrust//prevent iron from rusting//inhibit rusting of iron nail

Metal S: copper//tin//lead//silver//aurumReason: Iron is more electropositive than metal S// Iron nail rusts//speed up

rusting(accept any suitable metal R and S)

1

1

11

(b) Metal: magnesium // zinc// lead // tin

Eg:Oxidation nombor of Mg increases from 0+2 //MgMg

2++2e

Magnesium undergoes oxidation

Oxidation nombor of copper(II) ion decreases from +20// Cu2+

+2eCuCopper undergoes reduction

Redox reaction occurs as oxidation of magnesium and reduction of copper(II)ions occur simultaneously.

1

11

11

1

(c)

Diagram:

1. label2. functional apparatus

11

Suggested chemical:Potassium iodide solution(or any suitable reducing agent) 1

Can conduct electricity in

molten and aqueous state

Consist of molecules Consist of ions

Neutral particles Charged particles//Move freelyin molten and aqueous state

1+1

1+1

mark 6

TOTAL 20

Carbon

electrode

Potassium

iodide

solution

Carbon

electrode

Bromine water

Sulphuric acid


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Procedure:

1. Dilute sulphuric acid is poured into a U-tube.2. Using a dropper, potassium bromide solution is added at one arm

and bromine water at another arm.4. Carbon electrode is placed in each side of the U-tube.5. The electrodes are connected to a galvanometer by using connecting

wires// The external circuit is completed.6. Any changes that can be observed are recorded.

Half-equations:

2I-I2+ 2eBr2+ 2e2Br

-

1

11

11

1

1

Max 10

Total 20

END OF MARK SCHEME



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MODULE B :KIMIA PAPER 3: Mark Scheme

Questions Mark Scheme Mark

1(a) Able to state the three variables correctlySample answer

Manipulated Variable: metals in contact with Fe//P,Q,R

Responding Variable: rusting//blue spots//pink spots

Constant Variable: iron nail//electrolyte

3

Able to state any two variables correctly 2

Able to state any one variables correctly 1

No response or wrong response 0

1(b) Able to state the relationship between the manipulated variable and theresponding variable and state the direction correctly.

Sample answer

The further the distance between two metals in electrochemical series,

When less electropositive metal in contact with iron, the higher is the

intensity/more of blue spots/rust

3

Able to state the relationship between the manipulated variable and the

responding variable without stating the direction

Sample answer

When different metal in contact with iron, the more blue spot/rust formed

2

Able to give an idea of hypothesis

Sample answer

Pair of metal willproduce rust.

1


1(c)Able to make inference correctly.

Sample answer

Set Inference

I Metal P is less elctropositive than iron

II Metal Q is the most electropositive.

III Metal R is more electropositive than iron

3

Able to state 2 inference correctly 2

Able to state 1 inference correctly 1


1(d) Able to give the operational definition for rusting correctly with the 3



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following aspects:i.what you do

ii.what you observe

Sample answer

When less electropositive metal in contact with iron, blue spot form

Able to give the operational definition for rusting incompletely with any

one of the following aspects:i.what you do

ii.what you observe

Sample answer

Metal is put into jelly blue spot form

2

Able to give an idea of operational definition for rusting

Sample answer

Metal rust

1


1(e) Able to compare the difference between 1 day and 2 days correctly

Sample answer

The size/quantity of blue spot increase with time

3

Able to compare the difference between 1 day and 2 daysSample answer

More blue spot form

2

Sample answer

Blue spot form

1


1(f) Able to arrange the four metals correctlySample answer

P, Fe, R, Q

3

Able to arrange any three metals in sequence correctlySample answers

Fe, R, Q , // P, Fe, R

2

Able to arrange any two metals correctlySample answers

P, Fe// Fe, R// R, Q

1


1(g) Able to predict the metal correctlySample answer

Copper/Cu // Silver/Ag

3

Able to predict the metal less correctlySample answer

2


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Set III : 1.4 // 1.40

Able to record at least one reading 1


1(k) Able to construct a table that consists of:1.Headings for manipulated and responding variables with unit

2. List all the variablesSample answer

Pairs of Metal Voltage (V)

Fe/P 2.2

Fe/Q 1.4

Fe/R 3.4

3

Able to construct a table that consists of:

1.Headings for manipulated and responding variables without unit2. List all the variablesSample answer

Pairs of Metal Voltage

Fe/P 2.2

Fe/Q 1.4

Fe/R 3.4

2


1.Headings for manipulated and responding variables

Sample answer

Pairs of Metal Voltage

1


2(a) Able to give the problem statement correctlySample answer

Does soap more effective than detergent for cleansing action in hard water?

3

Able to give the problem statementSample answer

Does soap more effective than detergent ?

2

Able to give an idea of the problem statement.Sample answer

Does soap more effective ?

1


2(b) Able to state all variables correctlySample answer

Manipulated variable: Detergent ,soap

Responding Variable: effectiveness of cleansing action

Fixed variable : hard water//mass/volume of detergent and

3


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soap//volume of water

Able to state any two variables correctly 2

Able to state any one variable correctly 1


2(c) Able to state the hypothesis correctlySample answer

Detergent is more effective than soap in hard water

3

Able to state the hypothesisSample answer

Detergent is more effective

2

Able to give an idea of the hypothesisSample answer

Detergent is for cleaning action

1


2(d) Able to list the materials and apparatus completelySample answer

Materials

1. dirty cloth/socks

2. soap and detergent

3. hard water

Apparatus

1. Beaker/basin

2.

Measuring cylinder3. Spoon/spatula

3

Able to list the materials and apparatusSample answer

Materials

1. cloth

2. soap and detergent

3. hard water

Apparatus

4. Beaker/basin/container

2

Able to give an idea of materials and apparatusSample answer

1. detergent/soap

2. cloth

3. water

1


2(e) Able to state all steps of procedure correctlySample answer

1.Pour 100-200 ml of hard water into a beaker

2. Add/put 1-2 spoon of detergent into the beaker3. Soak/dip a dirty cloth in the beaker

4. Leave for 30 minutes

5.Record the observation

6. Repeat steps 1-5 using soap.

3

Able to state the steps 1,2,3 and 5 2


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Able to state steps 1.2 and 3 1


2(f) Able to construct a table that consists of:

1.Headings for manipulated and responding variables2. List all the variablesSample answer

Type of cleaning agent Observation/Effectiveness

Detergent

Soap

2


1.Headings for manipulated and responding variables

Sample answer

Type of cleaning agent Observation

1


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