Download - Physics Spm
SULIT 4531/1
4531/1 © 2013 Hak Cipta BPSBPSK SULIT
1
PENTAKSIRAN DIAGNOSTIK AKADEMIK SBP
SIJIL PELAJARAN MALAYSIA 2013
MATAPELAJARAN FIZIK
SKEMA JAWAPAN KERTAS 1
NO. SOALAN JAWAPAN NO. SOALAN JAWAPAN
1 C 26 C
2 B 27 D
3 D 28 B
4 B 29 D
5 B 30 C
6 D 31 A
7 C 32 D
8 A 33 B
9 B 34 D
10 D 35 B
11 B 36 A
12 C 37 D
13 C 38 C
14 C 39 B
15 B 40 D
16 C 41 D
17 A 42 A
18 A 43 A
19 D 44 B
20 A 45 C
21 C 46 C
22 B 47 D
23 C 48 C
24 B 49 B
25 B 50 A
1
PENTAKSIRAN DIAGNOSTIK AKADEMIK SBP
SIJIL PELAJARAN MALAYSIA 2013
MATAPELAJARAN: FIZIK
SKEMA JAWAPAN KERTAS 2
No Answer Marks Total
1 (a) length 1
(b) Tail 1
(c) to measure depth 1
(d) 0.42 cm 1
Total 4
No Answer Marks Total
2 (a) Product of an applied force and displacement / distance //Force X distance
1 1
(b) W = F X S M1 = 110 x0.5 M2 = 55 J / Nm
1 1
2
(c) F = ma M1 110 – 100 = 10 (a) M2 10 = 10 a a = 1 ms-2
1 1
2
Total 5
No Answer Marks
Total
3 (a) Thermionic emission
1
(b) Uniform acceleration
1
(c) (i) VP = 4 V 1
(ii)
T = 3 x 0.02 = 0.06 s
f = 16.7 Hz
1
(iii) Sinusoidal with one complete cycle 1
2
Total 6
No Answer Marks Total
4 (a) The amount of heat energy required to increase the the
temperature of 1kg mass by 10 C.
1 1
(b) Pt = mcӨ
c = 48(900)
60
= 720 J kg-1 0
C-1
2 2
(c) M1 Land has a smaller specific heat capacity than sea
// Land faster increase in temperature // Land is
warmer than the sea
M2 Air above the land is heated up and rises
M3 Cooler air from the sea moves towards the land
Or diagram
M1 Label Sea(cold), Land (Hot)
M2 Show Hot air on land rises up
M3 Show Cold air moves towards the sea
1
1
1
3
(d) Sea breeze 1 1
7
No Answer Marks Total
5 (a)(i) Spring balance reading: diagram 5.1 > 5.2 1
(ii) Buoyant force / Upthrust 1 2
3
(b)(i) Spring balance reading: diagram 5.3 > 5.2 1
(ii) Density of water > density of oil 1
(iii) As density of liquid increases, buoyant force increases 1 3
(c)(i) pressure at Y > pressure at X // vice versa // Y is at
greater depth than X // pressure is directly proportional to
depth.
1
1
(ii) Buoyant force = (Difference in pressure) x A 1 3
Total 8
No Answer Marks Total
6 (a) Longitudinal waves // Mechanical wave 1 1
(b) 1. Loud sound - when antinodes/crest/trough
overlapped/meet/encounter another
antinodes/crest/trough, a constructive interference
occur
2. Soft sound – when nodes/crest/trough
overlapped/meet/encounter another nodes/ trough,
a destructive interference occur
1
1
2
(c) (i) Diagram 6.1 > Diagram 6.2 // vice-versa 1
(ii) Diagram 6.1 < Diagram 6.2 // vice-versa 1
(iii) a α 1 3
(d) M1 frequency// wavelength
M2 amplitude
M3 Distance between loud speaker and observer
(Any two)
1
1
2
8
No Answer Marks Total
7 (a) Reflection 1 1
(b) (i) 1
1
1
3
4
(ii) Virtual // Upright // Diminished 1 1
(c) 1. Aim the concave mirror to the sun
2. parallel ray from sun reflected and focus to F
3. amount of heat increases as all rays focus at F
Max : 2 points
1
1
2
(d) (i) 1. lens Q
2. f is smaller
1
1
1
(ii) Use concave mirror 1
1
Total 10
No. Answers Marks
8 (a) When a potential difference of 9V is connected across the
bulb, it will produce power of 20J per second.
