peperiksaan percubaan sijil pelajaran · pdf file[jisim atom relatif: h=1, n=14, o=16;isipadu...

94
Lihat sebelah NAMA :.................................................................................................... KELAS :................................................................................................... PEPERIKSAAN PERCUBAAN SIJIL PELAJARAN MALAYSIA 2015 4541/1 CHEMISTRY Kertas 1 September 1 ¼ jam 1 jam 15 minit DO NOT OPEN THIS PAPER UNTIL YOU ARE TOLD TO DO SO JANGAN BUKA KERTAS SOALAN INI SEHINGGA DIBERITAHU INFORMATION FOR CANDIDATES MAKLUMAT UNTUK CALON 1. This question paper consists of 50 questions Kertas soalan ini mengandungi 50 soalan 2. Answer all questions. Jawab semua soalan. 3. Each question is followed by four alternative answers, A, B, C or D. For each question, choose one answer only. Blacken your answer on the objective answer sheet provided. Tiap-tiap soalan diikuti oleh empat pilihan jawapan, iaitu A, B, C dan D. Bagi setiap soalan, pilih satu jawapan sahaja. Hitamkan jawapan anda pada kertas jawapan objektif yang disediakan. 4. The diagrams in the questions provided are not drawn to scale unless stated. Rajah yang mengiringi soalan tidak dilukis mengikut skala kecuali dinyatakan. 5. You may use a non-programmable scientific calculator. Anda dibenarkan menggunakan kalkulator saintifik yang tidak boleh diprogram. ------------------------------------------------------------------------------------------------------------------------------- Kertas soalan ini mengandungi 26 halaman bercetak https://cikguadura.wordpress.com/

Upload: dinhdiep

Post on 06-Mar-2018

262 views

Category:

Documents


9 download

TRANSCRIPT

Page 1: PEPERIKSAAN PERCUBAAN SIJIL PELAJARAN · PDF file[Jisim atom relatif: H=1, N=14, O=16;Isipadu molar gas = 24 dm3mol-1 pada keadaan bilik) A Hydrogen, nitrogen, ... Anion that exist

Lihat sebelah

NAMA :....................................................................................................

KELAS :...................................................................................................

PEPERIKSAAN PERCUBAANSIJIL PELAJARAN MALAYSIA 2015 4541/1

CHEMISTRYKertas 1September1 ¼ jam 1 jam 15 minit

DO NOT OPEN THIS PAPER UNTIL YOU ARE TOLD TO DO SOJANGAN BUKA KERTAS SOALAN INI SEHINGGA DIBERITAHU

INFORMATION FOR CANDIDATESMAKLUMAT UNTUK CALON

1. This question paper consists of 50 questionsKertas soalan ini mengandungi 50 soalan

2. Answer all questions.Jawab semua soalan.

3. Each question is followed by four alternative answers, A, B, C or D. For each question,choose one answer only. Blacken your answer on the objective answer sheet provided.Tiap-tiap soalan diikuti oleh empat pilihan jawapan, iaitu A, B, C dan D. Bagi setiapsoalan, pilih satu jawapan sahaja. Hitamkan jawapan anda pada kertas jawapan objektifyang disediakan.

4. The diagrams in the questions provided are not drawn to scale unless stated.Rajah yang mengiringi soalan tidak dilukis mengikut skala kecuali dinyatakan.

5. You may use a non-programmable scientific calculator.Anda dibenarkan menggunakan kalkulator saintifik yang tidak boleh diprogram.

-------------------------------------------------------------------------------------------------------------------------------Kertas soalan ini mengandungi 26 halaman bercetak

https://cikguadura.wordpress.com/

Page 2: PEPERIKSAAN PERCUBAAN SIJIL PELAJARAN · PDF file[Jisim atom relatif: H=1, N=14, O=16;Isipadu molar gas = 24 dm3mol-1 pada keadaan bilik) A Hydrogen, nitrogen, ... Anion that exist

2 4541/1

4541/1 PAHANG

1. What is the first step in a scientific investigation?Apakah langkah pertama dalam penyisatan saintifik?

A Identifying the problemMengenalpasti masalah

B Making an observationMembuat pemerhatian

C Making a hypothesisMembuat hipotesis

D Planning an experimentMerancang eksperimen

2. Which of the following statements is true about atomic model proposedby Neils Bohr?Antara berikut, pernyataan manakah yang benar tentang model atom yangdicadangkan oleh Neils Bohr?

A The nucleus of the atom contains proton.Nukleus atom mengandungi proton

B The nucleus of the atom contains proton and neutrons.Nukleus bagi atom mengandungi proton dan neutron

C The atom was described as a sphere of positive charge embedded withelectronAtom merujuk kepada sebuah sfera bercas positif dengan elektronbertaburan di atasnya.

D The electrons in an atom move in shells around the nucleusElektron suatu atom bergerak di petalanya mengelilingi nukleus.

3. Which of the following statements is true about the isotopes Br7935 and Br81

35 ?

Antara berikut, pernyataan manakah adalah benar mengenai isotop Br7935 and Br81

35 ?I They have the same chemical properties.

Isotop tersebut mempunyai sifat kimia yang samaII They have same physical properties.

Isotop tersebut mempunyai sifat fizikal yang sama.III They have the same number of valence electrons.

Isotop tersebut mempunyai bilangan electron valens yang samaIV They have different numbers of neutrons.

Isotop tersebut mempunyai bilangan neutron yang berbeza.

https://cikguadura.wordpress.com/

Page 3: PEPERIKSAAN PERCUBAAN SIJIL PELAJARAN · PDF file[Jisim atom relatif: H=1, N=14, O=16;Isipadu molar gas = 24 dm3mol-1 pada keadaan bilik) A Hydrogen, nitrogen, ... Anion that exist

3 4541/1

4541/1 PAHANG

A I , II and III onlyI , II dan III sahaja

B I, III and IV onlyI, III dan IV sahaja

C II, III and IV onlyII, III dan IV sahaja

D I, II ,III and IVI, II ,III dan IV

4. Table 1 shows the melting point and boiling point of substances P,Q, R and S.Jadual 1 menunjukkan takat lebur dan takat didih untuk bahan P, Q, R, dan S.

SubstanceBahan

Melting point °CTakat lebur °C

Boiling point °CTakat didih °C

P - 157 - 9Q - 13 55R 80 196S 256 300

Table 1Jadual 1

Which substance is a liquid at room temperature?Bahan manakah wujud sebagai cecair pada suhu bilik?

A PB QC RD S

5. 1 mol of oxygen gas, O2 and 1 mol of carbon dioxide gas, CO2 have1 mol gas oksigen, O2 dan 1 mol gas karbon dioksida, CO2 mempunyai

A same massjisim yang sama

B same number of atomsbilangan atom yang sama

C same number of moleculesbilangan molekul yang sama

D same number of electronsbilangan elektron yang sama

Page 4: PEPERIKSAAN PERCUBAAN SIJIL PELAJARAN · PDF file[Jisim atom relatif: H=1, N=14, O=16;Isipadu molar gas = 24 dm3mol-1 pada keadaan bilik) A Hydrogen, nitrogen, ... Anion that exist

4 4541/1

4541/1 PAHANG

6. The formula for a nitrate ion is NO3- and for a sulphate is SO4

2-. If the formula of thenitrate salts of M is MNO 3 2, what is the formula of the sulphate salt of M?Formula untuk ion nitrat ialah NO3

- manakala ion sulfat ialah SO42-. Sekiranya formula

garam nirat M ialah MNO 3 2, apakah formula untuk garam sulfat M?

A MSO4

B M2SO4

C M SO4 2

D M SO3 3

7. Diagram 1 shows three balloons with hydrogen, nitrogen and oxygen gasrespectively.Rajah 1 menunjukkan tiga biji belon mengandungi gas hidrogen, nitrogen, danoksigen setiap satu.

Diagram 1Rajah 1

Arrange the gases in descending order of volume.[Relative atomic mass: H=1, N=14, O=16 and 1 mol of gas occupies 24 dm 3 at roomtemperature and pressure]

Susun gas-gas tersebut mengikut susunan menurun isipadu.[Jisim atom relatif: H=1, N=14, O=16; Isipadu molar gas = 24 dm3mol-1 pada keadaanbilik)

A Hydrogen, nitrogen, oxygenHidrogen, nitrogen, oksigen

B Hydrogen, oxygen, nitrogenHidrogen, oksigen, nitrogen

C Nitrogen, oxygen, hydrogenNitrogen, oksigen, hidrogen

D Oxygen, nitrogen, hydrogenOksigen, nitrogen, hidrogen

2.5 g ofhydrogen

gas2.5 g gashidrogen

7.0 g ofnitrogen

gas7.0 g gasnitrogen

2.5 g ofoxygen

gas2.5 g gasoksigen

Page 5: PEPERIKSAAN PERCUBAAN SIJIL PELAJARAN · PDF file[Jisim atom relatif: H=1, N=14, O=16;Isipadu molar gas = 24 dm3mol-1 pada keadaan bilik) A Hydrogen, nitrogen, ... Anion that exist

5 4541/1

4541/1 PAHANG

8.

Diagram 2Rajah 2

Diagram 2 shows melamine plates. Melamine plates usually used at home becauseof the good appearance, hardy and unbreakable. Melamine plates consist of mixtureincluding melamine with molecular formula C3H6N6. Find the relative molecular massof melamine.[Relative atomic mass: H=1, N=14, C=12]Rajah 2 menunjukkan pinggan melamin. Pinggan melamin biasanya digunakan dirumah kerana selain rupanya yang cantik, ia juga tahan lasak dan tidak mudahpecah. Pinggan melamin terdiri daripada bahan campuran termasuk melamin yangmempunyai formula molekul C3H6N6. Hitungkan jisim molekul relatif melamin. [Jisimatom relatif: H=1, N=14, C=12]

A 121B 126C 130D 132

9. Which statement is correct about noble gases?Penyataan manakah yang benar tentang gas adi?

A Do not form chemical bondsTidak membentuk ikatan kimia

B Exist as diatomic moleculesWujud sebagai molekul dwiatom

C Form ions with different oxidation numberMembentuk ion dengan nombor pengoksidaan berbeza

D Combine with transition metals to form coloured compoundsBergabung dengan logam peralihan membentuk sebatian berwarna

Page 6: PEPERIKSAAN PERCUBAAN SIJIL PELAJARAN · PDF file[Jisim atom relatif: H=1, N=14, O=16;Isipadu molar gas = 24 dm3mol-1 pada keadaan bilik) A Hydrogen, nitrogen, ... Anion that exist

6 4541/1

4541/1 PAHANG

10. Table 2 shows the boiling points of three elements in Group 17.Jadual 2 menunjukkan takat didih bagi tiga unsur dalam Kumpulan 17.

HalogenHalogen

Boiling point ° CTakat didih ° C

FluorineFluorin

-188

ChlorineKlorin

-35

BromineBromin

59

Table 2Jadual 2

Which of the following best explain why the boiling point increases down thegroup?Antara berikut, yang manakah menjelaskan dengan tepat mengapa takat didihmeningkat apabila menuruni kumpulan?

A Increase in proton number.Bilangan proton bertambah

B Intermolecular forces of attraction become strongerDaya tarikan antara molekul semakin kuat

C Increase in number of occupied shells of the atomBilangan petala yang berisi elektron bertambah

D Increase in strength of the covalent bond between the atomsKekuatan ikatan kovalen antara atom bertambah

11. During the formation of ionic bonds, the atoms of elementsSemasa pembentukan ikatan ion, atom untuk setiap unsur

A share electronsberkongsi elektron

B accept electronsmenerima elektron

C donate electronsmenderma elektron

D transfer electronsmemindahkan elektron

Page 7: PEPERIKSAAN PERCUBAAN SIJIL PELAJARAN · PDF file[Jisim atom relatif: H=1, N=14, O=16;Isipadu molar gas = 24 dm3mol-1 pada keadaan bilik) A Hydrogen, nitrogen, ... Anion that exist

7 4541/1

4541/1 PAHANG

12. Among the following compounds, which one contains particles bonded by strongelectrostatic forces?Antara sebatian-sebatian berikut, yang manakah mengandungi zarah yang terikatdengan daya elektrostatik yang kuat?

A AmmoniaAmmonia

B NaphthaleneNaftalena

C Potassium oxideKalium oksida

D Carbon dioxideKarbon dioksida

13. The number of valence electrons of atoms X and Y are 2 and 7 respectively. Whichof the following chemical formulae and types of bonding are true for the compoundformed between X and Y?Bilangan elektron valens atom X dan Y ialah 2 dan 7 untuk setiap satu. Yangmanakah antara berikut menunjukkan formula kimia dan jenis ikatan yang terbentukantara X dan Y?

Chemical FormulaSifat kimia

Type of BondingJenis Ikatan

A XY2IonicIon

B XY2CovalentKovalen

C X2YIonicIon

D X2YCovalentKovalen

Page 8: PEPERIKSAAN PERCUBAAN SIJIL PELAJARAN · PDF file[Jisim atom relatif: H=1, N=14, O=16;Isipadu molar gas = 24 dm3mol-1 pada keadaan bilik) A Hydrogen, nitrogen, ... Anion that exist

8 4541/1

4541/1 PAHANG

14.

Diagram 3Rajah 3

Diagram 3 shows a picture of cooking gas cylinder which is always used at home.Butane in cooking gas burns to release gas X. Both butane and gas X areRajah 3 menunjukkan gambar silinder gas memasak yang sering digunakan dirumah. Butana dalam gas memasak terbakar membebaskan gas X. Kedua-duabutana dan gas X adalah

A ionic compoundssebatian ion

B organic compoundssebatian organik

C covalent compoundssebatian kovalen

D hydrocarbon compoundssebatian hidrokarbon

15. Which is the example of electrolyte?Yang manakah antara berikut adalah contoh elektrolit?

A Sugar solutionLarutan gula

B Molten naphthaleneLeburan naftalena

C Solid sodium chloridePepejal natrium klorida

D Molten lead II bromideLeburan plumbum II bromida

Page 9: PEPERIKSAAN PERCUBAAN SIJIL PELAJARAN · PDF file[Jisim atom relatif: H=1, N=14, O=16;Isipadu molar gas = 24 dm3mol-1 pada keadaan bilik) A Hydrogen, nitrogen, ... Anion that exist

9 4541/1

4541/1 PAHANG

16. Anion that exist is molten zinc chloride includeAnion yang terdapat dalam zink klorida lebur termasuklah

A Cl-

B Cl- , OH-

C Cl- , Zn2+

D Zn2+, H+, OH-, Cl-

17. Diagram 4 shows a chemical cell using magnesium and copper as the electrodes.Rajah 4 menunjukkan satu sel kimia menggunakan magnesium dan kuprum sebagaielektrod

Diagram 4Rajah 4

Which of the following half equations represents the reaction at the copperelectrode?Antara berikut, yang manakah merupakan persamaan setengah yang menunjukkantindak balas pada elektrod kuprum?

A Cu2+ + 2e → CuB 2 H+ + 2e → H2

C Cu → Cu2+ + 2eD 2 Cl- → Cl2 + 2e

MagnesiumMagnesium

CopperKuprum

Copper (II) sulphate solutionLarutan kuprum (II) sulfat

Page 10: PEPERIKSAAN PERCUBAAN SIJIL PELAJARAN · PDF file[Jisim atom relatif: H=1, N=14, O=16;Isipadu molar gas = 24 dm3mol-1 pada keadaan bilik) A Hydrogen, nitrogen, ... Anion that exist

10 4541/1

4541/1 PAHANG

18.

Diagram 5Rajah 5

A student has an iron ring as shown in Diagram 5. He wants to make the ring morebeautiful and durable to give to his friend as a present. What is the best way to do it?Seorang pelajar mempunyai sebentuk cincin besi seperti yang ditunjukkan dalamRajah 5. Pelajar tersebut ingin menjadikan cincin tersebut lebih cantik dan tahanlama untuk dihadiahkan kepada rakannya. Bagaimanakah cara terbaik untukmencantikkan cincin tersebut?

