modul mke refrigerasi prof amiral aziz msc apu

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MESIN KONVERSI ENERGI Prof. Ir. Amiral Aziz, MS.c. APU MESIN REFRIGERASI

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Page 1: Modul Mke Refrigerasi Prof Amiral Aziz MSc APU

MESIN KONVERSI ENERGI

Prof. Ir. Amiral Aziz, MS.c. APU

MESIN REFRIGERASI

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MESIN REFRIGERASI

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Principles of Refrigeration

Refrigeration means to

COOL AN OBJECT BELOW ITS SURROUNDING TEMPERATURE

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Vapour Compression Cycle

CONDENSER

EVAPORATOR

COMPRESSOREXPANSION VALVE

2

1

3

4

Basic Components of the vapour compression refrigeration system

• Compressor• Condenser• Throttling Device• Evaporator

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Vapour Compression CyclePRESSUR

E

COMPRESSION

CONDENSATION

EVAPORATION

THROTTLING

REFRIGERATION EFFECT WORK DONE

CONDENSER HEAT REJECTION

ENTHALPY

KN/m2

KJ/Kg

Pd

Pe 1

23

4

CONDENSER

EVAPORATOR

COMPRESSOREXPANSION VALVE

2

1

3

4

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Ideal Vapour Compression Cycle

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Ideal Vapour Compression Cycle

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Actual Vapour Compression Cycle

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VAPOUR COMPRESSION CYCLECOMPONENTS

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REFRIGERANTSCHLOROFLUOROCARBONS (CFC)

• R-11• R-12

HYDROCHLOROFLUOROCARBONS (HCFC)R- 22R-123

HYDROFLUOROCARBONS (HFC)R-32R-125R-134aR-143a

INORGANIC COMPOUNDSR- 717R- 718R- 729

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Unit of Refrigeration

The unit of refrigeration is TON OF REFRIGERATION ( TR )1 TR = 12’000 Btu/hr BRITISH UNITS

1 TR = 3.517 KW SI UNITS

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Refrigeration Cycle Efficiency

The refrigeration cycle efficiency is known asCOEFFICIENT OF PERFORMANCE (COPREF) (COPREF) = Refrigeration Effect KJ/Kg

Work Done KJ/Kg

(COPHP) = Condenser Heat Rejection KJ/Kg

Work Done KJ/Kg

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Refrigeration Equipment Efficiency

The equipment efficiency is given as EER or kW/TRENERGY EFFICIENCY RATIO (EER) Use for smaller capacity equipment such as Window type & Split type

equipment(EER) = Capacity Btu/hr

Power Input Watts

kW/TR Use for large capacity equipment such as Chillers

(kW/TR) = Power Input kW

Capacity TR

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P-h DIAGRAM FOR REFRIGERANT 134a

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1. Face-out of CFC in year 20052. Introduction of Quota for HCFC in

year 20153. Face-out of HCFC in year 2040

MONTRÉAL PROTOCOL OBLIGATIONS

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ASHRAE Standard 34-1992 Refrigerant Safety Classifications

Group A3 Group B3

Group A2 Group B2

Group A1 Group B1

INC

RE

AS

ING

FLA

MM

AB

ILIT

Y

INCREASING TOXICITY

HigherFlammability

LowerFlammability

No FlamePropagation

LowerToxicity

HigherToxicity

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Refrigerant Data & Safety Classifications

REFRIGERANT CHEMICALFORMULA

CHEMICALNAME

REFRIGERANTSAFETYCLASSIFICATION

AMOUNT OF REFRIGERANTPER OCCUPIEDSPACE (ppm)

TLV-TWA(ppm)

R-11 CCl3 Trichlorofluoromethane A1 4’000 C1’000

R-12 CCl2F2 Dichlorodifluoromethane A1 40’000 1’000

R-22 CHClF2 Chlorodifluoromethane A1 42’000 1’000

R-134a CH2FCF3

1,1,1,2-tetrafluoroethane A1 60’000 1’000

R-717 NH3 Ammonia B2 500 25

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• In-expensive Refrigerant best suited for industrial use

• Higher refrigeration effect 474 Btu/lb,comparison; R-12 = 50 Btu/lb , R-22 = 70 Btu/lb, R-134a = 64 Btu/lb, R-404A = 48 Btu/lb 7- times higher refrigeration effect!!!