1 1
(b) (i) P = V/I
20W = 9V/I
I = 20W/9V
= 2.22A
1
1
2
(ii) R = V/I
= 9V/2.22A
= 4.05 Ω
1
1
2
(c) (i) The more the thickness of the wire, the lower the loss of
energy from the filament.
1
2
(ii) Efficiency = Energy Output / Energy Input x 100%
E Filament P = 15 x 100 %
20
= 75.00%
E Filament Q = 28 x 100 %
30
= 93.33%
E Filament R = 43 x 100 %
50
= 86.00%
1
1
1
1
5
(iii) Filament Q has highest efficiency 1
1
2
Total 12
No Answer Marks Total
5
9 (a) (i) Property of material that enable it to return to its original
shape and size after an external force that acting on it is
removed
1
(ii) Compression of the spring in Diagram 9.2(a) is higher
than 9.1 (a)
Distance moved by the trolley in Diagram 9.2 (b) is
further than 9.1 (a)
Elastic potential energy of the spring Diagram 9.2(a) is
higher than 9.1 (a)
The higher the compression, the further the distance
moved by the trolley
The bhigher the compression, the higher the elastic
potential energy
1
1
1
1
1
(b) The forces between atom are attractive force and
repulsive force
When the force is applied , the distance between atoms
decreases
The repulsive force is acted on the atoms
When applied force is removed, repulsive force pushes
the atoms back to original
1
1
1
1
(c)
Design Reasons
Many springs
(arranged in parallel) High elasticity
Strong material for
frame // steel
Not break easily //
Not rust easily
Low spring constant To get more extension
Nylon// polyethene//
strong fabric Does not tear easily
Has net around / /
bigger diameter of
trampoline
Prevent children from
slipping to the floor
2
2
2
2
2
2
6
Total 20
No Answer Mark Total
10 (a) A magnetic field is a region in which a magnetic material
will experience a magnetic force
1 1
(b) The number of turns of the coils shown in diagram 10.2
is greater than 10.1
The pattern of magnetic field in diagram 10.2 is denser
than 10.1
The deflection of ammeter in diagram 10.2 is bigger than
10.1
1
1
1
3
(c) The closer the pattern of magnetic field // the denser of
magnetic field, the greater the strength of the magnetic
field.
The strength of the magnetic field increase when the
number of turns of coils increase
1
1
2
(d) (i) 1. Repel each other
1 1
(ii) 1. When current flows, magnetic field is form //
Diagram
2. Direction of magnetic field at the centre is the same
// Magnitude of magnetic field is stronger at the
centre // Diagram
3. Two forces produced is in opposite direction //
Diagram
1
1
1
3
(e) Modification Explanation
More number of
turn for the coil/
Increase the strength of
magnetic field // increase the speed of
motor
Has commutator To reverse the current flow
in the coil // ensure core
1,1
Force Force
7
rotate in one direction
Brush Enable current flow through the coil
Semicircular
magnet // curved
magnet
To produce radial magnetic field
Soft iron core Concentrate the magnetic field.
1,1
1,1
10
Total 20
11 (a) Archimedes’ Principle states that the buoyant force is
equal to the weight of fluid displaced.
1 1
(b) 1.Density of air decreases as altitude increases
2.Bouyant force become smaller
3.At certain height, weight of displaced air equal to
weight of the balloon.