A Dip the ring in acidRendam cincin tersebut di dalam asid

B Wash the ring with detergentBasuh cincin dengan serbuk pencuci

C Plate the ring with silverSadur cincin tersebut dengan perak

D Brush the ring with glossy materialBerus cincin tersebut dengan bahan pengilat

19. Which of the following is true about an alkali?Manakah antara berikut adalah benar tentang alkali?

A an alkali is not corrosivealkali adalah tidak menghakis

B an alkali is a base that is soluble in wateralkali ialah bes yang larut dalam air

C a weak alkali has a high pH valuealkali lemah mempunyai nilai pH yang tinggi

D a strong alkali has a low degree of ionizationalkali kuat mempunyai darjah pengionan yang rendah

Page 11: PEPERIKSAAN PERCUBAAN SIJIL PELAJARAN · PDF file[Jisim atom relatif: H=1, N=14, O=16;Isipadu molar gas = 24 dm3mol-1 pada keadaan bilik) A Hydrogen, nitrogen, ... Anion that exist

11 4541/1

4541/1 PAHANG

20. Table 3 shows information about three chemical cells.Jadual 3 menunjukkan maklumat tentang tiga sel kimia.

Pair of metalsPasangan logam

Potential difference VBeza keupayaan V

Positive terminalTerminal positif

R,S 0.3 RT, S 0.8 TS, U 1.9 S

Table 3Jadual 3

The arrangement of the metals in the electrochemical series in ascending order ofelectropositivity isSusunan logam dalam siri elektrokimia mengikut susunan menaik keelektropositifanialahA R, U, S, TB T, R, S, UC T, R, U, SD U, S, R, T

21. Which of the following solutions has the lowest pH value?Yang manakah antara larutan berikut mempunyai nilai pH paling rendah?A 0.01 mol dm-3 nitric acid

0.01 mol dm-3 asid nitrikB 0.10 mol dm-3 nitric acid

0.10 mol dm-3 asid nitrikC 0.01 mol dm-3 sodium hydroxide

0.01 mol dm-3 natrium hidroksidaD 0.10 mol dm-3 sodium hydroxide

0.10 mol dm-3 natrium hidroksida

22. Acid rain causes the land to become acidic. Farmers neutralize acidity in the soilby addingHujan asid menyebabkan tanah menjadi berasid. Petani boleh meneutralkankeasidan tanah dengan menambah

A SulphurSulfur

B Zinc nitrateZink nitrat

C Soda limeKapur tohor

D Ammonium sulphateAmmonium sulfat

Page 12: PEPERIKSAAN PERCUBAAN SIJIL PELAJARAN · PDF file[Jisim atom relatif: H=1, N=14, O=16;Isipadu molar gas = 24 dm3mol-1 pada keadaan bilik) A Hydrogen, nitrogen, ... Anion that exist

12 4541/1

4541/1 PAHANG

23. Diagram 6 show two aqueous solutions.Rajah 6 menunjukkan dua jenis larutan akueus.

Rajah 6Diagram 6

Which of the following statements is true?Yang manakah antara pernyataan berikut adalah benar?

A Both solutions are strong acidKedua-dua larutan merupakan asid kuat

B The pH of both solutions are equalpH untuk kedua-dua larutan adalah sama

C Both solutions has low degree of ionizationKedua-dua larutan mempunyai darjah pengionan yang rendah

D Both solution can react with sodium hydroxide solutionKedua-dua larutan boleh bertindak balas dengan larutan natrium hidroksida

24. Which of the following is an insoluble salt?Yang manakah antara berikut adalah garam tidak larut?

A Silver nitrateArgentum nitrat

B Ammonium kloridaAmmonium chloride

C Zinc sulphateZink sulfat

D Magnesium carbonateMagnesium karbonat

HCl0.1 mole dm-3

CH3COOH0.1 mole dm-3

Page 13: PEPERIKSAAN PERCUBAAN SIJIL PELAJARAN · PDF file[Jisim atom relatif: H=1, N=14, O=16;Isipadu molar gas = 24 dm3mol-1 pada keadaan bilik) A Hydrogen, nitrogen, ... Anion that exist

13 4541/1

4541/1 PAHANG

25. A metal carbonate, XCO3, is green in colour. When it is heated strongly, theremaining solid is black. Which of the following metals could be X?Sejenis logam karbonat, XCO3 adalah berwarna hijau. Apabila dipanaskan dengankuat, pepejal yang tertinggal berwarna hitam. Yang manakah kemungkinan adalahlogam X?

A ZincZink

B LeadPlumbum

C CopperKuprum

D AluminiumAluminium

26.

Diagram 7Rajah 7

Diagram 7 shows a bottle of salt which has been used for cooking at home. This saltcan react with silver nitrate salt to produce an insoluble salt. Name the insoluble salt.Rajah 7 menunjukkan sebotol garam yang digunakan untuk memasak di rumah.Garam ini boleh bertindak balas dengan garam argentum nitrat menghasilkan sejenisgaram tak larut. Namakan garam tak larut yang terhasil

A Sodium nitrateNatrium nitrat

B Sodium chlorideNatrium klorida

C Silver chlorideArgentum klorida

D Siver sulphateArgentum sulfat

Page 14: PEPERIKSAAN PERCUBAAN SIJIL PELAJARAN · PDF file[Jisim atom relatif: H=1, N=14, O=16;Isipadu molar gas = 24 dm3mol-1 pada keadaan bilik) A Hydrogen, nitrogen, ... Anion that exist

14 4541/1

4541/1 PAHANG

27. Which of the following equation represents the most suitable reaction to prepare aninsoluble salt?Manakah antara persamaan kimia berikut menunjukkan tindak balas yang palingsesuai untuk menyediakan garam tak terlarutkan.

A PbNO 3 2 + 2KCl PbCl2 + 2KNO3

B Ba NO 3 2 + 2KCl BaCl2 + 2KNO3

C Pb + H2SO4 PbSO4 + H2

D PbOH 2 + 2HCl PbCl2 + 2H2O

28. Table 4 shows the result of a series of tests carried out on a solution of salt J.Jadual 4 menunjukkan keputusan beberapa siri ujian yang dijalankan terhadap satularutan garam J.

TestUjian

ObservationPemerhatian

Add dilute sulphuric acidTambahkan asid sulfurik cair

No changesTiada perubahan

Add leadII nitrate solution , thenheat itTambahkan plumbum II nitrat,kemudian panaskan

White precipitate dissolves whenheated.Mendakan putih larut apabiladipanaskan

Add sodium hydroxide solution untilin excessTambahkan larutan natriumhidroksida sehingga berlebihan

White precipitate is formed.It is insoluble in excess sodiumhydroxide solutionMendakan putih terbentuk.Mendakan tidak larut dalam natriumhidroksida berlebihan

Add ammonia solution until inexcessTambahkan larutan ammoniaberlebihan

White precipitate is formed.It is insoluble in excess ammoniasolutionMendakan putih terbentukMendakan tidak larut dalam larutanammonia berlebihan

Table 4 / Jadual 4Based on the results of the experiment, what is salt J?Berdasarkan keputusan eksperimen, apakah garam J?A Magnesium chloride

Magnesium kloridaB Zinc sulphate

Zink sulfatC Zinc chloride

Zink kloridaD Magnesium sulphate

Magnesium sulfat

Page 15: PEPERIKSAAN PERCUBAAN SIJIL PELAJARAN · PDF file[Jisim atom relatif: H=1, N=14, O=16;Isipadu molar gas = 24 dm3mol-1 pada keadaan bilik) A Hydrogen, nitrogen, ... Anion that exist

15 4541/1

4541/1 PAHANG

29.

Diagram 8Rajah 8

Diagram 8 shows ceramic vase which are made from clay. Name the maincomponent of clay.Rajah 8 menunjukkan pasu seramik yang diperbuat daripada tanah liat. Namakankomponen utama tanah liat.

A KaolinKaolin

B PerspexPerspeks

C Silicon dioxideSilikon dioksida

D Aluminium oxideAluminium oksida

30. Which of the following reactions occurs at the highest rate?Antara tindak balas berikut, yang manakah berlaku pada kadar yang paling tinggi?

A PhotosynthesisFotosintesis

B Rusting of ironPengaratan besi

C FermentationPenapaian

D Precipitation reactionTindak balas pemendakan

Page 16: PEPERIKSAAN PERCUBAAN SIJIL PELAJARAN · PDF file[Jisim atom relatif: H=1, N=14, O=16;Isipadu molar gas = 24 dm3mol-1 pada keadaan bilik) A Hydrogen, nitrogen, ... Anion that exist

16 4541/1

4541/1 PAHANG

31. The chemical equation shows a reaction between sodium thiosulphate solution withhydrochloric acid solution.Persamaan kimia di bawah menunjukkan tindak balas antara larutan natrium tiosulfatdan larutan asid hidroklorik

Na2S2O3 + 2HCl 2NaCl + SO2 + S + H2O

Which of the following changes cannot be used to determine the rate of reaction?Antara berikut, perubahan manakah yang tidak boleh digunakan untukmenentukan kadar tindak balas?

A Change in the pH of the mixturePerubahan pH campuran

B Time taken for ‘X’ mark disappear from sightMasa untuk pangkah ‘X’ hilang daripada pandangan

C Increase in mass of sulphurPeningkatan jisim sulfur

D Change in volume of sulphur dioxide gas releasedPerubahan isipadu gas sulfur dioksida yang terbebas

32. Table 5 shows the total volume of gas collected at regular intervals in a reaction.Jadual 5 menunjukkan jumlah isipadu gas yang dikumpul pada sela masa yangsekata bagi satu tindak balas.

Time / min 0.0 0.5 1.0 1.5 2.0 2.5 3.0 3.5

Volume of gas / cm3 0.00 8.00 14.50 20.50 24.00 26.50 26.50 26.50

Table 5Jadual 5

What is the average rate of reaction?Berapakah kadar tindak balas purata?A 0.10 cm3 min-1

B 7.60 cm3 min-1

C 10.60 cm3 min-1

D 37.40 cm3 min-1

Page 17: PEPERIKSAAN PERCUBAAN SIJIL PELAJARAN · PDF file[Jisim atom relatif: H=1, N=14, O=16;Isipadu molar gas = 24 dm3mol-1 pada keadaan bilik) A Hydrogen, nitrogen, ... Anion that exist

17 4541/1

4541/1 PAHANG

33.

Diagram 9Rajah 9

Based on the above statement, choose the best explanation.Berdasarkan pernyataan di atas, pilih penjelasan yang paling sesuai.

A The smaller the size of reactant, the higher the kinetic energy of the particlesLebih kecil saiz bahan tindak balas, lebih tinggi tenaga kinetik zarah-zarah.

B The smaller the size of reactant, more particles in reactant will existLebih kecil saiz bahan tindak balas, semakin banyak jumlah zarah yangwujud.

C The smaller the size of reactant, the lower activation energy needs for areaction to occur.Lebih kecil saiz bahan tindak balas, lebih rendah tenaga pengaktifan yangdiperlukan untuk tindak balas.

D The smaller the size of reactant, the bigger the total surface area.Lebih kecil saiz bahan tindak balas, lebih besar luas jumlah permukaanbahan tindak balas tersebut

A slice of meat which has been cut into smaller pieces takes a shorter time tocook if compared to a slice of meat which did not cut to smaller piecesSekeping daging yang dipotong kepada kepingan-kepingan kecil akan

mengambil masa yang lebih cepat untuk dimasak berbanding sekeping dagingyang tidak dipotong.

.

Page 18: PEPERIKSAAN PERCUBAAN SIJIL PELAJARAN · PDF file[Jisim atom relatif: H=1, N=14, O=16;Isipadu molar gas = 24 dm3mol-1 pada keadaan bilik) A Hydrogen, nitrogen, ... Anion that exist

18 4541/1

4541/1 PAHANG

.

Situation A Situation BSituasi A Situasi B

Diagram 10Rajah 10

34. Diagram 10 shows Puan Siti dry the cloth at two different places, which are situationA: outside home, while situation B: inside home. Which situation can dry the clothfaster and why?Rajah 10 menunjukkan Puan Siti menjemur pakaian pada dua tempat yang berbeza,iaitu situasi A: di luar rumah, manakala situasi B: di dalam rumah. Situasi manakahyang dapat mengeringkan baju dengan lebih cepat dan mengapa?

SituationSituasi

ReasonSebab

A A There are more air particles outside homecompared to inside the home.Lebih banyak zarah udara terdapat di luar rumah

berbanding di dalam rumah.B A Temperature outside home is higher than inside

home.Suhu di luar rumah lebih tinggi berbanding di dalamrumah

C B The smaller space inside home can provide moreheat compared to outside home.Ruang yang sempit di dalam rumah boleh

menghasilkan lebih banyak haba berbanding di luarrumah.

D B There are air movement inside the home comparedto outside the home.Terdapat pergerakan udara di dalam rumah

berbanding di luar rumah.

Page 19: PEPERIKSAAN PERCUBAAN SIJIL PELAJARAN · PDF file[Jisim atom relatif: H=1, N=14, O=16;Isipadu molar gas = 24 dm3mol-1 pada keadaan bilik) A Hydrogen, nitrogen, ... Anion that exist

19 4541/1

4541/1 PAHANG

35. Table 6 shows the experiments carried out to study the rate of reaction between zinccarbonate and nitric acid.Jadual 6 menunjukkan eksperimen yang dijalankan untuk mengkaji kadar tindakbalas antara zink karbonat dan asid nitrik

ExperimentEksperimen

Zinc carbonate, ZnCO3

Zink karbonat, ZnCO3

Nitric acid, HNO3

Asid nitrik, HNO3

Mass gJisim g

StateKeadaan

Volume cm 3

Isipadu cm 3Concentration mol dm -3

Kepekatan mol dm -3

I 5 GranuleButiran

50 0.1

II 5 PowderSerbuk

25 0.2

Table 6Jadual 6

Which of the following graph represents the two experiments?Antara berikut, graf manakah menunjukkan graf untuk kedua-dua eksperimen?

A B

C D

Page 20: PEPERIKSAAN PERCUBAAN SIJIL PELAJARAN · PDF file[Jisim atom relatif: H=1, N=14, O=16;Isipadu molar gas = 24 dm3mol-1 pada keadaan bilik) A Hydrogen, nitrogen, ... Anion that exist

20 4541/1

4541/1 PAHANG

36. Which of the following is correct about the conversion of unsaturated fats to saturatedfats?Antara berikut, yang manakah betul tentang penukaran lemak tak tepu kepada lemaktepu?A Intermolecular forces of attraction become weaker

Daya tarikan antara molekul menjadi lemahB The boiling point of the fats increases

Takat didih lemak meningkatC Physical state changes from solid to liquid

Keadaan fizikal berubah daripada pepejal ke cecairD Relative molecular mass of the oil molecule decreases

Jisim relatif molekul minyak berkurang

37. The structural formulae of two isomers are as follows.Formula struktur untuk dua isomer ditunjukkan seperti berikut.

H H H H H H H Br| | | | | | | |

H – C – C – C – C – H H – C – C – C – C – H| | | | | | | |H H Br H H H H H

Which of the following name can be used for both isomers?Nama yang manakah antara berikut boleh digunakan untuk kedua-dua isomer?A Bromoethane

BromoetanaB Bromopropane

BromopropanaC Bromobutane

BromobutanaD Bromopentane

Bromopentana

Page 21: PEPERIKSAAN PERCUBAAN SIJIL PELAJARAN · PDF file[Jisim atom relatif: H=1, N=14, O=16;Isipadu molar gas = 24 dm3mol-1 pada keadaan bilik) A Hydrogen, nitrogen, ... Anion that exist

21 4541/1

4541/1 PAHANG

38. When propane is burned in excess oxygen, carbon dioxide and water are formed andis represented by the equationApabila propana terbakar dalam oksigen berlebihan, karbon dioksida dan airdihasilkan dan persamaan yang terhasil adalah

a C3H8 + b O2 c CO2 + d H2O

What are the values of a, b, c and d?Apakah nilai a, b, c dan d?

a b c dA 1 5 1 3B 2 5 1 5C 2 5 3 8D 1 5 3 4

39. Fuel is needed for machine to operate and vehicles to move. Both butane and butenecan be used as fuel because the reaction of combustion in air is an exothermic. Whatare the others similar characteristics that butane and butene have?Bahan api diperlukan untuk sesebuah mesin beroperasi dan kenderaan untukbergerak. Kedua-dua butana dan butena boleh digunakan sebagai bahan api keranatindak balas pembakaran keduanya adalah eksotermik, Apakah ciri-ciri sepunya lainyang dipunyai oleh butana dan butena?I Exist as gas at room temperature.

Wujud sebagai gas pada suhu bilikII Decolourise the purple colour of acidified potassium manganateVII.

Menyahwarna ungu kalium manganat VII berasidIII Cannot dissolve in water.