• Specific volume of suction gas is high 8 ft3/lb compare to 1.2 ft3/lb of R-22, needs larger pipes, compressors

• Higher delivery temperatures 210 ºF, needs water cooled heads for compressor

AMMONIA (NH3) R-717

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COOLING TOWER (CT)INDUCED DRAUGHT

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COOLING TOWER (CT)CROSS FLOW

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COOLING TOWER (CT)FORCED DRAUGHT

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WATER PUMPSVERTICAL IN-LINE

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COMPRESSED AIR SYSTEMS

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Provides air under compression to pneumatic drives

Use reciprocating or screw compressors with storage receiver

Use pressure regulators at the air user point to reduce the air pressure

Use water separators to prevent water vapour entering the air user equipment

Compressed air system provides……..

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ROTARY SCREW COMPRESSORS

Pulsation free air 100% continuous duty Quiet operation Energy efficient at full load Extended service intervals Reliable long life Improved air quality

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The temperature limits of an ammonia refrigerating system are 25° C and - 10° C. If the gas is dry at the end of compression, calculate the coefficient of performance of the cycle assuming no undercooling of the liquid ammonia. Use the following table for properties of ammonia :

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Since the entropy at point 1 is equal to entropy at point 2, therefore equating equations (i) and (ii),0.5443 + 4.934 Z1 = 5.04

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A water cooltr using R-12 works on the condensing and evaporatingtemperatures of 26° C and 2° C respectively. The vapour leaves theevaporator saturated and dry. The average output of cold water is 100kgjhr cooled from 26° C to 6°C. Allowing 20% of useful heat into watercooler and the volumetric efficiency of the compressor as 80% andmechanical efficiency of the compressor and the electric motor as 85%and 95% respectively, find (a) volumetric displacement of the compressor,and (b) power of the motor. Data for R-12 is given below

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T-s and p-H diagrams are shown in Fig. 4-12 (a) and (b)respectively. Since 20% of the usefJ heat is lost into watercooler therefore, actual heat extracted from the water cooler

We know that heat extracted or the net refrigerating effectper kg of the refrigerant

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(b) Power of the motorFirst of all, let us 8nd the temperature at point 2 (T2). We know thatentropy at point 2,

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A vapour compression refrigeration plant works between pressurelimits of 5-3 bar and 2'1 bar. The, vapour is superheated at the endof compression, its temperature being 37° C. The vapour issuperheated by 5° C before entering the compressor. If the specificheat of superheated vapour is 0,63 kJjkg.K, find the coefficient ofperformance of the plant. Use the data given below :

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The T-s and p-H diagrams are shown in Fig. 4-14 (a) and (b) respectively

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A food storage lorkcr requires a refrigeration capacity of 12 TR andworks between the evaporating temperature of —8°C andcondensing temperature of 30° C, The refrigerant R-12 is subcooledby 5° C before entry to expansion valve and the vapour issuperheated to—2° C before leaving the evaporator coils. Assuminga two cylinder single acting compressor operating at WOO r p.m.with stroke equal to 1-5 times the bore, determine (a) coefficient ofperformance, (b) theoretical power per ton of refrigeration, and (c)bore and stroke of compressor when (i) there is no clearance, and-(ii) there is a clearance of 2%.Use the following data for R-12

The specific heat of liquid R-12 is 1-235 kJ/kg °K, and ofvapour R-12 is 0'733 kJ/kg °K

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The T-s and p-H diagrams are shown in Fig. 4.26 (a) and (b)respectively,(a) Coefficient of performance

First of all, let us find the temperature of superheated vapour atpoint 2 (T2).

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We know that entropy at point 1

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Since the entropy at point 1 is equal to entropy at point 2,therefore equating equations (i) and (ii),

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(b) Theoretical power per ton of refrigerationWe know that the heat extracted or refrigerating effect per kg of therefrigerant,

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First of all, let us find the specific volume at suction to thecompressor, i.e. at point 1. Applying Charles1 law

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(i) When there is no clearanceWe know that theoretical suction volume or piston displacement per minute

= 0.0245 m3/kg

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We know that volumetric efficiency of the compressor,

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THANK YOU

Prof. Ir. Amiral Aziz, MS.c. APU

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