4.Net force zero
1
1
1
1
4
(c) Characteristics Explanation
Fiber composite Light and strong
Bigger volume High buoyant force
The distance between
plimsoll line from the
surface of the sea is high
Can carry more load
Bigger size of the
propeller
To produce greater
forward thrust
Q is chosen the body is made from
fibre composite, volume
is bigger, the distance
between plimsoll line
from the surface of the
sea is higher and bigger
size of the propeller
2
2
2
2
2
10
(d) (i) F = ρgv
= 1020 × 10 × 5
= 51000 N
1
1
2
(ii) Total weight
15000 + W = 51000 N
W = 36000 N
1
1
1
3
8
Total 20
No Answer Marks Total
12 (a)
Cosmic ray// radiation from surrounding
//radioactive materials from earth// leakage of
radioactive from nuclear power plant
1
1
(b)(i) Alpha 1 1
(ii) 1. The ray ionises the air molecule
2. Negative ions attracted to the plate
3. Neutralised the electroscope
1
1
1
3
(c) Characteristics Reasoning
Liquid Easy to flow with blood
Short half life Not long in the body //
less harmful
Gamma Ray Cannot ionised the
living cell // high
penetrating power
GM tube detector Can detect ray
effectively// portable
K is chosen Because it is in liquid
state , has short half
life, emits gamma ray
and can be detected
easily detected by GM
tube detector.
2
2
2
2
2
10
9
(d)(i) (i) m = [235.04392 + 1.00867] – [140.91963 +
92.92157 + 2(1.00867)]
= [236.05259] – [ 235.85854]
= 0.19405u
m = 0.19405 x 1.66 x 10 -27
= 0.0322 x 10 -27
= 3.22123 x 10-28
kg
1
1
1
3
(ii)
E = mc 2
= (3.22123 x 10-29
) (3.0 x 10 8) 2
= 28.99107 x 10-12
= 2.899107 x 10 -11
J
1
1
2
Total 20
1
PENTAKSIRAN DIAGNOSTIK AKADEMIK SBP
SIJIL PELAJARAN MALAYSIA 2013
MATAPELAJARAN: FIZIK
SKEMA JAWAPAN KERTAS 3
SECTION A
No. 1 Answer Mark
(a) (i) Manipulated variable = Object distance, u // Image distance, v 1
(ii) Responding variable = Image distance, v // M 1
(iii) Constant variable = Thickness//focal length//power 1
(b) Tabulate u, v and m correctly in the table.
A Shows a table u,v and m.
B State the correct unit of u, v and m.
C At least 3 values of v are correct
D All values of v are correct
E At least 3 value of m are correct
F All values of m are correct
G State a consistent decimal place for u, v and m.
u/cm v/cm m
6.3 8.8 1.40
6.5 7.7 1.18
6.7 6.7 1.00
6.9 5.5 0.80
7.1 4.3 0.61
7
(c) Draw the graph of v against m .
A - Label y-axis and x-axis correctly
B - States the unit at the axis correctly
C - Both axes with the even and uniform scale:
D - 5 points correctly plotted:
E - a smooth best straight line
F - minimum size of the graph is 5 x 4 squares of 2 x 2 cm.
Draw the graph of v against m .
A - Label y-axis and x-axis correctly
B - States the unit at the axis correctly
C - Both axes with the even and uniform scale:
D - 5 points correctly plotted:
E - a smooth best straight line
F - minimum size of the graph is 5 x 4 squares of 2 x 2 cm.
No of ticks Score
6 5
5 4
2
3-4 3
2 2
1 1
5
(d) State the correct relationship based on the candidate’s graph
v is increasing linearly to m
1
TOTAL 16
No 2 Answer Mark
(a)(i) 1 increases // I decreases
I
1
(ii) 1.0 Ω 1
(b) Show a big on the graph to determine the gradient(5 x 4 blocks)
The correct 12
12
xx
yy
from the drawn
m = 5.14A (Ans + unit)
1
1
1
(c)
R = E ( 1 ) - r
I
E = gradient of the graph
= 5.14 V // 5.14 A
1
1
1
(d) Show line on graph to get 1/I
1/I =2.25
I = 0.44
1
1
1
(e) 1. The connection of the wires must be tight.