Tidak larut dalam airIV Terbakar di udara berlebihan menghasilkan gas yang mengeruhkan air kapur

Burn in excess air to produce a gas that turns limewater cloudy.

A I and III onlyI dan III sahaja

B II and IV onlyII dan IV sahaja

C I, III and IV onlyI, III dan IV sahaja

D I, II, III dan IVI, II, III dan IV

Page 22: PEPERIKSAAN PERCUBAAN SIJIL PELAJARAN · PDF file[Jisim atom relatif: H=1, N=14, O=16;Isipadu molar gas = 24 dm3mol-1 pada keadaan bilik) A Hydrogen, nitrogen, ... Anion that exist

22 4541/1

4541/1 PAHANG

40. The lorry tyres are made from vulcanized rubber. What property of vulcanized rubbermakes it suitable to be used for making these lorry tyres?Tayar lori diperbuat daripada getah tervulkan. Apakah ciri getah tervulkan yangpaling sesuai menyebabkan ia digunakan sebagai tayar lori?A Resist to heat

Tahan habaB Harder and stronger

Keras dan kuatC Resist to oxidation

Tahan pengoksidaanD Can maintain their elasticity

Boleh mengekalkan sifat elastik

41. Which of the following is an oxidation process?Manakah antara berikut menunjukkan proses pengoksidaan?

A Zinc atom forms zinc ionAtom zink membentuk ion zink

B Butene changes into butaneButena ditukarkan kepada butana

C Lead II oxide loses its oxygenPlumbum II oksida kehilangan oksigen

D Bromine molecule gains electronsMolekul bromin menerima electron

42. Which of the following chemical equation, is not a redox reaction?Manakah antara berikut bukan tindak balas redoks?

A CuO + Zn ZnO + CuB Mg + 2 AgNO3 MgNO 3 2 + 2 AgC Cl2 + S2- 2Cl- + SD Ag+ + Cl- AgCl

43. What is the oxidation number of sulphur in Na2S2O3?Apakah nombor pengoksidaan sulphur dalam Na2S2O3?

A +2B +3C +4D +6

Page 23: PEPERIKSAAN PERCUBAAN SIJIL PELAJARAN · PDF file[Jisim atom relatif: H=1, N=14, O=16;Isipadu molar gas = 24 dm3mol-1 pada keadaan bilik) A Hydrogen, nitrogen, ... Anion that exist

23 4541/1

4541/1 PAHANG

44. The manufacture of sulphuric acid in the Contact Process involves the followingsteps.Pembuatan asid sulfurik dalam Proses Sentuh melibatkan langkah berikut.

S SO2 SO3 H2SO4

Based on the equation above, which of the following is the correct oxidation numberof sulphur?Berdasarkan persamaan di atas, yang manakah antara berikut merupakan nomborpengoksidaan yang betul untuk sulfur?

S SO2 SO3 H2SO4

A 0 +2 +3 +4B 0 +2 +6 +6C 0 +4 +6 +6D 0 +4 +6 +8

45. The following thermochemical equation shows the reaction between sodiumhydrogen carbonate and hydrochloric acid.Persamaan termokimia berikut menunjukkan tindak balas antara natrium hidrogenkarbonat dan asid hidroklorik.

NaHCO3 + HCl NaCl + H2O + CO2 ∆H = +11.8 kJmol-1

Which of the following is true about the reaction?Antara berikut yang manakah benar tentang tindak balas itu?

Heat changePerubahan haba

Type of reactionJenis tindak balas

A Heat absorbedHaba diserap

ExothermicEksotermik

B Hear absorbedHaba diserap

EndothermicEndotermik

C Heat releasedHaba dibebas

EndothermicEndothermic

D Heat releasedHaba dibebas

ExothermicEksotermik

Page 24: PEPERIKSAAN PERCUBAAN SIJIL PELAJARAN · PDF file[Jisim atom relatif: H=1, N=14, O=16;Isipadu molar gas = 24 dm3mol-1 pada keadaan bilik) A Hydrogen, nitrogen, ... Anion that exist

24 4541/1

4541/1 PAHANG

46. The thermochemical equation for a neutralisation reaction is given below.Persamaan termokimia untuk tindak balas peneutralan diberi di bawah.

KOH + HCl KCl + H2O ∆H = -57 kJ mol-1

Which neutralization reaction has the same value of the heat of neutralisation?Manakah tindak balas peneutralan yang mempunyai nilai haba peneutralan yangsama?

A HCl + NH3 NH4ClB CH3COOH + KOH CH3COOK + H2OC NaOH + HNO3 NaNO3 + H2OD CH3COOH + NH4OH CH3COONH4 + H2O

47. In an experiment, excess zinc powder is added to 50 cm3 0.1 mol dm-3 copper IIsulphate solution. The thermochemical equation is as shown:Dalam satu eksperimen, serbuk zink ditambah secara berlebihan kepada 50 cm3

0.1 mol dm-3 larutan kuprum II sulfat. Persamaan termokimia untuk tindak balas ituadalah seperti berikut:

Mg + Zn2+ Zn + Mg2+ ∆H = -210 kJ mol-1

Calculate the temperature rise in this experiment.[Specific heat capacity of solution: 4.2 Jg-1 0C-1, density of solution : 1gcm-3]Hitungkan kenaikan suhu dalam eksperimen ini.[Muatan haba tentu larutan: 4.2 Jg-1 0C-1, ketumpatan larutan: 1gcm-3]

A 50 x 0.1 x 210000 0C50 x 4.2

B 50 x 4.2 x 210000 0C50 x 0.1 x 1000

C 50 x 4.2 x 210.00 0C50 x 0.1

D 50 x 0.1 x 210.00 0C50 x 4.2

Page 25: PEPERIKSAAN PERCUBAAN SIJIL PELAJARAN · PDF file[Jisim atom relatif: H=1, N=14, O=16;Isipadu molar gas = 24 dm3mol-1 pada keadaan bilik) A Hydrogen, nitrogen, ... Anion that exist

25 4541/1

4541/1 PAHANG

48. Diagram 11 shows the energy level diagram for the reaction between silver ions andchloride ions.Rajah 11 menunjukkan rajah aras tenaga untuk tindak balas antara ion argentumdan ion klorida.

Diagram 11Rajah 11

Which of the following statements is true about this reaction?Antara berikut, pernyataan manakah adalah benar mengenai tindak balas ini?

A Endothermic reaction occursTindak balas endotermik berlaku

B The energy content of the product is higher than the reactantsKandungan tenaga hasil tindak balas tinggi daripada bahan tindak balas

C 65 kJ of heat is absorbed when 1 mol of silver chloride is formed65 kJ haba diserap apabila 1 mol argentums klorida terbentuk

D The final temperature at the end of the reaction is higher than the initialtemperature.Suhu akhir pada akhir tindak balas lebih tinggi daripada suhu awal.

49. Hilmi has the following symptoms: fever, headache, muscle and joint pains. Themedicine that can be taken to relieve the symptoms isHilmi mempunyai gejala-gejala seperti berikut: demam, pening kepala, sakit otot, dansakit sendi. Ubat yang boleh diambil untuk menangani gejala-gejala itu adalah

A CodeineKodeina

B PenicilinPenisilin

C ParacetamolParasetamol

D AmphetamineAmfetamin

EnergyAg+aq + Cl - aq

AgCls)

H = - 65.5 kJmol-1

Page 26: PEPERIKSAAN PERCUBAAN SIJIL PELAJARAN · PDF file[Jisim atom relatif: H=1, N=14, O=16;Isipadu molar gas = 24 dm3mol-1 pada keadaan bilik) A Hydrogen, nitrogen, ... Anion that exist

26 4541/1

4541/1 PAHANG

50. Why detergents are more effective than soaps?Mengapa detergen lebih efektif berbanding sabun?

A Detergents are soluble in greaseDetergen larut dalam gris

B Detergents do not form scum in hard waterDetergen tidak membentuk kekat dalam air liat

C Detergent has hydrocarbon chain which makes detergent dissociate less inhard waterDetergen mengandungi ikatan hidrokarbon yang membuatkan detergenkurang terpisah dalam air liat

D The presence of magnesium ions in detergent forms scumKehadiran ion magnesium dalam detergen menghasilkan kekat.

END OF QUESTION PAPERKERTAS SOALAN TAMAT

https://cikguadura.wordpress.com/

Page 27: PEPERIKSAAN PERCUBAAN SIJIL PELAJARAN · PDF file[Jisim atom relatif: H=1, N=14, O=16;Isipadu molar gas = 24 dm3mol-1 pada keadaan bilik) A Hydrogen, nitrogen, ... Anion that exist

SULIT

NAMA :....................................................................................................

KELAS :...................................................................................................

PEPERIKSAAN PERCUBAANSIJIL PELAJARAN MALAYSIA 2015 4541/2

CHEMISTRYKertas 2September2 ½ jam 2 jam 30 minit

DO NOT OPEN THIS PAPER UNTIL YOU ARE TOLD TO DO SOJANGAN BUKA KERTAS SOALAN INI SEHINGGA DIBERITAHU

1. Tulis nama dan tingkatan andapada ruangan yang disediakan diatas.

2. Kertas soalan ini adalah dalamdwibahasa.

3. Soalan dalam Bahasa Inggerismendahului soalan yang sepadandalam Bahasa Melayu.

4. Calon dibenarkan menjawabkeseluruhan atau sebahagian soalansama ada dalam Bahasa Inggerisatau Bahasa Melayu.

5. Calon dikehendaki membacamaklumat di halaman belakangkertas soalan ini

Untuk Kegunaan Pemeriksa

Bahagian Soalan MarkahPenuh

Markahdiperoleh

A

1 9

2 9

3 10

4 10

5 11

6 11

B7 20

8 20

C9 20

10 20

JUMLAH

-------------------------------------------------------------------------------------------------------------------------------Kertas soalan ini mengandungi 33 halaman bercetak

https://cikguadura.wordpress.com/

Page 28: PEPERIKSAAN PERCUBAAN SIJIL PELAJARAN · PDF file[Jisim atom relatif: H=1, N=14, O=16;Isipadu molar gas = 24 dm3mol-1 pada keadaan bilik) A Hydrogen, nitrogen, ... Anion that exist

2 4541/2

4541/2 PAHANG [Lihat sebelah]

Section ABahagian A[60 marks]

[60 markah]

Answer all the questions in this section.Jawab semua soalan dalam bahagian ini.

1. Diagram 1.1 shows the observation of an experiment when solid iodine is put into a gasjar to prove the kinetic theory of matter.Rajah 1.1 menunjukkan pemerhatian satu eksperimen apabila pepejal iodin diletakkan didalam satu balang gas bagi membuktikan teori kinetik jirim.

Diagram 1.1Rajah 1.1

(a) (i) Name the process in this experiment.Namakan proses dalam eksperimen itu.

......................................................................................................................[1 mark]

[1 markah]

Purple coloured gasGas berwarna ungu

Solid iodinePepejal iodin

Gas jarBalang gas

After several hours

Selepas beberapa jam

https://cikguadura.wordpress.com/

Page 29: PEPERIKSAAN PERCUBAAN SIJIL PELAJARAN · PDF file[Jisim atom relatif: H=1, N=14, O=16;Isipadu molar gas = 24 dm3mol-1 pada keadaan bilik) A Hydrogen, nitrogen, ... Anion that exist

3 4541/2

4541/2 PAHANG [Lihat sebelah]

(a) (ii) Draw the arrangement of the iodine particles in the solid and gaseous state.Lukiskan susunan zarah-zarah iodin dalam keadaan pepejal dan gas.

Solid / Pepejal Gas/Gas[2 marks]

[2 markah]

(a) (iii) State the type of particles in gaseous iodineNyatakan jenis zarah dalam gas iodin.

..................................................................................................................[1 mark]

[1 markah]

(b) Diagram 1.2 shows the setup of the apparatus used in an experiment todetermine the empirical formula of an oxide of copper.Rajah 1.2 menunjukkan radas yang digunakan dalam eksperimen untukmenentukan formula empirik kuprum oksida.

Diagram 1.2Rajah 1.2

Page 30: PEPERIKSAAN PERCUBAAN SIJIL PELAJARAN · PDF file[Jisim atom relatif: H=1, N=14, O=16;Isipadu molar gas = 24 dm3mol-1 pada keadaan bilik) A Hydrogen, nitrogen, ... Anion that exist

4 4541/2

4541/2 PAHANG [Lihat sebelah]

(i) What is meant by empirical formula?Apakah yang dimaksudkan dengan formula empirik?

.................................................................................................................................

................................................................................................................................[1 mark]

[1 markah]

(ii) State the name of two reactants to prepare hydrogen gas in the laboratory.Nyatakan nama bagi dua bahan tindak balas untuk menyediakan gas hidrogen didalam makmal.

………………………………………………………………………………………………

………………………………………………………………………………………………[2 marks]

[2 markah]

(iv) State how to determine that the reaction between copper(II) oxide with hydrogengas has been completed.Nyatakan bagaimana untuk menentukan bahawa tindak balas yang berlakuantara kuprum(II) oksida dengan gas hidrogen telah lengkap.

................................................................................................................................[1 mark]

[1 markah]

(iii) State another metal oxide whose empirical formula can be determined using thesame method.Nyatakan satu oksida logam lain yang formula empiriknya boleh ditentukandengan menggunakan kaedah yang sama.

............................................................................................................................. ....[1 mark]

[1 markah]

Page 31: PEPERIKSAAN PERCUBAAN SIJIL PELAJARAN · PDF file[Jisim atom relatif: H=1, N=14, O=16;Isipadu molar gas = 24 dm3mol-1 pada keadaan bilik) A Hydrogen, nitrogen, ... Anion that exist

5 4541/2

4541/2 PAHANG [Lihat sebelah]

Diagram 2.1Rajah 2.1

2 Diagram 2.1 shows the set up apparatus of an experiment to investigate the reactionbetween calcium carbonate and hydrochloric acid. A student collect the gas released byusing a syringe. 30 cm3 of carbon dioxide gas was collected at room condition.Rajah 2.1 menunjukkan susunan radas satu eksperimen bagi mengkaji tindak balas diantara kalsium karbonat dan asid hidroklorik. Seorang pelajar mengumpul gas yangterbebas dengan menggunakan picagari. 30 cm3 gas karbon dioksida telah dikumpulkanpada keadaan bilik.

(a) (i) Write the chemical equation for the reaction.Tuliskan persamaan kimia bagi tindak balas tersebut.

………………………………………………………………………………………………[2 marks]

[2 markah]

(ii) Calculate the number of moles of carbon dioxide gas in the syringe.Hitungkan bilangan mol gas karbon dioksida yang terdapat dalam picagaritersebut.[Molar volume=24 dm3 mol-1 at room condition][Isipadu molar = 24 dm3 mol-1 pada keadaan bilik]

[1 mark][1 markah]

Calcium carbonate powderSerbuk kalsium karbonat

Hydrochloric acidAsid hidroklorik

Carbon dioxide gasGas karbon dioksida

SyringePicagari

Page 32: PEPERIKSAAN PERCUBAAN SIJIL PELAJARAN · PDF file[Jisim atom relatif: H=1, N=14, O=16;Isipadu molar gas = 24 dm3mol-1 pada keadaan bilik) A Hydrogen, nitrogen, ... Anion that exist

6 4541/2

4541/2 PAHANG [Lihat sebelah]

(iii) Calculate the number of molecule of carbon dioxide gas in the syringeHitungkan bilangan molekul gas karbon dioksida dalam picagari.[Avogadro Constant: 6.02 x 1023 mol-1 ][Pemalar Avogadro : 6.02 x 1023 mol-1 ]

[1 mark][1 markah]

(iv) Calculate the maximum mass of calcium carbonate needed to produce carbondioxide gas in the syringe.Hitungkan jisim maksimum kalsium karbonat yang diperlukan untukmenghasilkan gas karbon dioksida di dalam picagari tersebut.[Relative atomic mass: Ca=40, C=12, O=16][Jisim atom relatif: Ca=40, C=12, O=16]

[2 marks][2 markah]

Page 33: PEPERIKSAAN PERCUBAAN SIJIL PELAJARAN · PDF file[Jisim atom relatif: H=1, N=14, O=16;Isipadu molar gas = 24 dm3mol-1 pada keadaan bilik) A Hydrogen, nitrogen, ... Anion that exist

7 4541/2

4541/2 PAHANG [Lihat sebelah]

Diagram 2.2Rajah 2.2

(b) Diagram 2.2 shows the structural formula of monosodium glutamate(MSG). Monosodium glutamate is food additives usually added into thefood to make it more delicious.Rajah 2.2 menunjukkan formula struktur bagi mononatrium glutamat(MSG). Mononatrium glutamat adalah bahan tambah makanan yangbiasanya ditambahkan ke dalam makanan untuk menyedapkan rasanya.

