penang_jitsin trial stpm 2012 mathst paper 1(q&a)

7/31/2019 Penang_jitsin Trial Stpm 2012 Mathst Paper 1(Q&A)

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T r i a l T r i a l T r i a l T r i a l S T P M S T P M S T P M S T P M P e n a n g P e n a n g P e n a n g P e n a n g J i t J i tJ i tJ i t S i n S i nS i nS i n 2 0 1 2 2 0 1 2 2 0 1 2 2 0 1 2 M a t h e m a t i c s M a t h e m a t i c s M a t h e m a t i c s M a t h e m a t i c s P a p e r P a p e r P a p e r P a p e r 1 111 - 1 -

A n s w e r A n s w e r A n s w e r A n s w e r a l l a l la l la l l q u e s t i o n s . q u e s t i o n s . q u e s t i o n s . q u e s t i o n s .

1 . S o l v e t h e i n e q u a l i t y [ 6 m a r k s ]

2 . F i n d t h e v a l u e s o f x a n d y i f - (4+ i ) = x + i y . [ 4 m a r k s ]

3 . G i v e n f ( x ) = x 3 + m x2 - 8 x + n , w h e r e m a n d n a r e c o n s t a n t s .

W h e n x = - 2 , f ( x ) = 0 a n d w h e n f ( x ) i s d i v i d e d b y x - 1 , t h e

r e m a i n d e r i s - 1 8 . F i n d t h e v a l u e s o f m a n d n . [ 5 m a r k s ]

S o l v e t h e e q u a t i o n f ( x ) = 0 a n d f i n d t h e s e t o f v a l u e s o f x s u c h

t h a t f ( x ) 0 . [ 4 m a r k s ]

4 . a ) E x p r e s s i n p a r t i a l f r a c t i o n s . [ 4 m a r k s ]

b ) H e n c e , o r o t h e r w i s e , s h o w t h a t

w h e r e a a n d b a r e i n t e g e r s t o b e f o u n d . [ 5 m a r k s ]

c ) D e t e r m i n e t h e l i m i t o f . [ 3 m a r k s ]

5 . T h e m a t r i x RRRR i s d e f i n e d b y RRRR =

G i v e n t h a t RRRR3333 = kIIII w h e r e k i s a c o n s t a n t a n d IIII i s a 3 X 3 i d e n t i t y m a t r i x ,

d e t e r m i n e t h e v a l u e o f k . H e n c e , f i n d RRRR- 1- 1- 1- 1. [ 8 m a r k s ]

6 . T h e f u n c t i o n fa n d ga r e d e f i n e d a s :

x x > 0

a ) S k e t c h t h e g r a p h o f f a n d s t a t e w h e t h e r e x i s t . [ 3 m a r k s ]

b ) F i n d g- 1 a n d s t a t e i t s d o m a i n . [ 3 m a r k s ]

c ) F i n d t h e c o m p o s i t e f u n c t i o n f g- 1 a n d s t a t e i t s r a n g e . [ 3 m a r k s ]


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7 . T h e f u n c t i o n f i s d e f i n e d a s f ( x ) =

C x > 4

a ) F i n d a n d [ 4 m a r k s ]

b ) D e t e r m i n e t h e v a l u e s o f A a n d B i f f i s c o n t i n u o u s a t x = 3 . [ 3 m a r k s ]

c ) F i n d t h e v a l u e o f C i f f i s c o n t i n u o u s a t x = 4 . [ 3 m a r k s ]

8 . S h o w t h a t t h e e q u a t i o n o f t h e t a n g e n t t o t h e p a r a b o l a y 2 = 4 a x a t

t h e p o i n t P ( a p 2, 2 a p ) i s p y = x + a p 2. T h e t a n g e n t i n t e r s e c t s t h e l i n e x + a = 0 a t T . F i n d , i n t e r m s o f a a n d p , t h e c o o r d i n a t e s f o r t h e m i d -

p o i n t o f P T .

P r o v e t h a t , f o r a l l v a l u e s o f p , t h i s m i d - p o i n t l i e s o n t h e c u r v e

y2 ( 2 x + a ) = a ( 3 x + a ) 2. [ 1 1 m a r k s ]

9 . a ) F i n d t h e e q u a t i o n o f t h e a s y m p t o t e s o f t h e c u r v e [ 2 m a r k s ]

b ) F i n d t h e p o i n t s w h e r e t h e c u r v e i n t e r s e c t s t h e x - a x i s a n d y - a x i s , a n d f i n d

t h e s t a t i o n a r y p o i n t s o f t h e c u r v e . [ 1 0 m a r k s ]

c ) S k e t c h t h e c u r v e . [ 4 m a r k s ]

d ) D e t e r m i n e t h e v a l u e s o f k f o r w h i c h t h e e q u a t i o n ( x - 3 ) = k ( x - 2 ) ( x + 1 )

d o e s n o t h a v e a n y r e a l r o o t s . [ 1 m a r k ]

1 0 . B y u s i n g s u b s t i t u t i o n x = 2 s i n . E v a l u a t e [ 5 m a r k s ]

1 1 . G i v e n t h a t t a n x = 1 + t a n y , f i n d i n t e r m s o f x a n d y . F i n d , i n t e r m s o f h ,

t h e a p p r o x i m a t e i n c r e a s e i n y w h e n x i n c r e a s e s f r o m t o w h e r e h i s

s m a l l . [ 5 m a r k s ]

1 2 . F i n d t h e v o l u m e o f t h e s o l i d f o r m e d w h e n t h e e l l i p s e w i t h t h e e q u a t i o n

= 1 i s r o t a t e d 3 6 0 o a b o u t t h e y - a x i s . [ 4 m a r k s ]


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penang_jitsin trial stpm 2012 mathst paper 1(q&a)

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