mte3110 kaedah adjoin

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MTE3110 KAEDAH MENCARI SONGSANG – KAEDAH ADJOIN A = [ a 11 a 12 a 13 b 21 b 22 b 23 c 31 c 32 c 33 ] LANGKAH 1: HITUNGKAN PENENTU MATRIKS |A| = ( a 11 ) (−1) 1+1 | b 22 b 23 c 32 c 33 | + ( a 12 ) (−1) 1+ 2 | b 21 b 23 c 31 c 33 | + ( a 13 ) (−1 ) 1 +3 | b 21 b 22 c 31 c 32 | LANGKAH 2: HITUNGKAN MATRIKS KOFAKTOR [ a 11 = | b 22 b 23 c 32 c 33 | =x 11 a 12 =− | b 21 b 23 c 31 c 33 | =x 12 a 13 = | b 21 b 22 c 31 c 32 | =x 13 b 21 =− | a 12 a 13 c 32 c 33 | =y 21 b 22 = | a 11 a 13 c 31 c 33 | =y 22 b 23 =− | a 11 a 12 c 31 c 32 | =y 23 c 31 = | a 12 a 13 b 22 b 23 | =z 31 c 32 =− | a 11 a 13 b 21 b 23 | =z 32 c 33 = | a 11 a 12 b 21 b 22 | =z 33 ] MTE3110 – ALICIAJUNEAJEN – T3MT1 – 2014

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Page 1: MTE3110 Kaedah Adjoin

MTE3110

KAEDAH MENCARI SONGSANG – KAEDAH ADJOIN

A=[a11 a12 a13b21 b22 b23c31 c32 c33

]LANGKAH 1: HITUNGKAN PENENTU MATRIKS

|A|=(a11)(−1)1+1|b22 b23c32 c33|+(a12)(−1)1+2|b21 b23

c31 c33|+(a13 )(−1)1+3|b21 b22c31 c32|

LANGKAH 2: HITUNGKAN MATRIKS KOFAKTOR

[ a11=|b22 b23c32 c33|=x11 a12=−|b21 b23

c31 c33|=x12 a13=|b21 b22c31 c32|=x13

b21=−|a12 a13c32 c33|= y21 b22=|a11 a13

c31 c33|= y22 b23=−|a11 a12c31 c32|= y23

c31=|a12 a13b22 b23|=z31 c32=−|a11 a13

b21 b23|=z32 c33=|a11 a12b21 b22|=z33 ]

LANGKAH 3: DAPATKAN MATRIKS ADJOIN DENGAN MELAKUKAN TRANSPOSISI MATRIKS KOFAKTOR

MTE3110 – ALICIAJUNEAJEN – T3MT1 – 2014

Page 2: MTE3110 Kaedah Adjoin

[ x11 x12 x13y21 y22 y23z31 z32 z33

]T

→[ x11 y21 z31x12 y22 z32x13 y23 z33

]LANGKAH 4: GANTIKAN KE DALAM RUMUS

A−1= 1|A|

adj(A )

MTE3110 – ALICIAJUNEAJEN – T3MT1 – 2014