(i) Write the molecular formula of MSG.Tuliskan formula molekul bagi MSG.

…………………………………………………………………………………..[1 mark]

[1 markah](ii) State the types of compound for MSG.

Nyatakan jenis sebatian bagi MSG.

…………………………………………………………………………………..[1 mark]

[1 markah]

(iii) Calculate the relative formula mass of monosodium glutamate.Hitungkan jisim formula relatif bagi mononatrium glutamat.[Relative atomic mass of C=12, O=16, N=14, Na=23, H=1][Jisim atom relatif C=12, O=16, N=14, Na=23, H=1]

[1 mark][1 markah]

Page 34: PEPERIKSAAN PERCUBAAN SIJIL PELAJARAN · PDF file[Jisim atom relatif: H=1, N=14, O=16;Isipadu molar gas = 24 dm3mol-1 pada keadaan bilik) A Hydrogen, nitrogen, ... Anion that exist

8 4541/2

4541/2 PAHANG [Lihat sebelah]

1 2 13 14 15 16 17 181 P23 Q U4 W56

Diagram 3.1Rajah 3.1

3 Diagram 3.1 shows the Periodic Table of elements. The letters P, Q, U and W do notrepresent the actual symbols of the elements.Rajah 3.1 menunjukkan suatu Jadual Berkala Unsur. Huruf P, Q, U dan W tidakmewakili simbol sebenar unsur berkenaan.

(a) Table 3 shows one characteristic for each of elements R, S and T.Jadual 3 menunjukkan satu ciri bagi setiap unsur R, S dan T.

ElementUnsur

CharacteristicCiri

R Located in Period 2 and has 6 valence electronsTerletak di kala 2 dan mempunyai 6 elektron valens

S Has electron arrangement of 2.8.8.1Mempunyai susunan elektron 2.8.8.1

T Has a stable duplet electron arrangementMempunyai susunan elektron duplet yang stabil

Table 3Jadual 3

(i) Referring to Table 3, indicate the positions of R, S and T by writing theletters in the correct boxes of the above Periodic TableMerujuk kepada ciri dalam Jadual 3, tuliskan abjad R, S dan T padakedudukan yang betul dalam Jadual Berkala Unsur di atas.

. [3 marks][3 markah]

Page 35: PEPERIKSAAN PERCUBAAN SIJIL PELAJARAN · PDF file[Jisim atom relatif: H=1, N=14, O=16;Isipadu molar gas = 24 dm3mol-1 pada keadaan bilik) A Hydrogen, nitrogen, ... Anion that exist

9 4541/2

4541/2 PAHANG [Lihat sebelah]

(b) Which element among P, Q, R, S, T, U and W exists as a monoatomic gas?Antara unsur P, Q, R, S, T, U dan W yang manakah wujud sebagai gasmonoatom?

……………………………………….. ........................................................................[1 mark]

[1 markah]

(c) Element P and R can react to form a liquid. Write the chemical formula of thecompound formed.Unsur P dan unsur R boleh bertindak balas menghasilkan suatu cecair. Tuliskanformula kimia bagi sebatian yang terbentuk.

.................................................................................................................................[1 mark]

[1 markah](d) Both elements of Q and S can react with water.

Kedua-dua unsur Q dan S boleh bertindak balas dengan air.

(i) Which element reacts more vigorously ?Unsur manakah menunjukkan tindak balas yang lebih cergas ?

……………………………………….........................................................[1 mark]

[1 markah](ii) Explain your answer in (d)(i).

Terangkan jawapan anda dalam (d) (i).

.....................................................................................................................

.....................................................................................................................

.....................................................................................................................

.....................................................................................................................[3 marks]

[3 markah]

Page 36: PEPERIKSAAN PERCUBAAN SIJIL PELAJARAN · PDF file[Jisim atom relatif: H=1, N=14, O=16;Isipadu molar gas = 24 dm3mol-1 pada keadaan bilik) A Hydrogen, nitrogen, ... Anion that exist

10 4541/2

4541/2 PAHANG [Lihat sebelah]

Diagram 3.2Rajah 3.2

(e) Diagram 3.2 shows the hydrogenation process of palm oil in manufacturing ofmargarine. Element W is used in the process. State one of the specialcharacteristic of element W in the hydrogenation process.Rajah 3.2 menunjukkan proses penghidrogenan minyak kelapa sawit untukmenghasilkan marjerin. Unsur W digunakan di dalam proses tersebut. Nyatakansatu ciri istimewa unsur W di dalam proses tersebut.

..................................................................................................................................[1 mark]

[1 markah]

Palm oilMinyak kelapa sawit

sawit

Saturated fat (solid or semi solid)Lemak tepu (pepejal atau separa pepejal)

White fat emulsion and milkEmulsi putih lemak dan susu

MargarineMarjerin

180oC2 atm

Element WUnsur W

+ Milk+ Susu+ flavouring, salt,

vitamin & colouring+ perisa, garam,

vitamin & pewarna

Page 37: PEPERIKSAAN PERCUBAAN SIJIL PELAJARAN · PDF file[Jisim atom relatif: H=1, N=14, O=16;Isipadu molar gas = 24 dm3mol-1 pada keadaan bilik) A Hydrogen, nitrogen, ... Anion that exist

11 4541/2

4541/2 PAHANG [Lihat sebelah]

4 Diagram 4 shows two types of cell.Rajah 4 menunjukkan dua jenis sel.

Diagram 4Rajah 4

(a) What is the meaning of cation?Apakah maksud kation?

............................................................................................................................. ....[1 mark]

[1 markah]

(b) State all the cations present in copper(II) sulphate solution.Nyatakan semua kation dalam larutan kuprum(II) sulfat.

............................................................................................................................. ....[1 mark]

[1 markah]

(c) Name the product formed at cathode in Cell R. Explain your answer.Namakan produk yang terhasil pada katod dalam Sel R. Terangkan jawapananda.

............................................................................................................................. ....

............................................................................................................................. ....[2 marks]

[2 markah]

Cell RSel R

Cell SSel S

Copper plateKepingankuprum

Copper plateKepingan kuprum

Zinc plateKepinganzink

Copper(II)sulphatesolutionLarutan

kuprum(II)sulfat

Page 38: PEPERIKSAAN PERCUBAAN SIJIL PELAJARAN · PDF file[Jisim atom relatif: H=1, N=14, O=16;Isipadu molar gas = 24 dm3mol-1 pada keadaan bilik) A Hydrogen, nitrogen, ... Anion that exist

12 4541/2

4541/2 PAHANG [Lihat sebelah]

(d) Copper(II) sulphate solution in Cell R is replaced with dilute sulphuric acid. Acolourless gas produced at the cathode is collected.Larutan kuprum(II) sulfat dalam Sel R digantikan dengan larutan asid sulfurikcair. Gas tidak berwarna yang terhasil di katod dikumpulkan.

(i) Name the gas produced.Namakan gas yang terhasil.

.....................................................................................................................[1 mark]

[1 markah]

(ii) Describe one chemical test to confirm the gas in (d)(i).Terangkan satu ujian kimia untuk mengesahkan gas di (d)(i).

.....................................................................................................................

.....................................................................................................................[2 marks]

[2 markah]

(e) State the metal used as negative terminal for Cell S.Nyatakan logam yang digunakan sebagai terminal negatif di Sel S.

............................................................................................................................. ....[1 mark]

[1 markah]

(f) Zinc electrode in Cell S is replaced with magnesium.Elektrod zink di Sel S digantikan dengan magnesium.

(i) Compare the voltage reading of the cell.Bandingkan bacaan voltan sel tersebut.

.....................................................................................................................[1 mark]

[1 markah]

(ii) Explain your answer in (f)(i).Terangkan jawapan anda di (f)(i).

.....................................................................................................................[1 mark]

[1 markah]

Page 39: PEPERIKSAAN PERCUBAAN SIJIL PELAJARAN · PDF file[Jisim atom relatif: H=1, N=14, O=16;Isipadu molar gas = 24 dm3mol-1 pada keadaan bilik) A Hydrogen, nitrogen, ... Anion that exist

13 4541/2

4541/2 PAHANG [Lihat sebelah]

5 (a) A student conducted an experiment to study the reaction between sulphuric acidand 0.1 mol dm-3 of sodium hydroxide solution by using phenolphthalein as anindicator.Seorang pelajar menjalankan satu eksperimen untuk mengkaji tindakbalasantara asid sulfurik dan larutan natrium hidroksida 0.1 mol dm-3 denganmenggunakan fenolftalein sebagai penunjuk.

(i) Write a chemical equation to represent the reaction.Tuliskan persamaan kimia bagi tindak balas yang berlaku.

....................................................................................................................[2 marks]

[2 markah]

(ii) 25 cm3 of 0.1 mol dm-3 sodium hydroxide solution is required to reactcompletely with 12.50 cm3 of dilute sulphuric acid. Calculate the molarityof the dilute sulphuric acid used.25 cm3 larutan natrium hidroksida 0.1 mol dm-3 diperlukan untukbertindak balas lengkap dengan 12.50 cm3 asid sulfurik cair. Hitungkankemolaran asid sulfurik cair yang digunakan.

[3 marks][3 markah]

Page 40: PEPERIKSAAN PERCUBAAN SIJIL PELAJARAN · PDF file[Jisim atom relatif: H=1, N=14, O=16;Isipadu molar gas = 24 dm3mol-1 pada keadaan bilik) A Hydrogen, nitrogen, ... Anion that exist

14 4541/2

4541/2 PAHANG [Lihat sebelah]

(iii) Draw a suitable diagram of the set-up of apparatus for the reactionbetween sulphuric acid and sodium hydroxide solution in the laboratory.Lukiskan gambarajah susunan radas yang sesuai bagi tindakbalas antaraasid sulfurik dengan larutan natrium hidroksida di dalam makmal.

[2 marks][2 markah]

(v) If sulphuric acid is replaced by hydrochloric acid with the sameconcentration, predict the volume of acid used. Explain your answer.Jika asid sulfurik digantikan dengan asid hidroklorik dengan kepekatanyang sama, ramalkan isipadu asid yang digunakan. Terangkan jawapananda.

.....................................................................................................................

.....................................................................................................................[2 marks]

[2 markah]

Page 41: PEPERIKSAAN PERCUBAAN SIJIL PELAJARAN · PDF file[Jisim atom relatif: H=1, N=14, O=16;Isipadu molar gas = 24 dm3mol-1 pada keadaan bilik) A Hydrogen, nitrogen, ... Anion that exist

15 4541/2

4541/2 PAHANG [Lihat sebelah]

Diagram 5.1Rajah 5.1

(b) Diagram 5.1 shows home remedy to treat a bee sting. In your opinion, give arational reason why the toothpaste is apply on the bee sting site?Rajah 5.1 menunjukkan rawatan di rumah untuk merawat sengatan lebah. Padapandangan anda, mengapakah ubat gigi disapukan ke atas kawasan sengatanlebah tersebut?

...................................................................................................................................

..................................................................................................................................[2 marks]

[2 markah]

home remedyrawatan di rumah

A child is stung by a beeSeorang kanak-kanak

terkena sengatan lebah

remove the bee sting as soonas possible

buangkan sengat lebahsecepat mungkin

Take a toothpasteAmbil ubat gigi

Rub the toothpaste on thebee sting site

Sapukan ubat gigi di ataskawasan sengatan lebah

Page 42: PEPERIKSAAN PERCUBAAN SIJIL PELAJARAN · PDF file[Jisim atom relatif: H=1, N=14, O=16;Isipadu molar gas = 24 dm3mol-1 pada keadaan bilik) A Hydrogen, nitrogen, ... Anion that exist

16 4541/2

4541/2 PAHANG [Lihat sebelah]

6. Diagram 6.1 shows changes of a carbon compound involving a series of reactions.Rajah 6.1 menunjukkan perubahan sebatian karbon yang melibatkan beberapa siritindak balas.

Diagram 6.1Rajah 6.1

(a) State the functional group of propanol.Nyatakan kumpulan berfungsi bagi propanol.

...................................................................................................................................[ 1 mark ]

[ 1 markah]

(b) Draw the structural formulae for two isomers of propanol.Lukiskan formula struktur bagi dua isomer propanol.

[ 2 marks][ 2 markah]

PropanePropana

PropenePropena

PropanolPropanol

porcelain chipsserpihan porselin

heatdipanaskan

Reaction ITindak balas I

Page 43: PEPERIKSAAN PERCUBAAN SIJIL PELAJARAN · PDF file[Jisim atom relatif: H=1, N=14, O=16;Isipadu molar gas = 24 dm3mol-1 pada keadaan bilik) A Hydrogen, nitrogen, ... Anion that exist

17 4541/2

4541/2 PAHANG [Lihat sebelah]

(c) Propanol undergoes Reaction I to form propene.Propanol mengalami tindak balas I membentuk propena.

(i) Name reaction I.Namakan tindak balas I

...................................................................................................................................[ 1 mark ]

[ 1 markah]

(ii) Write the balanced chemical equation for the conversion of propanol to propenein reaction I.Tuliskan persamaan kimia yang seimbang bagi penukaran propanol kepadapropena dalam tindak balas I.

................................................................................................................................[ 1 mark]

[ 1 markah]

(d) Propane and propene are hydrocarbons. Compare the observation when acidifiedpotassium manganate(VII) solution is added into propane and propene.Propana dan propena adalah hidrokarbon. Bandingkan pemerhatian apabila larutankalium manganat(VII) berasid ditambahkan ke dalam propana dan propena.

....................................................................................................................................

.....................................................................................................................................

....................................................................................................................................

.....................................................................................................................................

[ 3 marks][ 3 markah]

Page 44: PEPERIKSAAN PERCUBAAN SIJIL PELAJARAN · PDF file[Jisim atom relatif: H=1, N=14, O=16;Isipadu molar gas = 24 dm3mol-1 pada keadaan bilik) A Hydrogen, nitrogen, ... Anion that exist

18 4541/2

4541/2 PAHANG [Lihat sebelah]

Diagram 6.2Rajah 6.2

(e) Diagram 6.2 shows the liquid car perfume that is usually placed inside the car togive a fragrance smell like apples. The liquid fragrance smell like apples containsethyl pentanoate, with the molecular formula of C4H9COOC2H5.

Rajah 6.2 menunjukkan cecair minyak wangi kereta yang biasanya diletakkan didalam kereta untuk memberikan bau wangi seperti epal. Cecair wangi yang berbauepal ini mengandungi etil pentanoate, dengan formula molekul C4H9COOC2H5.

(i) Name the homologous series of the liquid car perfume.Namakan siri homolog bagi cecair pewangi tersebut.

..........................................................................................................................[ 1 mark ]

[ 1 markah]

(ii) Describe briefly how the liquid fragrance smell like apples can be prepared inthe laboratory.Huraikan secara ringkas bagaimana cecair wangi yang berbau seperti epalboleh disediakan di dalam makmal.

..........................................................................................................................

..........................................................................................................................

..........................................................................................................................[ 2 marks]

[2 markah]

Page 45: PEPERIKSAAN PERCUBAAN SIJIL PELAJARAN · PDF file[Jisim atom relatif: H=1, N=14, O=16;Isipadu molar gas = 24 dm3mol-1 pada keadaan bilik) A Hydrogen, nitrogen, ... Anion that exist

19 4541/2

4541/2 PAHANG [Lihat sebelah]

Bahagian BSection B

[20 markah]

Jawab mana-mana satu soalan dalam bahagian ini.Answer any one question from this section.

7. Diagram 7.1 shows the flow map for the industrial manufactured of sulphuric acid.Rajah 7.1 menunjukkan peta alir bagi pembuatan asid sullfurik dalam industri.

+ O2 + O2Heat Step X

Panaskan Langkah X

+ H2SO4 + H2O

Diagram 7.1Rajah 7.1

(a) (i) Name the process of manufacturing sulphuric acid in industry and write abalanced chemical equation for Step X and Step Y.Namakan proses pembuatan asid sulfurik dalam industri dan tuliskan persamaankimia yang seimbang bagi langkah X dan langkah Y.

[5 marks][5 markah]

(iii) Excess gas that produced during the manufacture of sulphuric acid can causeenvironmental pollution. Explain how.Gas berlebihan yang dibebaskan semasa pembuatan asid sulfurik bolehmenyebabkan pencemaran alam sekitar. Terangkan bagaimana.

