spm perlis addmath p1 2010 ans

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  • 8/8/2019 SPM Perlis Addmath P1 2010 Ans

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    ADD MATHEMATICS PAPER 1,2010

    Mark SchemeNo Answers Sub-

    marksTotalmark

    1 a) 5

    b) 3

    1

    1

    22 -2

    B1:3

    5)(

    x

    xf

    3

    3

    3 a) 3kx +8

    a)12

    5

    B1: 3k=4

    5

    1

    2

    3

    4 2.766 and1.266

    B2:

    )2(2)7)(2(4)3()3(

    2

    B1: 0732 2 xx

    3

    3

    5 a) 5)4( 2 x

    b) 11

    B1: 5)40( 2

    1

    2

    3

    65

    3

    1 x

    B2:

    B1: (3x + 4)(x

    5) < 0

    Or roots3

    1 and 5

    3

    3

    7 3

    B2: 3x +1 = 2(x1)

    B1: 21

    )5(5)1(413 xx or

    3

    3

    8n

    m

    22

    5

    B3:

    2

    log2log2log5 qp

    B2: change base and 1law of log

    B1: use 1 law of log

    4

    4

    9 27

    B2: 23

    9x

    B1: 32

    x seen

    3

    3

    No Answers Sub-mark

    Totalmark

    10a)

    3

    2

    B1:729

    8

    18

    1 5 arorar

    b) 25.04

    1or

    B1:12

    1a

    2

    2

    4

    11 a) 15

    b) 217

    B2: )4)(17()19(22

    7 or

    )4(5)5(22

    6)4(12)5(2

    2

    13

    B1: 197 T or )4(12)5(2213

    or )4(5)5(22

    6

    1

    3

    4

    12 xxy 42 2

    B2: 42 xx

    y

    B1: m = 2

    3

    3

    13

    2

    3 or 1.5

    B2: 1

    5

    6

    4

    5

    p

    B1:p4

    5 or

    5

    6 seen

    3

    3

    14a) ji 34 or

    3

    4

    B1: OBAOAB

    b) 5

    2

    1

    3

    15

    3

    10

    B3: 10k= 3mB2: 2m and 35 k

    B1: RSPQ seen

    4

    4

    16a)

    k

    1

    b) 21 k

    B1: xx sinsincoscos

    1

    2

    3

    3

    1 5

  • 8/8/2019 SPM Perlis Addmath P1 2010 Ans

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    No Answers Sub-mark

    Totalmark

    17 a) 0.3948

    B1:13

    12cos POR

    b) 11.13B1: 3948.013

    2

    24

    1825

    3

    2 3 xxy

    B2: c )3(5)3(3

    21

    3

    B1: xx 53

    2 3

    3

    3

    19 24x16

    B1:

    6 or

    2 seen

    2

    2

    20

    3

    1

    B2: 12x4 = 0

    B1: 12x4

    3

    3

    21 4

    B2: 4k2k= 8B1: 5 seen

    3

    3

    22 8

    B2: 0)87(2 2 kk

    or

    87(22

    kk

    B!:22

    3

    7

    3

    29

    kk

    3

    3

    23a)

    7

    3

    B1:7

    2

    3

    1or seen

    b)21

    2

    B1:7

    2

    3

    1

    2

    2

    4

    24 a) 3B1: p = 0.05

    2

    b) 2.85B1:

    95.005.060

    2

    4

    25 a) 65.15

    B1: 95.03

    68

    b) 0.7

    B1: 0.242

    2

    2

    4