2. The circuit is switched off whenever the readings were not taken
from the meters. This is to reduce energy loss from the cell.
3. The eye is perpendicular to the scale of ammeter // Pointer’s image
is not seen on the mirror strip of ammeter.
Max 1 mark
1
Total 12
3
SECTION B
No Answer Mark
3 (a) State the suitable inference
The foot feels more painful when it is stepped on by an object that has
smaller surface area // Pressure depend on surface area
(b) State a relevant hypothesis
The smaller the surface area the greater the pressure
1
(c)
State the aim of experiment
To investigate the relationship between surface area and pressure.
1
State the suitable manipulated variables and responding variable
(Quantity that can be measured)
MV - surface area
RV - pressure/depth of depression
1
State the constant variable
CV – Weight/force/mass
1
State the complete list of apparatus and materials
Plasticine, slotted weight , wooden rod and meter rule
1
Draw the functional arrangement of the apparatus
1
State the method to control the manipulated variable The apparatus is set up as shown in the diagram.
Start the experiment with a wooden rod has surface area 1 cm2 .
Placed the load of mass 200 g on the top of wooden rod as shown on
diagram
1
State the method to measure the responding variable
Measure the depth of depression made on the plasticine
1
Repeat the experiment at least 4 times with the values
Repeat the experiment 4 times with surface area of rod 2 cm2, 3 cm
2 , 4
cm2 and 5cm
2
(Note : Based on SPM standard , at least five manipulated values
required.)
1
4
State how the data tabulated with the title MV and RV
Surface area Depth
1
2
3
4
5
1
State how the data is analysed, plot a graph RV against MV
1
TOTAL MARK 12
4(a) State the suitable inference
The brightness of the lamp increases when the speed of the magnet in the
coils(solenoid) increases// Induced current depend on the speed of
magnet
1
(b) State a relevant hypothesis
The magnitude of the induced current increases when the speed of the
magnet increases.
1
(c) State the aim of experiment
To study the relationship between the speed of a magnet in a coil and the
magnitude of the induced current.
1
State the suitable manipulated variables and responding variable
(Quantity that can be measured) Manipulated variables : the height of the magnet fall
Responding variables : Deflection/ reading of the galvanometer
1
State the constant variable
strenght of the magnet / number of the turns in the coils.
1
State the complete list of apparatus and materials
Bar magnet, cardboard tube, galvanometer, insulated copper wire, retort
stand and metre rule.
1
5
Draw the functional arrangement of the apparatus
1
State the method to control the manipulated variable 1. Make a solenoid of 50 turns by winding an insulated copper wire
round a cardboard tube. Connect the ends of the wire to a galvanometer.
2. Hold a small bar magnet at a height of h = 5 cm above the top end of
the solenoid.
1
State the method to measure the responding variable
3. Drop the magnet into the solenoid into the solenoid and record the
deflection of the galvanometer as the induced current.
1
Repeat the experiment at least 4 times with the values
4. Repeat the eksperiment by changing the height h to 10 cm, 15 cm, 20
cm , 25 cm and 30 cm.
1
State how the data tabulated with the title MV and RV
Height of the magnet,h Induced current I
5.0
10.0
15.0
20.0
25.0
30.0
1
State how the data is analysed, plot a graph RV against MV
1
TOTAL MARK 12
6
7
4c(viii) Tabulation of data:
Number of turns of
wire in secondary
coil, N
Output voltage, V
/ V
1
4c(ix) Analyse the data .
Voltage
No. of turns
1
TOTAL MARKS 12