[2 marks][2 markah]

SulphurSulfur

Sulphur dioxideSulfur dioksida

Sulphur trioxideSulfur trioksida

OleumOleum

Sulphuric acidAsid sulfurikStep Y

Langkah Y

https://cikguadura.wordpress.com/

Page 46: PEPERIKSAAN PERCUBAAN SIJIL PELAJARAN · PDF file[Jisim atom relatif: H=1, N=14, O=16;Isipadu molar gas = 24 dm3mol-1 pada keadaan bilik) A Hydrogen, nitrogen, ... Anion that exist

20 4541/2

4541/2 PAHANG [Lihat sebelah]

(b) Diagram 7.2 shows the steps to produce fertilizers X from the reaction betweensulphuric acid and the product of Haber Process.Rajah 7.2 menunjukkan langkah-langkah untuk menghasilkan baja X daripadatindak balas di antara asid sulfurik dan produk proses Haber.

Diagram 7.2Rajah 7.2

(i) State the chemical formula of fertilizers X.Nyatakan formula kimia bagi baja X.

[ 1 mark ][1 markah]

Diagram 7.3Rajah 7.3

(ii) A farmer found that the crops in his farm is infertile as shown in Diagram 7.3. Hisfriend suggested two fertilizers to improve the fertility of the soil, urea, CO(NH2)2 andfertilizers X. Choose the best fertilizer for the growth of the plants. Explain youranswer.[Relative atomic mass: C=12, O=16, N=14, S=32, H=1]Seorang petani mendapati tanaman di kebunnya tidak subur seperti yangditunjukkan dalam rajah 7.3. Rakannya telah mencadangkan dua jenis baja yangboleh menambah kesuburan tanah, urea, CO(NH2)2 dan baja X.Pilih baja yang terbaik untuk penanaman tumbuhan. Terangkan jawapan anda.[Jisim atom relatif: C=12, O=16, N=14, S=32, H=1]

[4 marks][4 markah]

Sulphuric AcidAsid sulfurik

Product ofHaber ProcessProduk Proses

Haber

Fertilizers XBaja X

reactbertindak balas

Page 47: PEPERIKSAAN PERCUBAAN SIJIL PELAJARAN · PDF file[Jisim atom relatif: H=1, N=14, O=16;Isipadu molar gas = 24 dm3mol-1 pada keadaan bilik) A Hydrogen, nitrogen, ... Anion that exist

21 4541/2

4541/2 PAHANG [Lihat sebelah]

(c) Table 7.1 shows five different manufactured substances in industry, P, Q, R, S and Tand their uses.

Jadual 7.1 menunjukkan lima bahan buatan berbeza dalam industri, P, Q, R, S, T dankegunaannya

Manufactured substances inindustry

Bahan buatan dalam industriUses

Kegunaan

P To make boats and badminton racketMembuat bot dan reket badminton

Q To make medals and statuesMembuat medal dan tugu

R To make the body of aeroplanesMembuat badan kapal terbang

S To make kitchen ware and internal wall of furnaceMembuat peralatan dapur dan dinding relau

T To make prism and lensesMembuat prisma dan kanta

Table 7.1Jadual 7.1

Based on Table 7.1, state the names of P,Q,R,S and TBerdasarkan Jadual 7,1, nyatakan nama bagi P,Q, R, S dan T

[5 marks ][5 markah]

(d) Polyethene is one of the polymer widely use in daily life.State two properties and one use of polyethene in daily life.Polietena adalah salah satu polimer yang digunakan dengan meluas dalam kehidupanharian.

Nyatakan dua sifat dan satu kegunaan polietena dalam kehidupan seharian.

[3 marks][3 markah]

Page 48: PEPERIKSAAN PERCUBAAN SIJIL PELAJARAN · PDF file[Jisim atom relatif: H=1, N=14, O=16;Isipadu molar gas = 24 dm3mol-1 pada keadaan bilik) A Hydrogen, nitrogen, ... Anion that exist

22 4541/2

4541/2 PAHANG [Lihat sebelah]

8. (a) A student has carried out an experiment to construct an ionic equation for theformation of lead (II) iodide. Seven test tubes of the same size were labelled 1 to 7. Afixed volume of 5.0 cm3 of 1.0 mol dm-3 potassium iodide solution was poured in eachtest tube. The volume of 1.0 mol dm-3 lead (II) nitrate solution that added is shown inTable 8. The height of precipitate formed in each test tube was measured. The resultsare shown in Table 8.

Seorang pelajar telah menjalankan eksperimen untuk membina persamaan ion bagipembentukan plumbum (II) iodida. Tujuh tabung uji yang sama saiz dilabelkan dengannombor 1 hingga 7. Isipadu tetap larutan kalium iodida 1.0 mol dm-3 sebanyak 5 cm3

dituangkan ke dalam setiap tabung uji. Isipadu larutan plumbum (II) nitrat 1.0 mol dm-3

ditambahkan ke dalam tabung uji seperti yang ditunjukkan di dalam Jadual 8. Tinggimendakan yang terbentuk dalam setiap tabung uji diukur. Keputusan eksperimenditunjukkan di dalam Jadual 8.

Table 8Jadual 8

(i) Based on Table 8, plot a graph of the height of precipitate against volume oflead (II) nitrate solution.

Berdasarkan Jadual 8, plotkan graf tinggi mendakan melawan isipadu larutanplumbum(II) nitrat.

[3 marks][3 markah]

Test tubeTabung uji 1 2 3 4 5 6 7

Volume of 1.0 moldm-3

lead(II) nitrate solution / cm3

Isipadu 1.0 moldm-3

plumbum(II) nitrat / cm3

0.5 1.0 1.5 2.0 2.5 3.0 3.5

Height of precipitate /cmTinggi mendakan / cm 1.1 2.2 3.4 4.4 5.5 5.5 5.5

Page 49: PEPERIKSAAN PERCUBAAN SIJIL PELAJARAN · PDF file[Jisim atom relatif: H=1, N=14, O=16;Isipadu molar gas = 24 dm3mol-1 pada keadaan bilik) A Hydrogen, nitrogen, ... Anion that exist

23 4541/2

4541/2 PAHANG [Lihat sebelah]

(ii) Determine the number of moles of lead (II) ions and iodide ions that arerequired for the formation of lead (II) iodide. Your answer should consist ofthe following:Tentukan bilangan mol bagi ion plumbum (II) dan ion iodida yang diperlukanbagi pembentukan plumbum (II) iodida. Jawapan anda hendaklah mengandungiperkara berikut :

The volume of lead (II) nitrate solution that had reacted completely with 5.0cm3 of 1.0 mol dm-3 potassium iodideIsipadu larutan plumbum(II) nitrat yang bertindak balas lengkap dengan 5.0cm3 1.0 moldm-3 larutan kalium iodida.

Calcúlate the number of moles of lead(II) ions and iodide ionsKirakan bilangan mol plumbum(II) ion dan ion iodida

Calculate the number of moles of iodide ions that has reacted with 1 mol oflead(II) ions.Kirakan bilangan mol ion iodida yang bertindak balas dengan 1 mol ionplumbum(II)

Write the ionic equation for the formation of lead(II) iodide.Tuliskan persamaan ion bagi pembentukan plumbum(II) iodide

[7 marks][7 markah]

Page 50: PEPERIKSAAN PERCUBAAN SIJIL PELAJARAN · PDF file[Jisim atom relatif: H=1, N=14, O=16;Isipadu molar gas = 24 dm3mol-1 pada keadaan bilik) A Hydrogen, nitrogen, ... Anion that exist

24 4541/2

4541/2 PAHANG [Lihat sebelah]

(b) Diagram 8 shows the reaction between oxide metal T which is black in colour withsulphuric acid to form blue salt solution of compound W.Salt solution W reacts with barium nitrate solution to form salt solution X and insolublesalt, Solid Y.Rajah 8 menunjukkan tindak balas di antara oksida logam T yang berwarna hitamdengan asid sulfurik untuk membentuk larutan garam W yang berwarna biru.Larutan garam W bertindak balas dengan larutan barium nitrat menghasilkan larutangaram X dan pepejal Y.

Diagram 8Rajah 8

Based on Diagram 8 :Berdasarkan Rajah 8 :

(i) Identify oxide metal T, salt W, salt X and solid Y.Kenal pasti oksida logam T, garam W, garam X dan pepejal Y.

[4 marks][4 markah]

(ii) State one observation when salt solution W reacts with barium nitrate solutionand name the type of reaction occurred.Nyatakan satu pemerhatian apabila larutan garam W bertindak balas denganlarutan barium nitrat dan namakan jenis tindak balas yang berlaku.

[2 marks][2 markah]

H2SO4

+Oxide Metal TOksida Logam T

Salt Solution WLarutan Garam W

WaterAir

Salt Solution XLarutan Garam X

+ Ba(NO3)2

Solid YPepejal Y+

Page 51: PEPERIKSAAN PERCUBAAN SIJIL PELAJARAN · PDF file[Jisim atom relatif: H=1, N=14, O=16;Isipadu molar gas = 24 dm3mol-1 pada keadaan bilik) A Hydrogen, nitrogen, ... Anion that exist

25 4541/2

4541/2 PAHANG [Lihat sebelah]

(iii) Salt solution W reacts with 50 cm3 of 1.0 mol dm-3 barium nitrate solution.Write the chemical equation for the reaction and calculate the mass of solid Yproduced.

[Relative formula mass of solid Y: 233]Larutan garam W bertindak balas dengan 50 cm3 1.0 mol dm-3 larutan bariumnitrat. Tuliskan persamaan kimia bagi tindak balas tersebut dan kirakan jisimpepejal Y yang terhasil.[Jisim formula relatif bagi pepejal Y : 233]

[4 marks][4 markah]

Page 52: PEPERIKSAAN PERCUBAAN SIJIL PELAJARAN · PDF file[Jisim atom relatif: H=1, N=14, O=16;Isipadu molar gas = 24 dm3mol-1 pada keadaan bilik) A Hydrogen, nitrogen, ... Anion that exist

26 4541/2

4541/2 PAHANG [Lihat sebelah]

SECTION CBahagian C[20 markah]

Answer any one question from this section.Jawab mana-mana satu soalan dalam bahagian ini.

9. Table 9 shows the experiments which are carried out to investigate factors that affect therate of reaction of zinc powder with acid X and acid Y.Jadual 9 menunjukkan ekperimen yang dijalankan untuk mengkaji faktor-faktor yangmempengaruhi kadar tindak balas antara serbuk zink dengan asid X dan asid Y.

ExperimentEksperimen

ReactantsBahan Tindak balas

ProductsHasil Tindak balas

I

2 g zinc powder + 50.0 cm3 of 0.5 mol dm–3

acid X2 g serbuk zink + 50.0 cm3 of 0.5 mol dm–3

asid X

Zinc chloride and gas ZZink klorida dan gas Z

II

2 g zinc powder + 50.0 cm3 of 0.5mol dm–3

acid Y2 g serbuk zink + 50.0 cm3 of 0.5 mol dm–3

asid Y

Zinc sulphate and gas ZZink sulfat dan gas Z

III

2 g zinc powder + 50.0 cm3 of 0.5 mol dm–3

acid Y + 5 drops copper(II) sulphate solution.2 g serbuk zink + 50.0 cm3 of 0.5 mol dm–3

asid Y + 5 titis larutan kuprum(II) sulfat

Zinc sulphate and gas ZZink sulfat dan gas Z

Table 9Jadual 9

(a) (i) Name acid X, acid Y and gas Z.Describe a chemical test to identify gaz Z.

Namakan asid X, asid Y dan gas Z.Huraikan ujian kimia untuk mengenal pasti gas Z.

[5 marks][5 markah]

https://cikguadura.wordpress.com/

Page 53: PEPERIKSAAN PERCUBAAN SIJIL PELAJARAN · PDF file[Jisim atom relatif: H=1, N=14, O=16;Isipadu molar gas = 24 dm3mol-1 pada keadaan bilik) A Hydrogen, nitrogen, ... Anion that exist

27 4541/2

4541/2 PAHANG [Lihat sebelah]

(ii) Calculate the maximum volume of gas Z produced at room condition inexperiment II.[Relative atomic mass: Zn, 65. volume of 1 mol of gas at room condition= 24 dm3]Kirakan isipadu maksimum gas Z yang terhasil pada keadaan bilik dalameksperimen II.[Jisim atom relatif: Zn, 65. Isipadu 1 mol gas pada keadaan bilik = 24 dm3]

[3 marks][3 markah]

(iii) Sketch a graph volume of gas Z against time for experiment I, II and III on thesame axes.Lakarkan graf isipadu gas Z melawan masa bagi eksperimen I, II dan III padapaksi yang sama.

[ 4 marks][4 markah]

(iv) Compare the rate of reaction in experiment II and III . Explain your answer basedon collision theoryBandingkan kadar tindak balas dalam eksperimen II dan III. Terangkan jawapananda berdasarkan teori perlanggaran..

[ 5 marks][5 markah]

Page 54: PEPERIKSAAN PERCUBAAN SIJIL PELAJARAN · PDF file[Jisim atom relatif: H=1, N=14, O=16;Isipadu molar gas = 24 dm3mol-1 pada keadaan bilik) A Hydrogen, nitrogen, ... Anion that exist

28 4541/2

4541/2 PAHANG [Lihat sebelah]

Diagram 9Rajah 9

(b) Diagram 9 shows a baker making his dough in order to make bread. The baker

discovers that the bread dough rises faster in a warm place than in a cool place.

From the situation above, identify the factor that affects the rate of rising of dough

and explain how the factor affects the rate of rising of the dough.

Rajah 9 menunjukkan seorang tukang masak membuat adunan roti. Tukang masak

tersebut mendapati bahawa adunan roti menaik dengan lebih cepat di tempat yang

panas berbanding tempat yang sejuk.

Dari situasi di atas, kenal pasti faktor yang mempengaruhi kadar kenaikan doh dan

terangkan bagaimana faktor tersebut mempengaruhi kadar kenaikan doh tersebut.

[ 3 marks ]

[3 markah]

Page 55: PEPERIKSAAN PERCUBAAN SIJIL PELAJARAN · PDF file[Jisim atom relatif: H=1, N=14, O=16;Isipadu molar gas = 24 dm3mol-1 pada keadaan bilik) A Hydrogen, nitrogen, ... Anion that exist

29 4541/2

4541/2 PAHANG [Lihat sebelah]

Respiration ProcessProses Respirasi

Photosynthesis ProcessProses Fotosintesis

Diagram 10.1Rajah 10.1

Diagram 10.2Rajah 10.2

Diagram 10.1 shows the respiration process. Cellularrespiration is the set of metabolic reactions andprocesses that take place in the cells of organisms toconvert biochemical energy from nutrients intoadenosine triphosphate (ATP), and then releasewaste products. The chemical equation may besimplified as:

C6H12O6 + 6O2 → 6H2O + 6CO2+ energyH = - x kJmol-1

Rajah 10.1 menunjukkan proses respirasi sel.Respirasi sel adalah satu set tindak balas metabolikdan proses yang berlaku di dalam sel organismauntuk menukarkan tenaga biokimia daripada nutrienkepada adenosin trifosfat (ATP), dan kemudianmembebaskan hasil buangan.Persamaan kimia boleh diringkaskan seperti berikut :

C6H12O6 + 6O2 → 6H2O + 6CO2+ tenagaH = - x kJmol-

Diagram 10.2 shows the photosynthesis process. Inplants, photosynthesis occurs mainly within the leaves.Photosynthesis requires carbon dioxide, water, andsunlight. All of these substances must be obtained by ortransported to the leaves to produce glucose andrelease oxygen gas. The chemical equation may besimplified as:

6CO2 + 6H2O + sunlight → C6H12O6 + 6O2H = + y kJmol-1

Rajah 10.2 menunjukkan proses fotosintesis. Dalamtumbuh-tumbuhan, fotosintesis berlaku dengan banyakpada bahagian daun. Fotosintesis memerlukan karbondioksida, air dan cahaya matahari. Kesemua bahan-bahan ini mesti diperoleh atau dipindahkan kepadabahagian daun untuk menghasilkan glukosa danmembebaskan oksigen. Persamaan kimia bolehdiringkaskan seperti berikut :

6CO2 + 6H2O + cahaya matahari → C6H12O6 + 6O2H = + y kJmol-

Page 56: PEPERIKSAAN PERCUBAAN SIJIL PELAJARAN · PDF file[Jisim atom relatif: H=1, N=14, O=16;Isipadu molar gas = 24 dm3mol-1 pada keadaan bilik) A Hydrogen, nitrogen, ... Anion that exist

30 4541/2

4541/2 PAHANG [Lihat sebelah]

10 (a) Based on Diagram 10.1 and 10.2, compare and contrast both processes above.Your explanation should include the following :

types of chemical reactions energy content of reactants and products draw the energy level diagrams

Berdasarkan Rajah 10.1 dan Rajah 10.2, banding bezakan kedua-dua proses diatas. Penerangan anda perlu memasukkan perkara-perkara berikut :

jenis tindak balas kimia kandungan tenaga bahan dan hasil tindak balas lukis gambarajah aras tenaga

[ 8 marks ][8 markah]

Diagram 10.3Rajah 10.3

(b) Excess metal X powder is added to 50 cm3 of 0.1 mol dm-3 copper (II) sulphatesolution produce 210 kJmol-1 heat energy. Based on diagram 10.3, suggest metalX. Calculate the change in temperature of the solution.[Given that Specific heat capacity of solution : 4.2 J g -1oC-1]

Serbuk logam X berlebihan ditambahkan kepada 50 cm3 0.1 mol dm-3 larutankuprum (II) sulfat menghasilkan 210 kJmol-1 tenaga haba. Berdasarkan rajah10.3, cadangkan logam X. Hitungkan perubahan suhu larutan.[Muatan haba tentu larutan : 4.2 J g -1oC-1]

[ 4 marks ][4 markah]

SpatulaSpatula

Metal XLogam X

Polystyrene CupCawan polistirena

Copper(II) sulphate solutionLarutan kuprum(II) sulfat

ThermometerTermometer

Page 57: PEPERIKSAAN PERCUBAAN SIJIL PELAJARAN · PDF file[Jisim atom relatif: H=1, N=14, O=16;Isipadu molar gas = 24 dm3mol-1 pada keadaan bilik) A Hydrogen, nitrogen, ... Anion that exist

31 4541/2

4541/2 PAHANG [Lihat sebelah]

(c) Based on ionic equation above, describe a laboratory experiment to determinethe heat of precipitation of solid WSO4. In your description, include the followingaspects :Berdasarkan persamaan ion di atas, huraikan satu eksperimen makmal untukmenentukan haba pemendakan bagi pepejal WSO4. Dalam huraian anda,sertakan aspek-aspek berikut:

Materials neededBahan-bahan yang diperlukan

Procedure of experimentProsedur eksperimen

A table to collect dataJadual untuk mengumpul data

[ 8 marks ][8 markah]

END OF QUESTION PAPERKERTAS SOALAN TAMAT

W2+ (aq) + SO42-(aq)WSO4 (s)

W2+(ak) + SO42- (ak)WSO4 (p)

https://cikguadura.wordpress.com/

Page 58: PEPERIKSAAN PERCUBAAN SIJIL PELAJARAN · PDF file[Jisim atom relatif: H=1, N=14, O=16;Isipadu molar gas = 24 dm3mol-1 pada keadaan bilik) A Hydrogen, nitrogen, ... Anion that exist

32

4541/2 PAHANG [Lihat sebelah]

Page 59: PEPERIKSAAN PERCUBAAN SIJIL PELAJARAN · PDF file[Jisim atom relatif: H=1, N=14, O=16;Isipadu molar gas = 24 dm3mol-1 pada keadaan bilik) A Hydrogen, nitrogen, ... Anion that exist

33

4541/2 PAHANG [Lihat sebelah]

INFORMATION FOR CANDIDATESMAKLUMAT UNTUK CALON

1. This question paper consists of three sections: Section A, Section B and Section C.

Kertas soalan ini mengandungi tiga bahagian: Bahagian A, Bahagian B danBahagian C.

2. Answer all questions in Section A. Write your answers for Section A in the spaces provided in thequestion paper.

Jawabsemua soalan dalam Bahagian A. Tuliskan jawapan bagi Bahagian A dalam ruang yangdisediakan dalam kertas soalan

3. Answer one question from Section B and one question from Section C.Write your answers for Section B and Section C on the `answer sheet’ provided by the invigilators.Answer questions in Section B and Section C in detail.You may use equations, diagrams, tables, graphs and other suitable methods to explain your answer.

Jawab satu soalan daripada Bahagian B dan satu soalan daripada Bahagian C. Tuliskan jawapanbagi Bahagian B dan Bahagian C pada kertas tulis yang dibekalkan oleh pengawas peperiksaan.Jawab Bahagian B dan Bahagian C dengan terperinci. Anda boleh menggunakan persamaan,gambar rajah, jadual, graf dan cara lain yang sesuai untuk menjelaskan jawapan anda.

4. The diagrams in the questions are not drawn to scale unless stated.

Rajah yang mengiringi soalan tidak dilukiskan mengikut skala kecuali dinyatakan

5. Marks allocated for each question or sub-part of the question is shown in brackets.

Markah yang diperuntukkan bagi setiap soalan atau ceraian soalan ditunjukkan dalam kurungan.

6. Show your working. It may help you to get marks.

Tunjukkan kerja mengira.Ini membantu anda mendapatkan markah.

7. If you wish to change your answer, neatly cross out the answer that you have done. Then write downthe new answer.

Sekiranya anda hendak membatalkan sesuatu jawapan, buat garisan di atas jawapan itu.

8. You may use a non-programmable scientific calculator.

Anda dibenarkan menggunakan kalkulator saintifik yang tidak boleh diprogramkan.

9. You are advised to spend 90 minutes to answer questions in Section A, 30 minutes for Section B and30 minutes for Section C.

Anda dicadangkan mengambil masa 90 minit untuk menjawab soalan dalam Bahagian A, 30 minituntuk Bahagian B dan 30 minit untuk BahagianC.

10. Tie together your answer sheets at the end of the examination.Ikat semua kertas jawapan anda di akhir peperiksaan.

Page 60: PEPERIKSAAN PERCUBAAN SIJIL PELAJARAN · PDF file[Jisim atom relatif: H=1, N=14, O=16;Isipadu molar gas = 24 dm3mol-1 pada keadaan bilik) A Hydrogen, nitrogen, ... Anion that exist

SULIT 1 4541/3

4541/3 PAHANG

NAMA :....................................................................................................

KELAS :...................................................................................................

PEPERIKSAAN PERCUBAANSIJIL PELAJARAN MALAYSIA 2015 4541/3

CHEMISTRYKertas 3

September

1 ½ jam 1 jam 30 minit

DO NOT OPEN THIS PAPER UNTIL YOU ARE TOLD TO DO SO

JANGAN BUKA KERTAS SOALAN INI SEHINGGA DIBERITAHU

1. Kertas soalan ini adalah dalam dwibahasa.

2. Soalan dalam Bahasa Inggeris mendahuluisoalan yang sepadan dalam Bahasa Melayu.

3. Calon dibenarkan menjawab keseluruhanatau sebahagian soalan sama ada dalamBahasa Inggeris atau Bahasa Melayu.

4. Calon dikehendaki membaca maklumat dihalaman belakang kertas soalan ini.

Kertas soalan ini mengandungi 11 halaman bercetak

Untuk Kegunaan Pemeriksa

Soalan Markahpenuh

Markahdiperoleh

1 15

2 18

3 17

JUMLAH

https://cikguadura.wordpress.com/

Page 61: PEPERIKSAAN PERCUBAAN SIJIL PELAJARAN · PDF file[Jisim atom relatif: H=1, N=14, O=16;Isipadu molar gas = 24 dm3mol-1 pada keadaan bilik) A Hydrogen, nitrogen, ... Anion that exist

SULIT 2 4541/3

4541/3 PAHANG

Answer all questions.Jawab semua soalan.

1. Diagram 1.1 shows the apparatus set-up for an experiment to determine themelting point of naphthalene. Solid naphthalene is heated in a water bath untilmelts completely.Rajah 1.1 menunjukkan susunan radas bagi bagi ekspeimen untuk menentukantakat lebur naftalena. Pepejal naftalena dipanaskan dalam kukus air hinggamelebur dengan lengkap.

Diagram 1.1Rajah 1.1

The readings of the temperature of naphthalene are recorded every 30 secondsfrom 60.0oC until 95.0oC.Table 1.1 shows the thermometer readings of the experiment.

Bacaan suhu naftalene telah direkodkan bagi setiap 30 saat daripada 60.0OChingga 95.0oC.Jadual 1.1 menunjukkan bacaan termometer bagi eksperimen itu.

ThermometerTermometer

Boiling tubeTabung didih

Water bathKukus Air

NaphthaleneNaftalena

https://cikguadura.wordpress.com/

Page 62: PEPERIKSAAN PERCUBAAN SIJIL PELAJARAN · PDF file[Jisim atom relatif: H=1, N=14, O=16;Isipadu molar gas = 24 dm3mol-1 pada keadaan bilik) A Hydrogen, nitrogen, ... Anion that exist

SULIT 3 4541/3

4541/3 PAHANG

Initial temperature:……….Suhu awal

Temperature at 30s: ……..Suhu pada 30 saat

Temperature at 60s:……Suhu pada 60 saat

(a) Record the temperature for every 30 second interval as shown in Table 1.1.Rekodkan suhu bagi setiap sela masa 30 saat dalam Jadual 1.1

[3 marks]

Temperature at 90s:…….Suhu pada 90 saat

Temperature at 120s: …….Suhu pada 120 saat

Temperature at 150s: …….Suhu pada 150 saat

Temperature at 180s: ……..Suhu pada 180 saat

Temperature at 210s: ……..Suhu pada 210 saat

Temperature at 240s: ……..Suhu pada 240 saat

ForExaminer’sUse

Table 1.1Jadual 1.1

3

Page 63: PEPERIKSAAN PERCUBAAN SIJIL PELAJARAN · PDF file[Jisim atom relatif: H=1, N=14, O=16;Isipadu molar gas = 24 dm3mol-1 pada keadaan bilik) A Hydrogen, nitrogen, ... Anion that exist

SULIT 4 4541/3

4541/3 PAHANG

(b) (i) Plot a graph of temperature against time for the heating of naphthalene on thegraph paper given in page 5.Plotkan graf suhu melawan masa bagi pemanasan naftalena di atas kertas grafyang disediakan pada muka surat 5.

[3 marks]

(ii) State the melting point of naphthalene, and show on the graph how youdetermine this melting point.

Nyatakan takat lebur naftalena, dan tunjukkan di atas graf bagaimanaanda tentukan takat lebur ini.

……………………………………………………………………………………………[3 marks]

( c) The temperature of naphthalene did not change from 90th second until the 150th secondduring the melting process. Explain why.Suhu naftalena tidak berubah dari saat ke-90 hingga saat ke-150 semasa prosespeleburan itu. Terangkan mengapa.

………………………………………………………………………………………………

……………………………………………………………………………………………..

……………………………………………………………………………………………….[3 marks]

3

3

3

ForExaminer’sUse

Page 64: PEPERIKSAAN PERCUBAAN SIJIL PELAJARAN · PDF file[Jisim atom relatif: H=1, N=14, O=16;Isipadu molar gas = 24 dm3mol-1 pada keadaan bilik) A Hydrogen, nitrogen, ... Anion that exist

SULIT 5 4541/3

4541/3 PAHANG

(b) (i)

Page 65: PEPERIKSAAN PERCUBAAN SIJIL PELAJARAN · PDF file[Jisim atom relatif: H=1, N=14, O=16;Isipadu molar gas = 24 dm3mol-1 pada keadaan bilik) A Hydrogen, nitrogen, ... Anion that exist

SULIT 6 4541/3

4541/3 PAHANG

d) Naphthalene is an example of a covalent compound and Magnesium chlorideis an example of an ionic compound. Classify the following into covalent or ioniccompounds.Naftalena adalah satu contoh sebatian kovalen manakala Magnesium klorida adalahsatu contoh sebatian ion. Kelaskan sebatian berikut kepada sebatian kovalen atausebatian ion.

..

[3 marks]

Ionic compoundSebatian ion

Covalent compoundSebatian kovalen

ForExaminer’sUse

Potassium bromide, zinc nitrate, glucose, methanol,ethyl ethanoate , sodium chloride

Kalium bromida, zink nitrat, glukosa, metanol,etil etanoat, natrium klorida

3

TOTAL

Page 66: PEPERIKSAAN PERCUBAAN SIJIL PELAJARAN · PDF file[Jisim atom relatif: H=1, N=14, O=16;Isipadu molar gas = 24 dm3mol-1 pada keadaan bilik) A Hydrogen, nitrogen, ... Anion that exist

SULIT 7 4541/3

4541/3 PAHANG

2. Table 2.1 shows the observation in five test tubes used to investigate the effect of othermetals on rusting. A mixture of jelly solution, potassium hexacyanoferrate(III),K3Fe(CN)6 solution and phenolphthalein were used as medium in each test tube. Theobservations were recorded after one day.

Jadual 2.1 menunjukkan pemerhatian dalam lima buah tabung uji yang digunakanuntuk menyiasat kesan logam lain ke atas pengaratan. Medium yang digunakan didalam setiap tabung uji adalah campuran larutan agar, larutan kaliumheksasianoferat(III), K3Fe(CN)6 dan fenolftalein. Pemerhatian direkod selepas satuhari.

Test tube 1Tabung uji 1

Test tube 2Tabung uji 2

Test tube 3Tabung uji 3

Test tube 4Tabung uji 4

Test tube 5Tabung uji 5

Table 2.1 // Jadual 2.1

ForExaminer’sUse

Iron nail coiled withmetal Q stripPaku besi dililit dengankepingan logam Q

Very low intensity of blue colourVery low intensity of pink colourKeamatan warna biru sangatrendahKeamatan warna merah jambusangat rendah

No blue spotLow intensity of pink colourTiada tompokan biruKeamatan warna merah jambusangat rendah

No blue spotHigh intensity of pink colourTiada tompokan biruKeamatan warna merah jambutinggi

Low intensity blue of blue colourLow intensity of pink colourKeamatan warna biru rendahKeamatan warna merah jamburendah

High intensity blue of blue colourLow intensity of pink colourKeamatan warna biru sangat tinggiKeamatan warna merah jamburendah

Iron nail coiled withstanum stripPaku besi dililit dengankepingan stanum

https://cikguadura.wordpress.com/

Page 67: PEPERIKSAAN PERCUBAAN SIJIL PELAJARAN · PDF file[Jisim atom relatif: H=1, N=14, O=16;Isipadu molar gas = 24 dm3mol-1 pada keadaan bilik) A Hydrogen, nitrogen, ... Anion that exist

SULIT 8 4541/3

4541/3 PAHANG

(a) State the observation and inference for test tube 2, 3 and 4.Nyatakan pemerhatian dan inferens untuk tabung uji 2, 3 dan 4.

Test tubeTabung uji

ObservationPemerhatian

InferenceInferens

2

3

4

[6 marks]

(b) State the hypothesis for the experiment.Nyatakan hipotesis bagi eksperimen ini.

…………………………………………………………………………………..……………………

……………..………………………….………………………………………………………………

………………………………………………………………………………………………………..[3 marks]

(c) For this experiment, state:Bagi eksperimen ini, nyatakan

(i) The manipulated variable :Pembolehubah dimanipulasi :

………………………………………………………………………………………………...

(ii) The responding variable :Pembolehubah bergerakbalas :

…………………………………………………………………………………………………

(iii) The constant variable :Pembolehubah dimalarkan :

……………………………………….......……………………………………………………..[3 marks]

6

3

3

ForExaminer’sUse

Page 68: PEPERIKSAAN PERCUBAAN SIJIL PELAJARAN · PDF file[Jisim atom relatif: H=1, N=14, O=16;Isipadu molar gas = 24 dm3mol-1 pada keadaan bilik) A Hydrogen, nitrogen, ... Anion that exist

SULIT 9 4541/3

4541/3 PAHANG

(d) State the one operational definition for the experiment.Nyatakan satu definisi secara operasi bagi eksperimen ini.

………………………………………………………………………………………………………

………………………………………………………………………………………………………

………………………………………………………………………………………………………

............................................................................................................................. ...............[3 marks]

(e) Based on the observation of test tube 5 in Table 2.1, predict metal Q.Berdasarkan pemerhatian bagi tabung uji 5 dalam Jadual 2.1, ramalkan logam Q.

………………………………………………………………………………………………………[3 marks] 3

TOTAL

3

ForExaminer’sUse

Page 69: PEPERIKSAAN PERCUBAAN SIJIL PELAJARAN · PDF file[Jisim atom relatif: H=1, N=14, O=16;Isipadu molar gas = 24 dm3mol-1 pada keadaan bilik) A Hydrogen, nitrogen, ... Anion that exist

SULIT 10 4541/3

4541/3 PAHANG

3

Based on the above statement, you are required to design an experiment to determine andcompare the heat of neutralization between sodium hydroxide solution with a named strongacid solution and a weak acid solution.Berdasarkan pernyataan di atas, anda dikehendaki merancang eksperimen untukmenentukan haba peneutralan di antara larutan natrium hidroksida dengan satu larutanasid kuat dan satu larutan asid lemah yang dinamakan.

Your planning should include the followings :Perancangan anda hendaklah mengandungi perkara-perkara berikut:

(a) Problem StatementPernyataan masalah

(b) HypothesisHipotesis

(c) All the variablesSemua pemboleh ubah yang terlibat

(c) List of materials and apparatusSenarai bahan dan alat radas

(d) Procedure of the experimentProsedur eksperimen

(e) Tabulation of dataPenjadualan data

[17 marks]

END OF QUESTION PAPERKERTAS SOALAN TAMAT

Experiment I : NaOH + HCl NaCl + H2O H = - 57.5 kJmol-1

Experiment II : NaOH + CH3COOH CH3COONa + H2O H = - 55 kJmol-1

The value of the heat of neutralization for the reaction between sodiumhydroxide solution and strong acid solution is higher than the value of the heatof neutralization for the reaction between sodium hydroxide solution and weak

acid solution.

Nilai haba peneutralan bagi tindak balas antara larutan natrium hidroksidadengan larutan asid kuat lebih tinggi daripada haba peneutralan larutan natrium

hidroksida dengan larutan asid lemah.

https://cikguadura.wordpress.com/

Page 70: PEPERIKSAAN PERCUBAAN SIJIL PELAJARAN · PDF file[Jisim atom relatif: H=1, N=14, O=16;Isipadu molar gas = 24 dm3mol-1 pada keadaan bilik) A Hydrogen, nitrogen, ... Anion that exist

SULIT 11 4541/3

4541/3 PAHANG

INFORMATION FOR CANDIDITES

1. This question paper consists of three questions. Answer all questions.

2. Write your answers for Question 1 and Question 2 in the spaces provided in thequestion paper.

3. Write your answers for Question 3 on the “helaian tambahan”. You may useequation, diagrams, tables, graphs and other suitable methods to explain youranswer.

4. Show your working, it may help you to get marks.

5. If you wish to change your answer, neatly cross out the answer that you have done.Then write down the new answer.

6. The diagrams in the questions are not drawn to scale unless stated.

7. Mark allocated for each question or part question are shown in brackets.

8. The time suggested to answers Question 1 and Question 2 is 45 minutes andQuestion 3 is 45 minutes.

9. You may use a non-programmable scientific calculator.

10. Hand your answer sheets at the end of the examination.

Marks awarded:

Mark Description3210

Excellent : The best responseSatisfactory : An average responseWeak : An inaccurate responseNo response or wrong response

Page 71: PEPERIKSAAN PERCUBAAN SIJIL PELAJARAN · PDF file[Jisim atom relatif: H=1, N=14, O=16;Isipadu molar gas = 24 dm3mol-1 pada keadaan bilik) A Hydrogen, nitrogen, ... Anion that exist

ANSWER SCHEMECHEMISTRY

PAPER 1(TRIAL 2015)

1 B 26 C2 D 27 A3 B 28 A4 B 29 A5 C 30 D6 A 31 A7 A 32 C8 B 33 D9 A 34 B

10 B 35 A11 D 36 B12 C 37 C13 A 38 D14 C 39 C15 D 40 B16 A 41 A17 A 42 D18 C 43 A19 B 44 C20 B 45 B21 B 46 C22 C 47 D23 D 48 D24 D 49 C25 C 50 B

https://cikguadura.wordpress.com/

Page 72: PEPERIKSAAN PERCUBAAN SIJIL PELAJARAN · PDF file[Jisim atom relatif: H=1, N=14, O=16;Isipadu molar gas = 24 dm3mol-1 pada keadaan bilik) A Hydrogen, nitrogen, ... Anion that exist

Marking SchemeChemistry Paper 2 (4541/2)

SPM Trial Exam 2015

Question Marking Criteria Submark

Mark

1 (a) (i) Diffusiona: sublimation

1 1

(ii)

Solid Gas

11

2

(iii) Molecule 1 1

(b) (i) Formula that shows the simplest ratio of atoms of eachelements in a compound

1 1

(ii) Any suitable named metalAny suitable named acid

Sample answer :- Zinc (r: formula) (r: Copper // Argentum)- Sulphuric acid

11

2

(iii) Repeat heating, cooling and weighing process untill constantmass is obtained

1 1

(iv) Any suitable oxide metal lower than Hydrogen in reactivityseriesSample answer : PbO // AgO

11

Total 9

https://cikguadura.wordpress.com/

Page 73: PEPERIKSAAN PERCUBAAN SIJIL PELAJARAN · PDF file[Jisim atom relatif: H=1, N=14, O=16;Isipadu molar gas = 24 dm3mol-1 pada keadaan bilik) A Hydrogen, nitrogen, ... Anion that exist

Question Marking Criteria Submark Mark

2 (a) (i) CaCO3 + 2HCl CaCl2 + CO2 + H2O

1- Correct formula of reactants and products2- Correct balance

11

2

(ii) 30/24000 mol // 0.00125 mol 1 1

(iii) 0.00125 x 6.02 x 1023 // 7.505 x 1020 1 1

(iv) 1. correct ratio mol //mol of CaCO32. correct mass with correct unit

Sample answer :1. 1 mol CO2 : 1 mol CaCO3

0.00125 mol CO2 : 0.00125 mol CaCO3

2. Mass CaCO3 = 0.00125 x 100 g // 0.125 g

1

1

2

(b) (i) C5H8NO4Na 1 1(ii) Ionic compound (r : ionic bond) 1 1(iii) 169 1 1

Total 9

Question Marking Criteria Submark

Mark

3 (a)

T

R

S

111

3

(b) T 1(c) P2R // H2O 1(d) (i) S 1

(ii) - Atom S is more reactive than atom Q.- Valence electron in atom S is further away from the nucleuscompare to atom Q.- The attraction force between the proton in the nucleus ofatom S is weaker than atom Q // Atom S is more easier toreleased electron than atom Q.

11

1

3

(iii) - Act as a catalyst 1 1Total 10

Page 74: PEPERIKSAAN PERCUBAAN SIJIL PELAJARAN · PDF file[Jisim atom relatif: H=1, N=14, O=16;Isipadu molar gas = 24 dm3mol-1 pada keadaan bilik) A Hydrogen, nitrogen, ... Anion that exist

Question Marking Criteria Submark

Mark

4 (a) Positively charged ion // Positive ion 1

(b) Cu2+ and H+ 1

(c) - Copper- Cu2+ received 2 electrons (to form copper)

11 2

(d) (i) Hydrogen (r: formula) 1

(ii) - Put the burning wooden splinter into the mouth of the testtube containing the gas- the ‘pop’ sound produced

11 2

(e) Zinc 1

(f) (i) The voltage reading of Cell S increase (when the zincelectrode is replaced with magnesium) //The voltage reading of Cell S is higher when the zincelectrode is replaced with magnesium

1

(ii) Magnesium is more electropositive than zinc //Magnesium is higher than zinc in the electrochemical series

1

Total 10

Page 75: PEPERIKSAAN PERCUBAAN SIJIL PELAJARAN · PDF file[Jisim atom relatif: H=1, N=14, O=16;Isipadu molar gas = 24 dm3mol-1 pada keadaan bilik) A Hydrogen, nitrogen, ... Anion that exist

Question Marking Criteria Submark

Mark

5 (a) (i) H2SO4 + 2NaOH Na2SO4 + 2H2O- Correct formula of reactants and products- Balanced equation

11 2

(ii) 1. Correct no of mol of NaOH2. Correct ratio mol3. Correct molarity with correct unit

Sample answer :1. mol NaOH : 0.1 x 25 /1000 // 0.00252. 0.0025 mol NaOH : 0.00125 mol H2SO43. Molarity H2SO4 = 0.1 mol dm-3

111

3

(iv)

- Functional diagram- Labelled diagram 1

1 2(v) - 25 cm3

- Concentration of H+ in the hydrochloric acid is half ofsulphuric acid // Concentration of H+ in the sulphuric acid isdouble of hydrochloric acid

11 2

(b) - Bee sting is acidic, toothpaste is basic//alkaline- Toothpaste neutralises the bee sting

11 2

Total 11

Sulphuric acid

burrette

Sodium hydroxide+ phenolphthalein

Page 76: PEPERIKSAAN PERCUBAAN SIJIL PELAJARAN · PDF file[Jisim atom relatif: H=1, N=14, O=16;Isipadu molar gas = 24 dm3mol-1 pada keadaan bilik) A Hydrogen, nitrogen, ... Anion that exist

Question Marking Criteria SubMark

TotalMark

6 (a) Hydroxyl group // -OH group 1 1

(b) 1+1 2

(c) (i) Dehydration 1 1

(ii) C3H7OH → C3H6 + H2O

1. Correct reactants and products

1 1

(d) 1. Propene change purple colour of Potassium manganate(VII) to colourless while propane purple colour remainunchanged

2. propene can undergoes addition reaction because it isunsaturated hydrocarbon // consist double bond betweencarbon atoms

3. propane cannot undergoes addition reaction because it issaturated hydrocarbon // consist single bond betweencarbon atoms

1

1

1

3

(e) (i) ester 1 1(ii) 1. pour [5-10 cm3] ethanol into a boiling tube of [5-10

cm3] pentanoic acid2. put a few drops of concentrated sulphuric acid into the

boiling tube and heat gently

1

1

2

TOTAL 11

Page 77: PEPERIKSAAN PERCUBAAN SIJIL PELAJARAN · PDF file[Jisim atom relatif: H=1, N=14, O=16;Isipadu molar gas = 24 dm3mol-1 pada keadaan bilik) A Hydrogen, nitrogen, ... Anion that exist

Question Marking Criteria SubMark

TotalMark

7 (a) (i) 1. correct name of the process2. correct formula of reactants and product of step X3. balance chemical equation of step X4. correct formula of reactants and product of step X5. balance chemical equation of step X

Answer :

Contact Process

Step X : 2SO2 + O2 → 2SO3

Step Y : SO3 + H2SO4 → H2S2O7

1

1+1

1+1

5

1. Dissolve in rain water to produce acid rain2. Increase the acidity of water in the river // disturbs the

ecosystem // aquatic organisms may die

11

2

(b) (i) NH4SO4 11

(ii) 1. Urea2. % of N in urea = 28 / 60 x 100 = 46.67%3. % of N in fertilizers X = 28 / 132 x 100 = 21.21%4. Percentage of N atoms by mass in urea is higher thanammonium sulphate

1111

4

(c) P : Fibre glassQ : BronzeR : DuraluminS : CeramicsT : Lead crystal glass

11111

5

(d) Properties:Durable / light /inert to chemical / insulator(any 2 answers)

Uses : Plastic plate / toys / shopping bag(any 1 answer)

1+1

1

3

TOTAL 20

https://cikguadura.wordpress.com/

Page 78: PEPERIKSAAN PERCUBAAN SIJIL PELAJARAN · PDF file[Jisim atom relatif: H=1, N=14, O=16;Isipadu molar gas = 24 dm3mol-1 pada keadaan bilik) A Hydrogen, nitrogen, ... Anion that exist

Question Marking Criteria SubMark

TotalMark

8 (a) (i) - correct label of axis and unit-correct plot-correct curve

111

3

(ii) - volume lead(II) nitrate – 2.5 cm3

-no of mol of Pb2+

2.5 x 1 // 0.0025 mol1000

- no of mol of I-5 x 1 // 0.005 mol

1000

- correct ratio0.0025 mol Pb2+ react with 0.005 mol I-

-correct number of mol of iodide ions react with 1 mollead(II) ions

1 mol Pb2+ react with 2 mol I-

-correct formula of reactants and products-correct balance

Pb2+ + 2 I- PbI2

1

1

1

1

1

11

7

(b) (i) Oxide T : CuO // copper(II) oxide

Salt W : CuSO4 // copper(II) sulphate

Salt X : Cu(NO3)2 // copper(II) nitrate

Solid Y : BaSO4 // barium sulphate

1

1

1

1

4

(ii)

-White precipitate formed-double decomposition reaction

11 2

Page 79: PEPERIKSAAN PERCUBAAN SIJIL PELAJARAN · PDF file[Jisim atom relatif: H=1, N=14, O=16;Isipadu molar gas = 24 dm3mol-1 pada keadaan bilik) A Hydrogen, nitrogen, ... Anion that exist

Question Marking Criteria SubMark

TotalMark

(iii) -correct chemical equationCuSO4 + Ba(NO3)2 Cu(NO3)2 + BaSO4

-No of mol of barium nitrate50 x 1 // 0.051000

- ratio1 mol Ba(NO3)2 : 1 mol BaSO40.05 mol Ba(NO3)2 : 0.05 mol BaSO4

- correct mass & unit of BaSO40.05 x 233 g // 11.65 g

1

1

1

1

4

TOTAL 20

Question Marking Criteria SubMark

TotalMark

9 (a) (i) Acid X : hydrochloric acidAcid Y : sulphuric acidGas Z : hydrogen gas

Reject : formula

-correct method and reagent to identify gas Z-correct observation

Answer :Put a burning wooden splinter to the mouth of test tube‘pop’ sound produce

111

11 5

(ii) -No of mol of acid Y50 x 0.5 // 0.0251000

- ratio1 mol H2SO4 : 1 mol H20.025 mol H2SO4 : 0.025 mol H2

- correct volume of gas Z0.025 x 24 dm3 // 0.6 dm3

1

1

1

3

https://cikguadura.wordpress.com/

Page 80: PEPERIKSAAN PERCUBAAN SIJIL PELAJARAN · PDF file[Jisim atom relatif: H=1, N=14, O=16;Isipadu molar gas = 24 dm3mol-1 pada keadaan bilik) A Hydrogen, nitrogen, ... Anion that exist

Question Marking Criteria SubMark

TotalMark

(iii)

- Both axis labeled & unit- Correct curve I & labeled- Correct curve II & labeled- Correct curve III & labeled

1111

4

(iv) 1. Rate of reaction in Experiment III is higher than inExperiment II

2. In Experiment III presence of copper(II) sulphate as acatalyst.

3. Activation energy in experiment III is lower than experimentII.

4. more colliding particles can overcome the activation energyin exp. III.

5. The frequency of effective collisions in exp III is higher.

1

1

1

1

1

5

(b) -Temperature-at warm place, kinetic energy of particles increases/higher-Rate of rising of the dough increases/higher

111

3

TOTAL 20

Volume of gas / cm3

III

II

I

time / s

Page 81: PEPERIKSAAN PERCUBAAN SIJIL PELAJARAN · PDF file[Jisim atom relatif: H=1, N=14, O=16;Isipadu molar gas = 24 dm3mol-1 pada keadaan bilik) A Hydrogen, nitrogen, ... Anion that exist

Question Marking Criteria SubMark

TotalMark

10 (a) Type of chemical reaction1. Diagram 10.1 : exothermic reaction.2. Diagram 10.2 : endothermic reaction.

11

8

Energy content of reactants and products :3. Diagram 10.1 : The energy content in the reactants is

higher than the energy content in the products4. Diagram 10.2 : the energy content in the reactants

less than the energy content in the products .

1

1

5-label energy and correct level diagram 10.16-correct equation & ∆H Energy level diagram 10.1

7-label energy and correct level diagram 10.28-correct equation & ∆H Energy level diagram 10.2

1 + 1

1 + 1

(b) 1. Number of moles of CuSO4 = (0.1)(50) // 0.005 mol1000 1

4

2. Heat change, mcθ = 210 x 0.005 J // 1.05 kJ // 1050 J 13. Metal X : Zn // Mg

4. θ = 1050 . oC // 5.0oC(50)(4.2)

1

1

Energy

TenagaC6H12O6 + 6O2

∆H = -x kJmol-1

6H2O + 6CO2

Energy

Tenaga C6H12O6 + 6O2

∆H = +y kJmol-1

6H2O + 6CO2 + sunlight

Page 82: PEPERIKSAAN PERCUBAAN SIJIL PELAJARAN · PDF file[Jisim atom relatif: H=1, N=14, O=16;Isipadu molar gas = 24 dm3mol-1 pada keadaan bilik) A Hydrogen, nitrogen, ... Anion that exist

Question Marking Criteria SubMark

TotalMark

(c) Material and apparatus

1. Lead(II) nitrate solution // barium nitrate solution //Calcium nitrate solution

2. copper(II) sulphate solution // magnesium sulphate // zincsulphate (any suitable soluble sulphate of +2 cation)

Procedure:

1. Measure 50 cm3 of copper (II) sulphate solution 0.5 moldm-3 using measuring cylinder and pour into polystyrenecup

2. Measure initial temperature of the solution.3. Measure 50 cm3 of lead(II) nitrate solution 0.5 mol dm-3

using measuring cylinder and pour into anotherpolystydsrene cup

4. Measure initial temperature of the solution.5. Mix the solution, stir by using thermometer and measure

the maximum temperature of the mixture.

Table:

Initial temperature ofLead(II) nitrate /oC

Ө1

Initial temperatureCopper(II) sulphate /oC

Ө2

Average Initial temperatureof the mixture /oC

Ө3

Maximum Temperature/oC Ө4Temperature change /oC Ө4 - Ө3

1

1

1

1

1

11

1

8

TOTAL 20https://cikguadura.wordpress.com/

Page 83: PEPERIKSAAN PERCUBAAN SIJIL PELAJARAN · PDF file[Jisim atom relatif: H=1, N=14, O=16;Isipadu molar gas = 24 dm3mol-1 pada keadaan bilik) A Hydrogen, nitrogen, ... Anion that exist

MARKING SCHEME PAPER 3 CHEMISTRY TRIAL SPM PAHANG 2015

Question Explanation/Rubric Maximumscore

1(b)(i) Able to plot a graph that contains the following information.

- Axes labeled with units- All the 8 points transferred correctly- A smooth curve is drawn

Sample answer:

Temperature/oC

Time/second

3

Question Explanation/Rubric Maximumscore

1(a) Able to record all reading accurately to one decimal point and with unit.

Sample answer:Initial temperature : 60.0oCTemperature at 30s : 68.0 oCTemperature at 60s : 78.0 oCTemperature at 90s : 80.0 oCTemperature at 120s : 80.0 oCTemperature at 150s : 80.0 oCTemperature at 180s : 82.0 oCTemperature at 210s : 85.0 oCTemperature at 240.0s : 95.0oC

3

Able to record all readings correctly without decimal point// Able to record 6-8 readings correctly

2

Able to record 3-5 readings correctly 1

No response or wrong response 0

https://cikguadura.wordpress.com/

Page 84: PEPERIKSAAN PERCUBAAN SIJIL PELAJARAN · PDF file[Jisim atom relatif: H=1, N=14, O=16;Isipadu molar gas = 24 dm3mol-1 pada keadaan bilik) A Hydrogen, nitrogen, ... Anion that exist

Question Explanation/Rubric Maximumscore

Able to plot the graph that contains the following information.

- Axes labeled without units// 6-7 points transferred correctly// a graph is not smooth

Sample answer:Temperature

Time

2

Able to give an idea to plot a graph 1

No response or wrong response or empty table 0

Question Explanation/Rubric Maximumscore

1(b)(ii) Able to state the melting point correctly with 1 decimal place and unitand show on the graph

Sample answer :

Temperature/oC

Melting point80.0 oC

Time/ second

3

Page 85: PEPERIKSAAN PERCUBAAN SIJIL PELAJARAN · PDF file[Jisim atom relatif: H=1, N=14, O=16;Isipadu molar gas = 24 dm3mol-1 pada keadaan bilik) A Hydrogen, nitrogen, ... Anion that exist

Question Explanation/Rubric Maximumscore

Able to state the melting point correctly with or without decimal placebut with correct unit only without showing on the graph// Able to state the melting point on the curve

Sample answer;

- Melting point of naphthalene : 80.0 oC // 80 oC //

Temperature/oC

Melting point

Time/ second

2

Able to state the melting point less accurately without unit and without 1decimal place // Able to show the melting point incorrectly;

Sample answer:- Melting point of naphthalene : 80 //

Temperature/oC

melting point

Time/ second

1

No response or wrong response 0

Page 86: PEPERIKSAAN PERCUBAAN SIJIL PELAJARAN · PDF file[Jisim atom relatif: H=1, N=14, O=16;Isipadu molar gas = 24 dm3mol-1 pada keadaan bilik) A Hydrogen, nitrogen, ... Anion that exist

Question Explanation/Rubric Maximumscore

1(c) Able to explain correctly according to 3 information :

- Heat energy absorbed- is used to overcome the forces of attraction between the

molecules/particles- So that the solid naphthalene can turn into liquid

Sample answer :Heat energy absorbed is used to overcome the forces of attractionbetween the molecules so that solid naphthalene can turn into liquid.

3

Able to explain less accurately

Sample answer :The heat energy is used to overcome the forces of attraction betweenmolecules / particles

2

Able to state an idea

Sample answer :The heat energy is used / absorbed

1

No response or wrong response 0

Question Explanation/Rubric Maximumscore

1(d) Able to classify all the compound correctly

Ionic compound covalent compoundPotassium bromide GlucoseZinc nitrate methanolSodium chloride ethyl ethanoate

3

Able to classify any 5 compound correctly. 2Able to classify at least 2 compound correctly 1No response or wrong response/ 0

Page 87: PEPERIKSAAN PERCUBAAN SIJIL PELAJARAN · PDF file[Jisim atom relatif: H=1, N=14, O=16;Isipadu molar gas = 24 dm3mol-1 pada keadaan bilik) A Hydrogen, nitrogen, ... Anion that exist

Question Explanation/Rubric Maximumscore

2 (a) Able to state any 3 observations and their related inferences correctly.Sample answer:

Testtube

ObservationsPemerhatian

InferencesInferen

2 Low intensity of pinkcolour/ solutions

//No blue spot

Iron(II) / Fe2+ ions are not formed/produced in the solutions //Zinc/Zn corroded / oxidized slowly //less OH- ions formed //

Iron / Fe does not rust/corrode/oxidised

3 Low intensity of bluecolour /solutions//

Low intensity of pinkcolour/ solutions

Less Iron(II) / Fe2+ ions formed /produced in the solutions //Iron / Fe rusted/ corroded/ oxidizedslowly //

less OH- ions formed //

4 High intensity of pinkcolour/ solutions

//No blue spot

Iron(II) / Fe2+ ions are not formed/produced in the solutions //Magnesium/Mg corroded /oxidizedfaster // more OH- ions formed

Iron / Fe does not rust/corrode/oxidised //

6

Able to state at least 5 observations and their related inferencescorrectly // less correctly

5

Able to state at least 4 observation af inferens correctly// 4Able to state at least 3 observation af inferens correctly 3Able to state at least 2 observation af inferens correctly 2Able to state at least 1 observation af inferens correctly 1No response or wrong response 0

https://cikguadura.wordpress.com/

Page 88: PEPERIKSAAN PERCUBAAN SIJIL PELAJARAN · PDF file[Jisim atom relatif: H=1, N=14, O=16;Isipadu molar gas = 24 dm3mol-1 pada keadaan bilik) A Hydrogen, nitrogen, ... Anion that exist

Question Explanation/Rubric Maximumscore

2 (b) Able to state the relationship between the manipulated variable and theresponding variable and state the direction correctly.

Sample answerWhen a less electropositive metal than iron is in contact with ironnail/ferum/Fe, the metal speeds up rusting/corrosion of iron but when amore electropositive metal is in contact with iron/ferum/Fe, the metalinhibits rusting/corrosion of iron //

When the metal in contact with iron is lower than iron/ferum/Fe inelectrochemical series, the rusting/corrosion of iron is faster but whenthe metal in contact with iron is higher than iron/ferum/Fe inelectrochemical series, the iron does not rust/ rusting/corrosion of ironslower//

The further the distance between less electropositive metals andiron/Fe in electrochemical series that in contact with iron, the higher isthe intensity/more of blue spots formed but the further the distancebetween more electropositive metals and iron/Fe in electrochemicalseries that in contact with iron, the higher is the intensity/more of pinccolour formed.

3

Able to state the relationship between the manipulated variable and theresponding variable without stating the direction/ less accurately

Sample answer

When different metal in contact with iron, the more blue spot/rustformed

2

Able to give an idea of hypothesis

Sample answer

Pair of metal will produce rust

1

No response or wrong response 0

Page 89: PEPERIKSAAN PERCUBAAN SIJIL PELAJARAN · PDF file[Jisim atom relatif: H=1, N=14, O=16;Isipadu molar gas = 24 dm3mol-1 pada keadaan bilik) A Hydrogen, nitrogen, ... Anion that exist

Question Explanation/Rubric Maximumscore

2 (c) Able to state all the variables in this experiment correctly.

Sample answer(i) Manipulated variables : Type/different metal // position of metal in

electrochemical series(ii) Responding variable : Rusting / corrosion // presence of blue/pink

colour(iii) Constant variable : Size/mass of iron nail // type of nail // clean iron

nails // temperature // medium in which the ironnail are kept

3

Able to state any two variables correctly 2

Able to state any one variable correctly 1

No response or wrong response 0

Question Explanation/Rubric Maximumscore

2 (d) Able to give one operational definition of the experiment correctly withthe following aspects:i.what you doii.what you observe

Sample answer

Blue spot form when less electropositive metal is in contact with ironnail and dipped/put into jelly solutions that contain potassiumhexacyanoferrate (III) and phenolphthalein//Rusting occurs when iron nail is in contact with tin/less electropositivemetal and form blue colouration in potassium hexacyanoferrate(III)solution and phenolphthalein

//No blue spot form when more electropositive metal is in contact withiron nail and dipped/put into jelly solutions that contain potassiumhexacyanoferrate (III) and phenolphthalein //Rusting does not occurs when iron nail is in contact with Mg/Zn/moreelectropositive metal and form blue colouration in potassiumhexacyanoferrate(III) solution and phenolphthalein

// (based on test tube 1)Blue spot form when iron nail dipped into jelly solutions that containpotassium hexacyanoferrate (III) and phenolphthalein

3

Page 90: PEPERIKSAAN PERCUBAAN SIJIL PELAJARAN · PDF file[Jisim atom relatif: H=1, N=14, O=16;Isipadu molar gas = 24 dm3mol-1 pada keadaan bilik) A Hydrogen, nitrogen, ... Anion that exist

Question Explanation/Rubric Maximumscore

Able to give the operational definition for rusting incompletely with anyone of the following aspects:i.what you doii.what you observe

Sample answer

Metal is put into jelly blue spot form

2

Able to give an idea of operational definition for rusting

Sample answer

Iron corrodes/rust/oxidised

1

No response or wrong response 0

Question Explanation/Rubric Maximumscore

2 (e) Able to predict the metal Q correctly

Sample answerCopper/Cu // Silver/Ag

3

Able to predict the metal Q less correctly

Sample answerGold/Au

2

Able to give an idea of predicting the metal

Sample answerMercury/Hg

1

No response or wrong response 0

Page 91: PEPERIKSAAN PERCUBAAN SIJIL PELAJARAN · PDF file[Jisim atom relatif: H=1, N=14, O=16;Isipadu molar gas = 24 dm3mol-1 pada keadaan bilik) A Hydrogen, nitrogen, ... Anion that exist

Question Explanation/Rubric Maximumscore

3 (a) Able to state the problem statement with the named strong acidsolution and weak acid solution accuratelySample answer :Does the heat of neutralisation between hydrochloric acid and sodiumhydroxide solution is higher than the heat of neutralisation betweenethanoic acid and sodium hydroxide solution?

3

Able to state the problem statement less accuratelySample answer :Does the heat of neutralization between strong acid and weak acidwith strong alkali different ? //To study the heat of neutralizationbetween strong and weak acid with strong alkali.

2

Able to state an idea about problem statementSample answer :Heat of neutralisation is affected by the strength of acid.

1

No response or wrong response 0

Question Explanation/Rubric Maximumscore

3 (b) Able to state the relationship between the manipulated variable and theresponding variable and state the direction correctly.

Sample answer :The reaction between hydrochloric acid/strong acid and sodiumhydroxide will give the higher value of heat of neutralization than thereaction between ethanoic acid/weak acid with sodium hydroxide.

3

Able to state the relationship between the manipulated variable and theresponding variable without stating the direction/ less accurately

Sample answer

Different strength of acid react with sodium hydroxide, different value ofheat of neutralisation

2

Able to give an idea of hypothesis

Sample answer

The strength of acid affect the heat of neutralisation

1

No response or wrong response 0

https://cikguadura.wordpress.com/

Page 92: PEPERIKSAAN PERCUBAAN SIJIL PELAJARAN · PDF file[Jisim atom relatif: H=1, N=14, O=16;Isipadu molar gas = 24 dm3mol-1 pada keadaan bilik) A Hydrogen, nitrogen, ... Anion that exist

Question Explanation/Rubric Maximumscore

3 (c) Able to state all the variables accuratelySample answer :Manipulated variable: Hydrochloric Acid and Ethanoic Acid (any

suitable named strong and weak acid)// Strong acid and weak acid

Responding variable : Heat of neutralisationFixed variable : Concentration and volume of NaOH

solution//NaOH solution//polystyrene cup //Concentration and volume of acid solution

3

Able to give any two variables accurately 2

Able to give any one variable accurately 1

No response or wrong response 0

Question Explanation/Rubric Maximumscore

3 (d) Able to list down the materials and apparatus completelySample answer :Materials : [0.5-2.0 mol dm-3 ] sodium hydroxide solution,

[0.5-2.0 mol dm-3 ] hydrochloric acid, [0.5-2.0 mol dm-3 ]ethanoic acid (any suitable strong and weak named acid),

Apparatus :Polystyrene/plastic cup, thermometer, [50-100cm3]measuring cylinder

3

Able to give the list of the apparatus and materials correctly but notcomplete

Sample answer :sodium hydroxide solution, hydrochloric acid / ethanoic acid,Polystyrene/plastic cup, thermometer,

2

Able to give an idea on the list of the apparatus and substancescorrectlyAny one materials and one apparatus with thermometer

1

No response or wrong responsereject : no thermometer

0

Page 93: PEPERIKSAAN PERCUBAAN SIJIL PELAJARAN · PDF file[Jisim atom relatif: H=1, N=14, O=16;Isipadu molar gas = 24 dm3mol-1 pada keadaan bilik) A Hydrogen, nitrogen, ... Anion that exist

Question Explanation/Rubric Maximumscore

3 (e) Able to state all the steps of the experiment accuratelyExample1. [25-100 cm3 ] of sodium hydroxide solution is poured into a

polystyrene cup using a measuring cylinder.2. The initial temperature of sodium hydroxide solution is recorded.3. [25-100 cm3 ] of hydrochloric acid is measured into another

polystyrene cup.4. The initial temperature of hydrochloric acid is recorded.5. Hydrochloric acid is then poured quickly into a cup containing

sodium hydroxide solution.6. The mixture is stirred using thermometer and the highest

temperature is recorded.7. Repeat steps 1 to 6 using ethanoic acid instead of hydrochloric

acid.

3

Able to state 5 steps of the experimentSteps 2, 4, 5, 6, 7

2

Able to state 2 minimum steps correctlySteps 5, 6

1

No response or wrong response 0

Page 94: PEPERIKSAAN PERCUBAAN SIJIL PELAJARAN · PDF file[Jisim atom relatif: H=1, N=14, O=16;Isipadu molar gas = 24 dm3mol-1 pada keadaan bilik) A Hydrogen, nitrogen, ... Anion that exist

Question Explanation/Rubric Maximumscore

3 (f) Able to construt the table that contains the following information1. Columns and rows2. Headings in the table3. With unit

Sample answer:

Pair of acid/alkaliInitial temperature/ oC Highest temperature

of the mixture/o C

Acid Alkali Average

NaOH/HCl

NaOH/CH3COOH

2

Able to construt the table that contains the following information1. Columns and rows2. Headings in the table3. Without unit

// Able to state an idea about the tabulation of dataTabulation of data has the following elements :1. minimum 2 columns and 2 rows

Sample answer :

Pair of acid/alkali

Initial temperature Highesttemperature of

the mixture

Acid Alkali

//Sample answer :

1

No response or wrong response 0

END OF MARKING SCHEME